Statistics, Correlation Function and Spectral Density 392 Small Perturbation Method Dirichlet Problem for One-Dimensional Surface Neumann Problem for One-Dimensional Surface Kirchhoff Ap
Trang 1Statistics, Correlation Function and Spectral Density 392
Small Perturbation Method
Dirichlet Problem for One-Dimensional Surface
Neumann Problem for One-Dimensional Surface
Kirchhoff Approach
Dirichlet Problem for One-Dimensional Surface
Neumann Problem for One-Dimensional Surface
References and Additional Readings
Scattering of Electromagnetic Waves: Theories and Applications
Leung Tsang, Jin Au Kong, Kung-Hau Ding Copyright 2000 John Wiley & Sons, Inc ISBNs: 0-471-38799-1 (Hardback); 0-471-22428-6 (Electronic)
Trang 2390 9 1-D RANDOM ROUGH SURFACE SCATTERING
Imagine now that the surface is rough It is clear from Fig 9.1.2 that the two reflected waves have a path length difference of 2h cos & This will give a phase difference of
If h is small compared with a wavelength, then the phase difference is in- significant However, if the phase difference is significant, the specular re- flection will be reduced due to interference of the reflected waves that can partially “cancel” each other The scattered wave is “diffracted” into other directions A Rayleigh condition is defined such that the phase difference is 90’ [Ishimaru, 1978; Ogilvy, 19911 Thus for
x
h < scosOi the surface is regarded as smooth, and for
x h> gcosBi
(9.1.2)
(9.1.3) the surface is regarded as rough For random rough surface, h is regarded as the rms height
We will consider rough surface scattering Both the cases of scalar waves and vector electromagnetic waves will be treated
For the case of scalar wave, let us consider an incident wave $&‘5;) im- pinging upon a rough surface The wave function $J obeys the wave equation:
The rough surface is described by a height function x = f(z, y) For a flat surface, f(z, y) = 0 Two common boundary conditions are those of the Dirichlet problem and the Neumann problem For the Dirichlet problem, at the rough surface boundary z = f (z, y) we have
For the Neumann problem, the boundary condition is at z = f(z, y)
w -
Trang 35 1 Introduction 391
d
where & is the normal derivative
For electromagnetic wave scattering by one-dimensional rough surface
z = f(z), the D’ rrrc e problem l hl t corresponds to that of a TE wave impinging upon a perfect conductor and $J is the electric field The Neumann prob- lem corresponds to that of a TM wave impinging upon a perfect electric conductor and + is the magnetic field
For acoustic waves, $J corresponds to the linearized pressure The lin- earized pressure pl is -iwp&, where po is the average density The linearized pressure pl is related to the linearized density pr by
to a pressure-free surface The boundary condition that g = 0 corresponds
to normal component of the linearized velocity equal to zero at the boundary
Trang 4392 9 1-D RANDOM ROUGH SURFACE SCATTERING
2 Statistics of a Random Rough Surface
2.1 Statistics, Correlation Function and Spectral Density
For a one-dimensional random rough surface, we let z = f(z), and f(z) is a random function of x with zero mean [Papoulis, 19841
The Fourier transform of the rough surface height function is
Strictly speaking, if the surface is infinite, the Fourier transform does not exist To circumvent the difficulty, one can use Fourier Stieltjes integral [Ishi- maru, 19781 Or one can define the truncated function
F(k,) = $ JW dxe-ikxxf(x) (9.2.2)
-00
f0 Lx= { f(x) 0 1x1 5 L/2 1x1 2 L/2 (9.2.3) The Fourier transform then becomes
and the exponential correlation function
In (9.2.6)-(9.2.7), I is nown as the correlation k length
In the spectral domain we have
Trang 5fj2.1 Statistics and Spectral Density 393
where W (Ic,) is known as the spectral density Since f(z) is real, we have used in (9.2.10) the relation
s
00 4z> - dkx ik, eikxxF(lcx)
-00 Hence if we let
(9.2.16)
(9.2.17)
(4~1>4~2>> = s 2 G&l - x2) (9.2.18) where s is the rms slope and CQI is the correlation function for the slope function so that Ca(0) = 1 We let Wa(kx) be the spectral density of the slope Then
s2C,(x) = dk, eikxx Wa (k,)
-00 From (9.2.10), (9.2.17), and (9.2.19) we obtain
(9.2.19)
Wa(Ic2) = k: w(lcx) (9.2.20)
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(9.2.22)
(9.2.23) For the exponential correlation function of (9.2.7), the rms slope does not exist For example, the integrand of (9.2.21) is not integrable This is because
