Attila Aszódi, BME NTI 13 – Power, power density – Fuel and cladding temperature – Cladding integrity and durability – Maximizing fuel burnup to enhance fuel economy – Maximal fuel tempe
Trang 1HUVINETT 2012/1
Thermal hydraulics
of nuclear reactors
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 1
Prof Dr Attila ASZÓDI
Director
Budapest University of Technology and Economics
Institute of Nuclear Techniques (BME NTI)
General considerations
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 2
Basic considerations of nuclear safety
• Nuclear Power Plant in normal operation: very low
emission, practically only thermal load to the environment.
• But high risk: Large amount of highly dangerous
radioactive material generated and accumulated in the
reactor core
• Safety objective: protect the environment from this highly
dangerous radioactive material
– Safety objective is ranked higher than electricity production!
• Specialties of nuclear fuel and NPPs:
– No real environmental risk of fresh (non-irradiated) fuel
– High risk of irradiated fuel
– High risk of irradiated fuel
– High thermal density
– Reactor power possible in a very wide range (even over nominal power, in a
short pulse hundreds of nominal power – see Chernobyl)
– Cooling of irradiated fuel needed after shut-down (removal of remanent (decay)
heat in the first ~5 years in water feasible, later in gas atmosphere over hundreds
of years possible)
Design of NPPs
Design necessary not only for normal operation, but also for anticipated operational transients and for wide range of so called Design Basis Accidents.
– Beside operational systems separated safety systems required
– Due to single failure criteria multiple independent safety systems needed for the same function
Construction of an NPP is much more expensive than of a fossil power plant, where safety is not that
Trang 2Example: Bulgaria, Kozloduy NPP, VVER-1000
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 5
Example: Bulgaria, Kozloduy NPP, VVER-1000
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 6
Example: Bulgaria, Kozloduy NPP, VVER-1000 Example: Bulgaria, Kozloduy NPP, VVER-1000
Trang 3Example: Bulgaria, Kozloduy NPP, VVER-1000
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 9
Example: Bulgaria, Kozloduy NPP, VVER-1000
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 10
Example: Bulgaria, Kozloduy NPP, VVER-1000
Independent and redundant water source to avoid loss of ultimate heat sink
Basic safety functions
– Efficient control of the chain reaction and hence the
power produced.
– Fuel cooling assured under thermal hydraulic conditions
designed to maintain fuel clad integrity, thus constituting
an initial containment system.
– Containment of radioactive products in the fuel but
also in the primary coolant, in the reactor building constituting the containment or in other parts of the plant unit.
unit.
Trang 4Fuel design
• Limits in design: thermal hydraulics
(cooling) is more limiting than reactor
physics
Na, Pb), pressure, temperature
– Choice of flow velocity and other flow
parameters (turbulence, mixing, boiling)
• Many parameters have to be optimized:
– Enrichment
– Burn-up
– Power, power density
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 13
– Power, power density
– Fuel and cladding temperature
– Cladding integrity and durability
– Maximizing fuel burnup to enhance fuel economy
– Maximal fuel temperature (to avoid fuel melting), – Maximal cladding temperature (to avoid cladding
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 14
– Maximal cladding temperature (to avoid cladding oxidation, decrease in strength)
– Maximal coolant temperature (to avoid boiling or boiling crisis)
– Other thermal limits (to keep reactivity feedbacks between reactor physical limits)
Fundamentals of heat
transport
Fundamentals of heat transport
• Heat: energy transport due to temperature difference.
• Conduction: In heat transfer, conduction (or heat conduction) is the transfer of
thermal energy between neighboring molecules in a substance due to a temperature gradient It always takes place from a region of higher temperature to a region of lower temperature, and acts to equalize temperature differences Conduction needs matter and does not require any bulk motion of matter
lower temperature, and acts to equalize temperature differences Conduction needs matter and does not require any bulk motion of matter
• Convection in the most general terms refers to the movement of molecules within
fluids (i.e liquids, gases) Convection is one of the major modes of heat transfer and mass transfer In fluids, convective heat and mass transfer take place through both diffusion – the random Brownian motion of individual particles in the fluid – and by advection, in which matter or heat is transported by the larger-scale motion of currents in the fluid In the context of heat and mass transfer, the term "convection"
is used to refer to the sum of advective and diffusive transfer.
