Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING ISBN 0-521-43108-5independently random sequences of these characters a conservative, but not always realistic ass
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k=ij[k][ip[(c+2) % 10][7 & m++]];
}
for (j=0;j<=9;j++) Find which appended digit will check properly.
if (!ij[k][ip[j][m & 7]]) break;
return k==0;
}
CITED REFERENCES AND FURTHER READING:
McNamara, J.E 1982, Technical Aspects of Data Communication , 2nd ed (Bedford, MA: Digital
Press) [1]
da Cruz, F 1987, Kermit, A File Transfer Protocol (Bedford, MA: Digital Press) [2]
Morse, G 1986, Byte , vol 11, pp 115–124 (September) [3]
LeVan, J 1987, Byte , vol 12, pp 339–341 (November) [4]
Sarwate, D.V 1988, Communications of the ACM , vol 31, pp 1008–1013 [5]
Griffiths, G., and Stones, G.C 1987, Communications of the ACM , vol 30, pp 617–620 [6]
Wagner, N.R., and Putter, P.S 1989, Communications of the ACM , vol 32, pp 106–110 [7]
20.4 Huffman Coding and Compression of Data
A lossless data compression algorithm takes a string of symbols (typically
ASCII characters or bytes) and translates it reversibly into another string, one that
is on the average of shorter length The words “on the average” are crucial; it
is obvious that no reversible algorithm can make all strings shorter — there just
aren’t enough short strings to be in one-to-one correspondence with longer strings
Compression algorithms are possible only when, on the input side, some strings, or
some input symbols, are more common than others These can then be encoded in
fewer bits than rarer input strings or symbols, giving a net average gain
There exist many, quite different, compression techniques, corresponding to
different ways of detecting and using departures from equiprobability in input strings
In this section and the next we shall consider only variable length codes with defined
word inputs. In these, the input is sliced into fixed units, for example ASCII
characters, while the corresponding output comes in chunks of variable size The
simplest such method is Huffman coding[1], discussed in this section Another
example, arithmetic compression, is discussed in§20.5
At the opposite extreme from defined-word, variable length codes are schemes
that divide up the input into units of variable length (words or phrases of English text,
for example) and then transmit these, often with a fixed-length output code The most
widely used code of this type is the Ziv-Lempel code[2] References[3-6] give the
flavor of some other compression techniques, with references to the large literature
The idea behind Huffman coding is simply to use shorter bit patterns for more
common characters We can make this idea quantitative by considering the concept
of entropy Suppose the input alphabet has N ch characters, and that these occur in
the input string with respective probabilities p i , i = 1, , N ch, so thatP
p i = 1
Then the fundamental theorem of information theory says that strings consisting of
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independently random sequences of these characters (a conservative, but not always
realistic assumption) require, on the average, at least
H =−Xp ilog2p i (20.4.1)
bits per character Here H is the entropy of the probability distribution Moreover,
coding schemes exist which approach the bound arbitrarily closely For the case of
equiprobable characters, with all p i = 1/N ch , one easily sees that H = log2N ch,
which is the case of no compression at all Any other set of p i’s gives a smaller
entropy, allowing some useful compression
Notice that the bound of (20.4.1) would be achieved if we could encode character
i with a code of length L i =− log2p i bits: Equation (20.4.1) would then be the
averageP
p i L i The trouble with such a scheme is that− log2p iis not generally
an integer How can we encode the letter “Q” in 5.32 bits? Huffman coding makes
a stab at this by, in effect, approximating all the probabilities p iby integer powers
of 1/2, so that all the L i ’s are integral If all the p i’s are in fact of this form, then a
Huffman code does achieve the entropy bound H.
