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Volume 2009, Article ID 347291, 18 pagesdoi:10.1155/2009/347291 Research Article Inequalities among Eigenvalues of Second-Order Difference Equations with General Coupled Boundary Conditi

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Volume 2009, Article ID 347291, 18 pages

doi:10.1155/2009/347291

Research Article

Inequalities among Eigenvalues of

Second-Order Difference Equations with

General Coupled Boundary Conditions

Chao Zhang and Shurong Sun

School of Science, University of Jinan, Jinan, Shandong 250022, China

Correspondence should be addressed to Chao Zhang,ss zhangc@ujn.edu.cn

Received 11 February 2009; Accepted 11 May 2009

Recommended by Johnny Henderson

This paper studies general coupled boundary value problems for second-order difference equations Existence of eigenvalues is proved, numbers of their eigenvalues are calculated, and their relationships between the eigenvalues of second-order difference equation with three

different coupled boundary conditions are established

Copyrightq 2009 C Zhang and S Sun This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited

1 Introduction

Consider the second-order difference equation

−∇p n Δy n



with the general coupled boundary condition



y N−1

Δy N−1



 e iα K



y−1

Δy−1



where N ≥ 2 is an integer, Δ is the forward difference operator: Δy n  y n1− y n,∇ is the backward difference operator: ∇yn  y n − y n−1, and p n , q n , and w n are real numbers with

p n > 0 for n ∈ −1, N − 1, w n > 0 for n ∈ 0, N − 1, and p−1  p N−1  1; λ is the spectral

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parameter; the interval 0, N − 1 is the integral set {n} N−1

n0; α, −π < α ≤ π is a constant parameter; i√−1,

K



k11 k12

k21 k22



The boundary condition 1.2 contains the periodic and antiperiodic boundary conditions In fact, 1.2 is the periodic boundary condition in the case where α  0 and

K  I, the identity matrix, and 1.2 is the antiperiodic condition in the case where α  π and

K  I.

We first briefly recall some relative existing results of eigenvalue problems for difference equations Atkinson 1, Chapter 6, Section 2 discussed the boundary conditions

when he investigated the recurrence formula

c n y n1a n λ  b n



y n − c n−1y n−1, n ∈ 0, m − 1, 1.5

where a n , b n , c n , α, and β are real numbers, subject to a n > 0, c n > 0, and

He remarked that all the eigenvalues of the boundary value problem1.4 and 1.5 are real,

and they may not be all distinct If c−1  c m−1 and α  β  1, he viewed the boundary

conditions1.4 as the periodic boundary conditions for 1.5 Shi and Chen 2 investigated the more general boundary value problem

−∇C n Δx n  B n x n  λw n x n , n ∈ 1, N, N ≥ 2, 1.7

R



−x0

x N



 S



C0Δx0

C N Δx N



where C n , B n , and w n are d × d Hermitian matrices; C0 and C N are nonsingular; w n > 0 for n ∈ 1, N; R and S are 2d × 2d matrices Moreover, R and S satisfy rankR, S  2d and the self-adjoint condition RS SR∗ 2, Lemma 2.1 A series of spectral results was obtained We will remark that the boundary condition1.8 includes the coupled boundary condition1.2 when d  1, and the boundary conditions 1.4 when 1.6 holds Agarwal and Wong studied existence of minimal and maximal quasisolutions of a second-order nonlinear periodic boundary value problem3, Section 4 In 2005, Wang and Shi 4 considered 1.1 with the periodic and antiperiodic boundary conditions They found out the following results

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see 4, Theorems 2.2 and 3.1 : the periodic and antiperiodic boundary value problems have

exactly N real eigenvalues {λ i}N−1

i0 and{ λ i}N

i1, respectively, which satisfy

λ0< λ1≤ λ2 < λ1≤ λ2< λ3≤ λ4< · · · < λ N−2≤ λ N−1< λ N , if N is odd,

λ0< λ1≤ λ2< λ1≤ λ2 < λ3≤ λ4< · · · < λ N−1≤ λ N < λ N−1, if N is even.

