HD cham KSCL 3 mon Toan-Văn-Anh TP . Ha noi 2016

HD cham KSCL 3 mon Toan-Văn-Anh TP . Ha noi 2016 tài liệu, giáo án, bài giảng , luận văn, luận án, đồ án, bài tập lớn về...

DAP AN, HI /6NG DAN CHAM

diem

B a i l

2,0 diem

1

diem

B a i l

2,0 diem

1

Thay x = 4 (thoa man dieu kien) vao bieu thurc A 0,25

B a i l

2,0 diem

1

Ti'nh duac A = —

B a i l

2,0 diem

_ , , i , , „ 2Vx x + 12vx

Rut eon bieu thuc B = —==

V x - 4 x-16

1.0 diem

B a i l

2,0 diem

2

2%/x x + \2\fx

V x - 4 ( V x - 4 ) ( ^ + 4)'

2\/x(Vx+4) X + 12N/X

( V x - 4 ) ( V x + 4 ) (>/x-4)(>/x+4)"

0,25

B a i l

2,0 diem

2

2x + 8\/x-x-12\/x (>/x-4)(>/x+4)

x - 4 V x ( V x - 4 ) ( 7 x + 4 ) "

0,25

B a i l

2,0 diem

2

( V x - 4 ) V x ( V x - 4 ) ( V x + 4 ) '

0,25

B a i l

2,0 diem

2

B a i l

2,0 diem

3 Tim x de — = — ^ A 5

B 6

0.5 diem

B a i l

2,0 diem

3

V r t i Y ^ 0 v o Y 1*- 1 ^ t i e n ^ — ^ ^ — ^ ^_< V U l A / u V a A ^ 1 U L a C U — v v , — s—/ O V X + t - J V A T J 1 {*( - fv i /t ^ — S f-i /Y" I S \

B 6 6 ^ ; V /

0,25

B a i l

2,0 diem

3

Bai II

2,0 diem

7 ^ 7

Goi khoi lugng hang moi xe du dinh phai cha luc dau la x (tan)

Dk: 0 < x < 1 0 0

0,25

Bai II

2,0 diem

Suy ra so xe du dinh luc dau cua doi la — (xe) 0,25

Bai II

2,0 diem

Khoi lugng hang moi xe phai cha khi dugc bo sung la ( x - l ) ( t a n )

So xe khi duac bo sung cua doi la (xe)

x - 1

0,5

Bai II

2,0 diem

Theo de bai so xe cua doi tang them 5 xe nua nen ta co pt

100 100 _5

x - 1 X

=> 5x(x-l) = lOOx-100(x-l)

o x2 - x - 2 0 = 0

0,5

Bai II

2,0 diem

Bai II

2,0 diem

K I : Luc dau moi xe cua doi phai cha 5 tan hang

0,25

Bai III 1 Giai he phirang trinh:

2,0 diem f 1 2

x + 3 y-l

- + =6

1j° diem

x + 3 y - l

Ta tim duac

1

x + 3

1

3

X _ 8

3

2 Ket luan he co nghiem (x;y) 8 2^

3 ' 3y

0,25

Tim m de dircmg thang (d) cat Parabol (P) 1,0

diem Hoanh do giao diem cua (d) va (P) la nghiem cua pt

1 2 1 2 1

— x = mx — m + —

2 2 2

<+> x2 = 2mx-m 2 +1

<=> x2 -2mx + m 2 - 1 = 0 (1)

0,25

A' = m 2 - (m 2 -1) = 1 > 0 Mm nen pt (1) luon co hai nghiem phan biet

x,;x2 voi moi m suy ra (d) luon cat (P) tai hai diem phan biet voi moi

m

Ap dung V i -et cho pt (1) ta co

fx, + x2 = 2m (1)

0.25

m -1 (2)

x, - 2x2 = 0 o x, = 2x2

2x2 + x2 = 2m

2x 1 • x2 = m - 1

3x2 = 2m

2x2 = m 2 •

_ 2m

21 f J-rf-1 («)

(*)<=> 2 2m

2

= 77?

