Trong khoang rQng 5 cm tr€n miin tfnh til vdn s6ng trung tdm, s6 vAn t6i quan sdt dugc ld: Cdu 6: Thi nghidrn giao thoa Idng trong kh6ng khi, chiOu vdo hai khe 6nh s:ing don sic, khodng
Trang 1E.Ar HOC KFTOA F{QC TU'NF{IEN
KHdI T.FIPT CHUYEN TcAN - TEN
pd rrs rE-[uDAr r+cc r.Aru I NAM F{oc ztlse
-MON TFrr : vAr y* -t-frp tz
CAu I: Ngudn drn S
dd 6m chuAn Io =
l0-A 30 dB
!:o sij !
D r1.
CAu2: O bA mflt nrQt ch6t long c6 haingudn phdt s6ng k6t ho.p Sr vd S: cdch nlrau 20crn Hai
"gu6n *y duo d6ng theo
16 phLrongtrinh ldn lugt ld ur = 5cos40nt (mm) vd u2=5cos(46nt + n) (rnri) roc'd6 truy'crirong
tr€n m[t chdt ldng li 80 crn/s Sd di€m dao dQng vdi bi€n dQ cr,rc dai tr€n doan thing S r52 le
Ce1 3, Khi c6 s5ng dlng tr€n mot soi ddy dhn hdi AB hai ddu cd dinh thi thdy tren dAy c6 7 nfit Biet tdn so s6ng lb
42H2 Y 6i day AB vh vAn toc truydn s6ng nhu tr€n, muon tren ddy c6 5 nf t thi tdn sd s6ng phdi lb
CAu 4: \guOn dm didm S ph6t ra s6ng drn truydn trong rn6i trucmg ding hu'dng C6 hai Oie'n n
"i-e nim tr€n nu.a 9I*.g tlrang xLrAt phrit tu S MiIc cuo'ng dd drn tai A la aA = 20 dB.iai trung Oieri C cua AB ld L.= 26 dB Bd qua su.
hAp thu Arn Mfic cudng dQ Am tai B ld,
Ciu 5: Trong thi nghiQm giao thoa ldng, khodng cdch hai khe a = 0,2mm, til hai khe d€n mdn D : 2m Bric xa dcm sfc
S co 2, = A,5W Trong khoang rQng 5 cm tr€n miin tfnh til vdn s6ng trung tdm, s6 vAn t6i quan sdt dugc ld:
Cdu 6: Thi nghidrn giao thoa Idng trong kh6ng khi, chiOu vdo hai khe 6nh s:ing don sic, khodng vdn quan s6t duoc trdn
mdn ld i Nhring todn bQ tlri nglriem vdo trong nu'dc thi:
A Khoring v6n quan sdt duo'c ldn hon i B Klroing vdn quan s6t ducc nho hon i
C Khdng the quan sdt dugc hiQn tu'o-ng giao thoa D Khoing vAn quan s6t duoc ld i
CAU 7: Trong.thi nghidm giao thoa iinh sdng ci-ra khe Young, khi ta clre m6t trong hai khe boi rndt bdn rn6ng c6 chi6u ddy I, chi6t su6t n rhi:
A Khodng vAn i khdngtlray d6i, vdntrung tdrn dich m_9t doAn x0 B Khodng vdn ithay d6i
c Khoang vdn i thay doi v6n trung rdm kh6ng thay o6i vi tri D ce 3 jlr6n d6u sai
Ciu 8: Trong tlri nghidm giao thoa 5nh silng v6'i 2 khe Young (a = lrnrn ; D = 2rn) Ngubn sring S g6m hai bric xa don
sdc c6 Ll = 0,5 prn vir 1"1 = 0,6 prn Khoring cdch nlro nhAt gi0a hai vdn cing mdu tr€n mirn ld.:
CAU 9: Trong thi nghi€m Young vd giao thoa dnh si{ng, khoing cr{ch gifa hai khe a = 2mm, tir 2 khe den mhn D = 1,2m.
Ngudn S ph6t ra ddng thdi 2 b*c xa don sic c6 )" , = 660 nm vd ), , - 550 nm Khoang c6ch tir v1n silng rrung rim den v8n sdng ddu ti€n cilng miu idi n6 li
Cdu 10: Trong thf nghiQrn Y-Ang vA giao thoa iinh siing, hai khe du<yc chiilu bing rlnh s6ng trfng c6 buoc song tt O,:g prn dlin 0,76pm Tai vi tri vdn s6ng b4c 4 cira 6nh sring don sic c6 budc s6ng 0,76 pm cdn c6 bao nhi6u vdn sang nira
CAU 11: Mach LC gdm L vi Cr, Q Khi dDng L vi C, thi khung bdt duoc s6ng dien tr) c6 f = 3 MHz, khi ding L vd C,
thi k!ryrg b6t duo c s6ng c6 f = 4 MLlz Khi dilng L vh C, noi tiep vdi C, thi khung bf t duoc s6ng di€n tir c6 tdn Jd li
CAu 12: MOt mach dao dQng di€n til LC li tuong gdm cudn ciirn thuAn c6 dQ tu cdm 5 pH vd tu diQn c6 di€n dung 5pF.
Khodngthoi gian giila hai ldn li€n ti6p md di€n tich trdn mQt bdn tu di0n c6 dd I6'n cLrc dai ld
Cffu 13: Mach dao ddng di€n tir tu do LC c6 chu kj, dao ddng ld 8ps Thd'i gian dti m6t nua ndng luong di€n tru'ong cuc dai trong tu chuydn thinlr ndng luo-ng tir trong cuQn cdm ld
Cf,u l4: D4t mQ!diQn dp xoay chidr-r c6 gi6 tri hi6u dung U vdo hai dAu doan rnach AB g6rn thuAn cdm L, di€n tro R vd 1' 1i{^C rnic.noi ti6p.,theo thir tu trcn Gqi UL, Ux vd Ug-lAn lu'-ot Id c6c diQn 6p hieLriung giu'a hai diLi *6'iJfra" r* Bi6t di6n dp gifr'a hai ddu doan nr4ch AB vu6ng pha so v6'i di€n iip giira hai ddLr doan mach NB (do4n mach Nd g6m R
vd C ) Hd thric ndo du'd'i ddy ld dring ?
A' U2=ui+ui+ui B u:=Ui+Ui+U' c u'*=u:+Ui+U2 D u'r=Ui+,€rr' ",
dd thi: 366
Trang 2C4u I5: Dat dien 6p u = U ./7 cos dD l vda hai dau c'oan mach gdrn cu6n d6y (L, r) n6i tiep tu dj
rniln 3LCas2 = I vd r = zJiri L Chqn k6t itran dring:
A, zr rrhanh pha n 13 so v6i i.
