Design computations according to ACI 318-14 [2] Step 1: Determine the factored bending moment, shear force, and torsional moment at the face of Bent 2 of the box-girder based on the load
Trang 1PRESTRESSED CONCRETE GIRDER BRIDGE
Kevin S Benítez C
February 2019
Keywords: prestressed concrete; torsion; shear; box girder bridges
Trang 2This report will present the design of a cast-in-place, post-tensioned concrete, multi-cell box girder bridge under combined torsion, shear and flexure, based on the geometry of an example from the California Department of Transportation [1] Figure 1 shows the elevation view of the bridge used for this example The total length of the three spans is 412’ (125.6 m): the first span is 126’ (38.4 m), the center span is 168’ (51.2 m), and the third span
is 118’ (36.0 m)
Figure 1––Elevation view of the bridge
Figure 2 presents the cross-section of the bridge The total width of the bridge is 58’-10’’ (17.93 m) The bridge carries three 12’ (3.7 m) traffic lanes, two 10’ (3.0 m) shoulders and two 1’-5’’ (0.45 m) concrete edge barriers
Figure 2––Cross-section of the bridge
The loads that act on the bridge include the self-weight, load of the asphalt concrete (A.C.) wearing surface with
a thickness of 3 in (75 mm), and the live load in accordance with AASHTO LRFD 2017 [3] HL-93 (design truck plus design lane load)
Trang 3Bending Moment, shear and torsional moment envelopes for bridge example
Trang 4Figure 5––Torsional moment diagrams for separate load cases Conversion: 1 kip-ft = 1.356 kNm, 1 ft =
Trang 5Design computations for flexure according to AASHTO LRFD 2017 [3]
The following steps will be used for the design of the example bridge in flexure:
Step 1 Determine the tendon profile
The tendon profile should be chosen so that the points of maximum eccentricities will occur at the points of maximum moments The tendon profile should include the radius of the parabolas, points of inflexion along the cross section and distances from the C.G of the cross section to points of maximum eccentricities
Figure 6––Prestressing tendon profile along bridge length
Step 2 Determine the balancing forces and balancing bending moments
The balancing bending moments for each one of the sections of the cable path is determined
2
8 j
P
P f q
l
First parabola: (From 0 ft to 110 ft)
2.02 10110
Trang 6These forces should be distributed over the whole width of the bridge, for this calculation the overhanging flanges are not taken into account and a mean value of the width of 50.5 ft, between the upper and lower flanges
is used, to count for the skewed exterior girders
5
2 1
5
2 2
5
2 3
5
2 4
5
2 5
ft kip q
ft kip q
ft kip q
ft kip q
Figure 7––Balancing moments from prestressing Conversion: 1 kip-ft = 1.356 kNm, 1 ft = 0.31 m
Step 3 Calculate the prestressing losses according with Section 5.9.3
Calculation of Friction Losses:
For the calculation of friction losses, the friction coefficient is calculated based on the following equation:
Then the cumulative coefficient is calculated adding the values of angular coefficients obtained for each section
Trang 7Table––1, presents the cumulative angular force coefficients for Two-End stressing
Table 1––Cumulative angular force coefficients for two-end stressing
LOCATION LEFT END
STRESSING
RIGHT END STRESSING
Losses due to Elastic shortening:
The elastic shortening is computed based on a value of Δf pES = 3 ksi As used by the California Department of Transportation [1]
It is then converted into a force coefficient:
3
0.015202.5
pES pES ps
Losses due to Anchor set:
For the losses due to Anchor set the following value is used:
0.097
pA FC
Time-dependant losses: Concrete Shrinkage and Creep
To calculate the losses due to concrete shrinkage, the strain due to shrinkage is calculated using the following equation:
Trang 8The total time-dependant losses converted into a force coefficient are:
Step 4 Check stresses at Service Flexure (considering just DC and PT)
Service flexure will just consider the effects of the Dead Load (DC) and prestressing force (PT), that are the force acting as soon as the bridge is terminated, it not includes the effects produced by the wearing surface (DW) and the Live Load (LL)
The allowable stresses are the following:
Table 2––Allowable stresses at Service Flexure
Compression 0.60 f’ci = 2.1(ksi) 14.5(MPa) Tension No tension allowed
The stresses will be computed at different positions along the bridge length:
Table 3––Calculated stresses at Service Flexure
Length (ft)
Stresses
at top of section (ksi)
Length (ft)
Stresses at bottom of section (ksi)
Trang 9The allowable stresses are the following:
Table 4––Allowable stresses at Service III (without losses)
Compression 0.60 f’c = 3.0(ksi) 30.7(MPa)
Stresses
