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Nung n6ng ch6t ran rdi khrl bang t6ch cho lu6ng khi Hd hoflc co du di qua ta thu du-o.. Lqc 6y Cu vi dung dich nu6c lgc B' Nung Cu tong khdng khi d nhiet dQ cao ta duo.. - Lgc 6y tet ma

Trang 1

so crAo DUC vA DAq r4o

rimr rnar NcwEN

rrn ruvEN srNH LoP 10 rHPT cnuYtN

NAwI Hec 2oL6 :20!

Thdi gian lim bii:150 phrit (khdng tC AOi gian giao de)

Ciu 1: 1t,S AiOm;

1 Hoan thenh PTHH theo c6c so đ sau, chi 16 circ chdttu Xr diSn Xs :

AlCls * X1 ) Yr+ COz+ NaCl

Xz + Xs -1 412(SƠ)3 + Na2SOa + HzO

Xr + Xl+ CO2 + """'

Xz+BăOFI)z+fưHzO

X1+NaOH+Xs+HzO

2 C6 5 il t o" triiui *6iorr#rhaa cap ctr6t ran riOng biet sau : KCl, KzCor, KzSơ, BaCo3, BaSon'

chi ttugc dung 2 hd"hd,

-Iern

,ililth,i, t av ,na" bi67 c6c ch6t ran trcn vitit c6c PTttrI xiy rạ

IID:

1

AlClg + 3NaHCOr+ Al(OH)r{ + 3COzf +:NaCl

zii(om, + 6NaHSơ+ A1z(sou)3 + 3Na2Soa + 6Hzo

Cx3)

NaHCOs + NaHSƠ -+ COzt + Na2SO4 + H2O

2Al(OfDr + BăOfD2 + BăAlO 2)2 + +H2O

(&)

NaHCOs + NaOH + NazCOl + H2O

(xs) Z.LdymQt it mSi chi6t nCn ra cac'-6ng nehigm kh6c nhau c6 ttanh diú

- cho nu6c t6n 1on,1l6],6g6"g

"gr,ieriva 6c dA,, ta nhan ru2 chitlfiong tan h Bacor vi Basớ

- suc khi colvio ; i;s-;;h|9[-;f6; ,h#;r" ih6"s-fu rcn, 5r,g nenie- nao ch6t r'in tan, ong tI6

ftmg BaCO3.Ong'cdn lPi li BaSỢ

CO2 + H2O + BaCOr+ BăHCOg)z

- L6y dung dich BăHCOs)zvua thu duọ c-& t6n cho t6c dlrng mn luqt voi 3 dung dich chria 3 chf,t

KCl, KzCOr, KzSOẹ

;6;" ,-f,i6 kh6ng c6 hiQn tuqng gi ld 6ng nghiQm chira KCÍ

+ z ileighiem ttr6y xu6t hign ktit tua chrla KzCOs vd KzSOá

BăHCOr)z + KzCOs -+ BaCOg J + 2KHCOT

_ sec khi coz vio 2 6ng,rn?il:fủIJr,YfJu],??ịo,.,",1,frff:ỉ.ú1p wru6ng nehi€m d6

chda ktit tua Bacor, h6a chit ban d6u iaEcor Orig nghieir Jo" iai chta h6a ch6t ban ttiu Ii Kzsớ

COz + HzO + BaCOr + BăHCOg)z

Ciu 2: (1,5 ili6m)

1 Tdnh biy phuong phip h6a hqc dC tach ri6ng ttng oxit ra ktr6i h$n hqrp g6m : CuO, Al2O3 vi

HD:

ffi-U6n hqp vio dung dich NaOH dú Chi c6 AlzOa phan img:

AlzOt + 2NaOH + 2NaA1O2+H2O Lgc 16y ch6t ran kh6ng tan li CuO, FezO3 vi dung dlch nudc lqc Á

Trang 2

Nung n6ng ch6t ran rdi khrl bang t6ch cho lu6ng khi Hd hoflc co) du di qua ta thu du-o c h6n hqp ch6t ran g6m zkimlo4i Cu, Fe

CuO+ ]HrL Cu + HzO

Fe2o3 + 3Hz " > 2Fe + 3Hzo.

