solution manual chemical reaction engineering 3rd Octave Levenspiel

solution manual chemical reaction engineering 3rd Octave Levenspiel solution manual chemical reaction engineering 3rd Octave Levenspiel solution manual chemical reaction engineering 3rd Octave Levenspiel Bài giải bài tập kỹ thuật phản ứng

SOLUTUONS MANUAL,

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JOHN WILEY & SONS, INC

NEW YORK « CHICHESTER » WEINHEIM « BRISBANE + SINGAPORE * TORONTO

Copyright © 1999 by John Wiley & Sons, Inc

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Heat added ahead of the reactor

O.= Eh, Cp AT = (100) (40) (700-300) z2-4niP TZ

aaa

xa

Heat removed from the reactor

Qa = Ty XA Í-AHr) + FA Cp lav)

CONES 20% A- 80% inert, adiabatic reactor A

slope = —e _ #+0x5 _ _ |

~TAHc 90ooo “09 Let us construct = VS Xa graph ,

From this graph we can See that recycle

_ the ch Q= For Cp AT Dà,Xa (-Anr) & chart

et rhe opt oF rectangles 2sp Reaction rate is Wo of that

Ỳ SUaa#4E whee to locate in the chart, I

= lL#xto?° 3% Cheating) \ [ Slope “in

Qa = FaoCp (ar) = (20)(200) (670-930) p.3St - eer xã

=-O84 x10 T/s5 (cool ing ) /

Note that this solution was obtained

after a Few trials

Aook 2A 650K

058 - -<

' {

Injection of cold feed

Fraction of feed A that

goes to the first reactor

Wa = fa, area2 =($)(221) =

A= Fay, Cp (AT) = (5x 0.7831) (800) (699 -300)= [22x10 I< (heating)

Neke: Only one heaf axchan ger i> Needed wm crs desig he

K 200 Even ve to Xez®4 we have the

the ex pre: So cous & hats Qe EUWE loa

guess XgS 40, Cy = AOA fw? J hon check Ib at the ect

ÊvaluaF€ quauhities needed to {24 the rate

th 5 “197? (714007 -5MìoO, a M+ = Lb | a Satter G dt \SO0) = 2 bu là ia se 6

& Atle % tg? ? New ky the cake 24 vabum,

Qui eơnelav# Pa throughout ne trrelele bed and will, the rake

inde penderk as <8 the weaFerval balance becomes vevy aimale, as cacy

Fay A = Teo Xe =¢ hy Vr

Ves = Ủy Coo -Ípx TU_C = 0,084\/s

Coweoav ` ise ‹2@ Heol

Cam Ca

the vghout tho vu,

Ose the equations Fow tle Ce >> Cy echeme

Ugeles sales = use these teyvms to wheavahe

maternal loalance prt "4 ‘i Ene A

Š THHEDnt0imtticivdktZkiireiranrdiartrsa-krỄ cư

7) pm | VN Test the 2 possible shrinks = —= CĐr© mechanisms to See Wheel eS

Consistent with the Followma naparted date

Xp =O.Q1S at t=thy | +

sor Xg = 2 af =e OS

Since the shape of the solids is not specified assume to start

wil Lat Theu are sphencal , Then From “Table 1

masse

IF ma đ(foseen controls: 4 = Xe

2 l but from the data: OS £0375 - this doestt a vee 50

Wwe reyect ths

mechanim

\F ash diffusion controls: = = |- 3(i-X,) 7+ 2(-Xe) 2 |

again From thedata OS = \- 3(b)% 420%) = OS - this

Carers

New before Wwe feel that all is solved let us try the thud

mechansin , Who kywdws maybe “oe Too will tt, So

& aaw from the data: OF = |= (Ye \’3 Iv

reaction & ash Atfoscin mechanisms it the data |

Note ~ Figuce FG oc JO shows that the data Were taken at

the precise powt wheve the asl Affusion Curve

cyosses the reactiin controlling, Cure ,

~\F we try the 2quations for Flat plate or cylindrical

pellets we find tat neither will fit tre data.

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