at top of section (ksi)
Length (ft)
Stresses at bottom of section (ksi)
Table 6––Allowable stresses at Service III (with Losses)
Compression 0.60 f’c = 3.0(ksi) 30.7(MPa)
Stresses
at top of section (ksi)
Length (ft)
Stresses at bottom of section (ksi)
Trang 10Design computations according to ACI 318-14 [2]
Step 1: Determine the factored bending moment, shear force, and torsional moment at the face of Bent 2 of the box-girder based on the load combinations of Article 5.3.1
56804.2 (77016 ) at the face of Bent 144485.1 (60314 ) at a distance of the face of Bent 1
3035 (13500.5 ) at a distance of the face of Bent 1
5kNm) at a distance of the face of Bent 1d
Step 2: Determine the section properties and material properties
Table 8––Section properties (ACI318-14)
A A
Trang 1162959.2 (85361.2 )
n
This area of reinforcement will correspond to 39 #8 (25 mm) bars
Step 5: Check if torsion can be neglected based on Article 22.7.4
Since 0.866ksi (5.97MPa)0.690ksi (4.76MPa) , the size of the cross-section is not adequate and the
dimensions should be increased By an iterative procedure, it is determined that the new b w = 86 in (2184 mm)
All vertical girders will be flared Exterior girders will now have a thickness t = 19 in (483 mm) and interior girders t = 16 in (407 mm)
44470 (60293.3 ) at a distance of the face of Bent 1
3035 (13500.5 ) at a distance of the face of Bent 1
Trang 12Step 7: Calculate the required area of transverse reinforcement for shear based on Article 22.5.10.5
For shear, the required transverse reinforcement is #5 (16 mm) bars at 5.50 in (140 mm) on center
Step 8: Calculate the required area of transverse reinforcement for shear in the exterior webs based on Article 22.5.10
The factored shear force for the left exterior girder considering the additional self-weight of the larger section is
Step 9: Calculate the required area of transverse reinforcement for torsion based on Article 22.7.6
Trang 13Step 10: Calculate the required area of transverse reinforcement for exterior girders considering the effects of shear and torsion
For the exterior (skewed) webs, the provided transverse reinforcement becomes two-legged #5 (16 mm) stirrups
at 3 in (75 mm) on center For the internal (vertical) webs, the required transverse reinforcement remains legged #5 (16 mm) stirrups at 5 in (125 mm) on center
two-Step 11: Calculate the transverse reinforcement in the flanges for torsion only based on Article 22.7.6.1
§9.7.6.2.2 states that the spacing for transverse reinforcement provided for shear shall not be larger than the
minimum between d = 64.8 in (1646 mm) or 12 in (305 mm) §9.7.6.3.3 limits the spacing for transverse torsional reinforcement to a value no larger than the minimum of p h = 1250 in (31750 mm) or 12 in (305 mm) For the interior webs, a spacing of 5.50 in (140 mm) was used, which fulfils this requirement For the exterior webs, a spacing of 3 in (75 mm) was used, which fulfils this requirement
For the flanges, a spacing of 6.25 in (160 mm) was used, which fulfils this requirement
Step 13: Calculate the required area of longitudinal reinforcement for torsion based on Article 22.7.6.1
Trang 14Step 14: Check minimum requiered longitudinal and transverse reinforcement
Design computations according to EN 1992-1-1:2004 [4]
Step 1: Determine the factored bending moment, shear force, and torsional moment at the face of Bent 2 of the box-girder based on the load combinations
61102.3 (82844 ) at the face of Bent 147741.3 (64715 ) at a distance of the face of Bent 13162.2 (14066.2 ) at a distance of the face of Bent 1
4kNm) at a distance of the face of Bent 1d
Step 2: Determine the section properties and material properties
Table 9––Section and material properties EN 1992-1-1:2004
f p,ud 235 ksi 1620.3 Mpa
f y,d 52.2 ksi 360 Mpa
f´ c,d 3.33 ksi 23 Mpa
f p0.1k 243 ksi 1676 Mpa
f p,d 211.3 ksi 1457 Mpa Step 3: Check the flexural resistance for the tendon layout shown in Fig 6, based on the factored bending moment produced at the face of Bent 2
Trang 15This area of reinforcement will correspond to 51 #8 (25 mm) bars
Step 5: Verify if transverse reinforcement must be provided
P
ksi A
Since V u > V rdc transverse reinforcement for shear must be provided
Step 6: Compute the maximum and minimum shear reinforcement
,min
0.08 '
0.000951.2
Step 7: Compute the maximum shear resistance
The calculations will be developed for angles of 45°, 35° and 22°
For θ = 45°
,max
'3631.8 (16155.1 )cot( ) tan( )
Trang 16Step 8: Compute the design torsional resistance moment
The calculations will be developed for angles of 45°, 35° and 22°
Step 9: Verify if the cross section is adequate
The calculations will be developed for angles of 45°, 35° and 22°
