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Giáo viên: LÊ BÁ BẢO Trường THPT Đặng Huy Trứ, Huế

SĐT: 0935.785.115 Địa chỉ: 116/04 Nguyễn Lộ Trạch, TP Huế

Nội dung: Lấy đối xứng đồ thị  C qua trục Ox

Nhận xét: Để từ đồ thị hàm số  C :yf x  biến đổi để có đồ thị hàm số  C :y  f x ta thực hiện

theo hai bước:

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và yf x  là hàm chẵn nên đồ thị  C nhận Oy làm trục đối xứng

* Cách vẽ  C từ  C :

+ Giữ nguyên phần đồ thị bên phải Oy của đồ thị  C :yf x 

+ Bỏ phần đồ thị bên trái Oy của  C , lấy đối xứng phần đồ thị được giữ qua Oy

Dạng 4: Từ đồ thị  C :yf x  suy ra đồ thị  C :yf x 

Nội dung: Ta có:      nÕu   

nÕu

0 0

+ Giữ nguyên phần đồ thị phía trên Ox của đồ thị (C): yf x 

+ Bỏ phần đồ thị phía dưới Ox của (C), lấy đối xứng phần đồ thị bị bỏ qua Ox

Nhận xét: Để từ đồ thị hàm số  C :yf x  biến đổi để có đồ thị hàm số  C :yf x ta thực hiện

theo hai bước:

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* Cách vẽ  C từ  C :

+ Giữ nguyên phần đồ thị trên miền u x   0 của đồ thị  C :yf x 

+ Bỏ phần đồ thị trên miền u x   0 của  C , lấy đối xứng phần đồ thị bị bỏ qua Ox

+ Giữ nguyên (C) với x 1

+ Bỏ (C) với x 1 Lấy đối xứng phần đồ thị bị bỏ

qua Ox

x y

Trong quá trình thực hiện phép suy đồ thị nên lấy

đối xứng các điểm đặc biệt của (C) như: giao điểm

với Ox, Oy, CĐ, CT…

 

 

nÕu nÕu

x x y

Nội dung: Tịnh tiến đồ thị  C lên phía trên (theo phương Oy ) a đơn vị nếu a 0, tịnh tiến

xuống dưới a đơn vị nếu a 0

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Dạng 7: Từ đồ thị  C :yf x  suy ra đồ thị  C :yf x a    ; a  

Nội dung: Tịnh tiến đồ thị  C sang phải (theo phương Ox ) a đơn vị nếu a 0, tịnh tiến sang

trái a đơn vị nếu a 0

Ví dụ minh hoạ:

a) Từ đồ thị     4 2

C yf xxx  suy ra đồ thị  C :yf x  1 

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II BÀI TẬP TRẮC NGHIỆM

Câu 1: Cho hàm số yf x  xác định, liên tục trên

 và có đồ thị như hình bên Đồ thị nào dưới đây là

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Câu 3: Cho hàm số yf x  xác định, liên tục trên

 và có đồ thị như hình bên Đồ thị nào dưới đây là

-3 -2

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-3 -2

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y

2 1

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y

2 1

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Câu 7: Cho hàm số yf x  xác định, liên tục trên

 và có đồ thị như hình bên Đồ thị nào dưới đây là

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Câu 9: Cho hàm số yf x  xác định, liên tục trên

 và có đồ thị như hình bên Đồ thị nào dưới đây là

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O

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O

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O

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O

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x y

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x y

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x y

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x y

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