C a nhanh pha tr 13 so vd'i i.
B rnhanh pha n n ,o {aV fiA T'iL'*;:; g'r;.r,ii't?" _ +?r; F,,./.,!rV \"^
^.a ^ , \ r']'
\-i,J )(
.-!_-/ _
CAu 16: D[t vio hai dAu rnach diQn RLC n6i tiep (gom di6n trd R, thuAn cdrn L vi tu C) m6t trieulfi the *duv cfiiEu
c6 giri tr! hi€u dpng klrdng d6i thi cac gi6 tri higu dgng Up : Ur- = Uc = 20V, Khi cu6n day b! noi tai rhi hi6u aign trre
hi6u dung hai dAu di6n tr6' ld:
I
A.L=_H
/L
B.L = l'5 *
1T
D i nhanh pha a /6 so
c.r-:1H
7r
d
D.L= - H
7T Zco s(L}nt - n I 2) cm .
D.4An cmls
CAu 17: Mach RLC nOititipgdrn: bitlnff6'R;cudnddyc6 r=40O,d6tgcdm L: I H: tr; di€na:9F; hi€udi€n
5n
thii hai dAu doan rnach c6 f = 50H2 Ciri tri crla R d6 cdng su6t toi nhiQt trdn R cuc dai ld:
CAU 18: Mach RLC noi ti6p g6m cu6n day (L, r) vd tu di6n C Dat vdo hai dAu do4n m4ch m6t hidu diqn thii u =
B}Jicosl00nt (V) Dieu chinh C d6 U = U,.no*: 100 V Hieu ttiqn thit hieu dung giira hai dAu cuQn ddy k-hi d6 ld:
CAU 19: Trong mach diOn xoay chidu RLC mic noi tiep d6 lOch pha gifra hiOn di€n the hai ddu mach vi cudng ti6 dbng diOn trong mach l)r - n 14.Ddp 6n nio sau ddy ddng
CAu 20: M6t doan mqch R, L,, C qac noi ti6p CuQn ddy thuAn cdm Gsi Uo*, UoL Uo fi nilu diQn thil cuc dai o'hai dAu
diOn tr6', hai dAu cu6n ddy vd hai dAu tr; di6n Bi6t 2Uo, = 2Uon = Uoc K6t tuan nao AuOi Oay li dring:
A u chdm pha hon i mdt goc nl4 B u sdm pha hon i rn6t g6c 3nl4
C u chdm pha hon i m6t g6c n/3 D u sorn pha i mQt gocn/
Cfiu 2l:Con l6c lo xo treo thing dring dao dQng diAu hda vo'i tAn so f = zJ Hz vd bl6n dg A :2 crn Tis6 do lon luc
dan h6i cuc dai vd cuc tidu cira ld xo ld:
Cau23: Conl6cdonc6khoi lLrongm =t00g,chi€udii/=l00cm.K6oconl6cl€chkhoivirric6nbingg6coar6i
tlrd khdng vdn t6c ban dAu de khi dao tlQng thi Iuc c6ng dAy T,,,u, = 3T,.i,,.Vdn t6c c0a vdt khi T = 2T,"in la
CAU 24; Chon cAu sai trong cdc c6u sau khi n6i vd dao,d6ng didu hoi
A Khi qua vi tri cAn bAng thi lLrc t6c dung l€n v6t b[ng kh6ng
B Khi dong nang ciia vAt t6ng th) thd nang cria vAt giAm
C Khi vAt dao ddng 6 vi tri cAn bAng thi dOng n6ng cfra h€ l6n nhat
D Khi vAt & vi tri bi€n thi the nang cfia h0 lon nhdt
CAu 25: Con lac ld xo treo thang dung Khi ld xo ddn l0 cm thi vdn t5c cira vflt d4t giri tri cpc d4i vd bing I m/s Gia t6c cu'c dai cua vdt ld
CAU 26: Con lic ld xo c5 khoi luo ng m = 100 g, dao ddng didu hod v6i bi€n d6 A = 2 cm.Tai thdi didm ban ddu v6t c6 vAn tdc v = 20.6 cm/s vh gia tdc a = - 4 m/s2 Pha ban cldu cira dao dong lh
Chu 27: Trong m6t dao d6ng di0u hod c6 chu ki' T thi thdi gian ng6n nhAt dd vat di ril'vi rri c6 c6 gia t6c cr,rc dai d6n vi
tri gia t6c bang m6t nua gia t6c cuc dai ld
I,au Z,S; M4ch xoay chidu ndi tiep c6 tdn sd f = 50 Hz gdm cuOn ddy thudn cim L di€n tro R = 50 Q vi tu di€n C.
Thay ddi di6n dung ta thay khi di€n dung cria tu tang IOn 2 ldn thi c6ng suat cira mach khong ddi nhung cudng'd6 ddng dien thi vu6ng pha v6i nhau Gid tri cira L lh:
ClyZ,Z: Trong mQt dao clQng di€u hod, khi gia t6c cira vdt b[ng mQt nira gia tdc cgc dai cua n6 thi tis6 giiia d6ng nang
vd th6 nang ld:
C6tu 29: VAt tham gia ddng thdi hai dao dQng c6 phuong trinh: x, = Zcosljnt cm vh x, =
VAn tdc cfra vAt khi r = 4s li
Trang 3C&u 30: Ddng hd quA t6c (coi nhu li con !6c don) chay dring khi d4t & mat ddt (br{n kinh tri{i iiar R = 6400km) H6i khi
dat ddng hd & d0 cao h = 64A m (cDng nhiOr dO) rhi m6i ngiy dting hti chay
A C|fi,rn 4,32s B ChAm 8,64 s C Nhanh 4.32 s D Nhanh 8,64 s
CAu 31: Con lSc ld xo dao d6ng didu hoi v6i biOn dQ A = 2 cm, chu ki T = l,2s, pha ban ddu ld n t3 Qu6ng dulng con l6c di duo-c trong 4s ddu tion ii
CAu32: MQt con l6c lo xo dao dgng di6u hda theo phuong ngang vdi tAn stl g6c I0 radls Biiit ring khi d6ng ndng vd th6 ning bing nhau tlri v4rr t6c cfia vdt cd d6 ld'n bing 0,5 ni1s BiOn d0 dao dQng cia con lic ld
A lu6n nguo c plra nhau.
C ludn cing pha nlrau.
