12.3.3, we obtain the governing dynamical equations of the system: 12.5.18 12.6 Closure The computational and analytical advantages of Kane’s equations and Lagrange’s tions are illustrat
Trang 1If we let the joint moments (M1, M2, and M3) be zero and if we let the point mass M
also be zero in Eqs (12.4.20), (12.4.21), and (12.4.22), we see that the equations are identical
Trang 2Generalized Dynamics: Kane’s Equations and Lagrange’s Equations 433
to Eqs (8.11.1), (8.11.2), and (8.11.3) reportedly developed using d’Alembert’s principle.Although the details of that development were not presented, the use of Lagrange’sequations has the clear advantage of providing the simpler analysis As noted before, thesimplicity and efficiency of the Lagrangian analysis stem from the avoidance of theevaluation of accelerations and from the automatic elimination of nonworking constraint
forces In the following section, we outline the extension of this example to include N rods.
Consider a pendulum system composed of N identical pin-connected rods with a point mass Q at the end as in Figure 12.5.1 (we considered this system [without the end mass]
in Section 8.11) As before, let each rod have mass m and length Also, let us restrict our
analysis to motion in the vertical plane The system then has N degrees of freedom
represented by the angles θi (i = 1,…, n) as shown in Figure 12.5.1 This system is useful
for modeling the dynamic behavior of chains and cables
We can study this system by generalizing our analysis for the triple-rod pendulum.Indeed, by examining Eqs (12.4.1) through (12.4.10), we see patterns that can readily be
generalized To this end, consider a typical rod B i as in Figure 12.5.2 Then, from Eq
(12.4.1), the angular velocity of B i in the fixed inertia frame may be expressed as:
(12.5.1)
where n3 is a unit vector normal to the plane of motion as in Figure 12.5.2
Next, from Eq (12.4.2), the velocity of the mass center G i may be expressed as:
(12.5.2)
where as before, and as in Figure 12.5.2, the niθ are unit vectors normal to the rods
Similarly, the velocity of the point mass Q is:
θ θ
Trang 3From Eq (12.4.4) we see that the partial angular velocities of B i are:
where M is the mass of Q.
From a generalization of Eq (12.4.11) the kinetic energy K of the N-rod system is:
j i
G j j
n n
20
Trang 4Generalized Dynamics: Kane’s Equations and Lagrange’s Equations 435
Finally, substituting from Eqs (12.5.6) and (12.5.9) into Lagrange’s equations in the form
of Eq (12.3.3), we obtain the governing dynamical equations of the system:
(12.5.18)
12.6 Closure
The computational and analytical advantages of Kane’s equations and Lagrange’s tions are illustrated by the examples In each case, the effort required to obtain thegoverning dynamical equations is significantly less than that with d’Alembert’s principle
equa-or Newton’s laws As noted earlier, the reason fequa-or the reduction in effequa-ort is that working constraint forces are automatically eliminated from the analysis with Kane’sand Lagrange’s equations; hence, an analyst can ignore such forces at the onset Also,with Kane’s and Lagrange’s equations, the exact same number of governing equationsare obtained as the degrees of freedom Finally, Lagrange’s equations offer the additionaladvantage of using energy functions, which makes the computation of vector accelera-tion unnecessary The disadvantages of Lagrange’s equations are that they are notapplicable with nonholonomic systems, and the differentiation of the energy functionsmay be tedious and even unwieldy for large systems
non-In the following chapters we will consider applications of these principles in tions, stability, balancing, and in the study of mechanical components such as gearsand cams
Trang 512.1 Kane, T R., Dynamics of nonholonomic systems, J Appl Mech., 28, 574, 1961.
12.2 Kane, T R., Dynamics, Holt, Rinehart & Winston, New York, 1968, p 177.
12.3 Huston, R L., and Passerello, C E., On Lagrange’s form of d’Alembert’s principle, Matrix
Tensor Q, 23, 109, 1973.
12.4 Papastavridis, J G., On the nonlinear Appell’s equations and the determination of generalized
reaction forces, Int J Eng Sci., 26(6), 609, 1988.
12.5 Huston, R L., Multibody dynamics: modeling and analysis methods [feature article], Appl.
Mech Rev., 44(3), 109, 1991.
12.6 Huston, R L., Multibody dynamics formulations via Kane’s equations, in Mechanics and Control
of Large Flexible Structures, J L Jenkins, Ed., Vol 129 of Progress in Aeronautics and Astronautics,
American Institute of Aeronautics and Astronautics (AIAA), 1990, p 71.