of the sharp edges that may exist in the rough surface profiles [Barrick, 19701
To calculate the rms value of a’ where
Trang 7fj2.1 Statistics and Spectral Density 395
In the spectral domain we obtain
F(LI = &J* dTle -&-FL f (Q
= @ll + &1)W(&l)b(x31 + z41)w(x31) + @IL + ~3L)w(&)@2L + E41)w(E21) + 6(&J- + &L)w(&l)@21 + ~31)w(~2I) (9.2.40)
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2.2 Characteristic Functions
For a Gaussian random process, the characteristic functions can be read- ily calculated For a Gaussian rough surface f(z), the probability density function (pdf) for f is
1
df > = $j h exP f 2
[ 1 2h2
The joint pdf for f(zl) = fi and f(22) = fi is
= (fl, f27 l , fn), where t = transpose - and f is the corresponding column vector The covariance matrix is K of dimension n x n
is the inverse of E and A is the determinant of 71
The characteristic function is
( eiu’fl+iY2f2+.*.+iunfn
> = exp
[
1
Trang 953 Small Perturbation Method
and A = h4(1 - C2) Thus
( @4f1+ivzf2 > = exp -2h 12 (q + u; + 2 2v&)]
39’7
(9.2.51)
3 Small Perturbation Method
The scattering of electromagnetic waves from a slightly rough surface can
be studied using a perturbation method [Rice, 19631 It is assumed that the surface variations are much smaller than the incident wavelength and the slopes of the rough surface are relatively small The small perturbation method (SPM) makes use of the Rayleigh hypothesis to express the reflected and transmitted fields into upward- and downward-going waves, respectively The field amplitudes are then determined from the boundary conditions The extended boundary condition (EBC) method may also be used with the perturbation method to solve for the scattered fields In the EBC method, the surface currents on the rough surface are calculated first by applying the extinction theorem The scattered fields can then be calculated from the diffraction integral by making use of the calculated surface fields Both perturbation methods yield the same expansions for the scattered fields, because the expansions of the amplitudes of the scattered fields are unique within their circles of convergence
3.1 Dirichlet Problem for One-Dimensional Surface
We first illustrate the method for a one-dimensional random rough surface with height profile x = f(z) and (f(z)) = 0 The scattering is a two- dimensional problem in 113-x without y-variation
Consider an incident wave impinging on such a surface with Dirichlet boundary condition (Fig 9.3.1) This is the same as a TE electromagnetic wave with an electric field in the c-direction impinging upon a perfect electric conductor Let
+ inc =e iki,x-iki, z (9.3.1) where Ici, = k sin&, kiz = k cos & In the perturbation method, one uses the height of the random rough surface as a small parameter This is based on the assumption that kh < 1, where h is the rms height
For the scattered wave, we write it as a perturbation series
(9.3.2)
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The boundary condition at x = f (rc) is
&-&c + +s = 0 (9.3.3) The zeroth-order scattered wave is the reflection from a flat surface at z = 0 Thus
1c) s (0) = -eiki,x+iki,z
Perturbation theory consists in expanding the exponential functions of
In the spectral domain, we also let
Trang 1153.1 Dirichlet Problem for 1-D Surface 399
Balancing (9.3.8) to zeroth order gives
If we substitute (9.3.10) into (9.3.5), we get back the zeroth-order solution
in the space domain as given by (9.3.4)
Balancing (9.3.8) to first order gives
terms of the zeroth-order solution Substituting the zeroth-order solution of
(9.3.3) Thus
The result of (9.3.13) can be interpreted as follows In order for the wave to
be scattering from incident direction ki, to scattered direction k,, the surface
has to provide the spectral component of k, - ki, This is characteristic of
Bragg scattering Balancing (9.3.8) to second order gives
Using (9.3.10) in (9.3.14), it follows that the first two terms in (9.3.14) cancel
each other Substituting (9.3.13) and (9.3.10) in (9.3.14) gives
Trang 12k, - Ic$ of the rough surface Since k& is an arbitrary direction, an integration over all possible k; is needed in (9.3.16)
The coherent wave is obtained by calculating the stochastic average of &
We note that, in view of (9.2.8) and (9.3.13),
of the flat surface case
To get power conservation, we note that the incident wave has power per unit area
-
S inc l z h = 1
