Thesis Assurance i1.1 Definition and main properties of characteristic exponents 3 1.2 The Lyapunov spectrum of a linear system.. • Continuity of the Lyapunov exponent The thesis consits
Trang 1HANOI PEDAGOGICAL UNIVERSITY 2
DEPARTMENT OF MATHEMATICS
Nguyen Thi Thu Huyen
ON INTEGRAL SEPARATION OF NONAUTONOMOUS DIFFERENTIAL EQUATIONS
GRADUATION THESIS
Hanoi – 2019
Trang 2HANOI PEDAGOGICAL UNIVERSITY 2
DEPARTMENT OF MATHEMATICS
Nguyen Thi Thu Huyen
ON INTEGRAL SEPARATION OF NONAUTONOMOUS DIFFERENTIAL EQUATIONS
GRADUATION THESIS
SUPERVISOR: Assoc.Prof- Dr.Sc Doan Thai Son
Hanoi – 2019
Trang 3Thesis Acknowledgement
I would like to express my gratitudes to the teachers of the
Depart-ment of Mathematics, Hanoi Pedagogical University 2, the teachers in
the Analytics group as well as the teachers involved The lecturers
have imparted valuable knowledge and facilitated for me to complete
the course and the thesis
In particular, I would like to express my deep respect and gratitude
to Assoc.Prof- Dr.Sc Doan Thai Son, who has direct guidance, help me
complete this thesis
Due to time, capacity and conditions are limited, so the thesis can
not avoid errors Then, I look forward to receiving valuable comments
from teachers and friends
Trang 4Thesis Assurance
I assure that the data and the results of this thesis are true and not
identical to other topics I also assure that all the help for this thesis
has been acknowledged and that the results presented in the thesis has
been identified clearly
Ha Noi, May 5, 2019
Nguyen Thi Thu Huyen
Trang 5Thesis Assurance i
1.1 Definition and main properties of characteristic exponents 3
1.2 The Lyapunov spectrum of a linear system 11
2.1 Characterization of continuity of Lyapunov spectrum 23
2.1.1 Simple Lyapunov spectrum 23
2.1.2 One point spectrum 25
2.2 Explicit examples 27
Trang 6Theory exponent Lyapunov has a long history and is known to be an
important tool in studying the stability of differential equations
Specifi-cally, Lyapunov’s exponent measures the separation velocity of the
near-derivative solutions of the differential equation and when the exponent
is negative, the solutions converge when the time is infinite In fact,
there are many equations that we do not know exactly the vector field
and then the question is how the Lyapunov exponent will change if the
vector field of the system is small One of the profound results
associ-ated with this problem is integral separation which is a necessary and
sufficient condition for the continuity of the Lyapunov exponent when
these exponents separate Within the framework of the thesis, student
wished to present systematically the problem of continuity of the
expo-nent Lyapunov and its relation to integral separation To do this, the
thesis will focus on:
• Introduction sketchy to the Lyapunov exponent and basis results
• Continuity of the Lyapunov exponent
The thesis consits of two chapter :
Chapter 1: Lyapunov exponent and basis results
Chapter 2: Continuity of the Lyapunov exponent
I sincerely thanks Assoc.Prof- Dr.Sc Doan Thai Son devotedly
in-structed the author to read the materials and practice the research I
Trang 7would also like to thank Assoc.Prof- Dr.Sc Doan Thai Son gave detailed
comments on how to present some results in the thesis
I sincerely thank the teachers of the Mathematics Department at
Hanoi Pedagogical University 2, especially the Analysis Team, for
cre-ating favorable conditions for me in the process of studying at the
Uni-versity and implementing the thesis
Ha Noi, 06/05/2019
Author of the thesis
Nguyen Thi Thu Huyen
Trang 8Lyapunov exponent and basic
results
The aim of this chapter is to introduce the notion of Lyapunov exponent
of an arbitrary function Next, we study the Lyapunov spectrum of a
linear nonautonomous differential equation We refer the reader to [2, 3]
for more details
exponents
We start this section by giving a definition of the Lyapunov
character-istic exponent of a non-zero function Roughly speaking this exponent
measures the growth of this function in comparison with the exponential
function
Definition 1.1.1 (Lyapunov Characteristic exponent) For any
non-zero function f : R → R, its Lyapunov characteristic exponent (for short
Trang 9characteristic exponent) is defined as
4 For a non-zero constant function c, we have χ[c] = 0
Now, we study the property of the Lyapunov characteristic exponent
of a function given as a sum or a product of a finite number of functions
For this purpose, we need the following technical lemma
Lemma 1.1.2 Let f : R → R be a non-zero function Then, χ[f ] =
α ∈ (−∞, ∞) if and only if for any ε > 0 the following two conditions
Trang 10fix ε > 0 By (1.1), there exists T > 0 such that
(Sufficiency) Suppose that two statements (1) and (2) hold We will
show that χ(f ) = α By condition (1), for any ε > 0 there exists T such
that
|f (t)| < e(α+ε)t for all t ≥ T
Trang 11of limit, for sufficient large k we have
Theorem 1.1.3 (Characteristic exponent of a sum of finite number
of functions) Let f1, , fn : R → R be non-zero functions Define
Then the following statements hold:
(i) The Lyapunov characteristic exponent f does not exceed the greatest
of the Lyapunov characteristic exponents of f1, , fn
Trang 12(ii) If only one functions has the greatest exponent of f1, , fn then
Since ε is arbitrary, we get χ[f ] 6 α
(ii) By definition of α and the assumption only one functions has the
greatest exponent of f1, , fn, there exists ` ∈ {1, , n} such that
lim sup
m→∞
|f`(t)|
e(α−ε)t m = ∞
Trang 13We have
The second term on the right-hand side of the last inequality tends to
zero and the first tends to infinity as m → ∞ By properties of limit,
for sufficient large m we obtain
!
