Phương pháp giải mạch 1 với Matlab

Trang 1

PHƯƠNG PHÁP GIẢI MẠCH VỚI MATLAB

Bài 1:

I1

R2 1k

V1

I3 R3 1k

R4

V2

R1 0.5k

I4 I2

0 function bai1

R1=0.5; R2=1; R3=1; R4=0.5; Ia=1;

G1=1/R1; G2=1/R2; G3=1/R3; G4=1/R4;

G=zeros(2,2);

G=A_array(1,0,G1+G2,G);

G=A_array(1,2,G3,G);

I=zeros(2,1);

I=b_array(0,2,Ia,I);

V=G\I;

disp(['Dien the nut 1: V1=',num2str(V(1)), ' V']);

disp(['Dien the nut 2: V2=',num2str(V(2)), ' V']);

disp(['Dong dien: I1=',num2str(V(1)/R1), ' A']);

disp(['Dong dien: I3=',num2str((V(1)-V(2))/R3), ' A']);

kết quả

Dien the nut 1: V1=0.090909 V

Dien the nut 2: V2=0.36364 V

Dong dien: I1=0.18182 A

Dong dien: I3=-0.27273 A

Trang 2

Bài 2

G1 2s Ia=1A

G2 1s

Ib=2A

G5 4s

G4 2s G3

1s

function bai2

G1=2; G2=1; G3=1; G4=2; G5=4; Ia=1; Ib=2;

G=zeros(3,3);

I=zeros(3,1);

I=b_array(2,3,Ib,I);

V=G\I;

disp(['dien the nut 1: V1=',num2str(V(1)),' V']);

disp(['dong dien I1=',num2str(V(1)*G1),' A']);

disp(['dong dien I2=',num2str((V(1)-V(2))*G2),' A']);

disp(['dong dien I4=',num2str((V(2)-V(3))*G1),' A']);

kết quả

dien the nut 1: V1=0.22222 V

dien the nut 2: V2=-0.33333 V

dong dien I1=0.44444 A

dong dien I3=-0.33333 A

Trang 3

Bài 3

R2 1k

V2

R3 6k

Ia 4A

0

V1

R4 2k

R1

2k

R5 3k

function bai3

R1=2;R2=1;R3=6;R4=2;R5=3;

G1=1/R1;G2=1/R2;G3=1/R3;G4=1/R4;G5=1/R5;Ia=4;

G=zeros(2,2);

G=A_array(2,0,G3+G4+G5,G);

I=zeros(2,1);

V=G\I;

disp(['dong dien I1=',num2str(V(1)/R1),' A']);

disp(['dong dien I2=',num2str((V(1)-V(2))/R2),' A']);

kết quả

dien the nut 1: V1=4 V

dong dien I1=2 A

dong dien I2=2 A

dong dien I4=1 A

Trang 4

Bài 4

Io R4

3k R3

6k R1

12k

V1

R5 18k

R6 5k

V2

Ia 12mA

R2 10k

V3

function bai4

R1=12;R2=10;R3=6;R4=3;R5=18;R6=5;

G1=1/R1;G2=1/R2;G3=1/R3;G4=1/R4;G5=1/R5;G6=1/R6;Ia=12;

G=zeros(3,3);

I=zeros(3,1);

V=G\I;

disp(['dong dien Io=',num2str(V(1)/R6),' A']);

kết quả

dong dien Io=8 A

Trang 5

Bài 5

Ib=6A

R2 6k

R1 2k

V2 V1

R3 3k Ia=4A

function bai5

R1=2;R2=6;R3=3;

G1=1/R1;G2=1/R2;G3=1/R3;Ia=4;Ib=6;

G=zeros(2,2);

I=zeros(2,1);

V=G\I;

kết quả

dien the nut 1: V1=-20 V

Bài 6

Ib=1A

V3

R2 0.25k

R4 1k

R1

0.5k

R5 0.5k

V1

R3 1k

V2

0

Ia=4A

function bai6

R1=0.5;R2=0.25;R3=1;R4=1;R5=0.5;

G1=1/R1;G2=1/R2;G3=1/R3;G4=1/R4;G5=1/R5;Ia=4;Ib=1;

G=zeros(3,3);

I=zeros(3,1);

Trang 6

kết quả

Bài 7

R5 1k

Ia=2A R1

2k

V3

R3 2k

R2=2k

function bai7

R1=2;R2=2;R3=2;R4=1;R5=1;

G1=1/R1;G2=1/R2;G3=1/R3;G4=1/R4;G5=1/R5;Ia=2;Ib=6;

G=zeros(3,3);

I=zeros(3,1);

V=G\I;

kết quả

dien the nut 1: V1=-7.2 V

Trang 7

Bài 8

Ib=2A

R4 2k Ia=6A

R1 1k

R6 1k

R2 2k

function bai8

R1=1;R2=2;R3=1;R4=2;R5=1;R6=1;

G1=1/R1;G2=1/R2;G3=1/R3;G4=1/R4;G5=1/R5;G6=1/R6;Ia=6;Ib=2;

G=zeros(3,3);

I=zeros(3,1);

V=G\I;

kết quả

Trang 8

Bài 9

R1

2k

Ia=4A

Vo=?

