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Ôn t p ch ng 4 - i s 10 c b n GV: Thái V n D ng

D NG 1 : GI I B T PH NG TRÌNH

1) 2x2 –5x + 2 < 0 ; 2) –5x2–4x + 12 < 0 ; 3) 16x2 +40x + 25 > 0 ; 4) –2x2 + 3x -7 > 0

5) 3x2 – 4x  0 ; 6) 15 2 1 1

x

x

; 7) x22x  ; 8) 8 0 2

4x 20x25 0 9)    2 

2x1 x  x 30  10) 0 (3x – x2)(x2– 6x + 9) > 0 11) (5 – x)( 16x2– 8x + 1) < 0

12)

2

2

3 4 4

0 6

x x

x x



  13)

2

2

2

0

2 5 2

x x

x x





  14) 2

2

0

3 5 2

x

x x

15) 2

0 ( 5)(6 2 )

x

  16)

2

8 15

0

2 5

x x x

 17)

2

2

4 4

0

4 3

x x

x x

18) 23 7

0 2

x

x x





  19)

2

2

2 0 9

x x x

 H BPT)

2 2

6 0



  

20)

   

2

2

4 4

0

x x

   21)

2

2

3 4 11

1 6

x x

x x



  22)

5 13 1

x

23) 23 7

2 2

x

x x



 

2

2

6 9

0

x x

   25)

2

2

2

0

2 5 2

x x

x x

26)

2

8 15

0

2 1

x x

x

2

2

3 10

0 9

x x x

2

2

2

0

4 5 6

x

x x

29) 4 1

2 4(2 )

x

x x

2

2

3 2

x x

x x

 

 

2

1

3 5 2

x

x x

32)

2

2

1

1 2

x x

x x



 

7 8 3(1 )

1

x x

x



0

3 9 2 1

D NG 2 : GI I BPT CH A N D I D U C N

0 B

A B





0 0

A

A B

 



 



;

2

0 0 0

A B

A B

B

A B

 







   







 1) x2 x 12  2) 7 x 2

21 4 x x   3) x 3 2

1 x 2x 3x  5 0 4) 5x x 2  6 3 2x ; 5) x2    6) (x 6 x 2 x6)(x12)   x 1

7) 2x2  x 3 x22x 8) 3 2 2

4 3 2 10 11

x  x  x  x 10) x2   x 1 3 11)x 2

3x 2 3x 5x 12)2 2 2

4x 9x 5 2x   x 1 13) x23x10  x 2 14) 2x2    x 3 1 x 15) x2 2 4 x23x 3 3x

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Ôn t p ch ng 4 - i s 10 c b n GV: Thái V n D ng

D NG 3 : GI I BPT CH A N TRONG GIÁ TR TUY T I

|A| B A B

A B





     ; |A| B A B

A B





 ; |A| | B|(A B A B )(  ) 0 1) | x   3 | 2 x  3 2) | 4   x | 2 x  3 3) | 4 3 |  x    2 x 3

4) | 5 x     3 | 6 x 3 5) | 4 2 | 2  x  x  3 6) | 4 3 | | 2  x  x  3 |

7) 2

2x | 5x 3 | 0 8) 2

8 | 3 4 |

|x   1| 2x 0

|x 4x 3 | |x 4x5 | 11) 2 2

|x 3x  2 | x 2x 12) 2

| |xx 13) | x   3 | 0 14) | 2 3 | 0  x  15) | 2 3 | 0  x 

16) |1 5 |  x   2 17) | 9    x | 1 18) | x   5 | 0

19)

2

2

4

1 2

1 0

| 3 |

x x

  

| 2 |

3

x

D NG 4 : BÀI TOÁN CH A THAM S

( ) 0

0

f x x

a

 



 ;

0 ( ) 0

0

f x x

a

 





( ) 0

0

f x x

a

 



 ;

0 ( ) 0

0

f x x

a

 





T đó: 1) f x ( )  0 vô nghi m  f x ( )    0, x

2) f x ( )  0 vô nghi m  f x ( )    0, x

3) f x ( )  0 vô nghi m  f x ( )    0, x

4) f x ( )  0 vô nghi m  f x ( )    0, x

Bài 1: Xác đ nh m đ BPT nghi m đúng v i m i x:

a) 2x2(m3)x m   b) 3 0 2

2x (m 2)x m 0

c) (2m1)x22(m1)x 1 0 d) mx22(m3)x3m 1 0

e) (m2)x2(3m1)x4m  f) 2 0 2

(m1)x (m1)x 1 2m0

Bài 2 Xác đ nh m đ b t ph ng trình sau vô nghi m:

a) mx2(2m1)x m   b)1 0 2

(m1)x 2(m3)x m   2 0 c) mx2 + (m – 1)x + m – 1 < 0 d) (2m – 5)x2– 2(2m – 5)x + 1 ≥ 0

Bài 3: Tìm các giá tr m đ ph ng trình:

a) x2 + 2(m + 1)x + 9m – 5 = 0 có hai nghi m phân bi t

b) x2 – 6m x + 2 – 2m + 9m2 = 0 có hai nghi m d ng phân bi t

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