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Tài liệu ôn tập vật lý 9 rất hay

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Tài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hayTài liệu ôn tập vật lý 9 rất hay

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�i�n v�o hi�u �i�n th� l� m�t ���ng th�ng �i qua g�c to� ��

�i�n tr� c�a d�y d�n l� ��i l��ng ��c tr�ng cho m�c �� c�n tr� d�ng �i�n c�a d�y d�n nhi�u hay �t.R = # EMBED Equation.3 ### ��nh lu�t �m.C��ng �� d�ng

�i�n ch�y qua d�y d�n t� l� thu�n v�i hi�u �i�n th� ��t v�o hai ��u d�y d�n v� t� l� ngh�ch v�i �i�n tr� c�a d�y d�n I = # EMBED

Equation.3 ### 5 ��nh lu�t �m cho �o�n m�ch m�c n�i ti�p

I = I1 = I2 = = In R1 R2 Rn#

U = U1 + U2 + + Un R = R1 + R2 + + Rnv�: # EMBED Equation.3 ### =# EMBED Equation.3 ### * N�u c� n �i�n tr�gi�ng nhau c� gi� tr� R0 m�c n�i ti�p th�:R = nR0 R1#6 ��nh lu�t �m cho �o�nm�ch m�c song song U = U1 = U2

* N�u c� 3 �i�n tr� m�c song song th�: R = # EMBED Equation.3 ###

* N�u c� n �i�n tr� b�ng nhau c� gi� tr� R0 m�c song song v�i nhau th�:

R = # EMBED Equation.3 ### 6 �i�n tr� c�a d�y d�n t� l� thu�n v�i chi�u d�i d�y d�n, v�i �i�n tr� su�t c�a v�t li�u l�m d�y d�n, t� l� ngh�ch v�i ti�t di�n c�a d�y d�n R = (# EMBED Equation.3

### 7 Bi�n tr� l� l� �i�n tr� c� th� thay ��i ���c tr� s� v� s� d�ng ��

�i�u ch�nh c��ng �� d�ng �i�n 8 S� o�t (W) ghi tr�n m�i d�ng c� �i�n cho bi�t c�ng su�t ��nh m�c c�a m�i d�ng c� �� Khi � hai ��u m�t d�ng c� �i�n c� hi�u �i�n th� b�ng hi�u �i�n th� ��nh m�c th� n� ho�t ��ng b�nh th��ng v� c�ng su�t ti�u th� b�ng c�ng su�t ��nh m�c 9 C�ng th�c t�nh c�ng su�t �i�n

P = UI = I2R = # EMBED Equation.3 ### 10 �i�n n�ng l� n�ng l��ng c�a d�ng �i�n 11 C�ng c�a d�ng �i�n s�n ra trong m�t m�ch �i�n l� s� �o l��ng �i�n n�ng chuy�n ho� th�nh c�c d�ng n�ng l��ng kh�c

A = P.t = UIt * M�i s� ��m c�a c�ng t�

�i�n cho bi�t l��ng �i�n n�ng �� s� d�ng trong 1 gi� 1 s� = 1kWh = 3 600 000 J 12 ��nh lu�t Jun-Len x� Q =I2Rt * 1 Jun = 0.24 calo 1 calo = 4.18 Jun* V� d�:Khi

�a�t va�o hai �a�u da�y da�n mo�t hie�u �ie�n the� 12 V th� c���ng �o� do�ng

�ie�n cha�y qua da�y da�n la� 0,5A Ne�u hie�u �ie�n the� �a�t va�o hai �a�u V� c � d � cha�y qua da�y da�n t� le� thua�n v��i hie�u �ie�n the� �a�t va�o hai

�a�u da�y da�n �o� ne�n:V��i U1 = 12V th� I1 = 0,5AV��i U2 = 36V th� I2 =# EMBEDEquation.3 ###Do�ng �ie�n cha�y qua mo�t da�y da�n co� c���ng �o� la� 6mA khi no� ����c ma�c va�o h� t 12V Muo�n do�ng �ie�n cha�y qua da�y da�n �o� co� c���ng �o� gia�m �i 4 mA t��c la� I = 2mA C���ng �o� do�ng �ie�n gia�m �i 3 la�n=> U gia�m �i 3 la�n khi �o� U2 = 4VCho �ie�n tr�� R= 15# EMBED Equation.3

###Khi ma�c �ie�n tr�� na�y va�o hie�u �ie�n the� 6V th� do�ng �ie�n cha�y qua tr�� ta�ng the�m 0,3A so v��i tr���ng h��p tre�n th� hie�u �ie�n the� �a�t va�o hai �a�u �ie�n tr�� �o� la� bao nhie�uHD: a)I= # EMBED Equation.3 ### b) U� = RI�= 15* 0,7 = 10,5V ( I� = 0,4+0,3=0,7A)4 Co� hai bo�ng �e�n ghi

HD: T�nh �ie�n tr�� cu�a mo�i bo�ng �e�n ro�i so sa�nh5 Mo�t da�y da�n

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����c ma�c va�o hie�u �ie�n the� 6V th� c���ng �o� do�ng �ie�n cha�y qua no� la�0,3A Mo�t ba�n ho�c sinh no�i ra�ng: Ne�u gia�m hie�u �ie�n the� �a�t va�o hai

�a�u da�y da�n �i 2V th� c���ng �o� do�ng �ie�n cha�y qua da�y da�n khi �o� co� hie�u �ie�n the� gia�m �i 2V t��c la� U2 = 6-2=4V C���ng �o� do�ng �ie�n khi �o� la� I2 = I1.U2/U1 = 0,3.4/6 = 0,2AVa�y ke�t qua� �� �a�y la� sai ba�n

�a� nha�m la� hie�u �ie�n the� gia�m �i 2 V ch�� kho�ng pha�i hie�u �ie�n the� gia�m �i hai la�n6 La�m th� nghie�m kha�o sa�t s�� phu� thuo�c cu�a c���ng �o�do�ng �ie�n va�o hie�u �ie�n the� �a�t gi��a hai �a�u va�t da�n ba�ng kim loa�i,ng���i ta thu ����c ba�ng so� lie�u sau:

U(v)#0#1,5#3,0#4,5#6,0#7,5#9,0##I(A)#0#0,31#0,61#0,90#0,129#0,149#0,178##R(# EMBED Equation.3 ###)#########Ve� �o� th� bie�u die�n s�� phu� thuo�c I va�o U Ne�u bo� qua nh��ng sai so� trong phe�p �o th� �ie�n tr�� cu�a va�t da�n �o� EMBED Equation.3 ###8 Mo�t �oa�n ma�ch go�m ba �ie�n tr�� R1 = 3# EMBED

Equation.3 ###; R2 = 5# EMBED Equation.3 ###; R3 = 7# EMBED Equation.3 ###

����c ma�c no�i tie�p v��i nhau Hie�u �ie�n the� gi��a hai �a�u �oa�n ma�ch la�

U = 6V.1/ T�nh �ie�n tr�� t��ng ���ng cu�a �oa�n ma�ch.2/ T�nh hie�u �ie�n the� gi��a hai �a�u mo�i �ie�n tr��.H���ng da�n1/ �ie�n tr�� t��ng ���ng cu�a ma�ch:#EMBED Equation.3 ### = 3 + 5 + 7 = 15# EMBED Equation.3 ###2/ C���ng �o� do�ng

�ie�n trong ma�ch ch�nh # EMBED Equation.3 ###Ma� ma�c no�i tie�p ne�n I ba�ng nhau Ne�u ta co� hie�u �ie�n the� hai �a�u mo�i �ie�n tr�� la�:# EMBED Equation.3 #### EMBED Equation.3 #### EMBED Equation.3 ###9.Cho ba �ie�n tr�� R1 = 6# EMBED Equation.3 ###; R2 = 12# EMBED Equation.3 ###;R3 = 16# EMBED Equation.3 ### ����c ma�c song song v��i nhau va�o hie�u �ie�n the� U = 2,4V1/ T�nh �ie�n tr�� t��ng ���ng cu�a �oa�n ma�ch.2/ T�nh c���ng �o� do�ng �ie�n qua ma�ch ch�nh va� qua t��ng �ie�n tr��.H���ng da�n1/ �ie�n tr�� t��ng ���ng cu�a ma�ch:# EMBED Equation.3 #### EMBED Equation.3 ###2/ C���ng

�o� do�ng �ie�n qua ma�ch ch�nh:# EMBED Equation.3 ###V� ma�c song ne�n U ba�ngnhau Ne�n c���ng �o� do�ng �ie�n qua t��ng �ie�n tr�� la�:# EMBED Equation.3

#### EMBED Equation.3 #### EMBED Equation.3 ###b�i t�p* �o�n m�ch n�i ti�pC�u 1.Cho 2

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#�#i#e#�#n# #t#r#�#�# #t#�#�#n#g# #�#�#�#n#g# #cu�a ma�ch:# EMBED Equation.3

### 6 = 36# EMBED Equation.3 ###2/ C���ng �o� do�ng �ie�n qua ma�ch ch�nh:# EMBED Equation.3 ###Ma�: # EMBED Equation.3 ###Ta co�: # EMBED Equation.3 ###V� R2 // R3 ne�n U2 = U3 = U2,3 Ta co�:# EMBED Equation.3 ####

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##Ba�i 2: Cho ma�ch �ie�n nh� h�nh ve�:H���ng da�n1/ �ie�n tr�� t��ng ���ng cu�aR2 va� R3 la�:# EMBED Equation.3 ### �ie�n tr�� t��ng

���ng cu�a ma�ch: # EMBED Equation.3 ### 2/ Hie�u �ie�n the� cu�a ma�ch:# EMBED Equation.3 ###3/ Ta co�: # EMBED Equation.3

### = 6V Ne�n ta co�: # EMBED Equation.3 ### # EMBED Equation.3 ###B�i t�p �p d�ng ��nh lu�t �m cho �o�n m�ch m�c n�i ti�p, song song v� h�n h�p.1 Khi ��t v�o hai ��u d�y d�n m�t hi�u �i�n th� l� 18V th� c��ng �� d�ng �i�n ch�y qua n� l� 0.9A N�u hi�u �i�n th� t�ng th�m 6V th� c��ngm�i c�i c� �i�n tr� R C� th� m�c ch�ng theo bao nhi�u c�ch kh�c nhau ��

���c m�c nh� h�nh v� Trong �� R1 = 35 (, R2 = 60 ( Ampe k� A1

(; R2 = 6 (; R3 = 8 ( ���c m�c th�nh m�t �o�n m�ch song song C��ng �� d�ng �i�n ch�y qua m�ch ch�nh l� 4A T�nh �i�n tr� t��ng ���ng c�a �o�n h�nh v� Cho bi�t: UAB = 70V; r1 =15 ( ; R2 = 30 (; R3 = 60 ( A R1

C B a) T�nh �i�n tr� t��ng ���ng c�a to�n tr� R1 = 4 (; R2 = 8 (; R3 = 24 ( ���c m�c v�o hai �i�m A, B c� hi�u �i�n th�

R1

B c) T�nh hi�u �i�n th� gi�a hai ��u �i�n

#7 C� 4 �i�n tr� c� gi� tr� R N�u c�c c�ch m�c c�c �i�n tr� �� th�nh m�t m�ch

( 30( v� 60( )##########12 Cho m�ch �i�n nh� h�nh v� Bi�t v�n k�

M N######### ch� 84V, ampe k� A ch� 4,2A, �i�n tr�## R1 = 52,5( ### T�m s� ch� c�a c�c ampe k� A1 , A2 v� t�nh �i�n tr� R2 ( 1.6A; 2.6A; 32.3( ) #13 Cho m�ch �i�n nh� h�nh v� ##### Hi�u �i�n th� gi�a hai

��u �o�n m�ch UMN = 60V.####### Bi�t R1 = 3R2 v� R3 =8( s� ch� c�a ### Ampe k� A l� 4A T�nh c��ng �� d�ng �i�n qua## c�c �i�n tr� R1 v� R2 v� gi� tr� c�c �i�n tr� R1 v� R2 ####

( 1A; 3A; 28( ;28/3( )###14 Cho m�ch �i�n nh� h�nh v� Trong �� R1= 4( ,#R2 = 10( , R3 = 15(, hi�u �i�n th� UCB = 5,4V T�nh �i�n tr� t��ng ���ng RAB c�a �o�n m�ch.#T�nh c��ng �� d�ng �i�n qua m�i �i�n tr� v� s� ch� c�a ampe k�

A ( 10( ; 0.9A; 0.54A; 0.36A)15 Cho m�ch �i�n nh� h�nh v� Bi�t R1 = 4( , R2 = 6( , R3 = 15( Hi�u �i�n th� gi�a hai ��u# �o�n m�ch UAB = 36V R1 R2#T�nh �i�n tr� t��ng ���ng c�a �o�n m�ch.#T�m s� ch� c�a Ampek� A v� t�nh R3 hi�u �i�n th� hai ��u c�c �i�n tr� R1, R2 ( 6(; 6A; 3.6A;

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14.4V; 21.6V)16 Cho m�ch �i�n nh� h�nh v�

A B Bi�t R1 =12( , R2 = 18( , R3 = 20( ,# Rx c� th� thay ��i ���c Hi�u �i�n th� gi�a hai R1 R2 # ��u �o�n m�ch UAB = 45V.## a) Cho Rx = 25( T�nh �i�n tr� t��ng ���ng A

B c�a m�ch v� c��ng �� d�ng �i�n trong m�ch ch�nh

b) ��nh gi� tr� Rx �� cho c��ng �� d�ng �i�n qua Rx nh� h�n hai l�n c��ng �� d�ng �i�n qua �i�n tr� R1 ( 18(; 2.5A; 40( )17 Cho m�ch �i�n nh� h�nh v�

R2 D R3 ##Trong ��: R1 = 15( ; R2 = 3 ( ; R3 = 7( ; R4 = 10 ( A R1 C ##Hi�u �i�n th� UAB = 35V

T�nh �i�n tr� t��ng ���ng c�a to�n m�ch T�nh c��ng �� d�ng �i�n qua c�c �i�n tr�.T�nh c�c hi�u �i�n th� UAC v� UAD ( 20(; 1.75A; 0.875A; 26.25V; 28.875V) 18 Tr�n h�nh v� l� m�t m�ch �i�n c� hai c�ng t�c

R1 R4 K2 ###

K1 v� K2

C�c �i�n tr� R1 = 12,5( , R2 = 4( , R3 = 6(

K1# Hi�u �i�n th� hai ��u �o�n m�ch UMN = 48,5V.## a) K1 ��ng, K2 ng�t T�m c��ng �� d�ng �i�n qua c�c �i�n tr�

b) K1 ng�t, K2 ��ng C��ng �� d�ng �i�n qua R4 l� 1A T�nh R4

M N c) K1 v� K2 c�ng ��ng, t�nh �i�n tr� t��ng ���ng c�a ( 2.94A; 30(; 3A)#S� ph� thu�c c�a �i�n tr� v�o chi�u d�i, ti�t di�nv� v�t li�u l�m d�y d�n - Bi�n tr� 1 Tr�n m�t bi�n tr� c� ghi 25( - 1A Con s� 25( - 1A

Constantan c� �i�n tr� su�t ( = 0.5.10-6 (m, c� chi�u d�i l = 20m v� c� ti�t d�y d�n �� 3 ��t v�o hai ��u m�t cu�n d�y d�n l�m b�ng ��ng m�t hi�u �i�n th�

U = 17V th� c��ng �� d�ng �i�n qua d�y d�n l� I = 5A Bi�t ti�t di�n c�a d�y d�n l� 1.5 mm, �i�n tr� su�t l� 1.7.1-8 (m T�nh chi�u d�i c�a d�y d�n 4 M�t d�y d�n l�m b�ng ��ng d�i 30m, c� ti�t di�n 1.5mm2 ���c m�c v�o hi�u �i�n th� 30.8V T�nh c��ng �� d�ng �i�n qua d�y d�n n�y, bi�t ( = 1.7.10-8(m 5 M�t b�ng ��n c� ghi 18V - 1A m�c n�i ti�p v�i m�t bi�n tr� con ch�y �� s� d�ng v�i hi�u �i�n th� kh�ng ��i 24V �i�u ch�nh �� bi�n tr� c� gi� tr� Rb = 12( T�nh to�n v� n�u nh�n x�t v� �� s�ng c�a b�ng ��n.H�i ph�i �i�u ch�nh bi�n tr� c� gi�

��nh m�c l� U1 = U2 =6V, khi s�ng b�nh th��ng c�c b�ng ��n c� �i�n tr� t��ng �ng l� R1 = 6( v� R2= 12( C�n m�c hai b�ng n�y v�i m�t bi�n tr� v�o hi�u �i�n th�

U = 9V �� hai b�ng s�ng b�nh th��ng V� s� �� m�ch �i�n tr�n v� t�nh �i�n tr� c�a bi�n tr� �� B�i t�p S� ph� thu�c c�a �i�n tr� v�o chi�u d�i, ti�t di�nv� v�t li�u l�m d�y d�n - Bi�n tr�.B�i 1 M�t bi�n tr� con ch�y c� �i�n tr� l�n nh�t l� 50( D�y �i�n tr� c�a bi�n tr� l� m�t h�p kim nicr�m c� ti�t di�n 0,11mm2 v� ���c cu�n ��u xung quanh m�t l�i s� tr�n c� ���ng k�nh 2,5cm T�nh s� v�ng d�y c�a bi�n tr� n�y.Bi�t c��ng �� d�ng �i�n l�n nh�t m� day n�y c� th� ch�u ���c l� 1,8A H�i c� th� ��t v�o hai ��u d�y c� ��nh c�a bi�n tr� m�t hi�u �i�n th� l�n nh�t l� bao nhi�u �� bi�n tr� kh�ng b� h�ng B�i 2 M�t b�ng

��n c� ghi 18V - 1A m�c n�i ti�p v�i m�t bi�n tr� con ch�y �� s� d�ng v�i ngu�n

�i�n c� hi�u �i�n th� kkh�ng ��i 24V.�i�u ch�nh bi�n tr� ��n gi� tr� Rb = 12( H�y t�nh to�n v� n�u nh�n x�t v� �� s�ng c�a b�ng ��n.H�i ph�i �i�u ch�nh bi�n tr� c� gi� tr� �i�n tr� bao nhi�u �� ��n c� th� s�ng b�nh th��ng B� qua �i�n tr� c�c d�y n�i B�i 3 C� hai b�ng ��n m� khi s�ng b�nh th��ng c� �i�n tr� t��ng �ng l� R1= 16( v� R2 = 12( D�ng �i�n ch�y qua hai ��n ��u c� c��ng ��

��nh m�c l� I = 0,8A Hai ��n n�y ���c m�c n�i ti�p v�i nhau v� v�i m�t bi�n tr� v�o hai ��u �o�n m�ch c� hi�u �i�n th� U = 28,4V.T�nh �i�n tr� c�a bi�n tr�

�� hai ��n s�ng b�nh th��ng.Khi ��n s�ng b�nh th��ng, s� v�ng d�y c�a bi�n tr� c� d�ng �i�n ch�y qua ch� b�ng 75% so v�i t�ng s� v�ng d�y c�a bi�n tr� T�nh con ch�y C L�c ��u ��y con ch�y C v� �i�m A �� bi�n tr� c� �i�n tr� l�n nh�t

B AKhi d�ch chuy�n con ch�y C v� ph�a B th� �� s�ng c�a

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�i�n tr� to�n ph�n c�a bi�n tr� l� 42( v� con ch�y C � �i�m # ch�nh gi�a AB Hi�u �i�n th� do ngu�n cung c�p l� 46,8V T�nh c��ng c� hi�u �i�n th� ��nh m�c 24V v� c��ng �� d�ng

�i�n ��nh m�c 0,6A ���c m�c v�i m�t bi�n tr� con ch�y �� s�d�ng v�i ngu�n �i�n c� hi�u �i�n th� kh�ng ��i 30V a) �� ��n s�ng B� qua �i�n tr� � d�y n�i b) N�u bi�n tr� c� �i�n tr� l�n nh�t l� 40(th� khi ��n s�ng b�nh th��ng d�ng �i�n ch�y qua bao nhi�u ph�n

��nh m�c l� U1= 12V, U2 = 24V, khi s�ng b�nh th��ng c� �i�n tr� t��ng �ng l� R1

= 6( v� R2 = 4( C�n m�c hai ��n n�y v�i m�t bi�n tr� v�o hi�u �i�n th� U = 36V �� hai ��n s�ng b�nh th��ng.V� s� �� c�a m�ch �i�n T�nh �i�n tr� c�a bi�n tr� khi ��.* B�I T�P PH�N �I�N N�NGBa�i 1: Mo�t da�y da�n ba�ng nike�lin co� chie�u da�i 100m, tie�t die�n 0,5mm2 ����c ma�c va�o nguo�n �ie�n co� hie�u

�ie�n the� 120V.1/ T�nh �ie�n tr�� cu�a da�y.2/ T�nh c���ng �o� do�ng �ie�n qua da�y.H���ng da�n

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# EMBED Equation.3 ###1/ �ie�n tr�� cu�a da�y:# EMBED Equation.3 ###2/ C���ng

�o� do�ng �ie�n qua da�y:# EMBED Equation.3 ###

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##Ba�i 4: Cho ma�ch �ie�n nh� h�nh ve�:H���ng da�n

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1/ �ie�n tr�� t��ng ���ng cu�a R2 va� R3:# EMBED Equation.3 ###�ie�n tr�� t��ng

���ng cu�a ma�ch:# EMBED Equation.3 ### 6 = 36# EMBED Equation.3 ###2/ C���ng

�o� do�ng �ie�n qua ma�ch ch�nh:# EMBED Equation.3 ###Ma�: # EMBED Equation.3

###Ta co�: # EMBED Equation.3 ###V� R2 // R3 ne�n U2 = U3 = U2,3 Ta co�:# EMBED Equation.3 #### EMBED Equation.3 ###3/ t = 5 ph = 300sCo�ng do�ng �ie�n la�:A = UAB.I.t = 24 0,67 300 = 4 824J

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##Ba�i 5: Cho ma�ch �ie�n nh� h�nh ve�:H���ng da�n

Trang 15

1/ �ie�n tr�� t��ng ���ng cu�a R2 va� R3 la�:# EMBED Equation.3 ###�ie�n tr�� t��ng ���ng cu�a ma�ch:# EMBED Equation.3 ###2/ Hie�u �ie�n the� cu�a ma�ch:# EMBED Equation.3 ###Ta co�: # EMBED Equation.3 ### = 6V Ne�n ta co�:# EMBED Equation.3 #### EMBED Equation.3 ###Co�ng sua�t to�a nhie�t tre�n t��ng �ie�n tr��:P1 = # EMBED Equation.3 ###P2 = # EMBED Equation.3 ###P3 = # EMBED

Equation.3 ###

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Ba�i 6: Mo�t be�p �ie�n co� ghi 220V � 1000W ����c s�� du�ng v��i hie�u �ie�n the� 220V �e� �un so�i 2,5l�t n���c �� nhie�t �o� ban �a�u la� 20oC th� ma�t mo�t th��i gian la� 14phu�t 35 gia�y.1/ T�nh hie�u sua�t cu�a be�p Bie�t nhie�tdung rie�ng cu�a n���c la� 4200J/kg.K.2/ Mo�i nga�y �un so�i 5l�t n���c �� �ie�ukie�n nh� tre�n th� trong 30 nga�y se� pha�i tra� bao nhie�u tie�n �ie�n cho vie�c �un n���c na�y Cho bie�t gia� 1kWh �ie�n la� 800�o�ng.H���ng da�n

Trang 17

V� be�p ����c s�� du�ng �� hie�u �ie�n the� 220V �u�ng v��i hie�u �ie�n the�

��nh m��c cu�a be�p ne�n co�ng sua�t �ie�n cu�a be�p la� 1000W.1/ Nhie�t l���ng cung ca�p cho n���c:# EMBED Equation.3 ### (v��i # EMBED Equation.3 ###)= 2,5

4200 80 = 840 000JNhie�t l���ng be�p to�a ra:Q = I2.R.t = P.t (v��i t = 14ph 35s = 875s)= 1000 875 = 875 000JHie�u sua�t cu�a be�p:# EMBED Equation.3 ###2/Nhie�t l���ng be�p to�a ra mo�i nga�y lu�c ba�y gi��:Q� = 2Q = 2 875000 = 1750000J (v� 5l = 2 2,5l)�ie�n na�ng tie�u thu� trong 30 nga�y:A = Q�.30 =

