PT LUONG GIAC TRONG DE THI DAI HOC

1) A_02 Gi¶i ph¬ng tr×nh: 5 cos3x + sin3x

sin +

1 2sin2x

x



= cos2x + 3

2) D_02 T×m c¸c nghiÖm thuéc [0; 14] cña ph¬ng tr×nh:

cos3x - 4cos2x + 3cosx - 4 = 0

3) A_03 Gi¶i ph¬ng tr×nh: cotx - 1 = cos2x

1 + tanx + sin

2x - 1

2sin2x

4) D_03 Gi¶i ph¬ng tr×nh: sin2(x

2 - π

4)tan2x - cos2 x

2 = 0 5) D_04 Gi¶i ph¬ng tr×nh: (2cosx - 1)(sinx + cosx) = sin2x - sinx

6) A_05 Gi¶i ph¬ng tr×nh: cos23xcos2x - cos2x = 0

7) D_05 Gi¶i ph¬ng tr×nh: cos4x + sin4x + cos(x - π

4)sin(3x -

π

4) -

3

2 = 0 8) A_05_dù bÞ1 T×m nghiÖm trªn kho¶ng (0 ; ) cña ph¬ng tr×nh:

4sin2 x

2 - 3cos2x = 1 + 2cos

2(x - 3π

4 )

9) A_05_dù bÞ 2 Gi¶i pt: 2 2 cos3( x - π

4) - 3cosx - sinx = 0

10) D_05_dù bÞ 1 Gi¶i pt: tan(3π

2 - x) +

sin

1 cos

x x

 = 2

11) D_05_dù bÞ 2 Gi¶i pt: sin2x + cos2x - 3sinx - cosx - 2 = 0

12) A_06_dù bÞ 1 Gi¶i pt: cos3xcos3x - sin3xsin3x = 2 + 3 2

8

13) A_06_dù bÞ 2 Gi¶i pt: 4sin3x + 4sin2x + 3sin2x + 6cosx = 0

14) B_06_dù bÞ 1 Gi¶i pt: (2sin2x - 1)tan22x + 3(2cos2x - 1) = 0

15) B_06_dù bÞ 2 Gi¶i pt: cos2x + (1 + 2cosx)(sinx - cosx) = 0

16) D_06_dù bÞ 1 Gi¶i pt: cos3x + sin3x + 2sin2x = 1

17) D_06 Gi¶i pt: cos3x + cos2x - cosx - 1 = 0

18) A_07 Gi¶i ph¬ng tr×nh: (1 + sin2x)cosx + (1 + cos2x)sinx = 1 + sin2x 19) B_07 Gi¶i ph¬ng tr×nh: 2sin22x + sin7x - 1 = sinx

21) D_07 Gi¶i ph¬ng tr×nh: (sin2 x

2 + cos

2x

2 )

2 + 3 cosx = 2

22) C§_07 Gi¶i ph¬ng tr×nh: 2sin2(π

4 - 2x) + 3 cos4x = 4cos

2x - 1

23) A_08 Gi¶i ph¬ng tr×nh:

3π

2

24) B_08 Gi¶i ph¬ng tr×nh: sin3x - 3 cos3x = sinxcos2x - 3 sin2xcosx 25) D_08 Gi¶i ph¬ng tr×nh: 2sinx(1 + cos2x) + sin2x = 1 + 2cosx 26) C§_08 Gi¶i pt: sin3x - 3 cos3x = 2sin2x

A09: GPT

(1 2 sin ) cos

3 (1 2 sin )(1 s inx)

x





B09: GPT rf

D09: GPT 3 os5c x 2sin 3 cos 2x x s inx 0 

A10: GPT

(1 s inx os2 )sin

1

x





B10: GPT (sin 2x c os2 )cosx x 2cos 2x sinx 0 

D10: GPT sin 2x c os2x3sinx cosx 1 0