- Hoi tan h5n hqp kim loai blng dung dich anit HCl ( du) '

Xiryraphanimg: Fe + 2HCl + FeClz + H1

Cu kh6ng phan rmg Lqc 6y Cu vi dung dich nu6c lgc B'

Nung Cu tong khdng khi d nhiet dQ cao ta duo c CuO : 2Cu + Or* 2CuO

'-'L6i-J""g

Aittg tfti Oro cho t6c dung vOi aa NaOH du-+ thu clu-o c tiSt tua Fe(OH)z

FeClz + 2 NaOH + Fe(OH)zJ + 2 NaCl

- Lgc 6y tet ma Fe(OFI)z vi nung trong ktr6ng kfii d nhiet dQ cao ta thu du-o c Fe2O3.

2Fe(Of!3 -$ FezO: + 3HzO - ,

- Th6i tu tt rttin du khi Coz veo dung dich A thu duo c kct A(orDr Lqc kist tua vi nung d nhiet d0

cao thu du-cYc AlzO:.

NaAlOz +COz+ ZHzO -+A1(Otf3l + NaHCOs

2N(OrDrJ+AlzOr + 3HzO'

2 Nung chi*rhnf o orrie, dQ cao thu duo.c i',Artri^Q mnu tr[ng vi khi C kh61s.P*

tha] B phan gng milh ligt voi nu6c tpo thenh dung dich D hm h61e nhgnolphtalei Khi C lim vdn cfuc dung

oici p I(hi cho B tac dgng voi cacbonb oniet iQ cao,thi thu duo c chAt E vi giii ph6ng khi F Cho E phan rmg voi nu6c thi thutuqc khi kh6ng miu G o6t ctuiy G thu dugc nudc vi khi C X6c <linh cic

"niit e, E, c, D, E, F, G vi vilit c6c PTIIH xiy ra

IID:

(A) (B) (c)

(D) (c)

to

(B) (E) (F)

CaC2 + zHzO -+ Ca(Offu + CzHz (5)

Ciu 3: (1,5 ili6m)

1 Vi6,r c6c PTHH xiy ra theo so rt6 sar,, ghi 16 tti6u kiQn phan rmg (neu co) graSi mti ten chi duqc vi6t mOt PTHTD

=Xt1& -+Cao suBuna

Xr *Xz€Xs -+ PE

\>k+Pvc

(2)

(3)

Trang 3

Biiit rang X1 ld hgp ch6t chi6m chri ytiu trong thanh phan khi thi0n nhi6n.Y,2,X3,X4,X5, )k li c6c chAt

htiu co

2 Nhan bi6t cas kfii sau tlpg tong c6c 19 ri6ng biQt bi

cacbonnic, etilen, axetilen, metan

HD:

1.

t.zcHA#W czHz+3Hz

Z.ZCrllrW CH=C-CH:CHz

3 CH=C-CH:CH2 +tlr- ,,LY CHr:g11-aH=CHz

m6t nnan bing phucrng ph6p ho6 hec:

4 nCH:=CH-CH=CHz + CCH2-CH{H-CHz-),

S.CzIh*Hr# Crfu

6 nCHz:CHz e''oc , CCHz-CHz-)n

7.CzHz+HCl # CHz:CHCI

8 nCHz=CHCI Proc > (-CHz-CHC1-)n

,

- DIn 4 ktri qua nudc v6i tong khi nio lim nu6c vdi trong bi van dpc li COz

CO2 +Ca(OH)z-+ CaCOs + HzO

3 klri kh6ng hiQntuqng h CH4, CzH+,CzHz

- DAn 3 khi cdn lpi qua dd agNOrAUl: ktri nao phmg teo k6t tua miu vang li CzI7z

CzElz+ 2AgNO: + 2NH3+ AgzCz+ 2NtI+NOl

- Cho 2 khi cdn ler qua dung dlch brom khf nio ldm mdt miu nudc brom li C2FIa

Czfu+Brz-> CzHtBrz

Cdn lai h CH4

@[: (2,0 tli6m)

DE phAn tich h5n hqp b6J g6m sit vi siit oxit ngrri ta ti6n henh cac thi nghiQm sau:

Thi ngbiQn 1: Hda hn 8,08 gam b6J cua h5n hqp nay tuong HCI1,32M (du), thu ttugrc 0,,148 lit khi d DKTC

vidurg diphA:

Thi nghigm 2: Cho dyng qiSh A tric dpng ,"* d*g dich NaOH du, qun n6ng fiong klr6ng khi, lQc ktit ttra va

"*g A *,iet d$ cao 46" [nOi hrqng kh6ngd6i thu thrqc 8,8 gam sen phdm.

a" Tfntr ttranh pt An ptrAn mm vC t<tr6i hgng ctn c6cdr4t c6 tong h5n hqp ban t16u

b Xtic tfnh c6ng thuc sit oxit

c Tinh thO tich dung dlch HCI tOi tfri6u can dung toong thi nglrQm 1.

