Volume 2009, Article ID 362983, 16 pagesdoi:10.1155/2009/362983 Research Article Existence and Uniqueness of Solutions for Higher-Order Three-Point Boundary Value Problems 1 Department o
Trang 1Volume 2009, Article ID 362983, 16 pages
doi:10.1155/2009/362983
Research Article
Existence and Uniqueness of
Solutions for Higher-Order Three-Point
Boundary Value Problems
1 Department of Mathematics, Bei Hua University, JiLin 132013, China
2 Department of Mathematics, Yeungnam University, Kyongsan 712-749, South Korea
Correspondence should be addressed to Sung Kag Chang,skchang@ynu.ac.kr
Received 5 February 2009; Accepted 14 July 2009
Recommended by Kanishka Perera
We are concerned with the higher-order nonlinear three-point boundary value problems: x n
f t, x, x, , x n−1 , n ≥ 3, with the three point boundary conditions gxa, xa, , x n−1 a 0; x i b μ i, i 0, 1, , n − 3; hxc, xc, , x n−1 c 0, where a < b < c, f : a, c ×Rn →
R −∞, ∞ is continuous, g, h : R n → R are continuous, andμ i ∈ R, i 0, 1, , n − 3 are
arbitrary given constants The existence and uniqueness results are obtained by using the method
of upper and lower solutions together with Leray-Schauder degree theory We give two examples
to demonstrate our result
Copyrightq 2009 M Pei and S K Chang This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited
1 Introduction
Higher-order boundary value problems were discussed in many papers in recent years; for
the above-mentioned references are for two-point boundary conditions2 11,14,17–22, and
nonlinear three point boundary conditions are quite rare in literatures
The purpose of this article is to study the existence and uniqueness of solutions for higher order nonlinear three point boundary value problem
x n ft, x, x, , x n−1
Trang 2with nonlinear three point boundary conditions
g
x a, xa, , x n−1 a 0,
x i b μ i , i 0, 1, , n − 3,
h
x c, xc, , x n−1 c 0,
1.2
where a < b < c, f : a, c × R n → R −∞, ∞ is a continuous function, g, h : R n → R are
continuous functions, and μ i ∈ R, i 0, 1, , n − 3 are arbitrary given constants The tools we
mainly used are the method of upper and lower solutions and Leray-Schauder degree theory
Note that for the cases of a b or b c in the boundary conditions 1.2, our theorems hold also true However, for brevity we exclude such cases in this paper
2 Preliminary
In this section, we present some definitions and lemmas that are needed to our main results
Definition 2.1 α t, βt ∈ C n a, c are called lower and upper solutions of BVP 1.1, 1.2, respectively, if
α n t ≥ ft, α t, αt, , α n−1 t, t ∈ a, c,
g
α a, αa, , α n−1 a≤ 0,
α i b ≤ μ i , i 0, 1, , n − 3,
h
α c, αc, , α n−1 c≤ 0,
β n t ≤ ft, β t, βt, , β n−1 t, t ∈ a, c,
g
β a, βa, , β n−1 a≥ 0,
β i b ≥ μ i , i 0, 1, , n − 3,
h
β c, βc, , β n−1 c≥ 0.
2.1
Definition 2.2 Let E be a subset of a, c × R n We say that ft, x0 , x1, , x n−1 satisfies the
f t, x0 , x1, , x n−1 ≤ φ|xn−1|, t, x0, x1, , x n−1 ∈ E,
∞
0
sds
2.2
Lemma 2.3 see 10 Let f : a, c × R n → R be a continuous function satisfying the Nagumo
condition on
Et, x0 , x1, , x n−1 ∈ a, c × Rn : γ i t ≤ x i≤ Γi t, i 0, 1, , n − 2 , 2.3
Trang 3where γ i t, Γ i t : a, c → R are continuous functions such that
Then there exists a constant r > 0 (depending only on γ n−2t, Γ n−2t and φt such that every
solution x t of 1.1 with
satisfies x n−1∞≤ r.