• Thermal radiation is electromagnetic radiation emitted from the surface of an
• Thermal radiation is electromagnetic radiation emitted from the surface of an
object which is due to the object's temperature Infrared radiation from a common household radiator or electric heater is an example of thermal radiation, as is the light emitted by a glowing incandescent light bulb Thermal radiation is generated when heat from the movement of charged particles within atoms is converted to electromagnetic radiation.
Trang 5The definition of heat transfer
• Heat transfer: across the surfaces of two different
materials it is a complex physical process which combines
the three fundamental heat transport methods (conduction,
convection, radiation).
• In the technical practise: investigation of the heat transfer
process between solid wall and liquid, solid wall and
steam/gas, for example:
– Cooling the fuel rods;
– Heat transfer through a surface between the primary and secondary
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 17
– Heat transfer through a surface between the primary and secondary
side of a steam generator
• Thermal hydraulics: coupled thermal- and hydrodynamics
analysis of the reactors
Energy production and heat transfer
• Volumetric heat power rate:
Q & / ≡ ′′′
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 18
• Core volumetric power density: Q / V ≡ Q ′′′
Energy production in fuel
• Energy release in fission: 200 MeV/fission
– 92-94% discharged in fuel
– 2,5% discharged in moderator
• Calculation of volumetric heat power generation
from the thermal neutron flux
i i
Energy release in one fission of an „i” type atom [J/fission]
Energy production and heat transfer
• Thermal hydraulical design of the fuel:
∫∫∫
V A
dV r q dA n A
dV r q dz z
Trang 6Newton's law of cooling
• A related principle, Newton's law of cooling, states that the rate of heat loss of a
body is proportional to the temperature difference between the body and its
surroundings, or environment The law is
the thermal power from the solid surface to the fluid, W;
Q&
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 21
• In the technical practise the average heat transfer coefficient is often used In this case temperature difference is an averaged value
along the F surface.
• In some cases the heat transfer coefficient strongly alters along the
) ( T w − T∞
surface due to the changing influential properties This is the local
heat transfer coefficient: at the x place on the dF surface the thermal
power is the following:
where:
dF T
T Q
d & x = α x ⋅ ( w , x − ∞ ) ⋅
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 22
The aim of investigation on thermal processes is to describe the heat
transfer coefficient.
Local heat transfer coefficient – example:
The distribution of the average heat
w CFX
T T
Spacer Grid 1
ave w w GEN
T T
q
−
= & ''
α
Stockholm, 10.10.2006 S Tóth, A Aszódi, BME NTI 18
• The average heat transfer coefficient calculated according to the general definition
agrees well with the value calculated by Dittus-Boelter correlation
• The T ∞ temperature is equal to that temperature which can
be measured far from the heated surface in case of flow in half unlimited space
• In closed channel flow, if the mass flow rate is , the
density is ρ, the velocity is w and the enthalpy is h = h(T) : m
&
density is ρ, the velocity is w and the enthalpy is h = h(T) :
If the specific enthalpy is h = c p ·T and c p = constant, than
Trang 7The equilibrium equations - Boussinesq-approach
• The flow velocity field: , in Descartes coordinate
system :
• The temperature field:
• The pressure field:
( x y z )
w
w x = x , , w y = w y ( x , y , z ) w z = w z ( x , y , z )
( ) r w
( ) T ( x y z )
T
• The pressure field:
• The general differential equation of heat
( λ ), isobaric heat capacity ( c ), density ( ρ ) are constant,
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 25
( λ ), isobaric heat capacity ( c p ), density ( ρ ) are constant,
steady-state condition):
T a
T = ⋅ ∇ 2
∇
p c
a
⋅
= ρ
λ (thermal diffusivity)
The equilibrium equations - Boussinesq-approach Navier-Stokes equations (steady-state, kinematic viscosity is const.):
Conditions for the above equations:
( w ⋅ ∇ ) ⋅ w = ⋅ ∇ w − ∇ p + g − β ⋅ ∆ T ⋅ g
ρ
Conditions for the above equations:
– The gravity has only a component in z direction, whereas
– The density dependency on the temperature is only considered at the gravity term of the above equation to consider the temperature difference ( ∆T ) which causes a buoyancy force due to the density difference (β is the volumetric heat expansion or
k
g = − g ⋅ , where: k is the unit vector in z direction;
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 26
the above equation to consider the temperature difference ( ∆T ) which causes a buoyancy force due to the density difference (β is the volumetric heat expansion or
compressibility )
– ∆T is the temperature difference, T is the temperature and T ∞ is the average
temperature difference.