HD:

Ggi c6ng thric sit oxit li Fe*Oy

Fe + 2HCl -+ FeCl2+ Hz t (1)

->

(3x - 2y) FeCl2+Qy - 2x) FeCl3 + y H2O (2)

Khitho6t rasauthinghiQm I li:0,448 litH2tuong,hrg H =0,02(mol)

22.4

Tir(l): ttF" = flH, =0,02(mol)

) ffir"=0,02.56=1,12(9) 9 rfrr"e, = 8,08-1,12=6,96(g)

HS tinh biy c6ch tfnh phen ffim kh6i luqng ckc chf*trong hh:

J

:1i1::r.3Ee@.}itr{s8$4*j@M&i*a*i

Trang 4

o/onr

r"= l3,86Yo; %m(Fe*Or) :86,14%o

trct thric thi nghiQm 1: dd A g6m FeCl2; HCI du vi c6 t}r6 c6 FeClg

Cho dd A trlc 4mg NaOH: FeClz + 2NaOH -+Fe(OtI)z+ 2NaCl (3)

FeCl: + 3NaOH +Fe(OH)s + 3NaCl C4)

Dun n6ng trong kl6ng kh1 4Fe(OH)z + 02 * 2H2O '0 > 4Fe(OFI)g (5)

Nung t<5t ma iliin kh6i luqng k*r6ng eOi: ZfelOlDr4f'e2O3 * 3HzO (6)

Luqng FezOr thu ttugc ln do chuyen h6atu: Fe vi Fe*O, ban ttiu'

Tit (1), (3), (5); (6): crl 2 molFe t4o ra 1 mol FezOg+ 0'02 mol Fe t4o ra 0'01 mol FezOr

+lugngFe2O3cluo.ct4oratirFe*Orli:8,8-0,01'160:7'2(g)tuorlgrmg0'045mol

Ttr(2), (3), (4), (5), (6): CtZ molFe*O, t?o ra x mol Fe2O3

=

0,09

mol Fe*ov t4oru0,045mol Fezos=Ta c6 phucrng trinh: o'!' (tu* + 16y) :6'96

xx

4

L

=1= c6ng thric sit oxit: Fe:O+

y4

56 mot HCl t6i thieu de hda tan h5n hqrp ban diu: (l) vn (7) H: 0,04 +

ffS=0,28(mol)

mc Ucn dd HCI (1,32M) toi tnieu:

#=0,2721(lit) Ciu 5: (1,5 tli6m)

H5n hqp ran X g6m nh6m vi kim 1o4i kidm M Hoi tan hoan todn 6,36 gam X tong lugng

vila dt dung dich a:rit HzSO+ lo6ng thu dugc 4,928lit1z& DKTC vi dung dich Y (chi gdm mu6i

sunfar trunghon) cho y tac dung voi lugmg vira <tt dung dich Ba(oH)z eho toiktri g5c sunfatchuy&I

n6t tfrann t6t tua thi thu dugc 54,38 gam kiSt tua'

a.XindinhkimloaiM - ^.^ r r r-4^ t2- ^:.

b Cho them 3,48 gam mutii MzSO+ vio dung dich Y thu dugc dung dich Z' Tilnhanh ktit tinh cdn th6n dung dichZ,fr" 6"il 5O,S-S gam tinh tndmuOi k6p c6 c6ng thric d4ng aMrSq'bAlr(SOo)''cH'O'

X6c dinhcdng thric ctiatinh th6 mudi k6p'

HD:

PT h6a hgc cfra Phan fng

2N + fHrSOo+ A12(SO4)3 + 3H, Q)

etrlSO*; + 3Ba(OH)r+3BaSOo + 2A1(OH), (4)

uiju + A(oH)3+ MAlo, + 2wro (5)