12.7 Huston, R L., and Passerello, C E., Another look at nonholonomic systems, J Appl Mech., 40,
101, 1973.
12.8 Kane, T R., and Levinson, D A., Dynamics, Theory, and Applications, McGraw-Hill, New York,
1985, p 100.
Problems
Section 12.2 Kane’s Equations
P12.2.1: Consider the rotating tube T, with a smooth interior surface, containing a particle
P with mass m, and rotating about a vertical diameter as in Problems P11.6.6 and P11.9.6 and as shown again in Figure P12.2.1 As before, let the radius of T be r, let the angular speed of T be Ω, and let P be located by the angle θ as shown in Figure P12.2.1 This
system has one degree of freedom, which may be represented by θ Use Kane’s equations,
Eq (12.2.1), to determine the governing dynamical equation
P12.2.2: Consider the pendulum consisting of a rod with length and mass m attached
to a circular disk with radius r and mass M and supported by a frictionless pin as in
Problems P11.9.1 and P11.12.1 and as shown again in Figure P12.2.2 This system has onedegree of freedom represented by the angle θ Use Kane’s equations to determine thegoverning dynamical equation
Trang 6Generalized Dynamics: Kane’s Equations and Lagrange’s Equations 437
P12.2.3: Consider the rod pinned to the vertically
rotating shaft as in Problems P11.9.2 and as shown
again in Figure P12.2.3 If the shaft S has a specified
angular speed Ω, the system has only one degree of
freedom: the angle θ between the rod B and S Use
Kane’s equations to determine the governing
dynamical equation where B has mass m and length
Assume the radius of S is small.
P12.2.4: Repeat Problem P12.2.3 by including the
effect of the radius r of the shaft S Let the mass of S
be M.
P12.2.5: See Problems P11.9.4 and P12.2.3 Suppose
the rotation of S is not specified but instead is free,
or arbitrary, and defined by the angle φ as in Problem
P11.9.4 and as represented in Figure P12.2.5 This
system now has two degrees of freedom represented
by the angles θ and φ Use Kane’s equations to
deter-mine the governing dynamical equations, assuming
the shaft radius r is small.
P12.2.6: Repeat Problem P12.2.5 by including the
effect of the shaft radius r and the shaft mass M.
P12.2.7: Consider a generalization of the double-rod
pendulum where the rods have unequal lengths and
unequal masses as in Figure P12.2.7 Let the rod
lengths be 1 and 2, and let their masses be m1 and
m2 Let the rod orientations be defined by the angles
θ1 and θ2, as shown Assuming frictionless pins,
determine the equations of motion by using Kane’s
equations
P12.2.8: See Problem P12.2.7 Suppose an actuator (or
motor) is exerting a moment M1 at support O on the
upper bar and suppose further that an actuator at
the pin connection between the rods is exerting a
moment M2 on the lower rod by the upper rod (and
hence a moment –M2 on the upper rod by the lower
rod) Finally, let there be a concentrated mass M at
the lower end Q of the second rod, as represented in
Figure P12.2.8 Use Kane’s equations to determine
the equations of motion of this system
P12.2.9: Repeat Problems P12.2.7 and P12.2.8 using
the relative orientation angles β1 and β2, as shown in
Figure P12.2.9, to define the orientations of the rods
P12.2.10: See Problems P11.6.8 and P11.9.8 Consider
again the heavy rotating disk D supported by a light
yoke Y which in turn can rotate relative to a light
horizontal shaft S which is supported by frictionless
bearings as depicted in Figure P12.2.10 Let D have
mass m and radius r Let angular speed Ω of D in Y
be constant Let the rotation of Y relative to S be
Trang 7measured by the angle β and the rotation of S in its bearings be measured by the angle α
as shown Recall that this system has two degrees of freedom, which may be represented
by the angles α and β By following the procedures outlined in Problems P11.6.8 andP11.9.8, use Kane’s equations to determine the governing equations of motion
P12.2.11: See Problems P11.6.7 and P11.9.7 Consider again the right circular cone C with altitude h and half-central angle rolling on an inclined plane as in Figure P12.2.11 As
before let the incline angle be β and let the position of C be determined by the angle φ between the contacting element of C and the plane and a line fixed in the plane as shown.
