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Tiêu đề Amplifiers - small signal model
Trường học Massachusetts Institute of Technology
Chuyên ngành Electrical Engineering
Thể loại Lecture notes
Năm xuất bản Fall 2000
Thành phố Cambridge, Massachusetts
Định dạng
Số trang 15
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6.002 CIRCUITS Amplifiers --Small Signal Model... Saturation discipline satisfied... v In other words, our circuit behaves like a linear amplifier for small signals... Input valid opera

Trang 1

6.002 CIRCUITS

Amplifiers

Small Signal Model

Trang 2

Review

„ MOSFET amp

S V

L

R

DS i

v O

v

„ Saturation discipline — operate

MOSFET only in saturation region

„Large signal analysis

1 Find v O vs v I under saturation discipline

2 Valid v I , v O ranges under saturation discipline

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Large Signal Review

1 v O vs v I

v O = V S K (v I −1)2

R

valid for v I ≥ V T

and

v O ≥ v I – V T

(same as i DS K v O 2 )

Trang 4

2 Valid operating ranges

S

O

O

v O =

v >

O

v <

v V

1V

“interesting” region

for v I Saturation discipline satisfied

Trang 5

But…

S

V O

v

O

v =

I

v

v I −V

v

v

Demo

V

1V

Amplifies alright, but distorts

v

v

Amp is nonlinear … /

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Small Signal Model

~ 5V V S

~ 1V

Hmmm …

L

T

I

S

O V K v V R

v

2

2

= Amp all right, but nonlinear!

I

v

O

v

T

V

V

1 ~ 2V

Insight:

(V I , V O )

Focus on this line segment

So what about our linear amplifier ???

But, observe v I vs v O about some

point (V I , V O) … looks quite linear !

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Trick v o

i

v

I

V

O

V ( V , I V O )

O

v

looks linear

™ Operate amp at V I , V O

Æ DC “bias” (good choice: midpoint

of input operating range)

™ Superimpose small signal on top of V

™ Response to small signal seems to be

approximately linear

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Trick v o

i

v

I

V

O

V ( V , I V O )

O

v

looks linear

™ Operate amp at V I , V O

Æ DC “bias” (good choice: midpoint

of input operating range)

™ Superimpose small signal on top of V I

™ Response to small signal seems to be

approximately linear

Let’s look at this in more detail —

I III from a circuit viewpoint

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We use a DC bias V I to “boost” interesting input

signal above V T , and in fact, well above V T

interesting

input signal

+ – + –

S

V

L

R

v O

V

Offset voltage or bias

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Graphically

interesting

v O

S

V

L

R

+ – + –

input signal

V

S

V v O

O

V

operating point

O

I V

V ,

I

V

T

V

O v

v =

0

I −V

v

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aka incremental model

aka linearized model

Notation —

Input:

total

v I = V I + v i

DC small

variable bias signal (like ∆v I) bias voltage aka operating point voltage

Output: v O = V O + v o

Graphically,

V I

V O

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II Mathematically

(… watch my fingers)

v O = V S R L K (v I −V T )2

V O = V S R L K (V I −V T )

2

substituting v I = V I + v i v i << V

v O = V S R L K ( [V I + v i ]− v T )

= V S R L K ( [V I −V T ]2 + 2[V I − v T ]v i + v i 2

O

T

I

L

S V V

2

K

R

V − − ) − R L K (V I −V T )v

v o = −R L K ( V I −V v T )

g m related to V

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Mathematically

v o = −R L K ( V I −V v T )

g m related to V

v o = −g m R L v

For a given DC operating point voltage V I

V I – V T

v o = − A v

constant w.r.t v

In other words, our circuit behaves like a linear amplifier for small signals

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Another way

v O = V S R L K (v I −V T )

v o =

dv

d

I

VS − R L 2 K (v I −V T )2

⋅ v

I

I

v

slope at V

v o = −R L K (V I −V T ) ⋅ v

g m = K (V I −V T )

A = −g m R L amp gain Also, see Figure 8.9 in the course notes

for a graphical interpretation of this result

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More next lecture …

Demo

DS

i

I

V

O

v

load line

operating point

input signal response

V O

How to choose the bias point:

1 Gain component g m ∝ V I

2 v i gets big Æ distortion

So bias carefully

3 Input valid operating range

Bias at midpoint of input operating

range for maximum swing

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