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Chuyên đề phương trình Toán 9

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Tiêu đề Chuyên đề phương trình Toán 9
Tác giả Vũ Văn Trà
Người hướng dẫn THCS Phạm Kha
Trường học THCS Phạm Kha
Thể loại Chuyên đề
Định dạng
Số trang 4
Dung lượng 546 KB

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Trang 1

Bµi 1: Gi¶i ph¬ng tr×nh.

a/ x 5 3− = b/ x 10− = −2

c/ 2x 1− = 5 d / 4 5x 12− =

e/ x 5 9+ = f/ 1+ 2x 10=

g/ 2x 3 1+ = + 2 h/ 3x 2 2− = − 3

k/ x 1+ = 5 3− m/ 3 x 1 8

15

7 x 5+ =

n /(7− x 8)( − x) = +x 11

17 3 x 1 23 4 x 1

p/ 2x 3 2

x 1− =

− u/ 2x 3 2x 1− =

s/ 4x 3 3

x 1+ = + t / 4x 3 3x 1+ =

+

o / x 5 1 x+ = − i / x 4− = 2 x−

¬/ x 4 4 x− = − l / x 13 x 1+ = +

y / 4 3 x 6 5x− + = w / 3+ 2x 3 x− =

*/ x2 + + = +x 1 x 2 m* / 2+ 3+ x =3

Bµi 2: Gi¶i ph¬ng tr×nh:

a/ x 1 2− = b/ 2x 1 4− =

c/ 2x 5 4− = d/ 3 7x− =2

e*/ 1 x 1− − =2 f/ ( )2

x 1− =5 g/ x2 −8x 16 5+ =

h/ 4x2 −20x 25 1+ =

k/ 1 4x 4x− + 2 =5

m/ x 15 3x 1+ = − n/ 7 x 5x 1− = +

p/ 5x 4− = −4 5x

u / x2 −5x 4+ = +x 4

v/ x2 −10x 25 x 3+ = +

s / 25x2 −30x 9 x 7+ = +

t / x2 −22x 121 2x 15+ = −

r/ 9x2 =2x 1+

z/ x2 +6x 9 3x 1+ = −

w/ x4 =7 i/ 16x2 =3x 7+

j/ 1 9x+ 2 −6x 2x 6= +

y/ ( )2 2

x 1− + +x 21 x− −13 0=

Bµ 3: Gi¶i pt:

a/ 2x 1− + 2x 1 4+ =

b/ x2 + =x 5x2 +7x 1−

c/ 2 3x− 2 − −6 x2 =0

d/ x 1 2 x 2 3 x 3 4− − − + − =

e/ x2 − +1 x2 − =4 3

f/ 5 x 2 x− = g/ x + − −x 1 2x 1 3− = h/ x2 +2x 1+ + x2 −6x 9 4+ =

u*/ x 3 4 x 1+ − − + x 8 6 x 1 5+ − − =

v*/ x 2 x 1+ − + x 2 x 1 2− − =

Bµi 4: Gi¶i pt:

a/ 5x 1− − 3x 2+ = x 1−

b/ x 2− + 2 x 0− =

c/ x 1− + 2 1= + x

d/ x 4+ − x 4 2− =

e/ x 7+ + x 1 4+ =

f/ 3x 1+ − x 1 2− =

g/ 5 x− + x 3 2− =

h/ 2x 1+ + x 3 4− = k/ x 6+ = 2x 5− − x 1+

m/ x 4+ + x 1+ = 2x 9+ n/ 6 2x− + 4x 3 3− =

l/ 2x 3+ + x 1 1+ =

j / x 2− − x 1 2+ =

Trang 2

s/ x2 − −9 3 x 3 0− =

t/ x2 − −4 2 x 2 0− =

u/ x + x 1 1+ =

o/ x 4+ + x 1 2− =

p/ 2x 1+ + x 3 4− = q/ x 1− − 5x 1− = 3x 2− w/ x 3+ − x 4 1− =

Bµi 5: Gi¶i ph¬ng tr×nh:

a/ 4x 20 x 5 1 9x 45 4

3

+ + + − + =

b / 36x 36− − 9x 9− − 4x 4 16− = − x 1−

c /2 3x 4 3x 27 3 3x− = −

d/ 3 2x 5 8x 7 18x 28− + = e/ 4x 20 x 5 1 9x 45 4

3

f/ 16x 16+ − 9x 9+ + 4x 4 16+ = − x 1+

Bµi 6*: Gi¶i pt:

a/ x 5 x 14 3

3 x 5

+ −

b/ ( ) (x )x

5 2 6− + 5 2 6+ =10

c/ 3x2 +2x 2 x= 2 + + −x 1 x

d/ x2 +4x 5 2 2x 3+ = +

e/ x2 −2 x 1 0− =

g/

2

x 1 x +x 1 x = −

+ + − +

h/ x4 + x2 +1993 1993=

f /

x

8 x

2

x 2

2

x 2

1 x 1

= +

+ +

+

( VÕ tr¸i cã 100 dÊu ph©n thøc)

Bµi 7: Gi¶i ph¬ng tr×nh:

a/ 4x2 − =9 0 b/x3 − =x 0

c/8x2 −0,75 0,58= d/ 2x2 −7x 0=

e/ 5 2

x 3380 0

9 − = f/x2 − =x 0

g/ 4x2 − =3 0 h/− −x2 3x 0=

k/ x2 −36 0= m/ −3x2 +7x 0=

n /x2 −20 0= l/ 2x2 +13x 0=

u/ 2x2 −12 0= v/ −3x2 +8x 0=

t/x2 + =1 0 q/−3x2 +14x 0= p/ −5x2 =0 r/x2 −14x 0= s/ 3x2 −10x 0= i/2x2 + =3 0

j / 2x2 +72 0= w / − 2x2 −1072 0=

¬ / 2x2 − 3x 0= / −56x2 +1120 0= z/x x 15( − ) (=3 108 5x− )

Bµi 8: Gi¶i pt:

a/ x2 −9x 14 0+ = b/ x2 −4x 4 9+ =

c/ 4x2 −4x 1 x+ = 2 d/ x2 −4x 12 0− =

e/x2 − − =x 2 0 f/ 4x2 −4x 3 0− =

g/x2 −3x 10 0− = h/ x2 −9x 36 0− =

k/x2 − −x 20 0= m/

2

2x −11x 12 0+ =

n/x2 − + =x 1 0 l/ 3x2 +7x 5 0+ =

s/2x2 +13x 20 0+ = t/ 3x2 +8x 4 0+ =

o/3x2 −14x 8 0+ = p/ 5x2 −6x 8 0− =

q/x2 −14x 29 0+ = r/ 3x2 −10x 7 0+ =

z/5x2 +9x 4 0+ = y/ 3x2 +8x 4 0+ =

1)3x2 −14x 8 0+ = 2) 5x2 −6x 8 0− =

3)(3x 1 1 x− ) ( + ) =15 4) x2 −2x 2 1 0+ =

5) 2x2 +7x 5 0+ = 6) 0,7x2 −2,3x 3 0− = 7)x2 − +(1 2 x) + 2 0=

Trang 3

8) x 2 22 − ( 3 1 x 3 2 0− ) − =

9) x2 −(2m 1 x 2m 0+ ) + =

10)x2 −(m n x mn 0+ ) + =

11) (2m 3 x− ) 2 −2mx 3 0+ =

12)x2 −2 1( + 2 x 4 3 2 0) + + = 13) 4x2 −2 1( + 3 x) + 3 0=

14)( ) (2 )2

5x 3− − 5x 3+ = +x 3 15) ( ) (2 )2 ( )

x 2− − +x 3 =2 x 5−

Bµi 9: Gi¶i pt:

1) x4 −7x2 +12 0=

2) x4 −18x2 +81 0=

3) 4x4 −5x2 − =9 0

4) x4 − + =x2 1 0

5) 2x4 +5x2 − =7 0

6) 2x4 +5x2 − =7 0

3 −2 + =6

8/ 3x4 − −(2 3 x) 2 − =2 0 9/ 2

2

1

x

10/ ( 2 )2 ( )

x +1 −x x 1− + + =x 1 0 11/ −2x4 −7x2 − =5 0

12/3x4 +11x2 −14 0=

13/ x4 − +(2 3 x) 2 +2 3 0=

Bµi 10: Gi¶i pt:

a/( )2

x 1− − =4 0 b/ ( )2

2x 3− −16 0=

c/( )2 ( )2

x 1− −4 x 3+ =0

d/ x4 +4x2 + =4 16x2 −8x 1+

e/ x3 −4x2 +8x 8 0− =

f/ ( 2 )2 ( 2 )

x +x +4 x + −x 12 0=

g/ (x2 − +x 1 x) ( 2 − + −x 2) 12 0=

h/ x2 12 x2 14 x2 18 x2 16

− − − = − − −

k*/ 2

2

u/ x5 + +x2 2x 2 0+ =

i/ (x 2 x 3− ) ( − =) 0

Þ/ (x 1 x 2 x 3+ ) ( + ) ( − =) 0

o/ ( )3

x 3− =27

p/

3

x

8

x 1

  w*/ ( )2 2

x 3− +x =0

z*/ ( ) (2 )2

x 2y+ + −y 1 =0 y*/ x2 −2 x 1 0− =

1) x4 +2x3 −6x2 +2x 1 0+ = 2) x x 1 x 2 x 3( + ) ( + ) ( + =) 3

3) x2 +4x 5 2 2x 3+ = + 4) x3 +3x2 +3x 1 0+ = 5) x4 −4x2 + + =x 2 0

6/ x4 − −x3 3x 3 0+ =

7/ ( 2 )2 2( )2

2x −3x 4− −x x 1− =0 8/ x3 −3x2 −3x 9 0+ =

9*/ x 3 x 4 49

3 + + + =x 4 x 12 10*/ x x 1 2 0

x 1 x

+

+

11/ ( 2 )2 ( 2 )

x −5x −30 x −5x −216 0=

12/

2

13/ ( )2 ( )2

9 3x 2+ −4 7 2x− =0

14/ ( 2 )2 ( )

y +5y −8y y 5+ −84 0=

15*/ (y2 − −5) 5 y2 − =5 6

Trang 4

16*/ x 1 x 2 x 3 x 4

+ + + = + + +

17*/ ( ) (4 )4

x 3+ + +x 5 =9

18*/ x2 −8 x[ ]+ =7 0 19*/ x4 + x2 +1993 1993= 20*/ (x2 + +x 1 x) ( 2 + +x 12) =12

Bµi 11: Gi¶i pt:

a/ x 4 2x 3 2

2x 3 x 4

b/ ( ) ( )2

x x 2 − x 1 =12

+ +

c/

0 2x 1 2x− 4=

− −

d/ 2x 1 3 x 1( )

6

x 1 x 1

− +

e/ x 4 2x 3 2

2x 3 x 4

f/ 1 1 1

x 1 x 9+ = x

− −

/ 2y 3 2 2 1

y 9 6y 2y+ =y 3y

¬/

3 2

x 2x x 2+ x 1 x 2 = x 1

− − − − − +

g/ 2x 5 x 0

2x+ −2x 5=

+

x x 5 x+ x 4 = −

h/

2

x x 1 x x 1

− + +

x 1 x 1 x 4+ + =

m*/ 3

3

+ = +

n*/ 3

3

8

x x

u*/

x 1 x 1 x 1 x 1

0

x 1 x 1 x 1 x 1

s/

2

x 9 3 x x 3 3 x

t/ x 1 x 1 3

x 1 x 1

− +

i/

2

j/ x 2 16x 7 0 2x+ − x 2+ =

+

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