V1

R3 4k

R2 1k

Ib=8A

V2

function bai9

R1=2;R2=1;R3=4;

G1=1/R1;G2=1/R2;G3=1/R3;Ia=4;Ib=8;

G=zeros(2,2);

I=zeros(2,1);

V=G\I;

disp(['dien ap Vo=',num2str(-V(2)),' V']);

kết quả

dien ap Vo=-18.2857 V

Bài 10

Ia

R5=2k

Vb=36V

I2=?

I3=?

R2=4k

R1=2k

R3 2k

R4 5k I1=?

function bai10

R1=2;R2=4;R3=2;R4=5;R5=2;Va=24;Vb=36;

R=zeros(2,2);

R=A_array(1,0,R1+R2,R);

Trang 9

disp(['dong dien I3=',num2str(I(1)-I(2)),' A']);

kết quả

dong dien vong 1=-2.1176 A

dong dien vong 2=3.5294 A

Bài 11

I3

Vd=24V

Vb=6V

R2=1k

Va=12V

R1=2k

R3=3k

I1

Vc=18V

R7=1k

R6=2k

I2

R5=4k

R4=1k

function bai11

R1=2;R2=1;R3=3;R4=1;R5=4;R6=2;R7=1;

Va=12;Vb=6;Vc=18;Vd=24;

R=zeros(3,3);

R=A_array(2,0,R5,R);

V=zeros(3,1);

V=b_array(1,0,-Va-Vd,V);

V=b_array(2,0,-Vb-Vc,V);

V=b_array(3,0,Vd+Vc,V);

I=R\V;

disp(['dong dien vong 1= ',num2str(I(1)),' A']);

kết quả

dong dien vong 1= -6.549 A

dong dien vong 3= 8.8627 A

Trang 10

Bài 12

R5 2k

I3

R6

4k

I1

3k

Ve=24V

I2

Vd=18V

I=?

Vc=12V

R4 2k

R8 1k

R2 3k

Vb=10V

R7 6k

R1

5k

I4

R9 7k

function bai12

R1=5;R2=3;R3=1;R4=2;R5=2;R6=4;R7=6;R8=1;R9=7;

Va=6;Vb=10;Vc=12;Vd=18;Ve=24;

R=zeros(4,4);

V=zeros(4,1);

V=b_array(1,0,-Va-Vc,V);

V=b_array(2,0,Vb,V);

V=b_array(3,0,Ve-Vd,V);

V=b_array(4,0,Vc+Vd,V);

I=R\V;

disp(['dong dien I= ',num2str(I(1)-I(2)),' A']);

kết quả

Trang 11

Bài 13

I3

R1=6k

R3 1k

R2=3k

R5 2k

Vo=?

R4=4k

I1

R6 3k

R7 6k

Va=72V

I2

function bai13

R1=6;R2=3;R3=1;R4=4;R5=2;R6=3;R7=6;

Va=72;

R=zeros(3,3);

R=A_array(2,0,0,R);

V=zeros(3,1);

V=b_array(1,0,-Va,V);

V=b_array(2,0,0,V);

V=b_array(3,0,0,V);

I=R\V;

disp(['dong dien I= ',num2str(I(3)),' A']);

disp(['dien ap Vo= ',num2str((I(3)*R3)),' V']);

kết quả

dong dien vong 1= 6 A

dong dien I= 3 A

dien ap Vo= 3 V

Trang 12

Bài 14

R4 3k

I2

Va=24V

Vo=?

R3=1k

I1

Vb=12V

R2 6k

I=?

R1=3k

function bai14

R1=3;R2=6;R3=1;R4=3;

Va=24;Vb=12;

R=zeros(2,2);

V=zeros(2,1);

V=b_array(1,0,-Va-Vb,V);

I=R\V;

disp(['dien ap Vo= ',num2str(I(2)*R4),' A']);

kết quả

dong dien I= 3.3333 A

dien ap Vo= 6 A

Bài 15

R3 2k

Vb=12V

R4 8k

Va=24V

Vo=?

R2=4k

I1

R1=1k

I2

function bai15

Trang 13

disp(['dien ap Vo= ',num2str((I(1)-I(2))*R3),' V']);

kết quả

dong dien I= -3.2903 A

dien ap Vo= -6.5806 V

Bài 16

R6=0.5k

Vo=?

