PTLG TRONG CAC DE THI ĐH 2002-2010

PHƯƠNG TRÌNH LƯƠNG GIÁC TRONG CÁC ĐỀ THI ĐẠI HỌC1.

PHƯƠNG TRÌNH LƯƠNG GIÁC TRONG CÁC ĐỀ THI ĐẠI HỌC

1 (1 + sin2x)cosx + (1 + cos2x)sinx = 1 + sin2x 2 2sin22x + sin7x – 1 = sinx

3 (sinx cos )x 2 3 cos x 2

2sin x sin 2x

5 2cos x+2 3sinxcosx+1=3(sinx+ 3cosx)2 6 sin(5x ) cos(x ) 2 cos3x

− − − =

7 sin 2x cos2x tan x cot x

cos x + sin x = − 8 2 2 sin(x )cos x 1

12

π

9 (1 – tanx)(1 + sin2x) = 1+ tanx 10

4sin( x) 3

sin x sin(x ) 4

2

π

−

11 sin x3 − 3 cos x sin x cos x3 = 2 − 3 sin x cos x2

12 2sinx(1 + cos2x) + sin2x = 1 + 2cosx 13 tanx = cotx + 4cos22x

14 sin(2x ) sin(x ) 2

+ − − =

16 3sinx + cos2x+sin2x=4sinxcos2

x

2 17 4(sin4x + cos4x) + cos4x + sin2x = 0

18 (1 2sin x)cos x 3

(1 2sin x)(1 sin x)

+ − 19 3 cos5x – 2sin3xcos2x – sinx = 0

20 sinx + cosxsin2x + 3 cos3x = 2(cos4x + sin3x)

21 (1 sinx cos2x)sin(x 4) 1 cos x

π

= + 22 (sin2x + cos2x)cosx + 2 cos2x – sinx = 0

23 sin2x – cos2x + 3sinx – cosx – 1 = 0 24 3 3 2 3 2

cos3x cos x sin 3x sin x

8

+

25 2sin(2x –

6

π

) + 4sinx + 1 = 0 26 cos2x + (1 + 2cosx)(sinx – cosx) = 0

27 (2sin2x – 1)tan22x + 3(2cos2x – 1) = 0 28 4sin3x + 4sin2x + 3sin2x + 6cosx = 0

29 cos3x + sin3x + 2sin2x = - 1 30

2(cos x sin x) sin x cos x

0

2 2sin x

−

31 cot x sinx(1 tan x tan ) 4x

2

+ + = 32 cos3x + cos2x – cosx - 1 =0

Bài tập thêm

sin(2 ) 16 2 3.sin cos 20sin ( )

2 2 sin 4 (1 sin 2 ) 1 tan

cos

 − 

 ÷

  + = +

π x

x

3.sin 2 sin 1 1 2cot 2

2sin sin 2

4.sin tan 2x x+ 3(sinx− 3 tan 2 ) 3 3x = 5.cos 2x+ =5 2(2 cos )(sin− x x−cos )x

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6.sin (1 cot ) cos (1 tan )3x + x + 3x + x = 2sin 2x

7

sin sin 3 cos cos3 1

8 tan tan

 −   + 

 ÷  ÷

   

1 sin sin cos sin 2cos

 

 

9.cos3 cos3 sin3 sin 3 2

4

x x x x 10.tan2x−tan sin2 x 3x+cos 1 03− =

11.2cos 1cos (2 ) 8 sin 2 3cos( ) 1sin2

+ +π = + + +π +

12.9sinx + 6cosx – 3sin2x + cos2x = 8 13 π − − π− = +  π

cos

x-4

14.sin 3x cos 4x sin 5x cos 6x2 − 2 = 2 − 2 15 +  + −  + =

16.9sinx + 6cosx – 3sin2x + cos2x = 8 17

sin cos 1

tan 2 cos sin 4

−

x

18.tan(5

2

π-x) + sinx

1 + cosx = 2 19.2cos3x + 3 sinx + cosx = 0 20.cos23xcos2x – cos2x = 0 21.sin 2x−2 2(sinx+cosx)=5

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