Lemma 2.4 Let φ : 0, ∞ → 0, ∞ be a continuous function Then boundary value problem
x n−2 a x i b x n−2 c 0, i 0, 1, , n − 3 2.7
has only the trivial solution.
Proof Suppose that x0t is a nontrivial solution of BVP 2.6, 2.7 Then there exists t0 ∈
a, c such that x n−20 t0 > 0 or x n−20 t0 < 0 We may assume x n−20 t0 > 0 There exists
t1∈ a, c such that
max
Then x n−10 t1 0, x n0 t1 ≤ 0 From 2.6 we have
0≥ x0n t1 x n−20 t1φx n−1
0 t1
> 0, 2.9 which is a contradiction Hence BVP2.6, 2.7 has only the trivial solution
3 Main Results
We may now formulate and prove our main results on the existence and uniqueness of
solutions for nth-order three point boundary value problem1.1, 1.2
Theorem 3.1 Assume that
i there exist lower and upper solutions αt, βt of BVP 1.1, 1.2, respectively, such that
−1n −i α i t ≤ −1 n −i β i t, t ∈ a, b, i 0, 1, , n − 2,
Trang 4ii ft, x0 , , x n−1 is continuous on a, c×Rn ,−1n −i f t, x0 , , x n−1 is nonincreasing in
x i i 0, 1, , n−3 on D b
a , and f t, x0 , , x n−1 is nonincreasing in x i i 0, 1, , n−
3 on Dc
b and satisfies the Nagumo condition on D c
a , where
ϕ i t minα i t, β i t , ψ i t maxα i t, β i t , i 0, , n − 2,
D b
at, x0 , , x n−1 ∈ a, b × Rn : ϕ i t ≤ x i ≤ ψ i t, i 0, , n − 2 ,
D c
b t, x0 , , x n−1 ∈ b, c × Rn : ϕ i t ≤ x i ≤ ψ i t, i 0, , n − 2 ,
D c
at, x0 , , x n−1 ∈ a, c × R n : ϕ i t ≤ x i ≤ ψ i t, i 0, , n − 2 ;
3.2
iii gx0 , x1, , x n−1 is continuous on Rn , and−1n −i g x0 , x1, , x n−1 is nonincreasing
in x i i 0, 1, , n − 3 and nondecreasing in x n−1on n i0−2ϕ i a, ψ i a × R;
iv hx0 , x1, , x n−1 is continuous on Rn , and nonincreasing in x i i 0, 1, , n − 3 and
nondecreasing in x n−1on n i0−2ϕ i c, ψ i c × R.
Then BVP1.1, 1.2 has at least one solution xt ∈ C n a, c such that for each i 0, 1, , n − 2,
−1n −i α i t ≤ −1 n −i x i t ≤ −1 n −i β i t, t ∈ a, b,
Proof For each i 0, 1, , n − 2 define
w i t, x
⎧
⎪
⎨
⎪
⎩
ψ i t, x > ψ i t,
x, ϕ i t ≤ x ≤ ψ i t,
ϕ i t, x < ϕ i t,
3.4
where ϕ i t min{α i t, β i t}, ψ i t max{α i t, β i t}.
x n t λft, w0t, xt, , wn−2
t, x n−2 t, x n−1 t
x n−2 t − λw n−2
t, x n−2 tφx n−1 t
,
3.5
where φ is given by the Nagumo condition, with the boundary conditions
x n−2 a λw n−2
a, x n−2 a− gw0a, xa, , wn−2
a, x n−2 a, x n−1 a,
x i b λμ i , i 0, 1, , n − 3,
x n−2 c λw n−2
c, x n−2 c− hw0c, xc, , wn−2
c, x n−2 c, x n−1 c.
