The main goals of quality management are customer satisfaction by delivery of defect free products at quality cost.. The primary objective of quality control in any organization is to re
Trang 1Nitin K Mandavgade¹ and Santosh B Jaju²
Department of Mechanical Engineering, G H Raisoni College of Engineering, CRPF Gate No.3, Digdoh Hills, Hingna Road, Nagpur 440016 (India)
1
E-mail: nitin_man@rediffmail.com and 2E-mail: sbjaju@gmail.com
Abstract
Quality plays very important role in today’s highly competitive industrial environment Quality leads to an improvement in productivity By improving quality, the method of optimization reduces process operational costs and variation in product Quality, productivity & cost of operation relatively depended to each other The main goals of quality management are customer satisfaction by delivery of defect free products at quality cost Controlled processes are the most important ways to reach this goal The primary objective of quality control in any organization is to reduce the costs of its operation If control efforts do not lead to any saving in costs or cost reduction then, in principle there is no need for quality control However, in most control activities, cost saving are real and they remain a principle objective of quality control for most organizations
Keywords: Quality, quality control, cost optimization, inspection
Introduction to quality control
Many companies in the world are gradually promoting quality as the central customer value and regard it as a key concept of company strategy in order to achieve the
competitive edge Quality improvement decisions are viewed as the catalyst for
substantial technological developments being made in the manufacturing sector Quality Costs are a measure of the costs specifically associated with the achievement
or non-achievement of product or service quality –including all product or service requirements established by the company and its contract with customers and society Measuring and reporting the quality cost is the first step in a quality management program Quality costs allow us to identify the soft targets to which improvement efforts can be applied
Trang 2Three types of cost are generally associated with quality control:
1 Assignment costs
2 Prevention costs
3 Non-conformance costs
Assignment costs are the cost which an organization incurs in measuring quality characteristics to ensure that they conform to quality standards This cost typically includes costs of inspection including labour , materials, and cost of approval or certification when organizations meet quality standards and so on Prevention costs involve cost when organizations undertake measures to prevent poor quality of products or performance Example of prevention cost would include the costs associated with quality planning, design and development of quality measurement instruments, quality training and so on Finally non conformance costs also called failure costs occur when an organization fails to meet quality standards This may be due to poor quality of labour, materials and overhead, i.e expenses accumulated
Seven Quality Control Tools
The various tools are used to check the quality of the product to define weather the product is a quality one or not and to take the further necessary actions to bring the process under control
• Check sheet
• Pareto chart
• Flow chart
• Cause and effect diagram
• Histogram
• Scatter diagram
• Control chart
Check sheet
The function of a check sheet is to present information in an efficient, graphical format This may be accomplished with a simple listing of items However, the utility
of the check sheet may be significantly enhanced in some instances by incorporating a depiction of the system under analysis into the form
Pareto Chart
Pareto charts are extremely useful because they can be used to identify those factors that have the greatest cumulative effect on the system and thus screen out the less significant factors in an analysis
Ideally, this allows the user to focus attention on a few important factors in a process
Trang 3Figure 1: Pareto Chart
Flowchart
Flowcharts are pictorial representations of a process By breaking the process down into its constituent steps, flowcharts can be useful in identifying where errors are likely to be found in the system In quality improvement work, flowcharts are particularly useful for displaying how a process currently functions or could ideally function
Figure 2: Flowchart
Trang 4Cause and Effect Diagram