1.9

These results are similar to those about eigenvalues of periodic and antiperiodic boundary value problems for second-order ordinary differential equations cf 5 8

Motivated by4, we compare the eigenvalues of the eigenvalue problem 1.1 with the coupled boundary condition 1.2 as α varies and obtain relationships between the eigenvalues in the present paper These results extend the above results obtained in4 In this paper, we will apply some results obtained by Shi and Chen2 to prove the existence

of eigenvalues of1.1 and 1.2 to calculate the number of these eigenvalues, and to apply some oscillation results obtained by Agarwal et al.9 to compare the eigenvalues as α varies This paper is organized as follows Section 2 gives some preliminaries including existence and numbers of eigenvalues of the coupled boundary value problems, and some properties of eigenvalues of a kind of separated boundary value problem, which will be used in the next section Section 3 pays attention to comparison between the eigenvalues

of problem1.1 and 1.2 as α varies

2 Preliminaries

Equation1.1 can be rewritten as the recurrence formula

p n y n1p n  p n−1 q n − λw n



y n − p n−1y n−1, n ∈ 0, N − 1. 2.1

Clearly, y n is a polynomial in λ with real coefficients since p n , q n , and w nare all real Hence, all the solutions of1.1 are entire functions of λ Especially, if y0/  0, y n is a polynomial of

degree n in λ for n ≤ N However, if y−1/  0 and y0 0, y n is a polynomial of degree n− 1 in

λ for n ≤ N.

We now prepare some results that are useful in the next section The following lemma

is mentioned in4, Theorem 2.1

Lemma 2.1 4, Theorem 2.1 Let y and z be any solutions of 1.1 Then the Wronskian

W y, z

n 

y n1 z n1

p n Δy n p n Δz n

 −p n



y n1z n − y n z n1

2.2

is a constant on −1, N − 1.

Theorem 2.2 If k11/  k12 then the coupled boundary value problem1.1 and 1.2 has exactly N

real eigenvalues.

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Proof By setting d  1, C n  p n , B n  q n,

R  R1, R2 



e iα k11 1

e iα k21 0



, S  S1, S2 



−e iα k12 0

−e iα k22 1



shifting the whole interval1, N left by one unit, and using p−1  p N−1  1, 1.1 and 1.2 are written as1.7 and 1.8 , respectively It is evident that rankR, S  2d and RS∗  SR∗ Hence, the boundary condition1.2 is self-adjoint by 2, Lemma 2.1 In addition, it follows from2.3 and C−1 1 that

R1 S1C−1, S2 



e iα k11− k12 0

e iα k21− k22 1



By noting that k11/  k12, we get rankR1 S1C−1, S2  2 Therefore, by 2, Theorem 4.1, the problem1.1 and 1.2 has exactly N real eigenvalues This completes the proof

Let y n λ be the solution of 1.1 with the initial conditions

Consider the sequence

If y n λ  0 for some n ∈ 0, N − 1 , then, we get from 2.1 that y n−1λ and y n1λ have

opposite signs Hence, we say that sequence2.6 exhibits a change of sign if yn λ y n1λ < 0 for some n ∈ 0, N − 1 , or y n λ  0 for some n ∈ 0, N − 1 A general zero of the sequence

2.6 is defined as its zero or a change of sign

Now we consider1.1 with the following separated boundary conditions:

where k12, k22 are entries of K It follows from 2.1 that the separated boundary value problem1.1 with 2.7 has a unique solution, and the separated boundary value problem will be used to compare the eigenvalues of1.1 and 1.2 as α varies in the next section

In9, Agarwal et al studied the following boundary value problem on time scales:

with the boundary conditions

R a



y : αyρ a  βyΔ

ρ a  0, R b



y : γyb  δyΔb  0, 2.9

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where T is a time scale, σt and ρt are the forward and backward jump operators in T,

yΔ is the delta derivative, and y σ t : yσt ; q : ρa , ρb  ∩ T → R is continuous;

2 β22 δ2 / 0; a, b ∈ T with a < b They obtained some useful oscillation results With

a similar argument to that used in the proof of9, Theorem 1, one can show the following result

Lemma 2.3 The eigenvalues of the boundary value problem are

−p t yΔt  q σ t y σ t  λr σ t y σ t , t ∈ ρ a , ρb ∩ T, 2.10

with

R a



y

 R b



y

where pΔ, q σ , and r σ are real and continuous functions in ρa , ρb  ∩ T, p > 0 over ρa , b ∩