3.6
Trang 5Then we can choose a constant M n−2> 0 such that
−M n−2< α n−2 t ≤ β n−2 t < M n−2, t ∈ a, c, 3.7
f
t, α t, , α n−2 t, 0−M n−2 α n−2 tφ 0 < 0, t ∈ a, c,
f
t, β t, , β n−2 t, 0M n−2− β n−2 tφ 0 > 0, t ∈ a, c, 3.8
α n−2 a − gα a, , α n−2 a, 0 < M
n−2,
β n−2 a − gβ a, , β n−2 a, 0 < M
n−2,
3.9
α n−2 c − hα c, , α n−2 c, 0 < M
n−2,
β n−2 c − hβ c, , β n−2 c, 0 < M
n−2.
3.10
In the following, we will complete the proof in four steps
Step 1 Show that every solution x t of BVP 3.5, 3.6 satisfies
x n−2 t < M
Suppose that the estimate|x n−2 t| < M n−2is not true Then there exists t0 ∈ a, c such that x n−2 t0 ≥ M n−2or x n−2 t0 ≤ −M n−2 We may assume x n−2 t0 ≥ M n−2 There
exists t1 ∈ a, c such that
max
There are three cases to consider
Case 1 t1 ∈ a, c In this case, x n−1 t1 0 and x n t1 ≤ 0 For λ ∈ 0, 1, by 3.8, we get the following contradiction:
0≥ x n t1
λft1, w0t1, x t1, , w n−2
t1, x n−2 t1, x n−1 t1
x n−2 t1 − λw n−2
t1, x n−2 t1φx n−1 t1
λft1, w0t1, x t1, , w n−3
t1, x n−3 t1, β n−2 t1, 0
x n−2 t1 − λβ n−2 t1φ0
≥ λf
t1, β t1, , β n−2 t1, 0M n−2− β n−2 t1φ0> 0,
3.13
Trang 6and for λ 0, we have the following contradiction:
Case 2 t1 a In this case,
max
and x n−1 a ≤ 0 For λ 0, by 3.6 we have the following contradiction:
For λ ∈ 0, 1, by 3.9 and condition iii we can get the following contradiction:
M n−2≤ x n−2 a,
λw n−2
a, x n−2 a− gw0a, xa, , wn−2
a, x n−2 a, x n−1 a,
≤ λβ n−2 a − gβ a, , β n−2 a, 0< M n−2.
3.17
Case 3 t1 c In this case,
max
and x n−1 c ≥ 0 For λ 0, by 3.6 we have the following contradiction:
For λ ∈ 0, 1, by 3.10 and condition iv we can get the following contradiction:
M n−2≤ x n−2 c,
λw n−2
c, x n−2 c− hw0c, xc, , wn−2
c, x n−2 c, x n−1 c
≤ λβ n−2 c − hβ c, , β n−2 c, 0< M n−2.
3.20
By3.6, the estimates
x i t < M
i: c − aM i1μ i, i 0, 1, , n − 3, t ∈ a, c 3.21 are obtained by integration
Trang 7Step 2 Show that there exists M n−1 > 0 such that every solution x t of BVP 3.5, 3.6 satisfies
x n−1 t < M
Let
E {t, x0 , , x n−1 ∈ a, c × R n:|x i | ≤ M i , i 0, 1, , n − 2}, 3.23
and define the function F λ:a, c × R n → R as follows:
F λ t, x0 , , x n−1 λft, w0t, x0, , w n−2t, x n−2, x n−1
In the following, we show that F λ t, x0 , , x n−1 satisfies the Nagumo condition on E,
|F λ t, x0 , , x n−1| λf t, w0t, x0, , w n−2t, xn−2, xn−1
x n−2− λw n−2t, xn−2φ|xn−1|
≤ 1 2M n−2φ|x n−1| : φ E |x n−1|.
3.25
Furthermore, we obtain
∞
0
s
φ E s ds
∞
0
s
ByStep 1andLemma 2.3, there exists M n−1> 0 such that |x n−1 t| < M n−1for t ∈ a, c Since
M n−2and φ E do not depend on λ, the estimate |x n−1 t| < M n−1ona, c is also independent
of λ.