Let be the element length of C, and let r be the base radius of C Let O be the apex of
C, and let G be the mass center of C Finally, let ψ measure the roll of C, as shown in Figure
P12.2.11 This system has one degree of freedom (see Problem P12.2.11) Use Kane’sequations to determine the equations of motion
Section 12.3 Lagrange’s Equations
P12.3.1 to P12.3.10: Repeat Problems P12.2.1 to P12.2.10 by using Lagrange’s equations toobtain the equations of motion Compare the analysis effort with that of using Kane’sequations
FIGURE P12.2.9
Double, unequal-rod pendulum with
relative orientation angles.
Trang 8In this chapter we will develop a brief and elementary introduction to mechanicalvibration It is only an introduction and is not intended to replace a course or a moreintense study The reader is referred to the references, which provide a partial listing ofthe many books devoted to the subject.
We begin with a brief review of solutions to second-order ordinary differential equations
We then consider single and multiple degree of freedom systems We conclude with abrief discussion of nonlinear vibrations
13.2 Solutions of Second-Order Differential Equations
Vibration phenomena are often modeled by second-order ordinary differential equations.Solutions of these equations provide a representation of the movement of vibrating sys-tems; therefore, to begin our study, it is helpful to review the solution procedures of second-order ordinary differential equations The reader is encouraged to also independentlyreview these procedures References 13.1 to 13.7 provide a sampling of the many textsavailable on the subject
We will consider first the so-called linear oscillator equation:
(13.2.1)where, as before, the overdot represents differentiation with respect to time, and ω is aconstant
In Eq (13.2.1) the time t is the independent variable and x is the dependent variable to
be determined It is readily verified that the solution of Eq (13.2.1) may be expressed inthe form:
Trang 9440 Dynamics of Mechanical Systems
where A and B are constants that may be evaluated by auxiliary conditions (initial tions or boundary conditions) (We can verify that the expression of Eq (13.2.2) is indeed asolution of Eq (13.2.1) by direct substitution It is in fact a general solution, as cosωt andsinωt are independent functions and there are two arbitrary constants, A and B.)
condi-Through use of trigonometric identities, we can express Eq (13.2.2) in the form:
(13.2.3)where  and φ are constants To develop this, recall the identity:
(13.2.4)Then, by thus expanding the expression of Eq (13.2.3) we have:
of  and – Also, the period T of the oscillation is determined by:
cos(α β+ )≡cos cosα β−sin sinα β
π/2
π
Trang 10Introduction to Vibrations 441
As noted earlier, the constants in Eqs (13.2.2) and (13.2.3) are to be evaluated by auxiliaryconditions These auxiliary conditions are generally initial conditions or boundary condi-tions Initial conditions (where t = 0) might be expressed as:
(13.2.9)Then, by requiring the solution of Eq (13.2.2) to meet these conditions, we have:
(13.2.10)and thus,
(13.2.11)Boundary conditions might be expressed as:
(13.2.12)
Then, by requiring the solution of Eq (13.2.2) to meet these conditions, we see that theconstants A and B must satisfy:
(13.2.13)The second expression is satisfied by either:
Trang 11442 Dynamics of Mechanical Systems
By comparing the solution procedures between the initial and boundary value problems,
we see that the solution of the initial value problem is simpler and more direct than that
of the boundary value problem Therefore, for simplicity, in the sequel we will consider
primarily initial value problems
Consider next the damped linear oscillator equation:
(13.2.18)where m, c, and k are constants This is the classical second-order homogeneous linear
ordinary differential equation with constant coefficients From References 13.9 to 13.13,
we see that the solution depends upon the relative magnitudes of m, c, and k If the product
4km is less than c2, we can write the solution in the form:
(13.2.19)where µ and ω are defined as:
(13.2.20)
If, in Eq (13.2.18), the product c2 exceeds 4km, the solution takes the form:
(13.2.21)where µ and ν are defined as:
(13.2.22)
Finally, if in Eq (13.2.18), the product 4km is exactly equal to c2, the solution takes the
form:
(13.2.23)where µ is:
(13.2.24)Next, consider the forced linear oscillator described by the equation (with 4km > c2):
(13.2.25)where f(t) is the forcing function The forcing function typically has the form:
2
4
2 2
2
4
2 2
Trang 12Introduction to Vibrations 443
Equation (13.2.25) then becomes:
(13.2.27)From References 13.9 to 13.13, we see that the general solution may be expressed as:
(13.2.28)
where x h is the general solution of the homogeneous equation (right side equal to zero)
as in Eqs (13.2.18) and (13.2.19), and where x p is any solution of the nonhomogeneous
equation (right side equal to Fcospt, as in Eq (13.2.27)) x p is commonly called the particular
solution From Eq (13.2.19) we see that x h is:
(13.2.29)
where, as before, µ and ω are defined by Eq (13.2.20) Also, from the references, we see
that x p may be expressed as:
(13.2.30)where ∆ is defined as:
(13.2.31)
(The validity of Eq (13.2.26) may be verified by direct substitution into Eq (13.2.23).)