T, r σ > 0 over ρa , ρb  ∩ T, pρa  pb  1 are arranged as −∞ < λ0< λ1 < λ2 < · · · , and

an eigenfunction corresponding to λ k has exactly k generalized zeros in the open interval a, b

By settingρa , b ∩ T  −1, N − 1 : {n} N−1

−1 , α  1, β  0, γ  −k22, δ  k12, the above boundary value problem can be written as1.1 with 2.7 , then we have the following result

Lemma 2.4 The boundary value problem 1.1 and 2.7 has N − 1 real and simple eigenvalues as

k12  0 and N real and simple eigenvalues as k12/  0, which can be arranged in the increasing order

μ0< μ1< · · · < μ N s , where N s: N − 2 or N − 1 2.12

Let y n λ be the solution of 1.1 with the separated boundary conditions 2.7 Then sequence 2.6 exhibits no changes of sign for λ ≤ μ0, exactly k 1 changes of sign for μ k < λ ≤ μ k10 ≤ k ≤ N s −1 , and N s  1 changes of sign for λ > μ N s

Let ϕ n and ψ nbe the solutions of1.1 satisfying the following initial conditions:

respectively ByLemma 2.1and using p N−1 1, we have

Δϕ N−1ψ N−1− ϕ N−1Δψ N−1 ϕ N ψ N−1− ϕ N−1ψ N  −1. 2.14

Obviously, ϕ n λ and ψ n λ are two linearly independent solutions of 1.1 The following

lemma can be derived from4, Proposition 3.1

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Lemma 2.5 Let μ k 0 ≤ k ≤ N s be the eigenvalues of 1.1 and 2.7 with k12 0 and be arranged

as2.12 Then, ψn μ k is an eigenfunction of the problem 1.1 and 2.7 with respect to μ k 0 ≤ k ≤

N s , that is, for 0 ≤ k ≤ N s , ψ n μ k is a nontrivial solution of 1.1 satisfying

ψ−1

μ k



 ψ N−1

μ k



Moreover, if k is odd, ψ N μ k > 0 and if k is even, ψ N μ k < 0 for 2 ≤ k ≤ N s

A representation of solutions for a nonhomogeneous linear equation with initial conditions is given by the following lemma

Lemma 2.6 see 4, Theorem 2.3 For any {fn}N−1

n0 ⊂ C and for any c−1, c0∈ C, the initial value

problem

−∇p n Δz n



q n − λw n



z n  w n f n , n ∈ 0, N − 1,

z−1 c−1, z0 c0

2.16

has a unique solution z, which can be expressed as

z n  c−1ϕ n  c0ψ nn−1

j0

w j



ϕ n ψ j − ϕ j ψ n



where−2

j0· −1

j0· : 0.

3 Main Results

Let ϕ n and ψ nbe defined inSection 2, let μk 0 ≤ k ≤ N s be the eigenvalues of the separated boundary value problem1.1 with 2.7 , and let λj e iα K 0 ≤ j ≤ N − 1 be the eigenvalues

of the coupled boundary value problem1.1 and 1.2 and arranged in the nondecreasing order

λ0

e iα K

≤ λ1



e iα K

≤ · · · ≤ λ N−1



e iα K

Clearly, λ j K 0 ≤ j ≤ N − 1 denotes the eigenvalue of the problem 1.1 and 1.2 with

α  0, and λ j −K 0 ≤ j ≤ N − 1 denotes the eigenvalue of the problem 1.1 and 1.2 with

α  π We now present the main results of this paper.

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Theorem 3.1 Assume that k11 > 0, k12 ≤ 0 or k11 ≥ 0, k12 < 0 Then, for every fixed α /  0,

−π < α < π, one has the following inequalities:

λ0K < λ0



e iα K

< λ0−K ≤ λ1−K < λ1



e iα K

< λ1K

≤ λ2K < λ2



e iα K

< λ2−K

≤ λ3−K < λ3



e iα K

< λ3K

≤ · · · ≤ λ N−2−K < λ N−2



e iα K

< λ N−2K

≤ λ N−1K < λ N−1



e iα K

< λ N−1−K , if N is odd,

λ0K < λ0



e iα K

< λ0−K ≤ λ1−K < λ1



e iα K

< λ1K

≤ λ2K < λ2



e iα K

< λ2−K

≤ λ3−K < λ3



e iα K

< λ3K

≤ · · · ≤ λ N−2K < λ N−2



e iα K

< λ N−2−K

≤ λ N−1−K < λ N−1



e iα K

< λ N−1K , if N is even.