The hydraulic boundary layer
be divided into two regions at the vicinity of solid wall:
– first: inside the boundary layer, where viscosity is
dominant and the majority of the drag experienced by a
dominant and the majority of the drag experienced by a
body immersed in a fluid is created,
– second: outside the boundary layer where viscosity can
be neglected without significant effects on the solution.
• The thickness of the hydraulic boundary layer
( δ ): if the velocity deviate from the main flow velocity
( δ ): if the velocity deviate from the main flow velocity
( w ∞ ) more than 1% then it is inside the hydraulic boundary
The bubbles have very slow lifting very slow lifting movement so they are suitable to visualize the flow.
Reference: Lajos Tamás: Az áramlástan alapjai (Fundamentals of fluid
mechanics – in Hungarian, CD), Műegyetemi Kiadó, Budapest, 2004.
Trang 8The hydraulic boundary layer in the flow
near a solid plane
The bubbles have very slow lifting
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 30
Reference: Lajos Tamás: Az áramlástan alapjai (Fundamentals of fluid
mechanics – in Hungarian, CD), Műegyetemi Kiadó, Budapest, 2004.
very slow lifting movement so they are suitable to visualize the flow.
The hydraulic boundary layer in pipe flow
Physical model:
• The boundary layer on the pipe wall abuts after a certain
distance from the entrance of the pipe.
distance from the entrance of the pipe.
• The constant velocity field before the entrance modify and a
characteristic velocity profile builds up after the suitable
distance from the entrance After this certain length this is
the so called fully developed flow.
The hydraulic boundary layer in pipe flow
Physical model:
The flow area is A , the mass flow rate is , the density is ρ.
A
m w
⋅
= ρ
The flow can be laminar along the whole pipe length, if the diameter:
Trang 9The thermal boundary layer
the hydraulic boundary layer If the wall temperature ( T w ) is
not equal to the bulk temperature ( T ∞ ), than:
not equal to the bulk temperature ( T ∞ ), than:
– the fluid temperature is equal to the wall temperature on the solid
wall;
– approaching to the bulk from the wall the temperature approximate
the bulk temperature.
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 33
• The thermal boundary layer ( δ
t ): if the temperature deviate from the main flow temperature ( T ∞ ) more than 1% then it is inside
the thermal boundary layer.
The heat transfer NUSSELT’s equation:
• The mechanism of heat transfer: if the heat radiation is negligible,
then the energy from the wall (which has T w temperature) to the fluid
(which has T ∞ temperature) transported by heat conduction through the boundary layer at x position where the thickness of boundary layer
is δ x The δ x alters along the heated length but the viscose sub layer exists everywhere near the solid wall x x
exists everywhere near the solid wall.
• At a certain place (x) the surface heat flux can be defined by two
ways , if the local heat transfer coefficient is α x :
• The heat transfer NUSSELT’s equation:
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 34
λ is the heat conductivity of the fluid,
• The heat transfer NUSSELT’s equation is not equal to the 3rd kind boundary condition.
Methods to calculate the heat transfer coef.
• Solving the steady state equations by using certain
boundary conditions the velocity and temperature
field can be determined Using the temperature field
and the NUSSELT equation the heat transfer
coefficient can be calculated
• Measuring the heat transfer coefficient and
the generalization of the experimental data,
using them for similar flows (Similarity
using them for similar flows (Similarity
theory) is possible
Similarity of heat transfer processes 1.