1750000 30 = 52500000J = 14,6kWhTie�n �ie�n pha�i tra�:T = 14,6 800 = 11680

�o�ng

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Ba�i 7: Mo�t ho� gia ��nh co� ca�c du�ng cu� �ie�n sau �a�y: 1 be�p �ie�n 220V �600W; 4 qua�t �ie�n 220V � 110W; 6 bo�ng �e�n 220V � 100W Ta�t ca� �e�u ����c s�� du�ng �� hie�u �ie�n the� 220V, trung b�nh mo�i nga�y �e�n du�ng 6 gi��, qua�t du�ng 10 gi�� va� be�p du�ng 4 gi��.1/ T�nh c���ng �o� do�ng �ie�n qua mo�i du�ng cu�.2/ T�nh �ie�n na�ng tie�u thu� trong 1 tha�ng (30 nga�y) va� tie�n �ie�n pha�i tra� bie�t 1 kWh �ie�n gia� 800 �o�ng.H���ng da�n

Trang 19

1/ V� ta�t ca� du�ng cu� �e�u ����c s�� du�ng �u�ng v��i hie�u �ie�n the� ��nh m��c ne�n co�ng sua�t �a�t ����c ba�ng v��i co�ng sua�t ghi tre�n mo�i du�ng cu� Ne�n ta co�:# EMBED Equation.3 ###T��ng t�� t�nh ����c: I� = 0,45A va� Iq

= 0,5A2/ �ie�n na�ng tie�u thu� cu�a mo�i du�ng cu� trong 1 tha�ng:Ab = 1 Pb.t

= 1 0,6 4 30 = 72kWhAq = 4 Pq.t = 4 0,11 10 30 = 108kWhA� = 6 P�.t = 6 0,1 6 30 = 132kWhTo�ng �ie�n na�ng tie�u thu�:A = Ab + Aq + A� = 312kWhTie�n

�ie�n pha�i tra�:T = 312 800 = 249600 �o�ng

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#Ba�i 8: Cho ma�ch �ie�n nh� h�nh ve�:#H���ng da�n

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a/ �ie�n tr�� t��ng ���ng cu�a R2 va� R3# EMBED Equation.3 ###�ie�n tr�� t��ng

���ng cu�a ca� ma�ch# EMBED Equation.3 ###b/ Hie�u �ie�n the� gi��a hai �ie�m MN# EMBED Equation.3 ###So� ch� cu�a vo�n ke�# EMBED Equation.3 ###c/ Hie�u

�ie�n the� hai �a�u R1U1 = UMN � U2,3 = 25,14 � 17,14 = 8VCo�ng sua�t to�a nhie�t tre�n t��ng �ie�n tr��P1 = # EMBED Equation.3 ###P2 = # EMBED Equation.3

###P3 = # EMBED Equation.3 ###d/ t = 3ph = 180sNhie�t l���ng to�a ra tre�n toa�n ma�ch# EMBED Equation.3 ###T�nh ba�ng calo: Q = 0,24 9050,4 = 2172 cal

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�i�n n�ng, c�ng v� c�ng su�t, ��nh lu�t Jun - Len- X�1 Tr�n m�t b�ng ��n c�

b�ng ��n v�o hi�u �i�n th� 30V th� d�ng �i�n ch�y qua n� c� c��ng �� 0,75A.T�nh

�i�n tr� v� c�ng su�t �i�n c�a b�ng ��n khi �� T�nh nhi�t l��ng t�a ra � d�y

c� ghi 220V- 100W v� m�t b�n l� c� ghi 220V - 400W c�ng ���c m�c v�o � l�y �i�n 220V � gia ��nh a) T�nh �i�n tr� t��ng ���ng c�a �o�n m�ch n�y b) T�nh c��ng �� d�ng �i�n ��nh m�c c�a m�i b�ng ��n b) H�y ch�ng t� r�ng c�ng su�t c�a �o�n m�ch b�ng t�ng c�ng su�t c�a ��n v� c�ab�n l� c) T�nh �i�n n�ng ti�u th� c�a hai thi�t b� tr�n trong th�i Trong hai tr��ng h�p sau, t�nh c��ng �� d�ng �i�n qua m�i ��n v� cho bi�t ��n m�ch �i�n 240V.5 Tr�n m�t �m �i�n c� ghi 220V - 770W.T�nh c��ng �� d�ng �i�n

��nh m�c c�a �m �i�n.T�nh �i�n tr� c�a �m khi ho�t ��ng b�nh th��ng.D�ng �m n�y

�� n�u n��c trong th�i gian 30 ph�t � hi�u �i�n th� 220V T�nh �i�n n�ng ti�u th� c�a �m.6 Tr�n hai b�ng ��n c� ghi 110V- 60W v� 110V- 75W.Bi�t t�ng d�y t�c c�a hai b�ng ��n n�y ��u b�ng v�nfam v� c� ti�t di�n b�ng nhau H�i d�yt�c c�a

m�t ��ng c� �i�n c� ghi 220V - 850W.T�nh c�ng c�a d�ng �i�n th�c hi�n trong 45 ph�t n�u ��ng c� ���c d�ng � hi�u �i�n th� 220V.N�u hi�u �i�n th� ��t v�o ��ng b�ng ��n d�y t�c c� ghi 220V - 100W.T�nh �i�n n�ng s� d�ng trong 30 ng�y khi th�p s�ng b�nh th��ng b�ng ��n n�y m�i ng�y 6 gi�.M�c n�i ti�p b�ng tr�n ��y v�im�t b�ng ��n d�y t�c kh�c c� ghhi 220V - 75W v� hi�u �i�n th� 220V T�nh c�ng su�t ti�u th� c�a m�i ��n v� c�a c� m�ch Coi �i�n tr� c�a c�c b�ng ��n l� kh�ng

��i 9 M�t d�y d�n l�m b�ng v�nfam c� p = 5,5 10-8 (.m, ���ng k�nh ti�t di�n d

= 1mm v� chi�u d�i l� l = 40m, ��t d��i hi�u �i�n th� U = 24V.T�nh

�i�n tr� c�a d�y.T�nh nhi�t l��ng to� ra tr�n d�y trong th�i gian 40 ph�t theo

��n v� jun v� calo 10 D�y xo�n c�a m�t b�p �i�n d�i 12m , ti�t di�n 0,2mm2 v�

�i�n tr� su�t p = 1,1.10-6 (.m.T�nh �i�n tr� c�a d�y xo�n.T�nh nhi�t l��ng to�

ra trong 10 ph�t khi m�c b�p �i�n v�o hi�u �i�n th� 220V.Trong th�i gian 10 ph�t, b�p n�y c� th� �un s�i bao nhi�u l�t n��c t� nhi�t �� 25oC Cho nhi�t dungri�ng c�a n��c 4200J / Kg.K B� qua m�i s� m�t m�t nhi�t 11 M�t �m �i�n c� ghi 220V - 600W ���c s� d�ng v�i hi�u �i�n th� ��ng 220V �� �un s�i 2,2l�t n��c T� nhi�t �� ban ��u l� 27oC B� qua nhi�t l��ng l�m n�ng v� �m v� nhi�t l��ng to� v�o m�i tr��ng T�nh th�i gian �un s�i n��c