The construction of a Huffman code is best illustrated by example Imagine
a language, Vowellish, with the N ch = 5 character alphabet A, E, I, O, and U,
occurring with the respective probabilities 0.12, 0.42, 0.09, 0.30, and 0.07 Then the
construction of a Huffman code for Vowellish is accomplished in the following table:
Here is how it works, proceeding in sequence through N chstages, represented
by the columns of the table The first stage starts with N ch nodes, one for each
letter of the alphabet, containing their respective relative frequencies At each stage,
the two smallest probabilities are found, summed to make a new node, and then
dropped from the list of active nodes (A “block” denotes the stage where a node is
dropped.) All active nodes (including the new composite) are then carried over to
the next stage (column) In the table, the names assigned to new nodes (e.g., AUI)
are inconsequential In the example shown, it happens that (after stage 1) the two
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E EAUIO
A
U
AUI AUIO
UI
I O
1.00
0.58
0.09
5
0.16 6
0.12
0.42 2
9
8
1
1 0
1 0
1 0
1 0
Figure 20.4.1 Huffman code for the fictitious language Vowellish, in tree form A letter (A, E, I,
O, or U) is encoded or decoded by traversing the tree from the top down; the code is the sequence of
0’s and 1’s on the branches The value to the right of each node is its probability; to the left, its node
number in the accompanying table.
smallest nodes are always an original node and a composite one; this need not be
true in general: The two smallest probabilities might be both original nodes, or both
composites, or one of each At the last stage, all nodes will have been collected into
one grand composite of total probability 1
Now, to see the code, you redraw the data in the above table as a tree (Figure
20.4.1) As shown, each node of the tree corresponds to a node (row) in the table,
indicated by the integer to its left and probability value to its right Terminal nodes,
so called, are shown as circles; these are single alphabetic characters The branches
of the tree are labeled 0 and 1 The code for a character is the sequence of zeros and
ones that lead to it, from the top down For example, E is simply 0, while U is 1010
Any string of zeros and ones can now be decoded into an alphabetic sequence
Consider, for example, the string 1011111010 Starting at the top of the tree we
descend through 1011 to I, the first character Since we have reached a terminal
node, we reset to the top of the tree, next descending through 11 to O Finally 1010
gives U The string thus decodes to IOU
These ideas are embodied in the following routines Input to the first routine
hufmak is an integer vector of the frequency of occurrence of the nchin ≡ N ch
alphabetic characters, i.e., a set of integers proportional to the p i’s hufmak, along
with hufapp, which it calls, performs the construction of the above table, and also the
tree of Figure 20.4.1 The routine utilizes a heap structure (see§8.3) for efficiency;
for a detailed description, see Sedgewick[7]
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#include "nrutil.h"
typedef struct {
unsigned long *icod,*ncod,*left,*right,nch,nodemax;
} huffcode;
void hufmak(unsigned long nfreq[], unsigned long nchin, unsigned long *ilong,
unsigned long *nlong, huffcode *hcode)
Given the frequency of occurrence tablenfreq[1 nchin]ofnchincharacters, construct the
Huffman code in the structurehcode Returned valuesilongandnlongare the character
number that produced the longest code symbol, and the length of that symbol You should
check thatnlongis not larger than your machine’s word length.
{
void hufapp(unsigned long index[], unsigned long nprob[], unsigned long n,
unsigned long i);
int ibit;
long node,*up;
unsigned long j,k,*index,n,nused,*nprob;
static unsigned long setbit[32]={0x1L,0x2L,0x4L,0x8L,0x10L,0x20L,
0x40L,0x80L,0x100L,0x200L,0x400L,0x800L,0x1000L,0x2000L,
0x4000L,0x8000L,0x10000L,0x20000L,0x40000L,0x80000L,0x100000L,
0x200000L,0x400000L,0x800000L,0x1000000L,0x2000000L,0x4000000L,
0x8000000L,0x10000000L,0x20000000L,0x40000000L,0x80000000L};
index=lvector(1,(long)(2*hcode->nch-1));
up=(long *)lvector(1,(long)(2*hcode->nch-1)); Vector that will keep track of
heap.
nprob=lvector(1,(long)(2*hcode->nch-1));
for (nused=0,j=1;j<=hcode->nch;j++) {
nprob[j]=nfreq[j];
hcode->icod[j]=hcode->ncod[j]=0;
if (nfreq[j]) index[++nused]=j;
}
for (j=nused;j>=1;j ) hufapp(index,nprob,nused,j);
Sort nprob into a heap structure in index.