• Two physical processes are similar, if
– The differential equations are the same;
– The geometries are similar;
– The initial and boundary conditions of the differential equations can be transformed in the same values using proper ratios.
• The similarity theory enables to investigate an unmeasured heat transfer process using a geometrically similar and previously measured example.
• To characterize the similarity many similarity number are
• To characterize the similarity many similarity number are used in practice.
• In the followings the practically important similarity numbers are defined.
Trang 10Similarity of heat transfer processes 2.
• To define the similarity numbers let’s use the
Boussinesq-approach of the steady state equations:
• The z component of Navier-Stokes equation:
T g g p w
w w w
w w w
w
w ⋅ ∂ z + ⋅ ∂ z + ⋅ ∂ z = ν ⋅ ∂2 z + ∂2 z + ∂2 z − 1 ⋅ ∂ − − ⋅ β ⋅ ∆
• The energy equation:
• The continuity equation:
T g g z
p z
w y
w x
w z
w w y
w w
x
w
z z y z
∂
∂ +
∂
∂
⋅ +
∂
∂ +
∂
∂
⋅ +
T x
T a z
T w y
T w
Similarity of heat transfer processes 3.
• Let’s transform the steady state equations into
dimensionless form using normalization The base value of
the normalization must be well measurable L is the characteristic geometrical parameter, w ∞ is the characteristic
characteristic geometrical parameter, w ∞ is the characteristic
velocity, T w is the surface temperature, T ∞ is the flow characteristic temperature!
• The dimensionless parameters:
T T
L
y
= η
L
z
= ζ
Similarity of heat transfer processes 4.
• Replacing the dimensionless parameters into the Navier-Stokes
equations and reassembling:
• Replacing the dimensionless parameters into the energy equation
β
ζ π ζ
ω η
ω ξ ω ν
ζ
ω η
ω ω
∂
∂ +
L
z z y
z
22222
• Replacing the dimensionless parameters into the energy equation
∂
∂ +
∂
∂
⋅ +
ζ ϑ
η ϑ
ξ ϑ ζ
ϑ ω η
ϑ ω ξ
L grad ϑ
λ
α
ϑ = − ⋅ ⋅
Similarity of heat transfer processes 5.
• The dimensionless similarity parameters in the above mentioned
equations are the following:
– The Péclet number (this number shows a relationship between the
velocity field and temperature field): w L
Pe = ∞⋅
velocity field and temperature field):
– The Reynolds number (this number shows the relationship between
the inertia and drag forces):
– The Nusselt number (the criteria of the similarity of the heat
transfer):
ν
L w
– The Froude number (this number shows the relationship between
the gravity and inertia forces):
– The Archimedes number (this number shows the relationship
between the buoyancy and inertia force): ( )
Ar β W
g L
w Fr
⋅
= ∞
λ
Trang 11Similarity of heat transfer processes 6.
• Further practically used similarity numbers
– The Prandtl number defines the ratio of the thickness of the
hydraulic and thermal boundary layer:
Pe ν
– The Grasshoff number:
– The Rayleigh number:
– The Stanton number:
2
32
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 41
– The Stanton number:
• Hereafter the fluid fully fill the whole domain for all of the discussed
heat transfer cases (there is no free surface) or the solid body is fully
bounded by the fluid Therefore the Froude number do not has an
Nu St
p
ρ α
Similarity of heat transfer processes 8.
• The Nusselt number (which consist of the α ) depends on the
Reynolds-, Grasshoff- and Prandtl number, furthermore the geometry
and boundary conditions:
Nu = f (Re, Gr, Pr, Geometry, Boundary
• But: the similarity numbers are defined using the
Boussinesq-approach which has the constant material properties (ρ, λ, ν, c p ) versus the temperature The temperature dependency of the material
properties influences the velocity and temperature fields, so finally the heat transfer coefficient too.
Nu = f (Re, Gr, Pr, Geometry, Boundary
conditions)
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 42
heat transfer coefficient too.
• This effect can be considered by a Φ T correction factor:
Nu = f (Re, Gr, Pr, Geometry, Boundary conditions)· Φ T
Practical determination of αααα 1.