12 M�t b�p �i�n ho�t ��ng li�n t�c trong 1 gi� 30 ph�t � hi�u �i�n th� 220V Khi �� s� ch� c�a c�ng t� �i�n t�ng th�m 2 s� T�nh �i�n n�ng m� b�p �i�n s� d�ng, c�ng su�t c�a b�p �i�n v� c��ng �� d�ng �i�n ch�y qua b�p trong th�i gian s� d�ng trong 30 ng�y, m�i ng�y 4 ti�ng.M�c n�i ti�p b�ng ��n tr�n v�i m�t b�ng

��n kh�c c� ghi 220V - 75W v�o hi�u �i�n th� 220V T�nh c�ng su�t ti�u th� c�a m�i b�ng v� c�a c� m�ch Coi �i�n tr� c�a c�c b�ng ��n l� kh�ng ��i

Ch��ng ii �i�n t� h�cI ki�n th�c c�n nh� 1 Nam ch�m c� hai c�c: c�c B�c (N), c�c nam (S) Khi ��t hai nam ch�m g�n nhau ch�ng t��ng t�c v�i nhau: C�ng c�c ��y nhau, kh�c c�c h�t nhau.2 T� tr��ng l� kh�ng gian nam ch�m ho�c xung quanh d�ng �i�n c� kh� n�ng t�c d�ng l�c t� l�n kim nam ch�m 3 T� ph� cho ta h�nh �nh tr�c quan v� t� tr��ng Thu ���c t� ph� b�ng c�ch r�c m�t s�t l�n t�m b�a r�i g� nh� cho c�c m�t s�t t� s�p x�p tr�n t�m b�a.4 ���ng s�ct� ch�nh l� h�nh �nh c� th� c�a t� tr��ng C�c ���ng s�c t� c� chi�u x�c ��nh

5 Quy t�c n�m tay ph�i ( �p d�ng t�m chi�u d�ng �i�n, chi�u ���ng s�c t�)N�m b�n tay ph�i, r�i ��t sao cho b�n ng�n tay h��ng theo chi�u d�ng �i�n ch�y qua c�c v�ng d�y th� ng�n tay c�i cho�i ra ch� chi�u c�a ���ng s�c t� trong l�ng �ngd�y8 Quy t�c b�n tay tr�i ( �p d�ng t�m chi�u d�ng �i�n, chi�u c�a l�c �i�n t�,chi�u ���ng s�c t�)��t b�n tay tr�i sao cho c�c ���ng s�c t� h��ng v�o l�ng b�n tay, chi�u t� c� tay ��n ng�n tay gi�a h��ng theo chi�u d�ng �i�n th� ng�n tay c�i cho�i ra 900 ch� chi�u c�a l�c �i�n t�.9 C�ng su�t hao ph� do to� nhi�t tr�n ���ng d�y t�i �i�n.P = # EMBED Equation.3 ### �� gi�m hao ph� �i�n n�ng

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tr�n ���ng d�y t�i �i�n th� t�t nh�t l� t�ng hi�u �i�n th� ��t v�o hai ��u ���ngd�y n�y.10.M�y bi�n th� G�m hai cu�n d�y s� c�p n1 v� th� c�p n2 ��t c�ch �i�n v�i nhau trong c�ng m�t l�i th�p k� thu�t.N�u ��t v�o hai ��u cu�n s� c�p m�t hi�u �i�n th� xoay chi�u th� � cu�n th� c�p xu�t hi�n d�ng �i�n xoay chi�u:

# EMBED Equation.3 ### = # EMBED Equation.3 ### N�u n1 < n2 th� m�y c� t�c d�ng t�ng th� N�u n1 > n2 th� m�y c� t�c d�ng h� th�.B�i t�p �i�n t� h�c##1.T�m chi�u d�ng �i�n, chi�u l�c t�, c�c t� c�a nam ch�m trong c�c tr��ng h�p sau:### N S

#########

I #

F I

F I # F## S N#2 Ha�y xa�c

��nh c��c cu�a nam cha�m trong ca�c tr���ng h��p sau:#3 Ha�y xa�c ��nh ����ng s��c t�� cu�a t�� tr���ng o�ng da�y �i qua kim nam cha�n trong tr���ng h��p sau.Bie�t ra�ng AB la� nguo�n �ie�n:4 Ha�y xa�c ��nh c��c cu�a o�ng da�y va� c��c cu�a kim nam cha�m trong ca�c tr���ng h��p sau:# 5 Xa�c ��nh c��c cu�a nguo�n

�ie�n AB trong ca�c tr���ng h��p sau:###6 V��i qui ���c: Do�ng �ie�n co� chie�u t�� sau ra tr���c trang gia�y Do�ng �ie�n co� chie�u t�� tr���c ra sau trang gia�y.T�m chie�u cu�a l��c �ie�n t�� ta�c du�ng va�o da�y da�n co� do�ng �ie�n cha�y qua trong ca�c tr���ng h��p sau:##7 Xa�c ��nh c��c cu�a nam cha�m trong ca�c tr���ng h��p sau V��i F la� l��c �ie�n t�� ta�c du�ngva�o da�y da�n:8 Xa�c ��nh chie�u do�ng �ie�n cha�y trong da�y da�n trong ca�c tr���ng h��p sau:#9 Cu�n s� c�p c�a m�t m�y bi�n th� c� 4000 v�ng, cu�n th� c�pc� 250 v�ng

��t v�o hai ��u cu�n s� c�p m�t hi�u �i�n th� xoay chi�u 220 V th� � hai ��u

( 13.75V)