This diagram, also called an Ishikawa diagram (or fish bone diagram) is used to associate multiple possible causes with a single effect Thus, given a particular effect, the diagram is constructed to identify and organize possible causes for it
Figure 3: Cause and effect Diagram
Causes in a cause & effect diagram are frequently arranged into four major categories While these categories can be anything, given below:
• Manpower, methods, materials, and machinery (recommended for manufacturing)
• Equipment, policies, procedures, and people (recommended for administration and service)
Histogram
A histogram is a specialized type of bar chart Individual data points are grouped together in classes, so that you can get an idea of how frequently data in each class occur in the data set Histograms provide a simple, graphical view of accumulated data
Trang 5Figure 4: Histogram
Scatter Diagram
Scatter diagrams are graphical tools that attempt to depict the influence that one variable has on another A common diagram of this type usually displays points representing the observed value of one variable corresponding to the value of another variable
Figure 5: Scatter Diagram
Control Chart
The control chart is the fundamental tool of statistical process control as it indicates the range of variability that is built into a system (known as common cause variation) Thus, it helps determine whether or not a process is operating
Trang 6consistently or if a special cause has occurred to change the process mean or variance
Problem: Optimization of cost by using 7 quality control tools
Step1:-Introduction to the problem
In operation 67 of control valve cylinder head (as shown in Figure 6) of the diameter 15.840/15.862 mm was getting oversize
Figure 6: Control Valve Cylinder Head
Background of problem selection:-
This problem was selected because in-house rejection was alarming and also
product returned from the line at vendor (automotive industry in central India) was
repeated time to time (refer figure 7 & 8) Total rejections in house are 10 units and
product returned is 16 units
Figure 7: Line rejection
Critical area
Line Rejection Trend Op67 Dia 15.840/15.862m m in CVCH
3
2
5
0 2 4
Months
Trang 7Figure 8: In House rejections
Problem Selected:-Elimination of rejection due to diameter 15.840/15.862 mm
which was getting oversize
Target: - Zero defects in diameter 15.840/15.862 mm of Operation 67
Step 2:- Observation
Information regarding process and operation are observed
(1) Operation done on vertical milling machine
(2) All the tools are operated like 14.68 mm drill hole, mill to correct the axis & then reamer
(3) Rigid clamping fixture
(4) This is operated after the operation 50 done In solid stage without putting on any machine
(5) Tool change frequency decided for every operation as discussed
(6) Coolant used for reaming is kerosene or solvent 2445
(7) Variable type gauging i.e Air plug Gauge is used for in-process inspection of this reamed bore with 1 in 5 inspection frequency
Step 3:- Identification of Probable Causes:- Probable causes are identified and
represented in the form of cause and effect diagram as shown in figure 9
2
0
2
Months
Trang 8Figure 9: Identification of probable causes
Step 4: Brainstorming
The most probable causes (Identified by cause and effect diagram and Brainstorming) Cause1: Insufficient knowledge of operator
Cause2: Hardness inconsistency in raw material
Cause3: Intermittent supply of coolant
Cause4: Tool run out not checked before putting on the machine & after the part detected oversize
Analysis done to test the validity of probable causes
Cause1:Test1: Insufficient Knowledge of operator
Observation:-After interviewing the machine operator it was confirmed that they are
having adequate operating and inspection knowledge
Also, there was standard operating procedure available near the machine which were regularly followed
Result: In valid cause for the problem
Cause 2: Test 1: hardness less in rejected components
Specification 179 to 229 BHN
Actual observation; 189,198,182,192,194
Also, hardness of 5 ok components were checked and it was observed that hardness was with in specification
Actual observation: 190,195,192,185,198
Result: In valid cause for the problem
Cause 3: Test 1: Intermittent supply of coolant
Observation: To get the proper finish kerosene or solvent 2445 is applied
continuously to the reamer to avoid the chip rubbing & proper cutting
Trang 9but found with in 10 microns
Result: Invalid cause for the problem
Why the rejected parts were oversize in between?