• The similarity theory enable to generalize the experimental
results of heat transfer If the similarity numbers are used
for the experimental results then the Nusselt number can be
expressed by the similarity numbers and their powers:
• Forced convection (the flow created by external force)
often the buoyancy effect is negligible, therefore the Nusselt
number is independent from the Grasshoff number.
T p n m
Φ Pr Gr
• Natural convection (due to inhomogeneous temperature
field the density field is inhomogeneous, which induces the
flow) here the Nusselt number is independent from the
Reynolds number
Nu = f (Gr, Pr, Geometry, Boundary conditions)· Φ T
Practical determination of αααα 2.
• The Nusselt number correlations are generally semi-empirical
equations using experimentally determined coefficient sets.
• The correlations are valid in their definition range.
• The error range of calculated α is typically ± 20…40%, at complex phenomenon that could be higher (for example boiling, condensation)!
• The values of the similarity numbers must be calculated at
reference temperature.
• All parameters must be used with correct units.
• Near the critical point of the fluid the following correlations and equations are not valid.
Trang 12Heat transfer coefficient at forced convection
• Single phase heat transfer in horizontal tubes. The
characteristic of α strongly depends on the flow mode (laminar or
turbulent)
– The averaged velocity in the Reynolds number is a value calculated
by the fluid mass flow rate ( ), the flow area ( A ) and the fluid
density (ρ):
– The characteristic length is the diameter ( D ), standard temperature is
the flow characteristic temperature ( T ∞ ), a needed additional size is
pipe length ( L ).
m &
A
m w
⋅
= ρ
&
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 45
pipe length ( L ).
Heat transfer coefficient at forced convection
• Single phase heat transfer in horizontal tubes.
• The α for laminar, hydraulically developed flow [1]:
Valid, if Re < 2300 and 0,1< Re·Pr·D/L < 10 4
(constant wall temperature)
.
T
L
D Pr Re
3/2
1 1
7 , 12 1
Pr 1000 8
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 46
Valid, if 3000 < Re < 5·10 6 and 0,1 < D/L and 0,5 < Pr < 2000
• Correlation for temperature:
where Pr W is the Prandtl number at T W wall temperature.
, ,
8 1 7
, 12
14,0
W T
12,0
T T
Heat transfer coefficient at forced convection
• Single phase heat transfer in horizontal tubes.
• The α can be calculated for turbulent flows by Dittus-Boelter formula
[3]:
Valid, if Re > 10 5 and 0,6 < Pr < 160 and L/D > 10
, where
T n
T ha 4 , 0
W
W
T
T n
Valid, if Re > 10 5 and 0,6 < Pr < 160 and L/D > 10
• If the tube cross section is not circular then the so called equivalent
diameter ( D e ) must be used:
• For curved pipe the heat transfer coefficient ( α R ) is higher compared
= 1 1,77
1st example – Heat transfer at the primary side of a steam generator
The diameter of heat exchanger pipe in a PWR steam generator is
10 mm The pressure of the primary side is 124 bar and the velocity of the primary water is 2 m/s The characteristic temperature of the primary water is 282 °C and the wall temperature at the primary side
is 260 °C The length of the pipe is far higher than the diameter of the pipe
Define the heat transfer coefficient between the primary water and wall!
The material properties of the water at 124 bar:
Trang 131st example – Heat transfer at the primary side of a steam generator
Solution.
Heat transfer in straight tube:
Characteristic temperature:
Characteristic dimension : the inner diameter of the tube,
Material properties at temperature with linear interpolation :
C
=
D
C
PrW =
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 49
The temperature correlation:
so the flow is turbulent.