CAU 34: Phrit biOu niro sau d6y ld sai khi n6i v0 s6ng di€n til'?
A S6ng di€n tu'lA s6ng ngang.
CAu 33: Trong m4ch dao dQng LC lf tudng dang c6 dao dQng diqn tu tu do, di6n tich cua mdt bin tV diQn vi cu'ong dQ
ddng diQn qua cu6n cdm bi€n thi6n di6Lr lrda theo thoi gian
B vdi cirng bi€n d6.
D vdi cirng tAn s6.
B Khi s6ng dien ti lan rrr-ry6rr vecto cuo'ng d0 dien trudng lu6n vuong g6c vd'i vectg/dfu{+dh$ll-f,''i'Jii Tt},1i};'\i1
C S6ng diQn tu lan truy€rr du'o c trong - chAn kh6ng.;" CCI SCI :
D Khi s6ng diQn tir lan truyen, vecto'cuong dQ di0n truong ludn ciing phu'ong v6'i vecto cirn img tir'.
CAu 35:Mach dao dOng c5 C= 6nF L= 6ltH Do mach c6 di€n trdR = 0.5 Q, n€n dao d6ng trong mach tdt ddn Dd
duy tr') dao d6ng vdi hiOu cli€n the cuc dai gifa hai bin tu di€n Ie U0 - lOV thi phni bd sung ning luo.ng cho mach m6r
cOng sudt lh
Cdu 36: gOi vOl sp' lan truyAn s6ng dign tir thi vecto cu'ong dQ di6n truong E vi vecto cirn ring tir B :
A E vd B lu6n vu6ng plra v6i nhau B E vi B ludn cDng phuong vdi phuorrg truydn s6ng.
C E vd E IuOn vu6ng gdc voi phuong truy0n s6ng D E vd E tuOn ngu'o c pha vdi nhau
Cf,u 37: Trong mach dao dQng LC ly tu'ong: c['sau nhfing khodng thdi gian nhu nhau ts thi ning luong trong cuQn cdm
vd trong tu di6n l4i bang nhau Chu kj' dao dQng ri€ng cira m4ch Id:
CAu 38: Mach LC gdm L vi C, G Khi ding L vh C, thi khung bit duo.c sdng diOn tir c5 f = 3 MHa khi dirng L vh C, song song v6i C, thi khung bit duo c s6ng c6 f = 2,4 MHz Khi dirng L vi C thi khung bit duoc s5ng dien tir c6 dn sd lh
CAU 39: MOt mach dao d6ng LC c6 L = 2mH vh C = 0.2pF Cuong d0 ddng diOn cuc dai trong cuOn c6m lh I,, = Q.54.
Hieu diOn thd gifra hai bAn tu diOn o thdi didm ddng diOn qua cu0n cAm li i = 0,3A Ii
CAu 40: Mach LC l! tu6ng gdm cuon dAy L vi tu diOn C = 20 nF Khi dao dOng trong mach dn dinh, gii{ tri cuc dai cira hiOu di6n the gifia hai bin tu diOn li U,, = I V vi cudng do ddng diOn trong rnach lir vd I,, = 0.2 A Hieu di€n the gifia hai
bdin tu di6n tai thdi ditim cr-tdng d0 ddng di0n trong mach c6 gid tri bdng 100 mA li
CAu 41: Cho do4n rnach AM (li cuQn ddy L,r) m6c n6i tiilp vdi doan MB (gdm R ndi ti6p C) Khi uay vu6ng pha vdi uvn thi h9 thric ndo sau ddy ln dfing
Chu 42: Mach ndi tidp giim di0n tr6 R, cuon d&y thudn c&m L, tu di€n C c6 di€n dung thay ddi duo c Hieu di€n thd hai ddu doan m4ch li 220V - 50H2 Thay Adi C ta th&y U.** = 440 V Chon phuong 6n dring
CAu 43: D4t vdo hai dAu mach xoay chieu n6i ti6p hiQu diQn thti u = 200cos(l00nt + nl6)Y
trong mach ld i = 40cos(l00nt - n/6) rnA Cdng suAt ti€u thu trong mach ld
CAu 442 Mach diQn xoay chidu nOi ti6p g6rn cuQn ddy (L, r), mic nOi ti6p v6'i tu di6n C Bitit hiQu rli€n thti gifia hai ctAu
cudn ddy l€ch pha n l2 so vd'i hi6u dien th6 gifi'a hai dAu do4n mach Chon phuong 6n dring:
A 12 = ZI(ZL-Zd B rr = Zc(Zc - ZL). C rz = ZL(ZL-Zd D 12 = ZL(Zg -Z).
CAu 45: Mach RLC nOi titip g6rn cudn day (L, r), tu di€n C vd di6n tro R :30O Dat vao hai dAu rnach hi6u di€n th6 (50 V - 50 Hz) tlri Un : 30V; Uc : 80V; Uo = l0 JN V.Cdng sudt ti€u thg cr-ra doan mach ld
D Z, = .[g
thi cuong d0 ddng dien D.2 kW
Trang 4Cdu 46: Buo'c s6ng ld khoarrg cilclr giii'a hai di6rn
A t€n cirng mdt phuo'ng truy6p s6ng rnd dao ddng t4i hai didrn d6 ngugc pha.
g e?n nlrau nhAt trdn cirng rn6t phuo'ng truy€n s6ng md dao dQng tai hai di6m d6 ctng pha.
C gdn nhau nhdt md dao dQng tqi hai diiirn d6 cunfpha
-D tr€n cung rnQt phLrcr'ng truydn s6ng nd dao dQng tai hai di6rn d6 cirng pha.
Cau 47: Khi s6ng Am truydn tU khOng khf vio nudc thi budc sdng:
Cf,u48:Ddyddnhdi ABddi l.2rnhaidAucodinhdangc6s6ngdung.Quansdttr€nddytath6yng"oainui dAuddy"c6
dinh con c6 hai di6rn khdc tr€n ddy khdng dao d6ng vd khoAng thoi gian giU'a hai lAn lidn ti6p vdi sqi ddy dudi thing Ia
O,O+ s V{rr t6c truydn s6ng trOn ddy ld
Chu 49: MQt s6ng co lan truyAn trong m6t m6i tru'ong vdi tOc dd l20crn/s, tAn s6 cta s6ng thay OOi rir tOHz dtin l5Hz
Hai di6rn c6ch nhau 12.-5cm lu6n dao d6ng vr-r6ng pha Budc s6ng cta s6ng co d6 ld:
CAu 50: MQt ngiLo'i quan s6t rn6t chi6c.phao tr€n,m[t biiin thAy n6 nh6 cao l€n 5 lAn trong B gidy vd thdy khodng circh2
ngon s6ng k€ nlrau ld 2rn VAn tdc truydn song bi€n ld :
Trang 5Cdu 1: Trong thi nghi€m Young vd giao thoa 6nh s6ng, khodng c6ch 2 khe ld 2 rnm, khodng c6ch ti'2 khe
dtin mdn ld 2 rn Chi€Lr sdng 2 khe bdng rinh s5ng tring co bu'd'c s6ng tf 0,4 pm d6n 0,75 pm thi tai di€m M
c6ch vdn siing clifnh gifi'a 5 mm c6 bao nhi€u tia don sdc cho vdn siing ?