Finally, if c is zero in Eq (13.2.27), we have the forced undamped linear oscillator
equation:
(13.2.32)From Eqs (13.2.28), (13.2.29), and (13.2.30), we see that the solution is:
(13.2.33)
where x h and x p are:
(13.2.34)and
(13.2.35)where from Eq (13.2.20) ω is defined as:
Trang 1313.3 The Undamped Linear Oscillator
Consider the undamped linear oscillator consisting of the mass–spring system, which we
considered in Chapter 11, Section 11.5, and as shown in Figure 13.3.1, where m is the mass
of a block B sliding on a smooth (frictionless) horizontal surface, k is the modulus of a linear supporting spring, and x measures the displacement of B away from its equilibrium configuration The system is said to be undamped because B moves on a frictionless surface
and the total energy of the mass–spring system is unchanged during the motion Usingany of the principles of dynamics, we find the equation of motion to be:
(13.3.1)or
(13.3.2)where:
(13.3.3)From Eq (13.2.2), we see that the solution of Eq (13.3.2) is:
(13.3.4)
where, as we noted, A and B are constants to be evaluated from auxiliary conditions such
as initial conditions for the mass–spring system For example, suppose that at time t = 0
the displacement and displacement rate are:
(13.3.5)Then, from Eq (13.3.4), we have:
(13.3.6)Hence, the solution becomes:
Trang 14where f is the frequency (or natural frequency) and T is the period.
Consider next the simple pendulum as in Figure 13.3.2 From Eq (12.2.9), we see thatthe equation of motion is:
(13.3.11)
where as before, θ measures the displacement away from equilibrium, g is the gravity
constant, and is the pendulum length Observe that if θ is small, as is the case with mostpendulums, we can approximate sinθ by the first few terms of a Taylor series expansion
of sinθ about the equilibrium position θ = 0 That is,
(13.3.12)Hence, for small θ, we have:
(13.3.13)The governing equation Eq (13.3.11), then becomes:
Trang 15Equation (13.3.14) is identical in form to Eq (13.3.2); therefore, the solution will havethe form of Eq (13.3.7) That is,
(13.3.15)where θ0 and 0 are the initial values of θ and , respectively, and where ω is:
(This is the reason why pendulums have been used extensively in clocks and timing devices.)
13.4 Forced Vibration of an Undamped Oscillator
Consider again the undamped mass–spring system of the foregoing section and as
depicted again in Figure 13.4.1 This time, let the mass B be subjected to a time-varying force F(t) as shown Then, it is readily seen by using any of the principles of dynamics
discussed earlier, that the governing equation of motion for this system is:
Trang 16Introduction to Vibrations 447
where F0 and p are constants The governing equation then becomes:
(13.4.3)From Eqs (13.2.32) through (13.2.35) we see that the general solution of Eq (13.4.3) is:
(13.4.4)
where as before A and B are constants to be determined from auxiliary conditions (such
as initial conditions) and where ω is defined as:
(13.4.5)
Consider the last term, [F0/(k – mp2)]cospt of Eq (13.4.4) Observe that if p2 has values
nearly equal to k/m (that is, if p is nearly equal to ω) the denominator becomes very small,
producing large-amplitude oscillation Indeed, if p is equal to ω, the oscillation amplitude
becomes unbounded This means that by stimulating the mass B with a periodic force
having a frequency nearly equal to ω (that is, ), the amplitude of the resulting oscillationbecomes unbounded
The quantity is called the natural frequency of the system When the frequency of
the loading function is equal to the natural frequency, giving rise to a large-amplitude
response, we have the phenomenon commonly referred to as resonance.
