Bài soạn DE THI DAI HOC CUC HAY

Mot so de thi giup cac ban thi dai hoc trai qua nhieu dang hon ‘de cua tui chico !" cac ban dung ngac nhien... xac dinh toa do tam duong tron ngoai tiep tam giac ABC CAU 5: 1 giai phuong

Mot so de thi giup cac ban thi dai hoc trai qua nhieu dang hon ‘de cua tui chico !" cac ban dung ngac nhien

tui chuc cac ban on thi tot!

THOI GIAN : 180’

CHI DANH CHO HOC SINH KHONG PHAN BAN “KHONG CO SU LUA CHON THONG CAM”

x+2

CAU 1:cho ham so: y = ¡ (

1 khao sat su bien thien va ve do thi ham so (c)

2 lay diem M thuoc (c).tiep tuyen tai M tao toi

hai tien can mot tam giac tinh dien tich tam giac do

CAU 2:

4 giai phuong trinh: V14x3 — 12x? + 7x — 6 = 2x” — 14x4+ 13

2 giai phuong trinh: 3sin2x — cos2x = 3cosx + 9sinx —5

CAU 3:

tinh tich phan: I = Jus aS

7 trong oxy cho A(1; 2), B(x;3), C(y; 0)

tim x,y de tam giac ABC deu

CAU 4:

1 cho tu dien ABC deucanh1.lay diem M thuoc AB sao cho:

1

AM = a _.lay diem N thuoc AC sao cho mp(DMN)vuong

goc voi mp(ABC).tinh the tich cua: DMNCB

> trong oxyz cho A(1;2;3).B(0;1;6),C(2;0;1)

xac dinh toa do tam duong tron ngoai tiep tam giac ABC CAU 5:

1 giai phuong trinh sau trentap so phuc: x*+1=0

2

cho hai ham so: h(x) = 2011x — 20111 * — 2010 ; g(x) = (m — 1)2011* — 2.2011 *+ 2m41 timm de ham tich:

h(x) g(x) co GINN bang khong voi moi x € [0;1]

THOI GIAN :180’

CHI DANH CHO HOC SINH PHAN BAN “KHONG CO SU LUA CHON THONG CAM”

CAU 1: cho ham so:y = x* + m* — 2m(x* — 1) —1(Cm)

1 khao sat su bien thien ,ve do thi ham so (C1)

> tim m de ham so (Cm) tiep xuc voi ox tai hai

diem phan biet

CAU 2:

2(x? — y?) =3

giai he phuong trinh: (x" — y”) xy

tai ph trinh : cos xÌ—sinxŸ — 2 2

2e! DituOTt( trinn - Vsinxi(cosx COS¿X

CAU 3:

¡tinh tich phan: I = J2 Jtgx dx

2 trong oxy cho : A(1; 2), b(x; 3), c(y; 0)

tim x,y de tam giac ABC vuong can taiA

CAU 4:

1 cho tu dien ABCD co mot canh lon hon 1

cac canh con lai khong qua mot

tinh the tichlon nhat cua tu dien nay

5 trong oxyz cho A(1; 2; 3) B(0; 1; 6), C(2; 0; 1)

tinh do dai duong phan giac hatu A xuong BC

CAU 5:

[A= (1+i)(2+30(4-2¡)

1 Pur gon: a~ (1-i)(1+2i)3

2

tinh dien tich hinh phang gioi han boi cac ham so: y =

|x? - 1| ta y = lx| + 5