PHƯƠNG TRÌNH LƯỢNG GIÁC - TRONG CAC DE THI DAI HOC TU 2002 DEN 2009 [DH A02] Tim x €(0; 22) :5| sinx + COSSX #SINSX =cos2x +3
1+2sin2x [DH B02] sin’ 3x - cos’ 4x =sin? 5x - cos” 6x
[ĐH D02] Tìm x e| 0:14| cos3x - 4cos2x +3cosx - 4 =0
[DH A031 cotx-1=- 9323 1
+sin’ x - —sin2x
1+tanx 2
[DH B03] cotx- tanx + 4sin2x =
sin2x
X
[DH D03] sin”
tna2x - cos” = =0
[DH B04] Ssinx - 2 =3(1- sinx) tan” x
[ĐH D04] (2cosx - 1)(2sinx +cos x) =sin2x - sinx
[DH A05] cos’ 3xcos2x - cos’ x =0
[DH B05] 1+sin+cosx +sin2x +cos2x =0
[ĐH D05] cos! x +sin' x + cos| x- =|sin| 3x - : - š =0
2{cos” x +sin" x) - sinx cosx
V2 - 2sinx
[ĐH D06] cos3x + cos2x - cosx - Ï =0
=4
[ĐH B06] cotx +sinx 1 + tan x tan C
[DH A07] (1 +sinˆ x) cos x +(1 +cos’ x) sinx =l +sin2x
[ĐH B07] 2sin” 2x +sin 7x - 1 =sinx
2
sin— +cos—
+
ae
[DH B08] sin® x - ¥3 cos’ x =sinxcos’ x - V3 sin’ xcosx
[DH D08] 2sinx(1 +cos2x) +sin2x =1+2cosx
[CD 08] sin3x - ¥3 cos3x =2sin2x
(1- 2sinx)cosx (1 +2sinx)(1- sinx)
[DH B09] sinx + cos xsin 2x + V3 cos3x =2(cos4x +sin’ x)
[DH D09] V3 cos 5x - 2sin3x cos 2x - sinx =0
[CD 09] (1+2sinx) cosx =l +sinx +cos x
774
—- X
4
[DH A09]