Therefore when assuming that θ = 35° and 22° the inequality is not fulfilled so the section should be enlarged
This process could be done by iteration, finally the sections are changed and the inequality is checked one more time
For θ = 35° and b w = 62in and t f = 13in
,max
'3526.5 (15687 )cot( ) tan( )
Trang 17For θ = 22° and b w = 84in and t f = 18in
,max
'
3532 (15711.1 )cot( ) tan( )
Step 10 Compute the required shear reinforcement
The calculations will be developed for angles of 45°, 35° and 22°
Trang 18Step 11.3 Check if cross-sections are adequate
The calculations will be developed for angles of 45°, 35° and 22°
For θ = 45°
,max
'726.4 (3231.2 )cot( ) tan( )
Trang 19For θ = 35° and t ext = 14in
,max
'796.3 (3542.1 )cot( ) tan( )
Step 11.4 Calculate the required shear reinforcement on exterior webs
The calculations will be developed for angles of 45°, 35° and 22°
Step 12 Calculate the required torsion reinforcement
The calculations will be developed for angles of 45°, 35° and 22° The angle of inclination of exterior webs
should be considered, therefore α = 27°
T
Trang 21Step 16 Compute the required spacing for stirrups on exterior and interior webs
As stirrups, #5 (16mm) bars with an area of 0.31in2 (198mm2)
Trang 22Design computations according to AASHTO LRFD 2017 [3]
Step 1: Determine the factored bending moment, shear force, and torsional moment at the face of Bent 2 of the box-girder based on the load combinations
60865.2 (82522 ) at the face of Bent 147683.3 (64650 ) at a distance of the face of Bent 13268.3 (14538.2 ) at a distance of the face of Bent 1
954kNm) at a distance of the face of Bent 1d
Step 2: Determine the section properties and material properties
Table 10––Section and material properties AASHTO LRFD 2017
Trang 23Step 4: Compute the nominal resistance of the section based on the resistance provided by the prestressing steel
P j = 9300kip (41369kN)
1
6.85 (174 )0.85 '
Trang 24Step 9 Check if longitudinal reinforcement can resist the required tension
Trang 25Step 13 Determine the amount of transverse reinforcement to be used on the exterior webs
Design computations according to Model Code MC-2010 [5]
Step 1: Determine the factored bending moment, shear force, and torsional moment at the face of Bent 2 of the box-girder based on the load combinations
61102.3 (82844 ) at the face of Bent 147741.3 (64715 ) at a distance of the face of Bent 13162.2 (14066.2 ) at a distance of the face of Bent 1
4kNm) at a distance of the face of Bent 1d
Step 2: Determine the section properties and material properties
Table 10––Section and material properties MC-2010
Trang 26f y,d 52.2 ksi 360 Mpa
f´ c,d 3.33 ksi 23 Mpa
f p0.1k 243 ksi 1676 Mpa
f p,d 211.3 ksi 1457 Mpa Step 3: Check the flexural resistance for the tendon layout shown in Fig 6, based on the factored bending moment produced at the face of Bent 2
This area of reinforcement will correspond to 51 #8 (25 mm) bars
Step 5 Determine the net longitudinal strain in the cross section
P j = 9300kips (41368.5kN) e p = d p – 45.6in = 19.2in
63.9 (1623 )(0.9 ) (0.9 )
0.92
Step 6 Compute the maximum shear resistance and torsional resistance
For Level of Approximation 1
k e1 = 0.55
1
30
0.96'
Trang 28Step 7 Check if the dimensions of the cross section are adequate
For θ = 25°, b w = 74in (1880mm), t f = 16in(406mm)
Trang 29Level of Approximation III
Trang 30Level of Approximation III
0.92
Trang 31T
Trang 32Step 13 Determine the amount of transverse reinforcement for torsion on flanges Level of Approximation I
Trang 33Level of Approximation III
1cot( )
Trang 34Level of Approximation III
Trang 35Level of Approximation III
Final results comparison
Table 11––Results comparison of gross concrete area and required transverse reinforcement
Design Code
A g
disregarding overhanging flanges (ft2)
Required transverse reinforce-ment for exterior web (shear and torsion) (in2/in)
Required transverse reinforce- ment for interior web (shear) (in2/in)
Required transverse reinforce-ment for flange (torsion) (in2/in)
Required longitudinal reinforcement for flexure (in2)
Required longitudinal reinforcement for torsion (in2)
Trang 36REFERENCES
[1] California Department of Transportation 2015 Bridge Design Practice, 7-33
[2] ACI Committee 318 2014 Building Code Requirements for Structural Concrete (ACI 318-14) and Commentary, Farmington Hills, MI
[3] American Association of Highway and Transportation Officials 2017 AASHTO LRFD Bridge Design Specifications, 8th Edition, Washington, D.C
[4] European Committee for Standardization 2004 Eurocode 2: Design of concrete structures - Part 1-1: General rules and rules for buildings, Brussels, Belgium
[5] The International Federation for Structural Concrete 2010 fib Model Code for Concrete Structures 2010, Lausanne, Switzerland