Mdi cdn cd 4 phuong cin trri ldi, Thi sinh chon mdt (01) phtmtg dn trd ldi hqp $ nhdt Ma dd thi:444
B Bu'6'c s6ng cua rinh sang hu!'nh quang nh6 ho-n bu6'c s6ng cria 6nh s6ng kich thic
C Bu6'c song c0a Srrh s6ng ldn quang nho hon bu6'c s6ng c0a 6nh sSng kich thich
D Anh sdng Idrr quang tft ngay sau khitit rigudin s6ng kich thich
Ciu 4: Trong thi nghiQm c0a Young c6c khe Sr vd Sz du'o-c chi6u d6ng thd'i hai 6nh s6ng don sfc c6 bu6'c
s6ng )"1 = 0,66pLrn vd 1.: chua bidt thi m6t vdn s6ng cira )"2 trirng v6i vdn s6ng b6c 2 cria )"r Giri tri cira bu'6'c
song ).2 ld
A.f,z = 0,44pm B.Iz :0,40prn C.trz = 0.42pm D X2= 0,461tm.
Ciu 5: Trong thf nghiOrn giao thoa 6nh sdng bing hai khe s6ng hep Nguiin ph6t d6ng thoi hai bfi'c x4 c6 bu'dc
s6ng )"1:0,4pm vd l,z:0,6prn Vdn siing gAn nhAt cilng mdu v6i vdn trung tAm ld vdn bQc m6y cira 6nh s6ng c6
EAI T{OC KHOA HOC TU NHItN
KHOI THPT CHUYEN TOAN TIN
. -m -pd rur THUDAT Hoc LAN 2 NAM r{oc 2009 2010
MON THI : vAr lY -LaP n
Thdi gian ldm bdi : 90 phitt
oiI_iittut
B Co t6c dung mpnh l6n phirn dnh
D C6 khdn ndng ion h6a kh6ng khi
Chu 2: Ch.gn cdu sai trong c6c cdu sau?
A C6c chAt ran, long vd nhfr'ng ch6t khi o 6p suAt l6'n khi bi nung nong, phiit ra quang ph6 lien tuc
B Quang phO vach phdt xa cfta ciic nguyOn t6 khAc nhau thi kh6c nhau.
C DC thu'duo-c quang phO hap tnp, ntrigt dd cria d6rn khi hay hoi hdp thu phAi ld'n hon nhi€t dd crja nguiin
s6ng ph6t ra quang ph6 li€n tuc
D Dua viro quang pfrO tien tuc ta co th6 x6c dinh du'oc nhi6t dQ cua vqt ph6t sdng.
Cdu 3: Chgn cdLr ching?
A Anh s6ng huj,nh q'-rng tit nhanh hon 6nh s6rrg ldn quang sau khi tit ngLrdn s6ng ki o,\
I \'l/
'+
bu6'c s6ng )"1?
Cdu 6: Trong thi nghi€rn Young, vAn tdi thu' hai xudt hi€n o'tr€n mdrr tai c6c vi tri rnd hi6u du'org di cria 6nh sring tit'hai ngu6n d€n cdc vi tri do bAng
-
CAu 7: Clri€Lr lAn lLlo.t hai bflc xa c6 bu'6'c s6ng l, vit ), =24 vdo cattit cia mot te bao quang didn c6 gi6'i han
quang di€n 1,, - 0^75pnt thi nhAn duoc c5c electron quang di€n co vdn t6c ban dAu hon nhau 2 lAn Tinh bu'6c s6ng ,! .
D Tia hOng ngoai
Cdu 8: Bri'c xa co bLl6'c song khoAng til l0 ern d6n 4.10-7m td song ndo drr6'i cldy:
A Tia Ronghen B Anh sdng nhin thdy C Tia tit ngoai
CSu 9: Phdt bi€Lr nao sau ddy ld sai lihi n6i vA d4c ditlm cira tia Ron-ghen
A C6 khdn ndng ddm xuyOn m4nh
C C6 th€ di qLra l6'p chi ddy vdi xentimdt (cm)
Cdu l0: Trorig chdn khOng rnoi phdt6n dAu c6 cirng
Cdu 11: NtiLi 6nh s6ng hui)nh qlrang co mdu lam thi 6nh s6ng kich thfch c6 th€ lA
C miru cam
D tdn s6.
D mdu tim
Ciu 12: Khi chi6u iAn luot hai birc xa co tAn s5 fr vd l: ( fi>fi) vdo mdt t6m kirn lo4i d4tcd l4p thi d€Lr xtty ra hi€n tLLo-ng quang di0n; voi di0n th€ cLLc d4i cira qLrA cAu dat dLLo-c ld Vr vd Vz N€u chi€u dOng thd'i hai b6'c xa tr€n vdo tAm l<irn to4i do thi diQn th6 cu'c d4i crra n6 ld
A rndu do. B rndu luc
^ r,.
CAu tr3: Chi6Lr lAn lu'or 3 bu'c xa co bu6'c s6rrg theo ti le )"r :i",:)",.=6:3:4 vdo cat6t cua rnot t5 bho qLrarrg diQnthi niiAndugcc6cquangdiQntric6v4nt6cbandAucu'ccl4itylQ: vt'.v2'.vi=i:3:/c.Trongcio k bang:
ilA TFLAN}{ T$AN
Trang 6CAu 14: Chi€Lr lAn luot 2 bu'c xa co butl'c song 71 = 0,25 pm', 1z = 0,5 [mt vdo cat5t c0a mdt t6 bao quang di€n
^ .: , ,l
tlri vdn tdc ban dAu cLrc dai c0a electron quang di0n th6a mdn vl : 2 v , Bu6'c song gi6'i han quang diQn ld:
CAu l5: Ei€u kiQn phrit sinh cita quang ph6 vach phdt xa?