10 Ng��i ta mu�n t�i m�t c�ng su�t �i�n 4500W t� nh� m�y thu� �i�n ��n m�t khu d�n c� c�ch nh� M�y 65km Bi�t c� 1km d�y d�n c� �i�n tr� 0,8(.Hi�u �i�n th� gi�a hai ��u d�y t�i �i�nl� 25 000V T�nh c�ng su�t hao ph� v� to� nhi�t tr�n ���ng d�y.N�u c� �� hi�u �i�n th� hai ��u �o�n d�y t�i �i�n l� ( 336.96 W ; 4349306W) 11 M�t m�y ph�t �i�n xoay chi�u cho m�t hi�u �i�n th� � hai c�c c�a m�y l� 1800V mu�n T�i �i�n �i xa ng��i ta ph�i t�ng hi�u �i�n th� l�n 36 000V.H�i ph�i d�ng m�y bi�n th� c� c�c cu�n d�y c� s� v�ng theo t� l�

hi�n t��ng kh�c x� �nh s�ng - L� hi�n t��ng tia s�ng truy�n t� m�i tr��ng trong su�t n�y sang m�i tr��ng trong su�t kh�c b� g�y kh�c t�i m�t ph�n c�ch gi�a hai m�i tr��ng.- Khi tia s�ng �i t� kh�ng kh� sang m�i tr��ng trong su�t r�n, l�ng th� g�c kh�c x� nh� h�n g�c t�i- Khi g�c t�i t�ng (gi�m) th� g�c kh�c x� c�ng t�ng (gi�m) theo - Khi g�c t�i b�ng 00 th� g�c kh�c x� b�ng 00 (tia s�ng truy�nth�ng)Th�u k�nh h�i t� - C� ph�n r�a m�ng h�n ph�n gi�a.- M�t ch�m tia t�i songsong v�i tr�c ch�nh cho ch�m tia l� h�i t� t�i ti�u �i�m c�a th�u k�nh.3 tia s�ng ��c bi�t c�n nh�:Tia t�i qua quang t�m cho tia l� �i th�ng.Tia t�i song song v�i tr�c ch�nh cho tia l� �i qua ti�u �i�m.#Tia t�i �i qua ti�u �i�m cho tia l� song song v�i tr�c ch�nh ( ( (F' O F F' O F F' O F �nhc�a v�t t�o b�i th�u k�nh h�i t�.V�t ��t ngo�i kho�ng ti�u c� cho �nh th�t, ng��c chi�u v�i v�t.V�t ��t trong kho�ng ti�u c� cho �nh �o, c�ng chi�u v�i v�t.V�t � r�t xa th�u k�nh cho �nh th�t l� m�t �i�m n�m t�i ti�u �i�m.�� d�ng �nh A'c�a m�t �i�m s�ng A, ta v� 2 trong s� 3 tia ��c bi�t (� tr�n) xu�t ph�t t�

�i�m A, giao �i�m c�a hai tia l� (hay ���ng k�o d�i) l� �nh A'.�� d�ng �nh A'B' c�u AB qua th�u k�nh ( AB vu�ng g�c v�i tr�c ch�nh, A n�m tr�n tr�c ch�nh) ta ch� d�ng �nh B' c�a B r�i h� vu�ng g�c xu�ng tr�c ch�nh #########

##########################Th�u k�nh ph�n k�.- Th�u k�nh ph�n k� c� ph�n r�a d�y h�n ph�n gi�a.- Ch�m tia t�i song song v�i tr�c ch�nh

cho ch�m tia l� ph�n k�.2 tia s�ng ��c bi�t c�n nh�.- Tia t�i song song v�i tr�c ch�nh cho tia l� c� ���ng k�o d�i �i qua ti�u �i�m - Tia t�i �i qua quang t�m ti�p t�c �i th�ng 5 �nh c�a v�t t�o b�i th�u k�nh ph�n k�.- V�t ��t � m�i v� tr� tr��c th�u k�nh ph�n k� ��u cho �nh �o, c�ng chi�u, nh� h�n v�t v�

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lu�n n�m trong kho�ng ti�u c� - Khi v�t ��t � r�t xa th�u k�nh, �nh �o c�av�t l� m�t �i�m n�m t�i ti�u �i�m C�ch v� �nh qua th�u k�nh t��ng t� nh� c�ch v� �nh nh� c�ch v� �nh qua th�u k�nh h�i t�.M�y �nh.- M�i m�y �nh ��u c� v�t k�nh, bu�ng t�i v� ch� ��t phim.- V�t k�nh c�a m�y �nh l� m�t th�u k�nh h�i t�.-

�nh tr�n phim l� �nh th�t, ng��c chi�u, nh� h�n v�t.M�t- Hai b� ph�n quan tr�ng nh�t c�a m�t l� th� thu� tinh v� m�ng l��i.- Th� thu� tinh ��ng vai tr� nh� v�t k�nh trong m�y �nh, c�n m�ng l��i nh� phim.- �nh c�a m� ta nh�n th�y l� �nh th�thi�n tr�n m�ng l��i.- Qu� tr�nh �i�u ti�t l� qu� tr�nh th� thu� tinh co gi�n �� ph�ng l�n hay d�t xu�ng �� �nh tr�n m�ng l��i ���c r� n�t.- �i�m xa nh�t m� m�t nh�n r� ���c g�i l� �i�m c�c vi�n Cv, �i�m g�n nh�t m� m�t nh�n r� ���c l� �i�m c�c c�n Cc 8 M�t c�n - M�t c�n th� nh�n r� nh�ng v�t � g�n nh�ng kh�ng nh�n r� nh�ng v�t � xa K�nh c�n l� th�u k�nh ph�n k� - K�nh c�n th�ch h�p v�i m�t th� ti�u �i�m tr�ng v�i �i�m c�c vi�n 9 M�t l�o - m�t l�o nh�n r� nh�ng v�t � xa nh�ng kh�ng nh�n r� nh�ng v�t � g�n K�nh l�o l� th�u k�nh h�it� 10 K�nh l�p - L� th�u k�nh h�i t� c� ti�u c� ng�n d�ng �� quan s�t c�c v�t nh� - V�t c�n quan s�t ���c ��t trong kho�ng ti�u c� �� cho �nh

�o l�n h�n v�t M�t nh�n th�y �nh �o.#V� d�1 Tr�n h�nh v� ch� c�c tia t�i th�u k�nh v� c�c tia l� ra kh�i th�u k�nh.# H�y v� th�m cho �� c�c tia t�i v� c�ctia l�.##

F O F' V� d� 2 ��t �i�m s�ng S tr��c m�t th�u k�nh h�i t� nh� h�nh v� # H�y v� �nh S' c�a S qua th�uk�nh

S

F O FV� d� 3 ��t v�t s�ng AB tr��c th�u k�nh h�i t� nh� h�nh v� H�y v� �nh c�a AB qua th�u k�nh �nh thu ���c l�

F A O F'V� d� 4 ��t v�t AB vu�ng g�c v�i tr�c ch�nh c�a m�t th�u k�nh h�i t� f = 18cm, c�ch th�u k�nh m�t kho�ng d =

r�ng chi�u cao c�a �nh v� c�a v�t b�ng nhau.V� d� 5 ��t v�t AB vu�ng g�c v�i tr�c ch�nh c�a th�u k�nh h�i t�c� ti�u c� f = 20cm, sao cho �i�m A n�m tr�n tr�c ch�nh v� c�ch th�u k�nh m�t kho�ng d H�y x�c ��nh t�nh ch�t (th�t hay �o) c�a �nh trong c�c tr��ng h�p : a) d = 30cm b) d

= 10 cm.#.S*V� d� 6 H�y v� tia l� c�a c�c tia t�i h�nh b�n

F O F� V� d� 7: Cho h�nh v� nh� b�n: S�*#b)V� sao bi�t th�u k�nh �� cho l� th�u k�nh ph�n k�c)B�ng c�ch v�, h�y x�c

��nh quang t�m O, hai ti�u �i�m c�a th�u k�nh �� chob�i t�p v� th�u k�nh B�i 1

��t v�t AB vu�ng g�c v�i th�u k�nh h�i tu c� ti�u c� f = 17cm, th� th�y �nh A'B'c�a AB l� �nh th�t v� cao b�ng v�t H�y x�c ��nh v� tr� c�a v�t v� �nh

so v�i th�u k�nh B�i 2 ��t v�t AB vu�ng g�c v�i tr�c ch�nh c�a th�u k�nh h�i t� c� ti�u c� f = 30cm, th� th�y �nh A'B' c�a AB l� �nh th�t v� cao g�p

2 l�n v�t H�y x�c ��nh v� tr� c�a v�t v� �nh so v�i th�u k�nh B�i 3 ��t v�t ABvu�ng g�c v�i th�u k�nh h�i t� c� ti�u c� f v� c�ch th�u k�nh 28cm th� th�y �nh l� th�t v� cao b�ng n�a v�t H�y x�c ��nh ti�u c� c�a th�u k�nh B�i 4

��t v�t AB vu�ng g�c v�i tr�c ch�nh c�a m�t th�u k�nh h�i t� c� ti�u c� f = 40cm Nh�n qua th�u k�nh ta th�y �nh A'B' cao g�p 2 l�n AB.H�y cho bB�i 5 V�t AB ��t vu�ng g�c v�i tr�c ch�nh c�a m�t th�u k�nh h�i t� cho �nh th�tA'B' cao b�ng v�t v� c�ch v�t 64cm H�y x�c ��nh ti�u c� c�a th�u k�nh.B�i 6 ��t v�t AB tr��c m�t th�u k�nh v� c�ch th�u k�nh m�t kho�ng 30cm th�

�nh A'B' c�a AB ch� cao b�ng n�a v�t H�y t�nh ti�u c� c�a th�u k�nh.B�i 7 Qua th�u k�nh h�i t�, v�t AB cho �nh A'B' = 2AB.�nh A'B' l� �nh th�t hay c�a v�t AB.B�i 8 ��t v�t AB vu�ng g�c v�i th�u k�nh ph�n k� sao cho A n�m tr�n tr�c ch�nh v� c�ch th�u k�nh 30cm th� �nh c�ch th�u k�nh 18cm.T�nh ti�u c� c�a th�u k�nh b) Bi�t AB = 4,5cm T�m chi�u cao c�a �nh.B�i

9 ��t v�t AB tr��c th�u k�nh h�i t� c� ti�u c� f = 25cm, Cho �nh A'B', bi�t

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r�ng khi d�ch chuy�n v�t l�i g�n th�u k�nh m�t kho�ng 5cm th� �nh A'B' c� �� caob�ng v�t X�c ��nh v� tr� �nh ban ��u c�a v�t.B�i 10 ��t v�t AB tr��c m�t th�u k�nh ph�n k� c� ti�u c� 36cm cho �nh A'B' c�ch AB m�t kho�ng 48cm H�y x�c ��nh v� tr� c�a v�t v� �nh.B�i 11 H�nh b�n cho bi�t: ( l� tr�c ch�nh c�a m�t th�u k�nh, S S l� �i�m s�ng, S' l� �nh c�a �i�m s�ng S t�o b�i th�u (# k�nh �� B�ng c�ch v�, h�y x�c ��nh quang t�m O, hai ti�u �i�m F v� F' c�a th�u k�nh �� l� C�u h�i nh� b�i 11 S'

S ( # SB�i 13 C�u h�i nh� b�i 11 S' (#B�i 14 H�nh b�n cho bi�t: AB l� v�t, A'B' l� �nh c�a AB,( l� tr�c ch�nh c�a th�u k�nh B�ng ph�p v�,h�y B##x�c ��nh v� tr� ��t th�u k�nh v� c�c ti�u

�i�m c�a th�u

A B' B�i 15 ��t v�t AB vu�ng g�c v�i th�u k�nh ph�n k� v� c�ch th�u k�nh 60cm th�

�nh A'B' ch� cao b�ng 1/ 3 v�t T�nh ti�u c� c�a th�u k�nh B�i16 V�t AB vu�ng g�c v�i tr�c ch�nh, A n�m tr�n tr�c ch�nh c�a m�t th�u k�nh ph�n k�c� ti�u c� f = 16cm Bi�t �nh A'B' ch� cao b�ng 1/ 3 v�t AB X�c ��nh v�tr� c�a v�t v� c�a �nh B�i 17 V�t AB cao 8cm ��t tr��c th�u k�nh ph�n k� v� c�ch th�u k�nh 16cm cho

�nh A'B' = 2cm.T�nh ti�u c� c�a th�u k�nh.Mu�n �nh A'B' cao 6cm th� ph�i d�ch

�nh ��ng c�ch m�y �nh 6cm Ng�i �y cao 1,72m Phim c�ch v�t k�nh ch�p �nh c�a v�t cao 140, ��t c�ch m�y 2,1m Sau khi tr�ng phim th� th�y �nh cao 2,8cm.T�nh kho�ng c�ch t� phim ��n v�t k�nh l�c ch�p �nh.T�nh ti�u c� c�a th�u k�nh �� d�ng l�m v�t k�nh c�a m�y �nh

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