3.2

Remark 3.2 If k11≤ 0, k12> 0 or k11 < 0, k12≥ 0, a similar result can be obtained by applying Theorem 3.1to−K In fact, e iα K  e i πα −K for α ∈ −π, 0 and e iα K  e i −πα −K for α ∈

0, π Hence, the boundary condition 1.2 in the cases of k11 ≤ 0, k12 > 0 or k11 < 0, k12 ≥ 0

and α /  0, −π < α < π, can be written as condition 1.2 , where α is replaced by π  α for

α ∈ −π, 0 and −π  α for α ∈ 0, π , and K is replaced by −K.

Before provingTheorem 3.1, we prove the following five propositions

Proposition 3.3 For λ ∈ C, λ is an eigenvalue of 1.1 and 1.2 if and only if

where

f λ : k22ϕ N−1λ  k11− k12 Δψ N−1λ − k21− k22 ψ N−1λ − k12Δϕ N−1 3.4

Moreover, λ is a multiple eigenvalue of 1.1 and 1.2 if and only if

ϕ N−1λ  e iα k11− k12 , Δϕ N−1λ  e iα k21− k22 ,

ψ N−1λ  e iα k12, Δψ N−1λ  e iα k22.

3.5

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Proof Since ϕ n and ψ nare linearly independent solutions of1.1 , then λ is an eigenvalue of the problem1.1 and 1.2 if and only if there exist two constants C1and C2not both zero

such that C1ϕ n  C2ψ nsatisfies1.2 , which yields



ϕ N−1λ − e iα k11− k12 ψ N−1λ − e iα k12

Δϕ N−1λ − e iα k21− k22 Δψ N−1λ − e iα k22



C1

C2



It is evident that3.6 has a nontrivial solution C1, C2 if and only if

det



ϕ N−1λ − e iα k11− k12 ψ N−1λ − e iα k12

Δϕ N−1λ − e iα k21− k22 Δψ N−1λ − e iα k22



which, together with2.14 and det K  1, implies that

Then3.3 follows from the above relation and the fact that e−iα  e iα  2 cos α On the other

hand,1.1 has two linearly independent solutions satisfying 1.2 if and only if all the entries

of the coefficient matrix of 3.6 are zero Hence, λ is a multiple eigenvalue of 1.1 and 1.2

if and only if3.5 holds This completes the proof

The following result is a direct consequence of the first result ofProposition 3.3

Corollary 3.4 For any α ∈ −π, π,

λ j

e iα K

 λ j



e −iα K

Proposition 3.5 Assume that k11 > 0, k12 ≤ 0 or k11 ≥ 0, k12 < 0 Then one has the following results.

i For each k, 0 ≤ k ≤ N s , f μ k ≥ 2 if k is odd, and fμ k ≤ −2 if k is even.

ii There exists a constant ν0< μ0such that f ν0 ≥ 2.

iii If the boundary value problem 1.1 and 2.7 has exactly N − 1 eigenvalues then there exists a constant ξ0such that μ N−2< ξ0and f ξ0 ≤ −2, where N is odd, and there exists

a constant η0such that μ N−2< η0and f η0 ≥ 2, where N is even.

Proof i If ψ n μ k is an eigenfunction of the problem 1.1 and 2.7 respect to μk then

k12Δψ N−1μ k − k22ψ N−1μ k  0 By Lemma 2.3and the initial conditions2.13 , we have

that if k12< 0 then the sequence ψ0μ k , ψ1μ k , , ψ N−1μ k exhibits k changes of sign and

sgnψ N−1

μ k

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Case 1 If k12< 0 then it follows from k12Δψ N−1μ k − k22ψ N−1μ k  0 that

ψ N−1

μ k

k12  Δψ N−1

μ k

k22

, k11k22ψ N−1

μ k

 k11k12Δψ N−1

μ k

By2.14 and the first relation in 3.11 , for each k, 0 ≤ k ≤ Ns, we have

ϕ N−1

μ k

Δψ N−1

μ k

− Δϕ N−1

μ k

ψ N−1

μ k

 ϕ N−1

μ k k22

k12ψ N−1

μ k



− Δϕ N−1

μ k



ψ N−1

μ k



k22ϕ N−1

μ k



− k12Δϕ N−1

μ k

ψ N−1

μ k

k12  1.