> α − ε,Which together with (i) implies that
The proof is complete
Example 1.1.4 Using Theorem 1.1.3, we obtain that
χ[e2t+ e3t + e−t] = 3
Theorem 1.1.5 The characteristic exponent of the product of a finite
number of function does not exceed the sum of the characteristic
expo-nents of the cofactors, i.e., for any non-zero functions f1, , fn : R → R
Trang 14Proof We assume that +∞ and −∞ are not simultaneously present
among characteristic exponents A direct computation yields that
= lim sup
t→∞
1t
The proof is complete
Example 1.1.6 1)χ[et.e−3t] = χ[e−2t] = −2 and χ[et.e−3t] = χ[et] +χ[e−3t] = 1 − 3 = −2 In this case a strict equality is realized in (2.2)2)χ[et sin t.e−t sin t] = χ[1] = 0
At the same time χ[et sin t.e−t sin t] < χ[et sin t] + χ[e−t sin t] = 2
In this case a strict inequality is realized in (2.2)
Next, we define the characteristic exponent of a matrix-valued
func-tions Throughout the content of this thesis, we restrict our attention to
only matrix-valued functions taking the value in Rn×n
Definition 1.1.7 (Lyapunov Characteristic Exponent of a
Matrix-Val-ued Function) For any matrix F (t) = {fij(t)}i,j=1, ,n, its Lyapunov acteristic exponent (for short characteristic exponent) is defined as:
char-χ[F ] = max
i,j χ[fij]
Trang 15Now, we show that the characteristic exponent of a matrix-valued
function coincides with the characteristic exponent of its norm To do
this, we recall that all norms on a finite-dimensional linear space are
equivalent Then, in the following we endow Rn with the max norm, i.e.,
kAk = max
1≤i,j≤n|aij|
Theorem 1.1.8 The charactertistic exponent of a finite dimensional
matrix F (t) coincides with the characteristic exponent of its norm, i.e.,
χ[F ] = max
i,j χ[fij] 6 χ[kF (t)k] (1.3)
Trang 16On the other hand,
kF (t)k 6 X
i,j
|fij(t)| Hence,
χ[F ] = χ[kF k]
The proof is complete
Consider a linear nonautonomous differential equation
Our aim in this subsection is to examine the characteristic exponents
of the solution of (1.4) To do this, we first prove the existence of the
global solution of (1.4)
Theorem 1.2.1 (Global unique and existence of solution for linear
Trang 17nonautonomous differential equations) Let x0 ∈ Rn be arbitrary Then,system (1.4) with the initial value condition x(0) = x0 has a uniquesolution.
