V6 Dinh Minh —
I- TICH PHAN CO BAN:
0
| cos3x cos xdx |
Il TICH PHAN CO TRI TUYET DOI VA CAN THUC:
0
i x dx lìn x+rÌ
Ill TICH PHAN DOI BIEN:
2/2
fx V4—x? dx | xV x? +1dx
6
.dx m8 øx
IV TICH PHAN TUNG PHAN:
7
Inx dx
Cs + N
2
|x sin 3xdx
0
1
0
4 y sinx | —#% [xInd+x?)dx í
THPT Phan Bội Châu- Tam Ky
dx
x’ —9
1- 2x ie Gap
2
J
1
2 | x
a
1
J
0
xv 2x —1dx
1
l= [V2x+ Idx
0
4 [V16 —x? dx
1
TT
peseex x
, COS” xX
vx
i Ve
7% tạnx+2
¡ COS” X
ax
fine? —x)dx
(x +sin’ x) cos xdx
1 (= 2 kx
0 e
5 [@ —1)sin xdx
0