3.12

By the definition of f λ , 3.11 , and det K  1,

k12f

μ k



 k12k22ϕ N−1

μ k



 k12k11− k12 Δψ N−1

μ k



− k12k21− k22 ψ N−1

μ k

− k2

12Δϕ N−1

μ k

 k12k22ϕ N−1

μ k

 k11k12Δψ N−1

μ k

− k12k21ψ N−1

μ k

− k2

12Δϕ N−1

μ k

 k12k22ϕ N−1

μ k

 k11k22ψ N−1

μ k

− k12k21ψ N−1

μ k

− k2

12Δϕ N−1

μ k

 k12k22ϕ N−1

μ k



− k2

12Δϕ N−1

μ k



 ψ N−1

μ k



.

3.13

Hence,

f

μ k



k22ϕ N−1

μ k



− k12Δϕ N−1

μ k



ψ N−1



μ k

Notingk22ϕ N−1μ k − k12Δϕ N−1μ k ψ N−1μ k /k12  1, k12 < 0, and3.10 , we have that if

k is odd then

f

μ k







ψ N−1

μ k

k12 −k22ϕ N−1

μ k



− k12Δϕ N−1

μ k

⎞⎠2

 2 ≥ 2, 3.15

and if k is even then

f

μ k

 −



ψ N−1

μ k

k12 −−k22ϕ N−1

μ k

− k12Δϕ N−1

μ k⎞⎠2

− 2 ≤ −2. 3.16

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Case 2 If k12 0 then it follows from 2.7 and 2.14 that for each k, 0 ≤ k ≤ Ns,

ϕ N−1

μ k



ψ N



μ k



From2.15 and by the definition of fλ , we get

f

μ k

 k22

ψ N



μ k

  k11ψ N

μ k

Hence, noting det K  k11k22  1, k11> 0, and byLemma 2.5, we have that if k is odd, then

f

μ k

and if k is even, then

f

μ k

ii By the discussions in the first paragraph ofSection 2, ϕN−1λ is a polynomial of degree N − 2 in λ, ϕ N λ is a polynomial of degree N − 1 in λ, ψ N−1λ is a polynomial of degree N − 1 in λ, and ψ N λ is a polynomial of degree N in λ Further, ψ N λ can be written

as

ψ N λ  −1 N A N λ N  A N−1λ N−1 · · ·  A0, 3.21

where A N  w0w1· · · w N−1p0p1· · · p N−1 −1> 0 and A n is a certain constant for n ∈ 0, N − 1.

Then

f λ  −1 N k11− k12 A N λ N  hλ , 3.22

where hλ is a polynomial in λ whose degree is not larger than N − 1 Clearly, as λ → −∞,

f λ → ∞ since k11 − k12 > 0 By the first part of this proposition, fμ0 ≤ −2 So there

exists a constant ν0< μ0such that fν0 ≥ 2

iii It follows from the first part of this proposition that if N is odd, fμ N−2 ≥ 2 and

if N is even, fμ N−2 ≤ −2 By 3.22 , if N is odd, fλ → −∞ as λ → ∞; if N is even,

f λ → ∞ as λ → ∞ Hence, if N is odd, there exists a constant ξ0 > μ N−2 such that

f ξ0 ≤ −2; if N is even, there exists a constant η0 > μ N−2such that fη0 ≥ 2 This completes the proof

Since ϕ n and ψ n are both polynomials in λ, so is fλ Denote

d

dλ f λ : f λ , d2

... coupled boundary value problem1.1 and 1.2 has exactly N

real eigenvalues.

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Proof... be the eigenvalues of the separated boundary value problem1.1 with 2.7 , and let λj e iα K 0 ≤ j ≤ N − be the eigenvalues< /i>

of the coupled boundary. ..

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Proof Since ϕ n and ψ nare linearly independent solutions of 1.1 ,

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