13.5 Damped Linear Oscillator
Consider next the damped linear oscillator as depicted in Figure 13.5.1 This is the same
system we considered in the previous sections, but here the movement of the mass B is
restricted by a “damper” in the form of a dashpot For simplicity of illustration, we will
assume viscous damping, where the force exerted by the dashpot on B is proportional to the speed of B and directed opposite to the motion of B with c being the constant of
proportionality That is, the damping force FD on B is:
Trang 17By considering a free-body diagram of B and by using the principles of dynamics (for
example, Newton’s laws or d’Alembert’s principle), we readily see that the governingequation of motion is:
(13.5.2)
where as before, m is the mass of B and k is the linear spring modulus.
From Eqs (13.2.18), (13.2.19), and (13.2.20), we see that the solution of Eq (13.5.2) may
be written in the form:
(13.5.3)where µ and ω are defined as:
(13.5.4)
and where, as before, A and B are constants to be evaluated from auxiliary conditions,
such as initial conditions, on the system
Observe in Eq (13.5.3) that if the damping constant c is small we have an oscillating
system where the amplitude of the oscillation slowly decreases, as in Figure 13.5.2 This
phenomenon is called underdamped vibration.
Next, observe in Eqs (13.5.3) and (13.5.4) that if the damping constant c is such that ω
is zero, there will be no oscillation That is, if
(13.5.5)then
(13.5.6)and
2
4
2 2
1 2 /
c= 2 km
ω = 0
x=e−µt(A Bt+ )
Trang 18Introduction to Vibrations 449
where µ is:
(13.5.8)
In this case, the block moves to its static equilibrium position without oscillation This
phenomenon is called critical damping.
Finally, suppose the damping constant is larger than critical damping, that is, largerthan 2 Then, from Eq (13.5.4), we see that ω is imaginary and that the solution for
the displacement x of B becomes:
(13.5.9)where µ and ν are:
(13.5.10)
Observe that µ is always larger than ν and we have a relatively rapidly decaying motion
of B This phenomenon is called overdamping.
13.6 Forced Vibration of a Damped Linear Oscillator
Consider next the forced vibration of a damped linear oscillator as depicted in Figure13.6.1 From the principles of dynamics, we readily find the governing equation of motion
2
4
2 2
Trang 19Equation (13.6.1) then takes the form:
(13.6.6)where µ, ω, and ∆ are defined by:
(13.6.7)
where we assume that c2 < 4km As before, the constants A and B in Eq (13.6.5) are to be
evaluated by auxiliary (initial) conditions on the system
Observe that the last term of Eq (13.6.6) can become quite large if the damping coefficient
c is small and if the frequency p of the forcing function is nearly equal to the natural
frequency of the undamped system Note, however, that unlike the undampedsystem, the presence of damping assures that the amplitude of the oscillation remainsfinite Thus, we see that damping (or effects of friction and viscosity) can have a beneficialeffect in preventing harmful or unbounded vibration of a mechanical system
The phenomenon of damping in physical systems, however, is generally more complexthan our relatively simple model of Eq (13.5.1) Indeed, damping is generally a nonlinearphenomenon that varies from system to system and is generally not well understood.Theoretical and experimental research on damping is currently a major interest of vibrationanalysts
13.7 Systems with Several Degrees of Freedom
We consider next mechanical systems where more than one body can oscillate An example
of such a system might be a double mass–spring system as in Figure 13.7.1 This system
has two degrees of freedom as represented by the displacements x1 and x2 of the masses.Accordingly, we expect to obtain two governing differential equations that must be solved
2
4
2 2
Trang 20Introduction to Vibrations 451
simultaneously Similarly, systems with three or more degrees of freedom will have three
or more governing differential equations to be solved simultaneously
To illustrate a procedure for studying such systems, consider again the system of connected smooth particles (or balls) in the rotating tube as in Figure 13.7.2 As before,
spring-let each particle have mass m and spring-let the connecting springs be linear with natural length
and modulus k.
To simplify our analysis, let θ be fixed at 90° so that the particles move in a fixed
horizontal tube with their position defined by the coordinates x1, x2, and x3 as in Figure13.7.3 From Eqs (12.2.27), (12.2.28), and (12.2.29), we see that, with θ fixed at 90°, theequations of motion may be written as:
(13.7.1)(13.7.2)(13.7.3)Equations (13.7.1), (13.7.2), and (13.7.3) may be written in the matrix form:
Trang 21To solve Eq (13.7.4), let x have the matrix form:
(13.7.7)where ω is a frequency to be determined and A is the array:
(13.7.11)That is,
As with the eigenvalue problem we encountered in Sections 7.7, 7.8, and 7.9 in studying
inertia, we have a system of simultaneous linear algebra equations for the amplitudes A1,
A2, and A3 The system is homogeneous in that the right sides are zero Thus, we have anontrivial (or nonzero) solution only if the determinant of the coefficients is zero Hence,
Trang 22Observe that instead of obtaining one solution we have three solutions That is, there
are three positive frequencies (three natural frequencies) that make the determinant of Eq.