I2

0.5k

R3 1k

R2=0.5k

I3 I1

I4

R5 0.5k

I=?

function bai16

R1=1;R2=0.5;R3=1;R4=0.5;R5=0.5;R6=0.5;

Va=6;Vb=12;

R=zeros(4,4);

R=A_array(2,0,0,R);

V=zeros(4,1);

V=b_array(1,0,-Va,V);

V=b_array(2,0,-Vb,V);

V=b_array(3,0,0,V);

I=R\V;

disp(['dong dien I= ',num2str(I(3)),' A']);

disp(['dien ap Vo= ',num2str((I(3)*R5)),' V']);

kết quả

Trang 14

dong dien I= 1.5 A

dien ap Vo= 0.75 V

Bài 17

Va=60V

V2

I3

R2 12k

R1 2k

R3 2k

I5 I4

R6 1k

R4 6k

2k I2

I1

Vo=?

function bai17

R1=2;R2=12;R3=2;R4=6;R5=2;R6=1;

G1=1/R1;G2=1/R2;G3=1/R3;G4=1/R4;G5=1/R5;G6=1/R6;

Va=60;

G=zeros(3,3);

I=zeros(3,1);

I=b_array(0,1,Va/R1,I);

V=G\I;

disp(['Dien ap V1= ',num2str(V(1)),' V']);

disp(['Dong dien I1= ',num2str((Va-V(1))/R1),' A']);

disp(['Dong dien I2= ',num2str(V(1)/R2),' A']);

disp(['Dong dien I3= ',num2str((V(1)-V(2))/R3),' A']);

disp(['Dien ap Vo= ',num2str(((V(2)-V(3))/R5)*R6),' A']);

Dien ap V1= 36 V

Dien ap V2= 18 V

Dien ap V3= 6 V

Dong dien I1= 12 A

Dong dien I2= 3 A

Dong dien I3= 9 A

Trang 15

V1

I2

I1

I3

R2 6k

R3 12k

function bai18

R1=3;R2=6;R3=12;

G1=1/R1;G2=1/R2;G3=1/R3;

Va=24;Ia=5;

G=zeros(1,1);

G=A_array(1,0,G1+G2+G3,G);

I=zeros(1,1);

I=b_array(0,1,(Va/R3)+Ia,I);

V=G\I;

disp(['Dong dien I3= ',num2str((Va-V(1))/R3),' A']);

Dien ap V1= 12 V

Dong dien I1= 4 A

Dong dien I2= 2 A

Dong dien I3= 1 A

Bài 19

I4 R2 2k

R1 4k

R3 4k Vb=?

Va=?

I1

I3

V1

Ia 3A

function bai19

R1=4;R2=2;R3=4;

G1=1/R1;G2=1/R2;G3=1/R3;

Ia=3;Ib=5;Ic=6;

G=zeros(2,2);

I=zeros(2,1);

I=b_array(0,2,Ic,I);

V=G\I;

Trang 16

disp(['Dong dien I4= ',num2str(-V(1)/R2),' A']);

disp(['Dien ap Va= ',num2str(((V(2)-V(1))/R1)*R1),' V']);

disp(['Dien ap Vb= ',num2str(V(1)),' V']);

Dien ap V1= -2.6667 V

Dien ap V2= 44 V

Dong dien I2= 11.6667 A

Dong dien I4= 1.3333 A

Dien ap Va= 46.6667 V

Dien ap Vb= -2.6667 V

Bài 20

function bai20

ZC=-2j; R2=1; ZL=j; R4=0.5; Ia=1+j;

G1=1/ZC; G2=1/R2; G3=1/ZL; G4=1/R4;

G=zeros(2,2);

I=zeros(2,1);

U=G\I;

disp(['Dien the U1=',num2str(U(1)), '(V)']);

disp(['Do lon : ',num2str(abs(U(1))), '(V)']);

disp(['Goc pha : ',num2str(rad2deg(angle(U(1)))), '(do)']);

disp(['Dien the U2=',num2str(U(2)), '(V)']);

disp(['Do lon :',num2str(abs(U(2))), '(V)']);

disp(['Goc pha : ',num2str(rad2deg(angle(U(2)))), '(do)']);

disp(['Dong dien I1=',num2str(U(1)/ZC), '(A)']);

disp(['Do lon :',num2str(abs(U(1)/ZC)), '(A)']);

3

I



1

I



-2j

  1

a



 

4

I



R2 1

j

1

U



R4 0.5

0

2

I



2

U



Trang 17

kết quả

Dien the U1=0.43902-0.04878i(V)

Do lon : 0.44173(V)

Goc pha : -6.3402(do)

Dien the U2=0.26829+0.41463i(V)

Do lon :0.49386(V)

Goc pha : 57.0948(do)

Dong dien I1=0.02439+0.21951i(A)

Do lon :0.22086(A)

Goc pha :83.6598(do)

Dong dien I2=0.43902-0.04878i(A)

Do lon :0.44173(A)

Goc pha :-6.3402(do)

Dong dien I3=-0.46341-0.17073i(A)

Do lon :0.49386(A)

Goc pha :-159.7751(do)

Dong dien I4=0.53659+0.82927i(A)

Do lon :0.98773(A)

Goc pha :57.0948(do)

Tiêu đề	Phương Pháp Giải Mạch 1 Với Matlab
Tác giả	Ths Phan Như Quân
Trường học	Trường Đại Học Kỹ Thuật
Chuyên ngành	Kỹ Thuật Điện
Thể loại	Biên Soạn

Định dạng
Số trang	17
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