To prove the above theorem, we need to show the existence of a
unique continuous function x : [0, ∞) → Rn satisfying the followingintegral equation
x(t) = x0 +
Z t 0
The idea is to find a suitable contraction operator on a suitable space
such that its unique fixed point of this operator gives rise to the solution
of (1.5) Now, choose and fix an arbitrary γ > 0 Let
Lemma 1.2.2 The space (Cγ, k.kγ) is a Banach Space
Proof Firstly, we verify that (Cγ, k.kγ) is norm space Indeed, we checkthree properties of a norm space:
kf kγ = 0 ⇔ sup e−γtkf (t)k = 0 ⇔ f (t) = 0 ∀t ∈ [0; +∞)
Trang 18kf + gkγ = sup e−γtkf + gk 6 sup e−γt(kf k + kgk)
6 sup e−γtkf k + sup e−γtkgk
= kf kγ + kgkγ ∀t ∈ [0; +∞) ,kαf kγ = sup e−γtkαf k = α sup e−γtkf k = αkf kγ, ∀t ∈ [0; +∞)
To complete the proof, we verify that the norm space (Cγ, k.kγ) iscomplete Now let Let {fn} be a Cauchy sequence in (Cγ, k.kγ) Then, weneed to construct f∗ ∈ Cγ such that lim fn = f∗ We do this throughoutthe following steps:
Step 1: For a fixed t ∈ [0, ∞) We will show that {fn(t)} is a cauchysequence in R Indeed, since {fn} is Cauchy in (Cγ, k.kγ), ∀ε > 0, ∃N ∈ Nsuch that ∀n, m > N , we have:
Trang 19that f∗ is continuous at t For this purpose, let {tm}∞m=1 be a sequencesuch that lim
m→∞tm = t We need to show that lim
m→∞f∗(tm) = f∗(t).Indeed, let ε > 0 be arbitrary but fixed Since (fn) is a Cauchy sequence
in Cγ, there exists K ∈ N such that
which together with continuity of the function fK proves the continuity
of the function f∗ Similarly, we aslo have kf∗kγ < ∞ Therefore,
f∗ ∈ Cγ
Step 3: To complete the proof, we verify that
lim
n→∞kfn− f∗kγ = 0Since {fn} is Cauchy sequence, so ∀ε > 0, ∃N ∈ N,such that ∀n, m > N,
Trang 20kfn− f∗kγ < ε for all n ≥ N.
Consequently,
lim
n→∞kfn− f∗kγ = 0The proof is complete
We are now in the position to prove the global uniqueness existence
Trang 21Tf ∈ Cγ Since A(s)f (s) is continuous function, then by the mental Theorem of Calculus, Tf(t) is a also continuous Morover, wehave:
eγskf kγ ds < ∞,
which implies that kTf(t)kγ < +∞
Step 2 We will show that for a suitable choice of γ, the linear operator
T is contractive Indeed, using the same estimate as in Step 1 we have
kTf − Tgkγ ≤ M sup
t≥0
e−γt
Z t 0
eγskf − gkγ ds
γ kf − gkγ,which implies that if γ > M the operator T is contractive
Step 3 So far, T is contractive therefore by Banach Fixed Point
The-orem, T has a unique fixed point To conclude the proof, we will show
that ξ(t) is solution of (1.4) satisfying x(0) = x0 if and only if ξ(t) is afixed point of T
(Necessity) Suppose ξ(t) is solution of (1.4) with ξ(0) = x0, i.e., ˙ξ(t) =A(t)ξ(t)
Trang 22Thus, ξ(t) is a fixed point of T
(Sufficiency) Suppose that ξ(t) satisfies:
Trang 23Therefore, ξ(t) is solution of (1.4) with ξ(0) = x0.
This complete the proof
So far, we have proved that for any initial valued problem x(0) = x0equation (1.4) has a unique solution In the remainning of this chapter,
we examine the characteristic exponents of solutions of (1.4) Firstly,
we show that the characteristic exponent of a non-zero slution of (1.4)
is finite
Theorem 1.2.3 Any non-trivial solution x(t) of the linear system (1.4)
has a finite characteristic exponent, i.e −M ≤ χ[x] ≤ M
Proof Let Rn be endowed with the Euclidean norm A driect tion yields that
t
Z
t0
2M dτ
Trang 24−M 6 lim sup
t→∞
1
t ln kx(t)k 6 M
That means −M 6 χ[x] 6 M The proof is complete
Next, we show that the set of Lyapunov characteristic exponents of all
non-zero solutions of (1.4) has no more than n elements Before proving
this fact, we need the following technical lemmas
Lemma 1.2.4 Vector functions x1(t), , xm(t) defined on [0; ∞) andhaving different finite characteristic exponents are linearly independent
Proof Let us consider the linear combination of these vectors with a
nontrivial set of coefficient is
m
P
i=1
cixi(t) According to Theorem 1.1.3,the characteristic exponent of this sum is equal to max
i χ[χi(t)] That is,χ[
m
X
k=1
ckxk(t)] = χ[0] = −∞
Trang 25This is contradiction Therefore, {xi}m
i=1 is linearly independent
Lemma 1.2.5 System (1.4) has n solutions x1(t), , xn(t) which arelinearly independent
Proof Suppose the contrary, i.e., there exists n+1 solutions x1(t), , xn+1(t)
of (1.4) which are linearly dependently Then, there exists c1, , cn+1such that
Hence,
ξ(t) ≡ x1(t),
Trang 26c1x1(t) + c2x2(t) + + cn+1xn+1(t) = 0.