- - 2rl cos 8i (9.3.22)
flowing into the rough surface The negative sign in (9.3.22) indicates that the Poynting vector has a negative %component
Trang 1353.1 Diricblet Problem for 1-D Surface 401
The power per unit area outflowing from rough surface is
(9.3.23)
Suppose we include only terms up to q!J”‘$~o)* + (&‘&‘*) + q!$“‘(q!&2)*) + (p)+‘o’*
S S in (9.3.23) That is, we include the intensity due to the product
of first-order fields and the product of the zeroth-order field and the second- order field Thus the power per unit area outflowing from the rough surface that is associated with the coherent field is
Putting (9.3.19), (9.3.20) and (9.3.21) into (9.3.24) gives
dk,(Rek,)W(Ici, - kz) (9.3.25)
Since k, is imaginary for evanescent waves and W is real, the integration limits of (9.3.25) are to be replaced by -k to k because evanescent waves do not contribute to the power outflow Thus
b (9.3.26)
For the incoherent wave power flow, we use the first-order scattered fields
(ss 4)incoh = Re [& (&‘)e)]
Using the spectral domain in (9.3.27), we have
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(cps(kc)m~>) = ~(w(k, - k;) (9.3.33) From (9.3.30), we define the power flow per unit area of the incoherent wave
Thus if we divide (9.3.37) by the incident power per unit area of (9.3.22),
we can define the incoherent bistatic scattering coefficients a(&) as
a(e,) = k cos2 8, cos8 Z(k, = ksin0,)
Note that (9.3.38) is defined in such a manner that the integration of a(&) over 0, will combine with the reflected power of the coherent wave to give
an answer that obeys energy conservation
For first-order scattering, &) (Ic,) = q!&” (kz), so that from (9.3.33) and (9.3.30) we obtain
Trang 1553.2 Neumann Problem for 1-D Surface 403
and (9.3.38) assumes the form
4°s> = 4k3 cos2 0, cos O$V(k sin 0, - k sin e,> (9.3.40) The results for Gaussian and exponential correlation functions can be readily obtained by using the spectral densities as listed in (9.2.14) and (9.2.15) The backscattering coefficient is, for 0, = -Oi,
a(-Oi) = 4k3 cos3 O$V(-2k sin Oi)
3.2 Neumann Problem for One-Dimensional Surface
Let the incident wave be
+ inc =e iki,x-iki, z
(9.3.41) where ki, = ksinOi, ki, = k cos Oi The scattered wave is written as a per- turbation series:
dX ( w
inc + w
S
> ( + w inc
&(F) = /OO dkxeikxx+ikzz~s(kx)
we match bzndary condition of (9.3.45):
(9.3.46)
& ik eikxX+“zf C”I$s (k,) + x x dk ik eikxX+‘kxf (XI+ (k x z s x >
-
Trang 16404 9 1-D RANDOM ROUGH SURFACE SCATTERING
In a spectrtil domain, we let
$b(kx) = &O)(kx) + 1cly(kx> + +:2)(lc,) + l * l
Also we expand exp(ik,f (z)) in a power series
,ikfb) = 1 + ik,f (x) _ $;f” + Putting (9.3.48) and (9.3.49) into (9.3.47) gives
Trang 1753.2 Neumann Problem for I-D Surface 405
Substituting (9.3.54) and (9.3.55) in (9.3.53) gives
I
O” dkx2kxkixF(kx)ei(kx+kix)x -
-00 + I 00 dk ik x z eikxx@)(k S x - ) - 0 (9.3.56)
In the firsGwo integrals, we next change dummy variable of k, + ki, + k, This gives
I -00 * dk, [2(k, - k,)kix - 2kfz] F(k, - kiz)eikxx
I
00 + dk,ik z e’kxx+‘l’(k S x - ) - 0 (9.3.57) Taking the inverse F’ourierGYansfer of (9.3.57) gives
k [k k 2 ix - k2]F(kx - kix) Next we balance (9.3.50) tof second order:
1 F(kk)e”(kx+k:)xf- z [Ic,ki, - k2] F(k, - ki,)
(9.3.61)
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On the right hand side of (9.3.61), let kk + k, = kg and then k, -+ kk,
kg + k, We get
= SP,dkx~~kxx~~dk~[-khlc,+k2]F(kx-k~)~[klbi,-k2]F(k~-k~x)
(9.3.62) Taking the inverse Fourier transfer of (9.3.62) gives
$L2’(kx) = $ Jm dk$(k2 - k;kx)(k;kix - k2)F(kx - k;)F(k; - kix)
(9.3.63)
Taking the average of (9.3.58) gives
The coherent reflected wave is in the specular direction and is less than that
of the flat surface for the case of Neumann boundary condition
Trang 19Transforming to that of the angles kx = k sin 8, and k, = k cos 8,, we obtain
7r
at any point on the surface are approximated by the fields that would be present on the tangent plane at that point For that to be valid, it is required that every point on the surface has a large radius of curvature relative to the wavelength of the incident field The Kirchhoff approach casts the form of the solution in terms of diffraction integral We first illustrate the approximation
by considering the Dirichlet problem of a one-dimensional surface
the
Consider an incident wave impinging on a rough surface (Fig 9.3.1) Let incident wave vector be ki = kixii - k&