A C6c khi hay hoi o 6p suAt thdp bi kich thich ph6t s6ng ph6t ra.
B C6c vAt rin, long hay khi c6 kh6i luo.'ng ri€ng l6n khi bi nung n6ng ph6t ra.
C Chi€u 6nh s6ng tr6ng qua mOt ch6t hoi bi nung n6ng ph6t ra'
D Nhirng v4t bi nung nOng O'nhiQt dQ tr€n 30000C
CAu 16: Dat,diQn 6p xoay chidu u*^ = 100J7cosi00nt(V) vdo mach RLC ndi ti6p theo thf tU ld diqn trd R,
1
thuin cArn L thay d$i duo-c vd tu C Khi L: Lr : -H hay L:3Lr thi m4ch c6 ci:ng c6ng sudt nhung dong
It
diQn i, vd i, khdc pha nhau 2xl3 Bi6u thri'c hiQu diQn th6 uxas (B ld di€m nim giira cuQn d6y vd tq ) khi
L=Lr [d
A d*, = s0J-2cos(l00nt + nlzlv
C unun = l00.,6cos(l00nt +ZrlllY
B ,r" = l0oJ-2cos(l00xt -znl3)v
D u",, = l00rf2cos(l00tt +nlz1v
phu'ong 6n dirng
Cflu 18: Chi6u bri'c xa c6 bu6'c s6ng l, vdo cat6t cria mdt tti bao quang diQn thi.hiQn tuo.ng quang diQn xAy ra- D€ triQt ti€u hodn todn ddng quang dign thi hiqu dien the hAm c6 d0 l6'n 2 V N€u dqt giira an6t vd catOt cria t€
bdo quang diQn hi€u di6n th6 Unr< : 8 V thl ddng nlng cuc dai cria €lectr6n quang cliqn khi t6i an6t ld
;.;jin1bi-';"""'-'-'i"-"- -ilb,o.ro'6:
c l0-r8 J D 16.10're J
Cdu 19: Sr,L dAo s6c c0a cdc v4ch quang pfrO ta
A Su ddo ngu'gc tr)'vi tri ngue'c clLieu llhe m6y thdnh cing chidu
B SU'd6o ngugc trAt tu c6c vach tr€n m6y quang ph6
C Cdc vach t6i trong quang ph6 tr6p thu trr)ng v6'i c6c vach s6ng trong quang ph6 ph6t xa cria nguy€n td il6
D Sr,L thay d6i mdLr i6c ciracdc vach qr-rang phd
CAu 20: Trong thf.nghiQnr giao thoa song tr€n m6t nr.r6'c hai ngiron kdt hgp A B cdch nhau 8 cm ph6t ra hai s6ng cirsg ptraiO dn sO f :20 Hz Tai di€m M tr€n mdt nuoc (MA : 25 cm", MB = 20,5 cm) s6ng c6 bi€n d0
cu.c*dai, g-iira M vd trr"rng tnro-c cfra AB c6 2 ddy cytc d4i khdc C vd D ld 2 di6m tr€n mdt nu'6'c sao cho ABCD
ld hinh vuOng S6 Oiem dao d6ng v6'i bi6n dd cu'c dai trdn doan CD ld
CAu 21: Clron cALr thing?
A ChLr ki cop lic kh$ng phu thudc vdo nhi€t d6 B Chu ki con ldc.kh6ng phu thuOc vTd0 dia ty
C Chu lci con I6c don glam khi nhiQt dQ tdng D DOng hd qLrd lic s€ ch4y chQm n6u.dua l€n cao. CAu22t MQt con l8c ti xo dao dQng AiCu tiOa Bi6t ld xo c6 dO cilng 36 N/m vd v4t nh6 cO khOi tuo-ng 100g.
Liy n2 = 10 EQng ndng cira con l6c bi€n thi€n theo tho'i gian v6'i tAn s6.
Cdu23: MQt vQr dao dOng di0u hod vdi chu'kj,T = 0,6 vd biOn d0 A :4 cnr Tdc dQ trung binh l6'n nhAt cria
vdt thLrc hi6n dLro'c trong khodng thd'i gian 0,4 s ld:
cau 17: Mach RLC nOi tiiip nhu hinh v6 ddt vdo hai dau mgch rndt hi€u di€n
th6 xoay chi€u thi cuo'ng dQ dong diQn tropg mach ld I : I A vd mach ti€u thu
c6ng suAt P=20rbW, hi€u diqn thti Urvrn kh6c pha nl2 so v6'i UnN; kh6c
pha nl3so v6'i UHaN; khdc pha n/6 so v6'i dong diQn Itrong m4ch Chqn
A l0 crnis B 20 cm/s C 30 cm/sl
R .c L,r
.M.AN
D.40 cm/s;
Cdu24: Con ldc do'n'diro-c treo viro trong thang mdy, khi tlrang nrdy dfrng y€n thi chu ki dao dQng nho cLra
con lic do'p td T Khi thang m6y chuy6n d6ng nhanh dAn d€u di l€n v6'i gia t6c bang l/4 gia tOc ro-i tq'do thi chir ki dao ddng cta con l6c bdng
6
B"
T^l-\i3
Trang 7Cdu 25: Mdt corr lic clon dac d6ng nho v6'i chu ky T, bi€n dd cira dao ddng ld S0 Tho'i gian ng6n nhAt d6 con
l6c don dao d6ng tir vi tri cdn bing d€n vi trf c6 d6rig nang bing th6 ndng la
CAu 26: MOt vat dao ddng didu hoa tr€n rn0t qu! d4o ddi 8 crn Qudng du'ong ngin nhAt md vAt di du'oc trong l/4 chu ki dao dong ld
Cdu21: Mdt con l6c don chi€Lr ddi l kh6i luong rn =2Ag, rnang dien tich q =4.10-7C Chu kj,con l6c khi
khdrig c6 di€n truong lA T:2s (cho g: l0m/s2) Chu kj,dao dQng cira con lac khi df,t con t6c trong mdt di6n
,l
trud'ng d€u co vdc to C narn ngang vd c6 d0 lo'n E : lO'V/crn ld
CAu 28: Mdt con l6c ld xo treo thing di'ng, khi vdt treo cAn bdng thi ld xo gi6n 3 crn Kfch th(ch cho vAt dao
dOrrg tu do theo phu'ong thing dri'ng v6i bi6n dd A = 6cm thi trong mdt chu kj' dao dQng T, ihd'i gian ld xo bi n6n lh:
3364
CAu 29: Mdt corr lic don co chiAu ddi so-i dAy ld / dao dong di€u hoa tai rndt noi c6 gia t6c ro'i tu do g v6'i bi€n dQ g6c as Khi vQt di qLra vi tri c6 li dQ g6c d no co vAn t6c v thi:
l
"& = u2 'r glt2
2
-1lV
B o6 = cr' *- C
ol 6'
CAu 30: S6ng Am chi truy€n du'oc trong cdc m6i trlro'ng
A Khi, bA mAt ch6t long B l<hf, long
CAu 31: Trdn rn[t nu6'c co hai ngudn ph6t song k6t ho.p, nguoc pha Khodng c6ch gifi'a hai di6m dao dQng v6'i .
bi€n dQ cuc dai gAn nhAt tr€n dud'ng thing n6i hai ngu6n ld
2 ))v
CXd =A- + .
