Code bài toán quản lí sử dụng stack c

Code Bài toán quản lí sử dụng Stack C KHAI BAO DU LIEU 2 KHAI BAO CAU TRUC DU LIEU 2 KHAI BAO DANG STACK CUA DU LIEU 2 KHOI TAO STACK RONG 3 KIEM TRA STACK RONG 3 THEM PHAN TU VAO STACK 3 NHAP 1 NV 4 NHAP DANH SACH NHAN VIEN 5 IN 1 NV 5 IN DSNV 6 TIM NV CO MA X NAO DO 6 TIM VA IN TTNV CO LUONG CAO NHAT 7 TIM VA IN TTNV CO LUONG THAP NHAT 8 TIM VA IN TTNV CO SO CON > 3 9 SAP XEP NV THEO SO LUONG TANG DAN 9 SAP XEP NV THEO SO LUONG GIAM DAN 10 XOA 1 NHAN VIEN KHOI DANH SACH 11 IN PHAN TU DUNG DAU DANH SACH 12 DEM SO NHAN VIEN CO MUC LUONG TREN 4 TRIEU 13 DOI TEN NHAN VIEN CO MA X 14 TIM NV THEO TEN 15 TIM VA IN TTNV CO BANG CAP CAO HOC 16 TIM NHAN VIEN CHUA KET HON 17 THAY DOI THONG TIN NHAN VIEN CO MA X 17 IN THONG TIN NHAN VIEN DAT KET QUA TOT 19 TIM VA IN TTNV CO HE SO LUONG CAO NHAT 20 TIM VA IN TTNV CHUA CO CON 20

M c L cụ ụ

Code Bài toán quản lí sử dụng Stack C

//KHAI BAO DU LIEU 2

//KHAI BAO CAU TRUC DU LIEU 2

//KHAI BAO DANG STACK CUA DU LIEU 2

//KHOI TAO STACK RONG 3

//KIEM TRA STACK RONG 3

//THEM PHAN TU VAO STACK 3

//NHAP 1 NV 4

//NHAP DANH SACH NHAN VIEN 5

//IN 1 NV 5

//IN DSNV 6

//TIM NV CO MA X NAO DO 6

//TIM VA IN TTNV CO LUONG CAO NHAT 7

//TIM VA IN TTNV CO LUONG THAP NHAT 8

//TIM VA IN TTNV CO SO CON > 3 9

//SAP XEP NV THEO SO LUONG TANG DAN 9

//SAP XEP NV THEO SO LUONG GIAM DAN 10

//XOA 1 NHAN VIEN KHOI DANH SACH 11

//IN PHAN TU DUNG DAU DANH SACH 12

//DEM SO NHAN VIEN CO MUC LUONG TREN 4 TRIEU 13

//DOI TEN NHAN VIEN CO MA X 14

//TIM NV THEO TEN 15

//TIM VA IN TTNV CO BANG CAP CAO HOC 16

//TIM NHAN VIEN CHUA KET HON 17

//THAY DOI THONG TIN NHAN VIEN CO MA X 17

//IN THONG TIN NHAN VIEN DAT KET QUA TOT 19

//TIM VA IN TTNV CO HE SO LUONG CAO NHAT 20

//TIM VA IN TTNV CHUA CO CON 20

#include<conio.h>

//KHOI TAO STACK RONG

void Initstack(Stack &s)

{

s.top = NULL;

}

//KIEM TRA STACK RONG

int IsEmpty( Stack s)

//THEM PHAN TU VAO STACK

void Push( Stack &s,NV x)

printf("Nhap ma nhan vien: ");scanf("%d",&x.MNV);

printf("Nhap ten nhan vien: ");fflush(stdin);gets(x.Hoten);

printf("Tinh trang hon nhan(m/s): ");fflush(stdin);gets(x.GD);

printf("So con: ");scanf("%d",&x.Con);

printf("Trinh do van hoa(C1,C2,C3,DH,CH): ");fflush(stdin);gets(x.TDVH);printf("Ket qua lam viec(TO,TB,KE): ");fflush(stdin);gets(x.KQ);

printf("Nhap he so luong(1->9): ");scanf("%f",&x.HSL);

tg=pt+(x.HSL*1350000);

x.Luong=tg;

}

//NHAP DANH SACH NHAN VIEN

void NhapDSNV(Stack &s)