k=hcode->nch;
the heap at each stage.
node=index[1];
index[1]=index[nused ];
hufapp(index,nprob,nused,1);
nprob[++k]=nprob[index[1]]+nprob[node];
hcode->left[k]=node; Store left and right children of a
node.
hcode->right[k]=index[1];
up[index[1]] = -(long)k; Indicate whether a node is a left
or right child of its parent.
up[node]=index[1]=k;
hufapp(index,nprob,nused,1);
}
up[hcode->nodemax=k]=0;
for (j=1;j<=hcode->nch;j++) { Make the Huffman code from
the tree.
if (nprob[j]) {
for (n=0,ibit=0,node=up[j];node;node=up[node],ibit++) {
if (node < 0) {
n |= setbit[ibit];
node = -node;
}
}
hcode->icod[j]=n;
hcode->ncod[j]=ibit;
}
}
*nlong=0;
for (j=1;j<=hcode->nch;j++) {
if (hcode->ncod[j] > *nlong) {
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*ilong=j-1;
}
}
free_lvector(nprob,1,(long)(2*hcode->nch-1));
free_lvector((unsigned long *)up,1,(long)(2*hcode->nch-1));
free_lvector(index,1,(long)(2*hcode->nch-1));
}
void hufapp(unsigned long index[], unsigned long nprob[], unsigned long n,
unsigned long i)
Used byhufmakto maintain a heap structure in the arrayindex[1 l].
{
unsigned long j,k;
k=index[i];
while (i <= (n>>1)) {
if ((j = i << 1) < n && nprob[index[j]] > nprob[index[j+1]]) j++;
if (nprob[k] <= nprob[index[j]]) break;
index[i]=index[j];
i=j;
}
index[i]=k;
}
Note that the structure hcode must be defined and allocated in your main
program with statements like this:
#include "nrutil.h"
#define MC 512 Maximum anticipated value of nchin in hufmak.
#define MQ (2*MC-1)
typedef struct {
unsigned long *icod,*ncod,*left,*right,nch,nodemax;
} huffcode;
huffcode hcode;
hcode.icod=(unsigned long *)lvector(1,MQ); Allocate space within hcode.
hcode.ncod=(unsigned long *)lvector(1,MQ);
hcode.left=(unsigned long *)lvector(1,MQ);
hcode.right=(unsigned long *)lvector(1,MQ);
for (j=1;j<=MQ;j++) hcode.icod[j]=hcode.ncod[j]=0;
Once the code is constructed, one encodes a string of characters by repeated calls
to hufenc, which simply does a table lookup of the code and appends it to the
output message
#include <stdio.h>
#include <stdlib.h>
typedef struct {
unsigned long *icod,*ncod,*left,*right,nch,nodemax;
} huffcode;
void hufenc(unsigned long ich, unsigned char **codep, unsigned long *lcode,
unsigned long *nb, huffcode *hcode)
Huffman encode the single character ich (in the range 0 nch-1) using the code in the
structure hcode, write the result to the character array*codep[1 lcode]starting at bit
nb(whose smallest valid value is zero), and incrementnbappropriately This routine is called
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repeatedly to encode consecutive characters in a message, but must be preceded by a single
initializing call tohufmak, which constructshcode.
{
void nrerror(char error_text[]);
int l,n;
unsigned long k,nc;
static unsigned long setbit[32]={0x1L,0x2L,0x4L,0x8L,0x10L,0x20L,
0x40L,0x80L,0x100L,0x200L,0x400L,0x800L,0x1000L,0x2000L,
0x4000L,0x8000L,0x10000L,0x20000L,0x40000L,0x80000L,0x100000L,
0x200000L,0x400000L,0x800000L,0x1000000L,0x2000000L,0x4000000L,
0x8000000L,0x10000000L,0x20000000L,0x40000000L,0x80000000L};
k=ich+1;
Convert character range 0 nch-1 to array index range 1 nch.