Therefore,{xi}n+1i=1 is linearly independent The proof is complete
Theorem 1.2.6 The number of elements of the spectrum doew not
Thus, spectrum of (1.4) consists of finite element α1 6 α2 6 6
αm, (m 6 n), where αi = χ[xi(t)] So, the number of elements of thespectrum does not exceed n
Trang 27Continuity of the Lyapunov
where Q ∈ C([0; +∞)), with sup kQ(t)k 6 σ The Lyapunov spectrum
of (2.3) is denoted by with the spectrum:
−∞ < λ10 6 λ2 0
Trang 28Under the influence of perturbation Q(t) , the characteristic exponents
of system (2.3) vary, generally speaking, discontinuously
Definition 2.0.1 The characteristic exponents of system (2.1) are said
to be stable if for any ε > 0 there exists a σ > 0 such that the inequality
Our aim in this chapter is to give a characterization of the stability of
Lyapunov spectrum of a linear planar system We distinguish the cases
simple spectrum, i.e., λ1 < λ2 and one point spectrum, i.e λ1 = λ2
(Section 2.2)
spec-trum
2.1.1 Simple Lyapunov spectrum
Firstly, we have the following result for a sufficient condition of continuity
of simple Lyapunov spectrum
Theorem 2.1.1 If system (2.1) has different characteristic exponent
λ1 < λ2, then their stability follows from the existence of a Lyapunovtransformation x = L(t)z of this system to a diagonal system
˙z = diag[p1(t), p2(t)]z = P (t)z (2.6)
Trang 29Where the functions p1(t) and p2(t) are integrally separared, i.e.,
It turns out the integral separatedness is also a necessary condition
for stability of simple Lyapunov spectrum
Theorem 2.1.2 If the exponents λ1 < λ2 of a two dimensional system:
λ1 = lim
t→∞
1t
t
Z
0
p2(τ )dτ
Proof The idea of the proof is as follows Assume that the diagond is
not integrally separated Fixing β ∈ (λ1 λ2), we show that under thisassumption for any σ > 0 the perturbation:
kQ(t)k < σ
Can be chosen such that there exists a solution y(t) of the perturbed
sytem with x[y] = β, and this contradicts the stability of the
expo-nents The method for constructing these perturbations was developed
Trang 30by Millionshchikov and is called the medthod of rotations or the method
of perturbations by rotations
2.1.2 One point spectrum
We pass to the case of a two-dimensional diagonal system with equal
characteristic exponent To formulate the characterization of continuity
of the spectrum in this case, we first need to introduction the notion of
where t > s > 0 and the quantities dr,ε, DR,ε do not depend on growth
of the solutions from below and from above, respectively
Definition 2.1.4 The number Ω defined as:
Ω = inf
R { lim
t→∞
1t
t
Z
0
is called the upper central exponent of system (2.1) Here the infimum
is taken over the set of all the upper functions R of system
Trang 31Definition 2.1.5 The number ω defined as
t
Z
0
Here r(t) is the set of all the lower functions of system (2.1)
Theorem 2.1.6 If a linear two-dimensional has equal characteristic
exponents λ1 = λ2 = λ, then they are stable if and only if
ω = λ = Ω
Proof Necessity Let the exponent of the system be stable but:
max{Ω − λ, λ − ω} = γ > 0
For the sake of definiteness, we assume that Ω − λ = γ > 0 According
to Millionshchikov’s Theorem (see [1]), there exists a perturbation Q(t)
of the linear system such that
kQ(t)k < σ, t > 0
Where σ is arbitrary small, and the perturbed system has a
character-istic exponent λ0 > Ω This contradicts the stabililty of the exponents.Similar arguments can be carried out for the case λ − ω = γ > 0 The
fact that ω is attainable was established by Millionshchikov
Hence
Ω − λ = λ − ω = 0
Or
ω = λ = Ω
... is completeConsider a linear nonautonomous differential equation
Our aim in this subsection is to examine the characteristic exponents
of the solution of (1.4) To this, we... the remainning of this chapter,
we examine the characteristic exponents of solutions of (1.4) Firstly,
we show that the characteristic exponent of a non-zero slution of (1.4)
is... is called the medthod of rotations or the method
of perturbations by rotations
2.1.2 One point spectrum
We pass to the case of a two-dimensional diagonal system with equal