(o'
,r2 0
D oi = q' +Lf
B bu6'c s6ng vd tAn sO ddu thay ddi
D bud'c s6ng khdng ddi nhung tAn sd thay dOi. CAu.33:.Ngud'i nghe c6 the phdn biQt duo'c 6m do ddn ghi ta vd do s6o ph6t ra ld do
A t6n s6 kh6c nhau B dd thi dao d6ng cira hai dm kh6c nhau.
C dO cao vd d0 to l<h6c nhau D bi€n dO crlia hai dm khdc nhau.
CAu 34: Tr€n mit nu6'c c6 hai ngudn sting nu6'c gi6ng nhau c6ch nhau 8 cm, s6ng truy€n trdn mflt nu'6'c c6
brL6'c s6ng ld l,2cm thi sd duoLrg cuc dai di qua doan thing n6i hai ngudn la:
CAu 35: NgLr6n dm di6m S ph6t ra song drn truydn trong nr6i trLLdtrg ding hLl6'ng C6 hai ditln A vd B n6rn
trOn nira ciuorg thlng xLrAt phdt tir S Mirc cu'ong dd drn tai A ld Ln : 40 dB tai B ld Le: 80 dB 86 qLra su
h6p thq drn Mflc cudtrg d6 drrr tai trung di€rn C cira AB ld
CAu 32: Khi 6m thanh truydn tir khdng khf vdo nu'6'c thi
A bu6'c s6ng thay ddi.nhu'ng tAn sO khdng d6i \
C brL6'c s6ng vd tdn sd khdng ddi
C6u 36: M4cli di€n xoay chidLr gdm cirdn dAy (L, 9 nOi tiep v6i tLr di€n C Bi€t di€n dp hai ddu cuOn ddy l€ch
pharl2 so v6'i cii€n 6p hai dAu n-r4ch Chon phuong 6n dfrng
.A
CAu 37: Mach RLC nOi tiep dang c6 tinh dung khdng N6Lr ta tdng dAn tAn s6 crha ddng diEn thi hQ sd cdng
suAt cira mach
A kh6ng thay d6i B gi6m C tang
CAu 38: Ph6t bi€u ndo dirng khi n6i vO m6y ph6t diQn xoay chi€u m6t pha?
A Ld dLrng cLr bi6n di6rr n6ng thdnh co n[ng vd ngu'o'c lai
B Ld dLrng cu hoat d6ng nhd'vdo vidc sri'dung tu'tru'd'ng quay
C Ld dLrng cLr hoat dOng du'a tr€n hr€n tu'ong c6rn [r'ng di€n tir'.
D LA clLrrrg cu phAi c6 phAn cdrn lA roto, phAn ung lA stato.
t/<O)f - 4\
D tdng l€n r6i gi6m xu5ng
Trang 8CAu 39: DAt dien ap xoay chi€u c6 gi6tri hi6u dung khdng d6i vao mach RLC nilititip, tAn s6 f thay dOidu-oc.
I(hi f,=5611zvdfz=200 Hzthi cdng su6t c0a mach c6 gid tri bdng nhau vd nho ho'n giri tri cuc dai Gi6 tri cria
; ,( ,.1 ^ i
tdn so dd cong sudt cira mach d4t gi6 tri cuc d4i lA
CAu 40: M6t rnay phdt di€n xoay chidu c6 4 cdp cuc roto cira n6 quay rn6i phirt 1800 vdng MQt.mdy ph6t
di€n khac c6 6 cdp cu'c N6 phdi qLray voi vdn toc bdng bao rrhi€u d€ ph6t ra dong di€n cirng tdn s6 v6'i mdy thu'nhAt?
A.240 vongiphCIt B 3q0 vdng/phrit 9.210 vong/phtt D l200.vong/ph[t
CAu 4l: Eoan mach xoaychi€u gdm diQn tro thuAn R mic ndi ti€p vo'itU diQn C DAt vdo hai dAu m4ch hiQu
diqn th€ u = l\}.l2cos(l 00zz) V thi cuong dQ ddng di€n qua doan mach ld i = 2 sin( '3100nt + 1l O Cdng su6t
ti€u thu di€n cua doan mach ld
th6 xoay chiAu c6 dang tt = 220Ji cos(l0021 - n I 2)V Ddn
CAn 42: M6t ddn neon duo c d4t dud'i hiQu diQn thO xoay chi€u co dang u = 220"1 2 cos(lOuzt - 7T t 2) v t]en
sC tit n6u hiQu dien th6 tri'c thd'i dat vdo ddn c6 gi6 tri nho hon ho4c b6ng I 10 Jt V Khodng thoi glan ddn s6ng trong m5i chu kj, c0a ddng diQn xoay chidu ld
Cdu 43: Mach diQn xoay chidu RLC n6i titlp co tAn s6 f thay d6i (cLrQn ddy thuAn cArn) Khi fr : 50Hz thi
Uc = U.n,"*, khi f2 =200 Hz thi U, = Urn,o" Gi6 tricira tAn s6 Ae nieu diQn thd hiQu dung trdn di€n tro'd4t gi6
tri cu'c dai ld
CAu 44: Chon cdu ihing trong c6c cAu sau?
