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Kỹ Thuật phân tán pha: Bài tập chương 3 – Trần Minh Mẫn MSSV:1511952 1.i A powder is contained in a vessel to form a cylindrical plug 0,8cm in diameter and 3cm long.. The powder density

Trang 1

Kỹ Thuật phân tán pha: Bài tập chương 3 – Trần Minh Mẫn (MSSV:1511952)

1.(i)

A powder is contained in a vessel to form a

cylindrical plug 0,8cm in diameter and 3cm

long The powder density is 2,5gcm-3 and 2,2g

of powder was used to form the plug The

porosity inside the plug The porosity inside the

plug of powder is (-):

a.0,58 b.0,42 c.0,75 d 0,25

Solution 1(i):

The volume of the cylindrical plug:

   2

2

3 3,14 0,8

o

cm D

The total volume of the powders:

3 3

2, 2

0,88 2,5

s s s

gcm

The total volume of the emties:

o s

The porosity inside the plug of powder:

3 3

0, 6272

0, 42

1, 5072

o

1.(ii)

Air was drawn through the plug at a rate

of 6.6 cm3 per minute A mercury

manometer was used to measure the

pressure drop during this process: a

pressure drop of 60 mm Hg was

recorded The specific gravity of mercury

is 13.6, thus the pressure drop across the

plug was (Pa):

a.80 b.800 c.8000 d.80000

Solution 1(ii):

The pressure drop:

1.(iii)

The superficial gas velocity in (ii) was (ms-1):

a.0,0022 b.3,65.10-5 c.2,2.10-6 d.0,00365

Solution 1(iii):

6 3

-1

10

6, 6

60 s

0, 0022 ms 3,14 0,8.10

o

m Q

U

1.(iv)

The viscocity of the air was 1,8.10-5 Pas, using

the Kozeny-Carman equation, the specific

surface area per unit volume of the powder was

(m-1):

a.2310 b.3,0.1011 c 5,5.10 5 d.1,2.106

Solution 1(iv):

3 2

3 2

5 1

1

5, 5.10

v

o

P S

L KU

Pa

m

1.(v)

The Sauter mean diameter of the powder was (

m):

a.2600 b.22 c.11 d.5

Solution 1(v):

5 1

11 5,5.10

v

S v

1.(vi)

The air density was 1,2kgm-3, the Modified

Reynolds Number of the system was (-):

a.0,1 b.8,4.10-10 c.4,6.10 -4 d.0,00021

Solution 1(vi):

1

4

Re

1, 2 0, 0022

4, 6.10

1 0, 42 5,5.10 1,8.10

dU

1.(vii)

Comment on whether your use of the

Kozeny-Carman equation was valid or not:

Solution 1(vii):

Trang 2

2.(i)

A cylindrical ion exchange bed composed

of spherical particles 2mm in diameter

packed at abed voidage of 0,45 is to be

used to deionise aliquid of density and

viscosity 1100kgm-3 and 0,0075Pas

respectively The design flow rate is 5m3h-1

and the bed height and diameter are 2 and

0,2m respectively, using the

Kozeny-Carman equation the pressure drop is (Pa):

a.99000 b.1,32.107 c.4400 d.44000

Solution 2(i):

Kozeny-Carman equation:

 2 2 1

3

1

o v

K U S P

L

Tính:

3

1

5 3600

0, 0442 3,14 0, 2

o

m s Q

1 3

3000 2.10

v

0, 45 99000

P Pa

  

2.(ii)

The Modified Reynolds Number is:

a.3,91 b.4,78 c.1290 d.0,478

Solution 2(ii):

1100 0, 0442

1 0, 0075 1 0, 45 3000

o v

U

2.(iii)

Comment on your use of the

Kozeny-Carman equation:

Solution 2(iii):

2.(iv)

The interstitial liquid velocity inside the

bed is (ms-1):

a.0,02 b.0,098 c.0.08 d.0,044

Solution 2(iv):

1

1

0, 0442

0, 098

0, 45

o

2.(v)

Using the Carman correlation the shear

stress on the ion exchange beads is (Pa):

a.17,2 b.3,5 c.13,5 d.27

Solution 2(v):

1 1

17, 2

Pa

2.(vi)

Hence the dynamic pressure drop over the

bed is (kPa):

a.84 b.130 c.99 d.150

Solution 2(vi):

2

2

1

1 2

0, 45

1 0, 45 3000

v

S m

m

2.(vii)

Why is the answer to (vi) different to that

in (i)?

Solution 2(vii):

(i) Không kể ma sát (ii) Kể đến ma sát

???

2.(viii)

If the liquid has a datum height equal to the

position at the base of the ion exchange

vessel and, therefore, needs raising to the

top of the column before it enters the ion

exchange bed the additional pressure drop

to effect this, i.e the static pressure drop

over the bed, is (kPa):

a.2,16 b.21,6 c.216 d.0,22

Solution 2(viii):

1100 9,81 2 21600 21, 6

static

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