if (k > hcode->nch || k < 1) nrerror("ich out of range in hufenc.");
for (n=hcode->ncod[k]-1;n>=0;n ,++(*nb)) { Loop over the bits in the stored
Huffman code for ich.
nc=(*nb >> 3);
if (++nc >= *lcode) {
fprintf(stderr,"Reached the end of the ’code’ array.\n");
fprintf(stderr,"Attempting to expand its size.\n");
*lcode *= 1.5;
if ((*codep=(unsigned char *)realloc(*codep,
(unsigned)(*lcode*sizeof(unsigned char)))) == NULL) {
nrerror("Size expansion failed.");
}
}
l=(*nb) & 7;
if (!l) (*codep)[nc]=0; Set appropriate bits in code.
if (hcode->icod[k] & setbit[n]) (*codep)[nc] |= setbit[l];
}
}
Decoding a Huffman-encoded message is slightly more complicated The
coding tree must be traversed from the top down, using up a variable number of bits:
typedef struct {
unsigned long *icod,*ncod,*left,*right,nch,nodemax;
} huffcode;
void hufdec(unsigned long *ich, unsigned char *code, unsigned long lcode,
unsigned long *nb, huffcode *hcode)
Starting at bit numbernbin the character arraycode[1 lcode], use the Huffman code stored
in the structurehcodeto decode a single character (returned asichin the range0 nch-1)
and incrementnb appropriately Repeated calls, starting with nb = 0 will return successive
characters in a compressed message The returned valueich=nchindicates end-of-message.
The structurehcodemust already have been defined and allocated in your main program, and
also filled by a call tohufmak.
{
long nc,node;
static unsigned char setbit[8]={0x1,0x2,0x4,0x8,0x10,0x20,0x40,0x80};
node=hcode->nodemax;
for (;;) { Set node to the top of the decoding tree, and loop
until a valid character is obtained.
nc=(*nb >> 3);
if (++nc > lcode) { Ran out of input; with ich=nch indicating end of
message.
*ich=hcode->nch;
return;
}
node=(code[nc] & setbit[7 & (*nb)++] ?
hcode->right[node] : hcode->left[node]);
Branch left or right in tree, depending on its value.
if (node <= hcode->nch) { If we reach a terminal node, we have a complete
character and can return.
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*ich=node-1;
return;
}
}
}
For simplicity, hufdec quits when it runs out of code bytes; if your coded
message is not an integral number of bytes, and if N ch is less than 256, hufdec
can return a spurious final character or two, decoded from the spurious trailing
bits in your last code byte If you have independent knowledge of the number of
characters sent, you can readily discard these Otherwise, you can fix this behavior
by providing a bit, not byte, count, and modifying the routine accordingly (When
N ch is 256 or larger, hufdec will normally run out of code in the middle of a
spurious character, and it will be discarded.)
Run-Length Encoding
For the compression of highly correlated bit-streams (for example the black or
white values along a facsimile scan line), Huffman compression is often combined
with run-length encoding: Instead of sending each bit, the input stream is converted
to a series of integers indicating how many consecutive bits have the same value
These integers are then Huffman-compressed The Group 3 CCITT facsimile
standard functions in this manner, with a fixed, immutable, Huffman code, optimized
for a set of eight standard documents[8,9]
CITED REFERENCES AND FURTHER READING:
Gallager, R.G 1968, Information Theory and Reliable Communication (New York: Wiley).
Hamming, R.W 1980, Coding and Information Theory (Englewood Cliffs, NJ: Prentice-Hall).
Storer, J.A 1988, Data Compression: Methods and Theory (Rockville, MD: Computer Science
Press).
Nelson, M 1991, The Data Compression Book (Redwood City, CA: M&T Books).
Huffman, D.A 1952, Proceedings of the Institute of Radio Engineers , vol 40, pp 1098–1101 [1]
Ziv, J., and Lempel, A 1978, IEEE Transactions on Information Theory , vol IT-24, pp 530–536.