A Dong diQn xoay chidLr ba p=t',u ia sr,r' ho p l4i cria ba dong diQn xoay chiAu mdt pha.
e phAn irng cua m6y phdt diQn xoay chi6u ba pha cd thti ld r6to hoic stato
C PhAn u'ng cira m6y ph6t di6n xoay chi6u ba pha la stato
D Ngu,u-6n tic cira m6y phdt ba pha du'a tr0n hi6n tu'o-ng cdrn ung diQn tu' vd tu trud'ng quay
CAu 45: Mach RLC noi tiep theo thrl tu gdm cudn ddy thudn cAm L = l,5ln H, diOn trd R vh tu C Dat vdo hai
cldu mach hi6u di6n thd uou =100J-2cos(l00nt) f fft^y Odi C ta thay khi dung kh6ng Zc= Zo thi UMu dat cuc
ciai vlL Ur,rR = 20OV (M ln didm nim gifa cuOn dAy vd di€n trd) Gi6 tri dung khr4ng cira tu Zc khi d6 la
CAu 46: M6r m6y phdt diQn xoay chi0u c6 cdng suAt 10O0kW Dong diQn do m6y ph6t ra sau khi tdng thi5
duo-c truydn di xa bang du'o'ng ddy c6 di€n tro' 20O Bi€t hi€u di€n th6 duo-c dua lOn cluo'ng ddy ld I lOkv
Hao phidi0n ndng tr6n du:o'ng dAy ld:
A AP = l2l.6W B AP=1653W C AP = 165.3W D AP =242W Cdu 47: M6t mach clao d$ng LC li tLrong c6 di€n dung C cu0n dAy thuAn cdm c6 dQ tr,r cdm L' Chu ki cua ndng lLLong cli€n vd ndng luo-ng tir la
C T - ^[t[ tz" . D.T="Jrc.
A T =LnJ LC' . B I=2zrl{rc.
Cflu 48: Chon cAr-r sai khi n6i vd s6ng di€n til?
A Song cli€n tir ld song ngang
B S6ng di6n til c6 th€ lan truydn trong rnoi m6i trLro'ng k€ cA trong chdn kh$ng
C Song di6n tir c6 th€ phdn xa vd khfrc xa.
D Hai thdnh phAn diQn trud'ng vd tir trud'ng luon dao d6ng vuong pha v6'i nhau
Cdv 49: M6t mach dao dQng diQn til tu do c6 diOn dung cira tq C = 4pF , cudn ddy thuAn cim c6 d0 tq cdm L
=7,52H.Trong qlratrinh dao ddng, hiOu diQn th6 cuc d4i giii'a hai b6n tq td 12V Khi hiQu di$n th€ gifi'a hai
bdn tu ld u :9V thi cu'd'ng dQ ddng di€n i trong rn4ch ld:
Ciu50:M$tmachdaod$rrgdiQntil'tucloc6 C=24pF,L=0,06H.hiQucliQnth6ctrcdai tr6ntudignUo:
4V Tai thd'i di6m md cu'o'ng dQ ddng di€n trong rnach i = 0,044 thi hiQu diQn th€ trOn tu di€n:
Trang 9ud rgr rHUpnr Hoc LAFI s NAna Froc z00e - z0t0
ptOl'{ THI : vAr lV
Thdi gian ldm bdi : 90 phttt Mdi cdtt cd 4 phuong dn trri loi,Thi sinh chon m6t (01) phtong dn trti ldi hop t! nhdt
Ciu 2: Con l6c lo xo dao d6ng di6u hda theo phucrng thing drmg vcri chu ki T = 0,4 s, bi6n dd A = 8 cm Cho g : 10 m/s2 vd, n2 = 10 Thdi gian ng6n nUAt ae vdt di tu vi tri cdn bing dtin vi tri ld xo c6 chidu ddi tu nhi€n ld
Ciu 3: Vdt thuc hiQn d6ng thdi 4 dao dQng di6u hoa cung phuongc6 circ phucrng trinh: x1 = 3sin(nt +:r) cml x2 = 3cosnt (cm); x3 = 2sin(nt + n) cm; x4 = Zcosnt (cm) Ly dQ cria v4t t4i thoi di6m t : 2 s ld
EAI HOC KHOA FIOC TU'NIII0N
riHOI T.FIPT CI{UYON ToAN TIN
-, -m -CAu 1: Trong thi nghiOm lAng v6 giao tiroa 6nh s6ng, khoAng cdch gifa hai khe a: 1,5mm, tu 2 khe ddn
mdnquansdt D:l,2m.Ngudnph6t6nhs6ngtringc6budcs6ng 0,387-zm<7<0,76pm S0c6cbilcxa
cho v6n s6ng t4i M c6ch vAn trung tdm2 mm lir
D l/30 s.
CAu 4: Khi n6i ve song di0ntri, phAt biOu ndo sau ddy Id sai?
A S6ng diQn tri bi phdnx4 khi g{p m{t phdn c6ch gita hai mdi trucrng
B S6ng diQn tu chi truydn duoc trong mdi tru&ng v4t ch6t dnn h6i
C S6ng diQn tu lA s6ng ngang
D S6ng diQn tu lan truy0n trong chdn ichdng vdi v4n t6c c = 3.108 m/s
Ciu 5: Mdy ph6t diQn xoay chi6u mQt pha mi phAn cdm c6 3 cep cWc bac nam, Rdto quay v6i vdn t6c
1500 vong/ phfrt.TAn s6 ddng diQn do m6y tao ra ld:
A f : 50Hz B f : 60Hz C f = 75Hz D f : 100 Hz
Ciu 6: Mdy bi6n th6 c6 s6 vong cu6n ss cAp vd thri cAp ldn lugt ld 800 vong vd 400 vong Dat hieu di€n th6 kh6ng d6i U = 50V vio hai d6u cuQn so cAp thi hiQu di6n th6 hi€u dung traiOAu cuQn thri c6p ld:
CAu 7: Trong so dd cria rnQt m6y ph6t song vO tuy6n diQn, kh6ng c6 mach (teng)
Ciu 8: Dao dQng co hgc cfra con lic vit lf trong d6ng hd qud l6c khi d6ng h6 chay dung ld dao dQng
CAu 9: Con lic lo xo c6 m = I kg, dao dQng di€u hoi vir c6 cs ndng E : 125 mJ T4i thoi diilm ban dAu vdr
co vdn tdc v: 25 cm/svi gia t6c a: - 6,25.6 *ltt DOng ndng con 6c tai thcyi di0m t= 4,25T lit
Ciu l0: Con li.c dsn co khOi luqng m : 100 g, chidu ddi / = 100 cm Kdo con lec lQch kh6i vi tri cdn bing
g6c o6 rdi thi kh6ng v{n t6c ban dAu de khi dao dQng thi lirc cdng d6y T,.* : 3T,in Cho g = 10 m/s2 VAn
t6c cia vdt khi T = 2Tr;n li
Ciu l1: Hai ngudn s6ng tr0n m6t nudc lh S, vi S, c6ch nhau S,S, = 71 phi{t ra hai dao ddng c5 phuong trinh
u, = | acosot vi u^ 2 = acos(rrrt + n l2) S6pg khong suy giim Sd dao _ _; e _i-_ dOng cuc dai _: _-_ trOn doan ;-: _l_2-S S^ ld
Ciu 12: Khi noi vO s6ng co hoc, ph6t bi6u ndo sau ddy id sai?
