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Tiêu đề Ampére’s Circuital Law
Tác giả Nannapaneni Narayana Rao, Edward C. Jordan
Người hướng dẫn Distinguished Amrita Professor of Engineering
Trường học University of Illinois at Urbana-Champaign
Chuyên ngành Electrical and Computer Engineering
Thể loại Slide Presentations
Thành phố Urbana
Định dạng
Số trang 14
Dung lượng 291 KB

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No Slide Title Slide Presentations for ECE 329, Introduction to Electromagnetic Fields, to supplement “Elements of Engineering Electromagnetics, Sixth Edition” by Nannapaneni Narayana Rao Edward C Jor[.]

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Introduction to Electromagnetic Fields,

to supplement “Elements of Engineering

Electromagnetics, Sixth Edition”

by

Nannapaneni Narayana Rao

Edward C Jordan Professor of Electrical and Computer Engineering

University of Illinois at Urbana-Champaign, Urbana, Illinois, USA

Distinguished Amrita Professor of Engineering Amrita Vishwa Vidyapeetham, Coimbatore, Tamil Nadu, India

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Ampére’s Circuital Law

Trang 3

Ampére’s Circuital Law

H • dl 

C

dt

S

dS

S C

J, D

Trang 4

 A m m, or A  

H • dl

C

J • dS

S

D • dS

S

= Magnetomotive force (only by analogy with electromotive

force),

= Current due to flow of charges

crossing S,

= Displacement flux, or electric

flux, crossing S,

C m2  m , or C.2

Amp m2  m , or A 2

Trang 5

dtS D •dS = Time rate of increase of

displacement flux crossing S,

or, displacement current

crossing S,

C s, or A

Right-hand screw rule

Any surface S bounded by C, but the same surface

for both terms on the right side

Trang 6

(a) Infinitely long, current carrying wire

No displacement flux

J • dS 

S1

2

H • dl I

C

To  From 

S1

S2

Trang 7

S1

S2 I(t)

J • dS =

S1

I but S J • dS =

2

D • dS =

S1

 0 but S D • dS 

2

d

dtS2 D • dS must be I

so that H • dlC is unique

(b) Capacitor circuit (neglect fringing of field

in the capacitor)

Trang 8

I C

S1

S2

(c) Finitely long wire

J • dS I and

S1

1

J • dS 0 and

S2

2

J • dS  d

dt

S1

D • dS must be S

1

J • dS  d

dt

S2

2

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Uniqueness of C H • dl

2

S1

rubber band

potato

H • dl  J • dS1  d

dt

S1

C

1

H • dl – J • dS2 – d

dt

S2

C

2

 J • dS1  d

dt

S1

dt

S2

2

S1

d

dtS1D • dS1  d

dtS2 D • dS2 – S J • dS1

1

2

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dtSS1S2 D • dS –SS1S2 J • dS

Displacement current emanating from a closed surface = – (current due to flow of charges

emanating from the same closed surface)

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23

23 23

0

3

S

d

dt

D S

Q 2

Q 3

Q 1

3I

S 2

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spherical surface of radius 0.1 m and centered at Q1

(c) Displacement current emanating from the spherical

surface of radius 0.1 m and centered at Q3.

3

3

23

23

3 3 3 6

S

S

d

dt

dt

    

D S

D S

1

1

4

S

S

d

dt

dt



D S

D S

Trang 13

E • dl = –

C

dt dS B • dS

H • dl =

C

dt

S

Magnetic Fields

Trang 14

Hertzian Dipole

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