For this we have checked the run out of the tool when the part was rejected After analyzing the problem after deep studies that the raw material is grey cast iron For machining of cast iron does not need any coolant, it may be cut in dry condition As in our case also, the operation for drilling and hole milling kept as in dry cutting condition As the property of the cast iron is to produce dust with small flakes of chip, such dust get fly off along with current air by the fans put in the shop floor & get accumulated every where In-due course of time this dust get accumulated on the BT
40 taper of the tool holder & causes to have run out in the tool As the tool run out increase the bore to become oversize
Result: Valid cause for the problem
Step 5:- counter measure:
Short term:
• Instruction was given to all the operators & the officials about the valid cause
of the size for getting over size
• Part checking frequency was changed from 1in 5 to 100% in process inspection
Long term:
• All the taper of the tools & the spindle to be clean after every 12 hours
• Air connection was given through the spindle to blow off the dust in the spindle taper for accumulating it
Step 6:- Implementation of countermeasure:
All the action are implemented at once
Step 7:- Standardization:
Standard operating procedure for operation 67 update Standard operating procedure for operation 67 was revised by putting these important points
Step 8:- Direct benefit:
Cost saving as no internal rejection for the same reason
Result: After implementation no Problem was observed from the last 3 months
Trang 10Cost analysis
Raw Material i.e casting is given by automotive industry from Approved Vendor M/S CASPRO LTD, Kolhapur
Costs-
• Raw material Cost : Rs.248/piece
• Machining Cost : Rs.200/piece
• Total costs : Rs.448 /Piece
Various consumables costs for Operation 67-
Tooling costs Description-
Sr
No
Rs
Life in parts
Costs
3 Drill dia 14.5 mm Solid carbide 8500 30,000 0.28
4 Hole mill Solid carbide 8500 30,000 0.28
Tool holder cost: Rs 3000
3000*6 (for above six operation) = Rs 18,000
1.5 lakh is the life of the tool holder so the cost of tool holder per piece is
18000/150000= Rs 0.12 /piece
lubricant cost:-
SAE20W40 IS USED
5 LIT Tank per shift
Rs125/lit
5*125 = Rs625/shift
90 Parts are produced in one shift
652/90 = Rs6.94/piece
Coolant cost: - Kerosene is used as coolant in order to improve the surface finish &
to avoid the corrosion
5 lit require per shift
Rs35/lit
35*5=Rs175/shift
90 Parts are produced in one shift
175/90=Rs.0.50/piece
Cotton waste: It is approximately Rs0.10/piece
Trang 11for 26 days in one month So the money paid by the company for 1 day = 5000/26= Rs192/day.He inspect approximately 300 parts in 1 day
Cost for inspecting one piece = 192/300 = Rs0.64/piece
Machining Cost
Labour Cost
The salary paid to the labour (machine operator) is Rs3500/month.He works for 26 days in one month So the money paid y the company for 1 day = 3500/26= Rs134/day.He produce a 90 parts in 1 day Cost for producing one piece =
134/90=Rs.1.49/piece
Machine Depression Cost
Generally there is 10-15% depression cost, But machine are in maintained condition
so there is only 10% depression cost in 1 year
Cost of machine is Rs18 lakh If we consider for 5 years 180000/5 = Rs3.6lakh 180000-36000=RS 144000 in 5 years
For 1 year = 30,000/year
For 1 month =30,000/12=Rs 2500/month
For 1 day = 2500/26=Rs 96/day
For 1 part = 96/270parts in one day=Rs.0.35/piece
Total Cost Associated In Operation 67 =
All cost associated in tooling + all cost associated Inspection cost + machining cost + Raw material cost
Total cost=0.3+0.29+0.28+0.28+0.65+0.0062+0.12+6.95+0.5+0.10+2.16+2.00+0.64
+1.49+0.35+248 = Rs.264.116 / piece in op67
There are 3 to 4 Parts are rejected due to diameter 15.840/15.862mm over size in
1 month
Costs saved per month = 264.116 *4 = Rs 1056.46 /month
Cost saved per year = 1056.46*12 =Rs 12,677.57/ year
Conclusion
Quality leads to an improvement in productivity Quality, productivity & cost of operation relatively depended to each other The main goals of quality management are customer satisfaction by delivery of defect free products at quality cost In operation 67 of control valve cylinder head (as shown in Figure 6) of the diameter
Trang 1215.840/15.862 mm was getting oversize We have studied the problems and actually solved the problem by using seven quality control tools which result in good amount
of saving in cost of product and overall reputation of the company get improved
References
[1] Company manual
[2] Chaddha, R., 1999, “Quality costs and financial performance: A pilot study,”
IE Journal, Vol XXVIII, No 5, pp19-25
[3] Jaju, S.B., Shrivastava, R.L., and Lakhe, R.R., 2003, “Performance Analysis through quality costs: a case study,” Industrial Engineering Journal, Vol XXXIII, No.6, June 2004, pp 15-20
[4] Jaju, S B., Lakhe, R R and Bhagade, S S., 2007, “Mathematical
Interrelationships among Quality Cost Categories for a Manufacturing Sector”
Industrial Engineering Journal, Vol XXXVI, No.3 March 2007 pp 32-41 [5] Juran J M., 1974, Quality Control Handbook, McGraw Hill, New York
[6] Roden, S., and Dale, B.G., 2001, “Quality costing in a small engineering company: Issues and difficulties,” The TQM Magazine, Vol 13, No.6,
pp388-399
Appendix
0.001 LTC 20
3 D.C NO QTY 1000.0000
MM
15.851 15.853 15.852 15.848 15.852 15.865 15.842 15.849 1 1.123 2.560 3.270 15.849 15.852 15.860 15.852 15.880 15.842 15.848 15.851 2 1.128 1.880 3.270 15.851 15.852 15.852 15.880 15.851 15.853 15.866 15.853 3 1.693 1.020 2.570 15.849 15.852 15.852 15.842 15.853 15.850 15.840 15.851 4 2.059 0.730 2.230 15.842 15.853 15.852 15.849 15.852 15.848 15.842 15.853 5 2.326 0.590 2.110
15.851 15.853 15.86 15.88 15.88 15.865 15.866 15.853 Xmax.= 15.8800
15.842 15.852 15.852 15.842 15.851 15.842 15.84 15.849 Xmin.= 15.8400
0.009 0.001 0.008 0.038 0.029 0.023 0.026 0.004 = 0.01490 4 NOS.