Step 3 Show that for λ 1, BVP 3.5, 3.6 has at least one solution x1t.
Define the operators as follows:
L : C n a, c ⊂ C n−1a, c −→ Ca, c × R n , 3.28
Trang 8Lxx n t, x n−2 a, xb, , x n−3 b, x n−2 c,
by
N λ xF λ
t, x t, , x n−1 t, A λ , λμ0, , λμ n−3, C λ
with
A λ: λw n−2
a, x n−2 a− gw0a, xa, , wn−2
a, x n−2 a, x n−1 a
C λ: λw n−2
c, x n−2 c− hw0c, xc, , wn−2
c, x n−2 c, x n−1 c. 3.31
defined by
Consider the setΩ {x ∈ C n−1a, c : x i∞< M i , i 0, 1, , n − 1}.
By Steps1and2, the degree degI − Tλ , Ω, 0 is well defined for every λ ∈ 0, 1, and
by homotopy invariance, we get
theory we have
x n t ft, w0t, xt, , wn−2
t, x n−2 t, x n−1 t
x n−2 t − w n−2
t, x n−2 tφx n−1 t
,
3.36
Trang 9with the boundary conditions
x n−2 a w n−2
a, x n−2 a− gw0a, xa, , wn−2
a, x n−2 a, x n−1 a,
x i b μ i , i 0, 1, , n − 3,
x n−2 c w n−2
c, x n−2 c− hw0c, xc, , wn−2
c, x n−2 c, x n−1 c,
3.37
has at least one solution x1t in Ω.
Step 4 Show that x1t is a solution of BVP 1.1, 1.2
In fact, the solution x1t of BVP 3.36, 3.37 will be a solution of BVP 1.1, 1.2, if it satisfies
ϕ i t ≤ x1i t ≤ ψ i t, i 0, 1, , n − 2, t ∈ a, c. 3.38
By contradiction, suppose that there exists t0 ∈ a, c such that x1n−2 t0 > ψ n−2t0 There exists t1 ∈ a, c such that
max
t ∈a,c
x1n−2 t − ψ n−2t: xn−21 t1 − ψ n−2t1 > 0. 3.39
Now there are three cases to consider
Case 1 t1 ∈ a, c In this case, since ψ n−2t β n−2 t on a, c, we have x1n−1 t1 β n−1 t1 and x n1 t1 ≤ β n t1 By conditions i and ii, we get the following contradiction:
0≥ x1n t1 − β n t1
≥ ft1, w0t1, x1t1, , wn−2
t1, x n−21 t1, x n−11 t1
x n−21 t1 − w n−2
t1, x1n−2 t1φx n−1
1 t1
− ft1, β t1, , β n−1 t1
≥ ft1, β t1, , β n−1 t1x n−21 t1 − β n−2 t1φx n−1
1 t1
− ft1, β t1, · · · , β n−1 t1
x n−21 t1 − β n−2 t1φx n−1
1 t1
> 0.
3.40
Case 2 t1 a In this case, we have
max
t ∈a,c
x n−21 t − ψ n−2t: xn−21 a − β n−2 a > 0, 3.41
Trang 10and x n−11 a ≤ β n−1 a By 3.37 and conditions i and iii we can get the following contradiction:
β n−2 a < x n−21 a,
w n−2
a, x n−21 a− gw0a, x1a, , wn−2
a, x n−21 a, x n−11 a
≤ β n−2 a − gβ a, , β n−2 a, β n−1 a≤ β n−2 a.
3.42
Case 3 t1 c In this case, we have
max
t ∈a,c
x n−21 t − ψ n−2t: xn−21 c − β n−2 c > 0, 3.43
and x n−11 c ≥ β n−1 c By 3.37 and conditions i and iv we can get the following contradiction:
β n−2 c < x n−21 c
w n−2
c, x n−21 c− hw0c, x1c, , wn−2
c, x n−21 c, x n−11 c
≤ β n−2 c − hβ c, , β n−2 c, β n−1 c≤ β n−2 c.