}}

}

for(p=s.top;p!=NULL;p=p->next)

{

if(Max==p->infor.Luong){

}}

Min=p->infor.Luong;

}}

for(p=s.top;p!=NULL;p=p->next)

{

if(Min==p->infor.Luong){

InNV(p->infor);

}}

}

d++;

}}

//SAP XEP NV THEO SO LUONG TANG DAN

void SXLUONGTANG(Stack &s)

for(q=p->next;q!=NULL;q=q->next){

if(p->infor.Luong>q->infor.Luong){

tg=p->infor;

p->infor=q->infor;

q->infor=tg;

}}

}

InDSNV(s);

}

//SAP XEP NV THEO SO LUONG GIAM DAN

void SXLUONGGIAM(Stack &s)

if(p->infor.Luong<q->infor.Luong){

p->infor=q->infor;q->infor=tg;

}}

void XoanV(Stack &s)

pop(s);

}}

}

//IN PHAN TU DUNG DAU DANH SACH

void top( Stack s)

}}

Node *p;

for(p=s.top;p!=NULL;p=p->next)

{

if(strcmp(p->infor.TDVH,"DH")==0){

d++;

}}

//DOI TEN NHAN VIEN CO MA X

void DOITEN(Stack &s)

if(p->infor.MNV==n){

printf("Nhap ten thay doi: ");fflush(stdin);gets(st);strcpy(p->infor.Hoten,st);

d++;

}}

d++;

}}

InNV(p->infor);

}}

}

//TIM NHAN VIEN CHUA KET HON

InNV(p->infor);

d++;

}}

//THAY DOI THONG TIN NHAN VIEN CO MA X

void THAYDOI(Stack &s)

if(p->infor.MNV==n){

printf("1.Thay doi ho ten nhan vien");

printf("2.Thay doi tinh trang hon nhan nhan vien");

printf("3.Thay doi so con cua nhan vien");

printf("4.Thay doi trinh do van hoa nhan vien");

printf("5.Thay doi ket qua nhan vien");

printf("6.Thay doi he so luong nhan vien");

printf("Moi chon chuc nang: ");scanf("%d",&x);

switch(x){

case 1:printf("Moi nhap ho ten thay doi:

if(p->infor.Con>=2){

pt=pt+(5*(p->infor.HSL*1350000))/100;}

if(strcmp(p->infor.TDVH,"CH")==0){

pt=pt+(10*(p->infor.HSL*1350000))/100;}

tg=pt+(p->infor.HSL*1350000);

p->infor.Luong=tg;

}}

InNV(p->infor);

}}

Max= p->infor.HSL;

}}

for(p=s.top;p!=NULL;p=p->next)

{

if(p->infor.HSL==Max){

InNV(p->infor);

}}

if(p->infor.Con==0){

InNV(p->infor);

}}

printf("\n2 In danh sach");

printf("\n3 Tim nhan vien co ma x");

printf("\n4 Tim va in thong tin nhan vien co luong cao nhat");

printf("\n5 Tim va in thong tin nhan vien co luong thap nhat");printf("\n6 Tim va in thong tin nhan vien co so con > 3");

printf("\n7 Sap xep nhan vien theo so luong tang dan");

printf("\n8 Sap xep nhan vien theo so luong giam dan");

printf("\n9 Xoa mot nhan vien khoi danh sach");

printf("\n10 In ra phan tu dung dau danh sach");

printf("\n11 Dem so nhan vien co luong tren 4 trieu");

printf("\n12 Dem so nhan vien co bang cap Dai hoc");

printf("\n13 Doi ten NV co ma x");

printf("\n14 Tim nhan vien theo ten");

printf("\n15 Tim in thong tin nhan vien co bang cap cao hoc");

printf("\n16 Tim nhan vien chua ket hon");

printf("\n17 Thay doi thong tin nhan vien");

printf("\n18 In thong tin nhan vien co ket qua lam viec tot");

printf("\n19 Tim va in thong tin nhan vien co he so luong cao nhat");printf("\n20 Tim va in thong tin nhan vien chua co con");

printf("\nMoi ban chon chuc nang: ");scanf("%d",&n);

case 11:DEMTREN4TRIEU(s);break;case 12:DEMNVBANGDH(s);break;case 13:DOITEN(s);break;

while(n!=0);

getch();

}