15.8484 15.8524 15.8536 15.8542 15.8576 15.8516 15.8476 15.8514 = 15.8514 0 NOS.
0.0362 FREQ CU FREQ.
5 15.8066 15.8147 0 0 0.000400 15.8147 15.8228 0 0 15.8228 15.8309 0 0 15.86019 15.86019 15.8602 15.8602 15.8602 15.8602 15.86019 15.8602 15.8309 15.8390 0 0
15.8426 15.8426 15.8426 15.8426 15.8426 15.8426 15.8426 15.8426 15.8390 15.8471 8 8
0.0314 0.0314 0.0314 0.0314 0.0314 0.0314 0.0314 0.0314 15.8471 15.8552 37 45
0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 15.8552 15.8633 1 46
15.8514 15.8514 15.8514 15.8514 15.8514 15.8514 15.8514 15.8514 15.8633 15.8714 2 48
0.0149 0.0149 0.0149 0.0149 0.0149 0.0149 0.0149 0.0149 15.8714 15.8795 0 48
15.8795 15.8876 2 50 15.8876 15.8957 0 50
M4 VALUE 15.8957 15.9038 0 50
0 1 2
3 4
NO.OF DECIMALS:
L.T.L
0.00780
15.860191
U.T.L.
15.84 15.862
NO OF PARTS ABOVE U.T.L =
Interval = Selecting no of classes =
1.10000
Shift Of ' ' from 'D' =
STATISTICAL PROCESS CONTROL STUDY
AGROFAB MACHINERIES ( I ) PVT.LTD W119/120 M.I.D.C HINGNA RIOAD NGP L.COUNT:
APG
1.05000
U.C.L ={ +A2x } L.C.L ={ -A2x } U.C.L ={ x D4}
L.C.L ={ x D3}
15.84261 0.031439 0
0.0401 Specification Width(S) = 0.0221 INTERVAL
NO.OF NON CONFORMING PART =
ALL DIMENSIONS ARE IN INCHES / MM
15.8390 No of readings= 50.0000
PROCESS NEEDS CORRECTION ,Cp & Cpk SHOULD BE >=1.33
Cp=(S/6 σ )=
Cpk={1-K}xCp)=
INSTRUMENT:
SPECIFIC:
OPERATION:
.CYLINDER HEAD
50
MACHINE:
A 0051315D01
0.0001
4
Std.Dev." σ "=
SUPPLIER
15.8510
15.840/15.862
OP67
NOS.
0.0100 0.0010
MINIMUM DECIMAL VALUE 1.0000 0.1000
Index (K)={2 x (D- ) / S}=
0.008100
NO OF PARTS BELOW L.T.L =
8390 15.8471 15.8552 15.8633 15.8714 15.8795 15.8876 15.8957
8309 15.8390 15.8471 15.8552 15.8633 15.8714 15.8795 15.8876
HISTOGRAM
15.83 15.835 15.84 15.845 15.85 15.855 15.86 15.865
1 2 3 4 5 6 7 8 9 10
8 - CHART
A G
0 0.01 0.02 0.03 0.04
2 - CHART
R N G…