In this chapter, you will learn about: DC current and voltage analysis, DC analysis of transistor circuits, modes of operation of a BJT Transistor, transistor characteristics.
Trang 1Dr. Nasim Zafar Electronics 1 EEE 231 – BS Electrical Engineering
COMSATS Institute of Information Technology
Virtual campus Islamabad
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Operation of an NPN Transistor:
Large current
Trang 5cutoff reverse biased reverse biased
Active(linear) Forward Biased Reverse Biased
saturation forward biased forward biased
Trang 6Circui
t
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Trang 9DC Analysis of Transistor Circuits.
Trang 10Ø The first step in the DC analysis, of any transistor circuit, is to solve for one of the unknown currents, IB, IC, or IE.
Trang 11Ø We need a set of equations – a model of the transistor – to be used in transistor circuit theory.
Ø In a basic transistor circuit, we have three terminals collector, base and the emitter.
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Ø If we solve for one of these unknowns, the other two can be found by using the current gain equations and the given value of .
Ø The recommended way of solving for one of the currents is to write a
Kirchhoff's Voltage Law (KVL) loop.
Ø The KVL states the sum of all voltages around a closed loop equals zero.
Va = V1 + V2
Trang 14NPN
Trang 15NPN
Trang 16DC Analysis of Transistor Circuits
Trang 17VBE = 0.7V(PNP)
Trang 18Example 41: CommonEmitter Configuration:
Given: IB = 50 A , IC = 3.65 mADetermine: IE , dc and dc
Solution:
IE= IB+ IC= 50 A + 3.65 mA= 3.7 mA
dc = IC / IB = 3.65 mA / 0.05 mA = 73
dc = IC / IE = 3.65 mA/ 3.7 mA = 0.986
Trang 19A certain transistor has a dc of 200. When the base current IB = 50 A. Determine the collector current. Also calculate dc .
Trang 20A given NPN transistor has dc = 150. Determine IB, IC , IE , VCB , VCB and VBE in the circuit shown below (ignore ac signal):
Trang 21and the collectortoemitter voltage VCE
BJTOutput Characteristics:
Common Emitter Configuration
Trang 22Common Emitter Configuration
Ø We must operate the transistor in the linear region
Ø A transistor’s operating point (Qpoint) is defined by IC , V CE , and IB.
Trang 23From the output characteristics of the common emitter
configuration shown below, find ac and dc with an Operating point
at IB=25 A and VCE =7.5V