2300 10
595 , 1 10 254 , 1
01 , 0 2
003 , 1 8159 , 0 8331 , 0 Pr
W T
Solution (continuation):
For turbulent flow the following formulas must be used:
The Nusselt number:
1st example – Heat transfer at the primary side of a steam generator
) 64 , 1 10 595 , 1 log 82 , 1 (
1 )
64 , 1 log 82 , 1 (
1
25
102
1 , 289 003 , 1 01632 , 0 1 8331 , 0 7 , 12 1
8331 , 0 1000 10 595 , 1 8 01632 , 0
1 7
, 12 1
Pr 1000 8
325
ξ ξ
L D Pr
⋅
⋅
−
⋅ +
3/2
1
8 1 7
, 12 1
Pr 1000 8
ξ ξ
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 50
The heat transfer coefficient:
8 01632 , 0 1 8331 , 0 7 , 12 1 8
1 7
, 12
1 + ⋅ Pr3 − ⋅ ξ + ⋅ 3 − ⋅
K D
, 0 5881 , 0 1 , 289 λ α
2nd example – Cooling a fuel rod
On the below figure a simplified sub-channel of a fuel rod
can be seen The mass flow rate of the coolant (water) in the
core is 8800 kg/s at 124 bar The number of fuel assemblies
is 349 Each fuel assembly has 126 fuel rods
The inlet water temperature is 267 °C
The outlet temperature is 297 °C
2nd example – Cooling a fuel rod
between the wall and water temperature!) The material properties of the water at 124 bar:
Trang 142nd example – Cooling a fuel rod
Solution.
Using these signs:
the flow area ( F ) and the equivalent diameter ( D e ):
mm.
1 , 6 2
12,2 m mm
222
2
m 10 5282 , 6 mm 282 , 65 9
61 , 6 6 6
The characteristic temperature
The material properties at 124 bar , T m = 282 °C with linear
C 282 2
297 267 2
T
25
mm 282 , 65 4
9 3
61 , 6 6 4 3 6
235 , 9 9
282 , 65 4 4
co e
D
F K
F
D
out in
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 53
The material properties at 124 bar , T m = 282 °C with linear
n n
m w
kaz p
055 , 4 10 5282 , 6 99 , 755 349 126
The Reynolds number:
The Nusselt number for turbulent flow by the Dittus-Boelter formula,
if ΦT = 1 :
s F
n
np⋅ kaz ⋅ ρ ⋅ 126 ⋅ 349 ⋅ 755 , 99 ⋅ 6 , 5282 ⋅ 10
( 2,986 10 ) ( 0 , 8331 ) 513 , 0 023
, 0 Pr Re 023 ,
2,986 10
254 , 1 0,009235 055
, 4
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 54
The heat transfer coefficient:
( 2,986 10 ) ( 0 , 8331 ) 513 , 0 023
, 0 Pr Re 023 ,
0 ⋅ 0.8⋅ 0.4 = ⋅ ⋅ 5 0.8⋅ 0.4 =
=
Nu
K m
W Nu
De ⋅ = ⋅ = ⋅
= 513 , 0 32669 , 0 2
009235 , 0 5881 , 0 λ
Trang 15Temperature dependency of λ Ι.
3 11
) 273 T ( 10 1256 6 T 4 402
3824 )
compared to the metals.
The Lyon formula:
) 273 T ( 10 1256 6 T 4 402 ) T
+
= λ
UO 2 hõvezetési tényezõje a Lyon-összefüggés alapján
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 57
The integral of Lyon formula:
0
− +
⋅ +
T
λ
Lyon összefüggés integrálja
300040005000600070008000
The integral of the Lyon formula
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 58
0100020003000
The influence of Porosity (density) I.
sintering.
• 90% or more can be reached compared to the theoretical density.
• If the dimension of the pores is smaller then theoretically, the heat conductivity could be higher.
• But the gas phase fission products deforms the fuel pellet and causes over pressure in the fuel pellet The generated gas fills the pores, that is why there is
an optimal porosity for the manufacturing.
The porosity:
V
V V V
V V solid the of volume the
and V pores the of volume the
V pores the of volume the
) ( )
(
) (
V V V solid the of volume the
and V pores the of volume the
P
s p
=
=
=
) ( )
Trang 16The influence of Porosity (density) II.
λ
) 1 ( 1
⋅ +
−
=
5 , 0 1 1
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 61
The influence of oxygen/metal atomic ratio
• Both, the hyper- and hipostoichiometric ratio decreases the heat conductivity.
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 62
Pu)O 2 can be seen in
the function of the 2
the function of the
content of PuO 2 on
the right hand side.
stresses
↓
Enhancement of pellet cracking
decreases due to the increasing dimensions of cracks.