[2]
Cleary, J.G., and Witten, I.H 1984, IEEE Transactions on Communications , vol COM-32,
pp 396–402 [3]
Welch, T.A 1984, Computer , vol 17, no 6, pp 8–19 [4]
Bentley, J.L., Sleator, D.D., Tarjan, R.E., and Wei, V.K 1986, Communications of the ACM ,
vol 29, pp 320–330 [5]
Jones, D.W 1988, Communications of the ACM , vol 31, pp 996–1007 [6]
Sedgewick, R 1988, Algorithms , 2nd ed (Reading, MA: Addison-Wesley), Chapter 22 [7]
Hunter, R., and Robinson, A.H 1980, Proceedings of the IEEE , vol 68, pp 854–867 [8]
Marking, M.P 1990, The C Users’ Journal , vol 8, no 6, pp 45–54 [9]
Trang 8Sample page from NUMERICAL RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-521-43108-5)
20.5 Arithmetic Coding
We saw in the previous section that a perfect (entropy-bounded) coding scheme
would use L i =− log2p i bits to encode character i (in the range 1 ≤ i ≤ N ch),
if p i is its probability of occurrence Huffman coding gives a way of rounding the
L i ’s to close integer values and constructing a code with those lengths Arithmetic
coding[1], which we now discuss, actually does manage to encode characters using
noninteger numbers of bits! It also provides a convenient way to output the result
not as a stream of bits, but as a stream of symbols in any desired radix This latter
property is particularly useful if you want, e.g., to convert data from bytes (radix
256) to printable ASCII characters (radix 94), or to case-independent alphanumeric
sequences containing only A-Z and 0-9 (radix 36)
In arithmetic coding, an input message of any length is represented as a real
number R in the range 0 ≤ R < 1 The longer the message, the more precision
required of R This is best illustrated by an example, so let us return to the fictitious
language, Vowellish, of the previous section Recall that Vowellish has a 5 character
alphabet (A, E, I, O, U), with occurrence probabilities 0.12, 0.42, 0.09, 0.30, and
0.07, respectively Figure 20.5.1 shows how a message beginning “IOU” is encoded:
The interval [0, 1) is divided into segments corresponding to the 5 alphabetical
characters; the length of a segment is the corresponding p i We see that the first
message character, “I”, narrows the range of R to 0.37 ≤ R < 0.46 This interval is
now subdivided into five subintervals, again with lengths proportional to the p i’s The
second message character, “O”, narrows the range of R to 0.3763 ≤ R < 0.4033.
The “U” character further narrows the range to 0.37630 ≤ R < 0.37819 Any value
of R in this range can be sent as encoding “IOU” In particular, the binary fraction
.011000001 is in this range, so “IOU” can be sent in 9 bits (Huffman coding took
10 bits for this example, see §20.4.)
Of course there is the problem of knowing when to stop decoding The
fraction 011000001 represents not simply “IOU,” but “IOU ,” where the ellipses
represent an infinite string of successor characters To resolve this ambiguity,
arithmetic coding generally assumes the existence of a special N ch+ 1th character,
EOM (end of message), which occurs only once at the end of the input Since
EOM has a low probability of occurrence, it gets allocated only a very tiny piece
of the number line
In the above example, we gave R as a binary fraction We could just as well
have output it in any other radix, e.g., base 94 or base 36, whatever is convenient
for the anticipated storage or communication channel
You might wonder how one deals with the seemingly incredible precision
required of R for a long message The answer is that R is never actually represented
all at once At any give stage we have upper and lower bounds for R represented
as a finite number of digits in the output radix As digits of the upper and lower
bounds become identical, we can left-shift them away and bring in new digits at the
low-significance end The routines below have a parameter NWK for the number of
working digits to keep around This must be large enough to make the chance of
an accidental degeneracy vanishingly small (The routines signal if a degeneracy
ever occurs.) Since the process of discarding old digits and bringing in new ones is
performed identically on encoding and decoding, everything stays synchronized