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Tiêu đề Bacterial Reproduction
Người hướng dẫn Dr. Tran Thi My Dieu
Trường học Van Lang University
Chuyên ngành Environmental Technology and Management
Thể loại Bài giảng
Năm xuất bản 2011
Thành phố Ho Chi Minh City
Định dạng
Số trang 3
Dung lượng 59,34 KB

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SPECIALIZED ENGLISH – SEMTESTER 5MANAGEMENT Chapter 24 FUNDAMENTALS OF BIOLOGICAL Dr.. 2011 WASTEWATER TREATMENT & REUSE Bacterial growth Bacterial reproduction Bacterial growth pattern

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SPECIALIZED ENGLISH – SEMTESTER 5

MANAGEMENT

Chapter 24 FUNDAMENTALS OF BIOLOGICAL

Dr Tran Thi My Dieu

Sep 2011

WASTEWATER TREATMENT & REUSE

Bacterial growth

Bacterial reproduction

Bacterial growth patterns in a batch reactor

VAN LANG UNIVERSITY DENTEMA

Bacterial growth patterns in a batch reactor

Bacterial growth and biomass yield

BACTERIAL REPRODUCTION

Is it important in biological treatment?

Binary fission

1 original cell becomes 2 new ones

VAN LANG UNIVERSITY DENTEMA

Bacteria reproduce by Asexual mode

Budding

new ones

Generation time ~ 20 min - days

Rapid change in biomass

BACTERIAL REPRODUCTION

Is it important in biological treatment?

Spherical-shaped bacteria

VAN LANG UNIVERSITY DENTEMA

Assume 1 m diameter

Specific gravity of 1.0 Generation time ~ 30 min

Estimate bacteria mass after 12 h?

BACTERIAL REPRODUCTION

Is it important in biological treatment?

Estimate bacteria mass after 12 h?

Weight of 1 cell ~ 5.0 x 10 -13 g

6

VAN LANG UNIVERSITY DENTEMA

Bacteria mass in 12 h ~ 8.4 x 10 -6 g

Number of cell is quite large compared to the mass

In biological treatment systems, bacteria would not

continue to divide indefinitely because of

environmental limitations (substrate and nutrient)

BACTERIAL GROWTH PATTERNS IN A

BATCH REACTOR

Lag phase Exponential growth phase

Stationary phase Dead phase

Substrate

To acclimate to new environment Multiplying at max rate

VAN LANG UNIVERSITY DENTEMA

Time

Substrate

Biomass

Batch process biomass growth phases with changed in substrate and biomass versus time

Amount of growth is offset

by the death of cells

No growth

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BIOMASS YIELD Biomass yield Y = g biomass produced

g substrate utilized

g biomass/g COD removed

VAN LANG UNIVERSITY DENTEMA

g biomass/g BOD removed

g biomass/g VFAs used

g biomass/g N-NH 4 oxidized

How to measure biomass?

BIOMASS YIELD

How to measure biomass?

Increase in biomass can be measured by Volatile suspended solids (VSS) or pCOD

VAN LANG UNIVERSITY DENTEMA

Volatile suspended solids (VSS) or pCOD Protein content (growth relates to true microbial mass) DNA (if the reactor solids contain proteins) ATP (if the reactor solid contain proteins) Turbidity (if very low biomass concentration) Bacterial cell counts

BACTERIAL GROWTH AND

BIOMASS YIELD

How to estimate biomass yield?

Estimating biomass yield and oxygen

VAN LANG UNIVERSITY DENTEMA

requirements from stoichiometry

Estimating biomass yield from bioenergetics

BACTERIAL GROWTH AND BIOMASS YIELD

Estimating biomass yield from stoichiometry

3C 6 H 12 O 6 + 8O 2 + 2NH 3 2C 5 H 7 O 2 N + 8CO 2 + 14H 2 O

Substrate Oxygen Nutrient Biomass

VAN LANG UNIVERSITY DENTEMA

The yield based on glucose consumed

Y =

g biomass produced

g glucose used

g C 5 H 7 O 2 N

g C 6 H 12 O 6

=

2 x 113

3 x 180

=

Y = 0.42 g cells/g glucose used

BACTERIAL GROWTH AND

BIOMASS YIELD

Estimating biomass yield from stoichiometry

In practice, used COD and VSS ~ organic & cells

Determine COD of glucose

C H O + 6O 6CO + 6H O

VAN LANG UNIVERSITY DENTEMA

C 6 H 12 O 6 + 6O 2 6CO 2 + 6H 2 O

180 6 x 32

COD of glucose =

6 x 32 180

= 1.07 g O 2 /g glucose

Y =

g C 5 H 7 O 2 N

g (glucose as COD)

= 0.39 g cells/g COD

2 x 113

3 x 180 x 1.07

=

BACTERIAL GROWTH AND BIOMASS YIELD

Estimating oxygen requirement from stoichiometry COD utilized = COD cells + COD of oxidized substrate

Oxygen consumed

VAN LANG UNIVERSITY DENTEMA

C 5 H 7 O 2 N + 5O 2 5CO 2 + NH 3 + 2H 2 O COD cells =

5 x 32 113

= 1.42 gO 2 /g cells

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BIOMASS YIELD

Estimating oxygen requirement from stoichiometry

Oxygen consumed = COD utilized – COD cells

= 1 07 gO /g glucose x 3 moles x 180 g glucose/mole

VAN LANG UNIVERSITY DENTEMA

= 1.07 gO 2 /g glucose x 3 moles x 180 g glucose/mole

- 1.42 gO 2 /g cells x 2 moles x 113 g cells/mole

= 577.8 g O 2 – 320.9 g O 2 = 256.88 g O 2

BIOMASS YIELD

Estimating oxygen requirement from stoichiometry Oxygen consumed per unit of COD used:

VAN LANG UNIVERSITY DENTEMA

Oxygen consumed Glucose as COD

=

256.88 g O 2

3 moles x 1.07 gCOD/g glucose x 180 g glucose/mole

= 0.44 g O 2 /g COD used

BACTERIAL GROWTH AND

BIOMASS YIELD

Estimating oxygen requirement from stoichiometry

Oxygen consumed per unit of COD used:

3C 6 H 12 O 6 + 8O 2 + 2NH 3 2C 5 H 7 O 2 N + 8CO 2 + 14H 2 O

VAN LANG UNIVERSITY DENTEMA

3 x 180 8 x 32

Oxygen consumed

Glucose as COD

=

8 x 32

3 x 180 x 1.07

= 0.44 g O 2 /g COD used

ASSIGNMENT 2

Estimate biomass yield in term of g cells/g saccharose

saccharose used and g cells/g COD used if used and g cells/g COD used if

VAN LANG UNIVERSITY DENTEMA

C 12 H 22 O 11 + O 2 + NH 3 C 5 H 7 O 2 N + CO 2 + H 2 O

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