Trang 17The influence of burn up (power reactors)
structure; in the fuel porosity; material content of the fuel and in the
stoichiometric ratio of the fuel.
maximum 3%), for fast reactors this effect is higher (the 10% of
original U and Pu atoms could be burned in the nuclear fission
process).
heat conductivity.
effective heat conductivity of fuel pellets.
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 65
then the material structure of the oxide fuel modify which process
leads an increased density This increased density – which occurs in
the inner region of the fuel pellet – has an influence on the thermal
conductivity and the temperature field too.
Generation of gases (power reactors)
• Certain fission products in gas phase can leave the UO 2 fuel material at low temperature conditions.
• At high temperature when structural modification can
be occurred, significant amount of fission products in gas phase could leave the fuel material and mix with the filling gas of the fuel rod.
• The generated gas phase fission products causes
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 66
• The generated gas phase fission products causes increased pressure in the fuel rod which effect have to
be considered during the design of the fuel rods.
The melting point
The melting point of UO2 is 2840 °C.
The melting point for the oxide of uranium-plutonium
mixture in the function of plutonium content
The specific heat
The heat capacity of the fuel play an important role during the transient calculations.
Trang 18Thermal properties of different fuels
Up to melting point Average heat
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 69
Linear thermal expansion
coefficient [1/oC]
0,0000101 (400-1400 oC)
0,0000111 (20-1600 oC)
0,0000094 (1000 oC)
Structure of crystals
Below 655 oC:
a, orthorombic Above 770 oC: g, body- centered cubic
cubic centered
cubic centered
cubic centered
Thermal properties of different cladding
materials (power reactors)
Zircaloy 2 SS 316 Aluminium*
Density [kg/m 3 ] 6500 7800 2700 Melting point [ o C] 1850 1400 660 Heat conductivity at 400 o C [W/m o C] 13 23 237 (25°C) Heat capacity at 400 o C [J/kg o C] 330 580 910
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 70
Heat capacity at 400 o C [J/kg o C] 330 580 910 Linear thermal expansion coefficient[1/ o C] 5.9E-06 1.8E-05 2.31E-05
*the values can differ for different alloys
The temperature
distribution in the core
Subchannels
Hexagonal (for example VVER-440) and rectangular (for
example western PWRs) subchannels
Trang 19The temperature distribution of the fuel rod
General differential equation of transient heat conduction:
( ) ( ( ) T T ( ) r , t ) q ( ) r , t
t
t , r T
Thermal hydraulics Prof Dr Attila Aszódi, BME NTI 73
The temperature distribution into the cross
section of the fuel rod
Cladding Fuel pellet
Radial temperature distribution in the fuel rod
Gap Central bore
The temperature distribution of the fuel rod
If L/D>10 then the axial temperature distribution can be considered as
0
0 )
( 1
2
= +
dT r
q dr
dT r dr
d r
&
&
λ λ
0 2
0 2
1 2 1
= +
′′′
+
= +
′′′
+
c
r q dr
dT r
c q
dr r
&
&
λ λ
The temperature distribution of the fuel rod
In case of compact pellet (no central bore)
r dT
Trang 20The temperature distribution of the fuel rod
In case of compact pellet (no central bore)
λ
r q dT
=
π λ
λ
4
4max
2 2
q R q
R q dT
r q dT
T
fo
fo T
T − fo = & ′
Using average heat transfer coefficient:
The temperature distribution of the fuel rod
0
2
= +
r
R q c
dr
dT q
v v
2
0
2 1
′′′
=
−
= +
T
r c R r
q dT
r
c r q dr dT
ln 4
0 2
1 2 2 1
max
&
&
λ λ
The temperature distribution of the fuel rod
Pellet with bore:
T
v
v v
T T
r R
R r
q dT
R
r R q R r q dT
ln 2
1
ln 2 4
2 2
2
2 2
2
maxmax
r r
R r
R r
R R
fo v
fo v
fo
v fo
The temperature distribution of the fuel rod
Pellet with bore:
T
T
fo v
fo vfo