D[t x, y ldn lugt li sd mol ctra M; Al trong 6,36 gamhh X (x; y > 0)

Theo bii ta c6: M'x + 27 'Y = 5'36 (I)

n n2 =4'928 2214 =o,Zbmol

4

Trang 5

TU (1), (2) nn, - xlT + 3yl2 =0,22 =2 x + 3y =0,44 GD

Tt(1), (2),(3),(4)tac6 nBoso -(lHz =0,22mo|

=)l[Busoo =0,22 '233 = 5l'268 < 54'389

=2 Trong kdt ttra c6 A1(OH)r:

ffiu(orr), = 54'38 - 5L'26 = 3'l2g =)rlat(on)'

Theo (5) c6 n^,o* bi hon tan = rl,on = x

=>tre1(oH), ksttie = Y - x = 0,04 @)

Tt (I), (tr), (m) c6 hQ: [tr't.x + 27.v = $,36

* + 3Y =0,44 =>

[- x = 0,04 Vfly kim lo4i kidm M li Kali (K)

Theo dA:n*zson th@6 vio = 3,481174 = 0,02mo1

=;, Sau tiri thcm c6: n^r,ro,), = 0,06mol

=) [Ir 1116 tdt ti*= 56,88 * 0'06'17 4 - 0'06342 = 25'929

=)(Igrekdt *=25,92118 = 1,44mol

C6 a : b : c = 0,06 : 0,06 : 1,44= t : L :24

Cf,u 6: (2,0 ili6m)

Cho 1 14,3 gamhdn hqp A gdm 1 ancol dcrn chrtc vi 1 u<it cacboxylic dcrn chrlc Chia A ftenh

3 phan b[ng nhau:

- PhAn 1: T6c dpng het voi Na, thu dugc 8,4 lit Hz 0 DKTC'

- Phin 2tDbtch6yhoantoanthu duo.c 59,4 gam CO2y-"9 gi-

"y-""' ,,.

- phin 3: Tfurc nien pf,an img este h6a voi fieo toArO0% Sau phan rmg thiy c6 3,24 gam nudc sinh ra

1 X6c ttinh c6ng thrlc phdn tt}, vi6t c6ng thtic cAu t4o cria c6c chtit tong A vi cia este t4o thanh'

2 Tioh b

fiO, Oat c6ng thrlc ancol don chric leROH, arit cacboxylic don chrlc liR'COOH

Phfln 1:

ROH+Na+RoNa *|H, trl

I

R'COOH +Na + R'COONa +

1Hz Q)

Theo (l), (2): -+ ,r\nr=z.nH2=,

#=0,75(mol)

PhAn 3:

ROH + R'COOH -+ R'COOR + H2O (3)

nn,o')=#=o,l8mol

=3,12fi8 = 0,04mo1

K= 0,08

-lv = o,tz

U=rg

Trang 6

Theo (3): * flnoneu)= zp,cooH(po> =bStnol

Gqi n m tEong rmg h s5 nguyen tr} C trong ancol, axit cacboxylic

+c6 hai trulng hqrP:

Trnime hoD 1: flRoH =0,3mol ) fl*coont=0'45mol

-> 2n+ 3m:9+ n:3 , m = 1

lcrH,o:o,3mol

= Ai\ucoott:o,45mol

I

M[tkhdc, i*n=Q2.3+t+16).0,3 +46'0,45=ry )t =6

5

Vpy CTPT, CTCT cic chdttrong A:C:H6O (CHz{H-CHz-O}I); HCOOH

CTCT ctia este: HCOO-CHz-CH:CHz'

Tinhb:

CrHeO -) 3HzO

0,3 0,9

HCOOH + HzO

0,45 0,45

->b : (0,9 + 0,45) 18 = 24,3 garl

Truirng hop 2l flncoo, =0,3mol ) frnon = 0,45mol

+ 3n *2m:9 + n= 1,m=3

s A :[cntoru :0'45mol =!*, =32.0,45+(68+r).0,3 = 38,1 ) r =ll

- lL' lcr[,or:o,3mol 3 ^

(loAi vi di6u kiQn r 32'3 = 6)

.:: H6t

'- * !

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