PQS is right-angled at Q.. Which of the folloowing numbers is not a possible perimeter of the triangle?. Question 9: The value of x... The diagram beside shows the isosceles trapesiod
Trang 1PEOPLE COMMITTEE OF
NGO QUYEN DISTRICT
NGOQUYEN EDUCATION AND
EDUCATION DEPARTMENT
NGO QUYEN ENGLISH MATHEMATICS AND SCIENCE COMPETITION FOR GRADE 8 STUDENTS
SCHOOL YEAR: 2021 – 2022
Time allowance: 120 minutes
PART 1: MULTIPLE – CHOICE (100 mark)
Question 1: If 2 3
p
p q
then
p
q equals
E None of the above.
Question 2: If 2 2
x y y x and x y What is the value x2y2?
Question 3: How many zerof are there in the last digits of the following number
11 12 13 88 89
Question 4 : What is the smallest possible value of M x2y2 – – –x y xy
A 1; B 1; C 2; D 2; E None of the above
Question 5: Find the unit digit of 3 2021
Question 6: In the diagram, PS5,PQ3. PQS is right-angled at Q. QSR· 30 and
QR RS The length of RS is:
(E) None of the above.
Question 7: Calculate 19992 19982 19972 19962 32 22 1 2
Question 8: Two of the three side of a triangle are 25 and 15 Which of the folloowing
numbers is not a possible perimeter of the triangle?
Question 9: The value of x
Trang 245 ;
A B 60 ; C 90 ; D 105
Question 10 The diagram beside shows the isosceles trapesiod ABCD, which is with 7
BD cm, ·ABD 45 Determine the area of the one
A 24,5cm2 B. 22.5cm2 C 49cm2 D 28.5cm2 E None of the above
PART II: COMPOSE (200 mark)
Problem 1 Given a33ab2 9;b33a b2 46. Find the value of P a 2 b2
Problem 2 Let n be a prime numbe n2 Prove that the value of expression
2
2021 3
A n which is divisible by 8.
Problem 3 Find all pairs x y,
of integers such that x xy y – 8
Problem 4 Let ABCD be a rectangular, ·BDC 30 Draw the straight line through point C, perpendicular to BD, intersects BD at E and intersects the bisector of angle ADB at M.
a) Prove that AMBD is an isosceles trapezoid
b) Let N and K be the projections of point M on DA and AB respectively Prove that N K, and E are collinear
-THE
Trang 3END -PART 1: MULTIPLE – CHOICE (100 mark)
ANSWERS AND MARKS Questio
PART II: COMPOSE (200 mark)
1(50
mark)
We have a33ab2 9;b33a b2 46.
Therefore ( a3 – 3ab2)2 + (b3 – 3a2b)2 = 2197 20
2(50
mark)
We have 2021n2 3 2016n25n1 n 1 8 20
And n be the prime number n2 , so 5n1 n M1 8
Therefore 2021n2 M 3 8 Where n P n ; 2.
20
3(50
mark)
We have x + xy – y = 8
20
So (x; y) (8;0);(2;6);( 6; 2);(0;8) 10
4
( 50 mark)
a, Easily proved µA1B¶2 300
so AM is parallel to BD
10 10
Trang 4easily proved we have ·ADB MDB· 60o
Hence AMBD is an isosceles trapezoid
1 0
NME so ·MNE30o
Have quadrilateral MNAK is a rectangle, so
1 30o MNK A
So three points N, K, E are collinear.
10 10