(13.7.16) equal to zero and thus allow a nonzero solution of Eqs (13.7.13), (13.7.14), and(13.7.15) to occur This in turn means that we can expect to find three sets of amplitudessolving Eqs (13.7.13), (13.7.14), and (13.7.15), one set for each frequency ωi (i = 1, 2, 3).
To find these amplitude solutions, we can select one of the ωi (say, the smallest of the
ωi ), substitute it into Eqs (13.7.13) to (13.7.15), and thus solve for the amplitudes A i (i =
1, 2, 3) We can then repeat the process for the other two values of ωi Notice, however,that although there are three equations for the three amplitudes, the equations are notindependent in view of Eq (13.7.16) That is, there are at most two independent equations,thus we need another equation to obtain a unique solution for the amplitudes Such anequation can be obtained by arbitrarily specifying the magnitude of one or more of theamplitudes For example, we could “normalize” the amplitudes such that
(13.7.19)
Then, Eqs (13.7.13), (13.7.14), (13.7.15), and (13.7.19) are equivalent to an independent set
of three equations, enabling us to determine unique values of the amplitudes
To this end, let us select the smallest of the ωi (ω1) and substitute it (that is, {(2 – )
(k/m)}1/2) into Eqs (13.7.13), (13.7.14), and (13.7.15) This produces the equations:
(13.7.20)
(13.7.21)
(13.7.22)
Observe that these equations are dependent (If we multiply the first and third equations
by and add them we obtain a multiple of the second equation.) Thus, by selecting two(say, the first two) of these equations and by combining them with Eq (13.7.19), we obtainupon solving the expressions:
3 2
= −( ) ( )k m , = ( )k m , = +( ) ( )k m
A12 A A
2 2 3
A1=1 2, A2= 2 2, A3=1 2
Trang 23Next, let ω be ω2 (that is, ) By substituting into Eqs (13.7.13), (13.7.14), and(13.7.15), we obtain the equations:
(13.7.24)(13.7.25)(13.7.26)These equations are also dependent (the first and third are the same) By using the first
two of these together with Eq (13.7.19) and solving for A1, A2, and A3, we have:
Trang 24Introduction to Vibrations 455
13.8 Analysis and Discussion of Three-Particle Movement:
Modes of Vibration
In reviewing the foregoing analysis of the three-particle system we see a striking similarity
to the analysis for the eigenvalue problem of Sections 7.7, 7.8, and 7.9 Indeed, a comparison
of Eqs (13.7.13), (13.7.14) and (13.7.15) with Eq (7.7.10), shows that they are in essencethe same problem This means that analyses similar to those of Sections 7.7, 7.8, and 7.9(such as determination of eigenvalues, eigenvectors, orthogonality, etc.) could also beconducted for the three-particle vibration problem In our relatively brief introduction tovibrations, however, it is not our intention to develop such detail Instead, we plan tosimply introduce the concept of vibration modes (analogous to eigenvectors)
To this end, consider again the governing differential equations for the spring-supportedparticles (see Eqs (13.7.1), (13.7.2), and (13.7.3)):
(13.8.1)(13.8.2)(13.8.3)
Trang 25Recall that we found not one but three nontrivial solutions to these equations Each solution
had its own frequency, which means that the system can vibrate in three ways, or in three
“modes,” as depicted in Figures 13.7.4, 13.7.5, and 13.7.6 These are called the natural modes
of vibration of the system.
To discuss this further, consider the amplitudes of these vibration modes as in Eqs.(13.7.23), (13.7.27), and (13.7.31) and as listed in Table 13.8.1 In view of the amplituderatios, let new variables ξ1, ξ2, and ξ3 be introduced as:
(13.8.4)
(13.8.5)
(13.8.6)Then, by differentiating, we have:
(13.8.7)
(13.8.8)
(13.8.9)Consider first 1 By substituting from Eqs (13.8.1), (13.8.2), and (13.8.3), we have:
TABLE 13.8.1
Modes of Vibration of Spring-Supported Particles
Mode Frequency Normalized Amplitudes