A S6ng co hoc c6 phucrng dao dQng vu6ng g6c vdi phucrng truydn song ld s6ng ngang.
B Song co hoc lir sg lan truydn dao.dQng co hgc trong mdi trucrng vdt ch6t
C Song co hoc truy€n dugc trong tdt ch citc m6i truong rin, l6ng, khi vd chdn kh6ng
D Song 6m truyAn trong kh6ng khi ld song dgc
Ciu 13: Ngu6n dm di€m S phet ra s6ng dm truyAn trong m6i trucrng ding huong- C6 hai di6m A vd B nim
tr6n nira duong thing xu6t ph6t tt S Mric cuctng dO am tai A vd B thoa mdn La - Le: 10 dB Bo qua su h6p thr; Am Tj' sd culng d0 Am IA / IB la
Ma dd rhi: 3il
Trang 10C^e: 11:Jtong*thi nghiQm giao thoa trdn mdt nu6c, hai ngudn ktlt hup A vd B dao d6ng cung pha v6i t6'
sd f = 20Hz; AB : 8cm Bi€t tdc dd truyAn song trdn mat iudc ld 30cm/s M6t
ducrlg tron co t6rn tai trung
di6m O cira AB, nim trong mqt phing ctrria cac vAn giao thoa, b6n kinh 3,2 J"t ;tji6;;';;; A'i"*.u" uri
tr6n duong tron lii
AB ddi 80 cm c6 dAu B c6 dinh, dAu A mic vdo mQt nhdnh am thoa dans dao
Khi dm thoa rung, trdn day c5 s6ng drmg vdi 4 br,urg s6ng Vdn t6c truy6risong
Cdu 16: MQt ngu6n s6ng trdn
B v: 15 rr"rs C v: 20 mJs D v = 25 rrls. mdt nudc c6 f = 500H2 Ngudi ta thdy 2 di6m cung o tr€n m6t phucrng truyAn s6ng gAn nhau nhAt, cdch nhau 10 cm lu6n dao dQng lQch '2phu 1 V4n tdc truyAn s6ng ld:
4.14.
Cdu 15: MQt dAy ddn h6i
dQng v6i tAn sd f : 50 Hz.
tr6n d6y ld :
A v =10 rrls.
A.200 cm/s
A.31)"/g
A,25 HZ
Ciu 23: M4ch RLC n6i
CAU 17: Hai ngudn s6ng trdn m6t nudc le Sr, 52 c6ch nhau S,S, = 7),ph6t ra hai s6ng c6 phucrng trinh u, =
asinrrlt vh u = acosot S6ng khOng suy gi&m Didm M tron trung truc cfia S1Sr, gdn nhat, c6 dao dong cr)ng
2
pha vdi dao dong phi{t ra 6 ngudn S, c6ch S, mOr khoing li
B 100 cm/s
8.33)"/8
8.50 Hz
C 100 n/s
c 4n,lg
D.200 rnls
D 49?,,19
D s0 Jzu,
trd thuAn r : 30Q, tu di€n co
D P:302.5 W
1,2s, pha ban ddu ld n fi.T(;c
CAU 18: Didu nio sau dAy kh6ng dring khi n6i vd s6ng dtrng
A Flinh Anh s6ng drnrg lap lai sau l14 n:\vs k! sdng
B cric phdn tt mOi trudng & hai bOn m6r nft'dao d6ng nguo.c pha vdi nhau
C Cr{c didm nam gifra hai nrit iiOn tidp dao d6ng cDng pha v6i nhau
D, Flinh inh s6ng alrlg t1q lai sau-m6i nir,a ch,u kI i9ng.
9^::^1?:[.rlff!t:l +l tiic3.9 cu6n scr,cdp Cqryif y"ngja{ y? fol thri c6p gop 80 vong ddy M6c hai
:li:r:l^:? can y11.1ang, diQn.xoay li:,u, khi d6 hiQu diQn thd hi6u dpng o hai dAu cuQn thu c6p d€ ho ld
20 v, A Bi6t , hao .,:phl diQn ndng cria m6y bii5n thc le kh6ng ddng k6 HiQu dilen the .1 hliQu dpng o hai dAu cu6n s0 cap co gla tn bang
Cf;u^2Ot
.y9l$1n46l d.i€n loay chiAu c6 c6ng s*5t kh6ng ddi, ruyAn diQn di xa voi diQn 6p hai da; day ta noi n-uydn Ci h 200kV thi t6n hao diQn nang ld 30% Ntiu tang diQn 6p tuyen tni l6n 500kV thi t6n hao diQn nang ld:
Ci.:u 2l: X4ach RLC noi tiep theo thrl tu gdm tu C, bidn tr& R vi thudn cArn L Dat vdo hai ddu mach hieu diQn thd xcray chitiu uo, = u,,cos(l00nt - nl3) V Thay ddi R ta thay khi R = 200e thi cudng d0 dbng di€n nhanh pha hoi hiOu diOn thd hai ddu mach, P = P,'u* = 100W vi Llr,as= 200V (M la didm nam"gi1a ru ua dien
tro) Dung khring cria tu c5 gi:i tri ld
Ciu22: Mach RLC ndi titip gdm diQn tro,thuAn R: 100 O, thuAn cdm c6 L = lHvd tu di€n co
TC
ln-4
C - ' " F Ei€n 6o xoay chiAu gifra hai dAu doan m4ch c6
gi6 tri hiQu dpng U = 200V, tAn s6 /thay d6i 2n
dusc Vdi gi6 tri ndo cua/ thi diQn 6p hiQu dpng gita hai bin cuc tp diQn co giittri cuc dai ?
C.2s J6 Hz
ti0p g6m bi6n tro R, cudn ddy c6 L = l0-4
C ='" F' Dat vdo hai dAu mach diQn 6p u = 220cos100nt (V) DiCu chinh R d€ cdng sudt toa nhi6t tr€n
7t
di6n tro R dat cuc dai Cdng suat .uc dai d6 ld :
lu ua
5n
Cdu 24: Con l6c ld xo dao d6ng didu hod v6i bi€n d6 A = 4 cm, chu k) T =
do trung binl lon nhAr v4t thuc hiQn duoc rrong khoAng rhoi gian 0.g s ii