3.44
Similarly, we can show that ϕ n−2t ≤ xn−21 t on a, c Hence
α n−2 t ϕ n−2t ≤ x n−21 t ≤ ψ n−2t β n−2 t, t ∈ a, c. 3.45
α i b x i1 b β i b, i n − 1 − 2j, j 1, 2, ,
n− 1 2
,
α i b ≤ x i1 b ≤ β i b, i n − 2 − 2j, j 1, 2, ,
n− 2 2
.
3.46
Therefore by integration we have for each i 0, 1, , n − 2,
−1n −i α i t ≤ −1 n −i x i1 t ≤ −1 n −i β i t, t ∈ a, b,
Trang 11that is,
ϕ i t ≤ x1i t ≤ ψ i t, i 0, 1, , n − 2, t ∈ a, c. 3.48
Hence x1t is a solution of BVP 1.1, 1.2 and satisfies 3.3
Now we give a uniqueness theorem by assuming additionally the differentiability for
Theorem 3.2 Assume that
i there exist lower and upper solutions αt, βt of BVP 1.1, 1.2, respectively, such that
−1n −i α i t ≤ −1 n −i β i t, t ∈ a, b, i 0, 1, , n − 2,
ii ft, x0 , , x n−1 and its first-order partial derivatives in xi i 0, 1, , n − 1 are
continuous on a, c × R n ,−1n −i ∂f/∂x i ≤ 0 i 0, 1, , n − 3 on D b
a , ∂f/∂x i ≤
0 i 0, 1, , n − 3 on D c
b and satisfy the Nagumo condition on D c
a;
iii gx0 , x1, , x n−1 is continuous on Rn and continuously partially differentiable on
n−2
i0ϕ i a, ψ i a × R, and
−1n −i ∂g
∂x i ≤ 0, i 0, 1, , n − 3,
∂g
∂x n−1 ≤ 0, onn−2
i0
ϕ i a, ψ i a× R;
3.50
iv hx0 , x1, , x n−1 is continuous on Rn and continuously partially differentiable on
n−2
i0ϕ i c, ψ i c × R, and
∂h
∂x i ≤ 0, i 0, 1, , n − 3,
∂h
∂x n−1 ≥ 0, onn−2
i0
ϕ i c, ψ i c× R;
3.51
Trang 12v there exists a function γt ∈ C n a, c such that γ n−2 t > 0 on a, c, and
γ n t < n−1
i0
∂f
∂x i · γ i t, on D c
a
n−1
i0
∂g
∂x i · γ i a > 0, onn−2
i0
ϕ i a, ψ i a× R,
n−1
i0
∂h
∂x i · γ i c > 0, onn−2
i0
ϕ i c, ψ i c× R,
γ i b 0, if n − i : odd, i 0, 1, , n − 3,
γ i b ≥ 0, if n − i : even, i 0, 1, , n − 3.
3.52
Then BVP1.1, 1.2 has a unique solution xt satisfying 3.3.
Proof The existence of a solution for BVP 1.1, 1.2 satisfying 3.3 follows from
Theorem 3.1
Now, we prove the uniqueness of solution for BVP1.1, 1.2 To do this, we let x1t and x2t are any two solutions of BVP 1.1, 1.2 satisfying 3.3 Let zt x2t − x1t It
is easy to show that zt is a solution of the following boundary value problem
z n t n−1
i0
n−1
i0
a i z i a 0, n−1
i0
where for each i 0, 1, , n − 1,
d i t
1
0
∂
∂x i
f
t, x1t θzt, x
1t θzt, , x n−11 t θz n−1 tdθ,
a i
1
0
∂
∂x i
g
x1a θza, x
1a θza, , x n−11 a θz n−1 adθ,
c i
1
0
∂
∂x i
h
x1c θzc, x
1c θzc, , x n−11 c θz n−1 cdθ.
3.56