-0,25

o 2 = m -1

o 8m2 =9m2 - 9

o m2 = 9 <e> m = ±3

3,5 diem

Ta co : BEC = 90° (BE 1 A C ) ; BFC = 90° ( C F 1 AB) Xet tu giac BFEC co : BEC = BFC = 90°

Suy ra tu giac BFEC noi tiep

0,25 0,25 0,25 0,25

2)

3)

4)

Chung minh PQ//EF

Vi tu giac BFEC la tu giac noi tiep nen FEB=FCB (2 goc noi tiep cung chan cung FB)

Xet (O) co : PQB = PCB (hai goc noi tiep cung chan cung PB) Suy ra FEB = PQB , ma 2 goc nay 6 vi tri dong vi

PQ // EF

Chung minh FDE = 2ABE vd FDE = FIE

Tarn giac ABC co H la true tarn nen A H vuong goc voi BC tai D

Chung minh tu giac BFHD noi tifip suy ra FDH = FBH Chung minh tu giac DHEC noi tiep suy ra H p E = HCE

Ma ABE = ACF nen FDH = HDE => FDE = 2FDH hay FDE = 2ABE

1 diem

0,25 0,25 0,25 0,25

1 diem

0,25 0,25

Do I la trung diem cua BC nen I la tarn ducmg tron ngoai tiep tu giac BFEC Khi do FIE = 2FBE( goc a tarn va goc noi tiep cung chan EF) 0,25

Xdc dinh vi tri diem A de 0,5 diem

Ta co ABE = ACF (cung phu BAC ) =e> AQ = AP => AO 1 PQ

Ma PQ // EF (cmt) => AO 1 EF Chung minh tuomg tu ta co BO 1 D F / C O 1 ED

1 1 1

0,25

SA E 0 F + SB F 0 D + SC D 0 E = - AO.FE + - OB.FD + — OC.ED

= -R.(FE + ED + DF)

^>FE + ED + DF= 2 S a b c

R

Vi R khong doi nen (FE + ED + DF) Ion nhat o SABC Ion nhat

o AD Ion nhat (do BC khong doi) o A la diem chinh giua cung Ion BC

0,25

Bai V

0,5 diem

T u x J +y J +3(x 2 +y J )+4(x+y)+4=0

<=> (x+l) 3 +(y+J) 3 +(x+y+2)=0

<=> (x+y+2)[(x+l) 2 -(x+l)(y+l)+(y+l) 2 +l]= 0

Chung minh: (x+1) 2 - (x+l)(y+I) + (y+l) 2 +l>0 v o i moi x; y

=> x + y— -2

0,25

1 ( 1 x + y - 2

x y xy xy

(x + y) > 4xy o 4 > 4xy o — > l o — < -2

xy xy

Vay G T L N cua M = - 2 khi x = y = - l ( tm xy>0)

0,25

Lim y: - Diem loan bai de le den 0,25

- Cdc each lam khdc neu dung van cho diem toi da

- Bai IV: Thl sinh ve sai hinh trong pham vi cdu ndo thi khong tlnh diem cdu do

Sd GIAO DUC VA DAO TAO KHAO SAT CHAT LI/0NG HOC SINH L0P 9-THCS

Hl/CJNG DAN CHAM KHAO SAT CHAT LI/0NG HS L0P 9-THCS MON N G 0 V A N

Ngay khao sat: 23/4/2016

Phan I (6,5 diem)

Cau 1

(1,03)

HS neu dung: - Ten tac gia: Vien Phuong (Phan Thanh Vien)

- Cau cam than: Oi !

0,5 0,5

Cau 2

(1,03)

HS neu dugc: "hang tre bat ngat" (cau 2) co y nghia thuc, "cay tre trung hieu" co y

nghia tugng trung (an du) cho khat vong cua nha tha 1,0

Cau 3

(1,03)

HS neu dung: ten bai tha co ket cau tuang tu va ten tac gia (Doan thuyen danh ca

-Huy Can, Ong do - Vu Dinh Lien, Khi con tu hu - To Huu ) 1,0

Cau 4

(3,53)

HS hoan thanh doan van dien dich:

- Ma doan: dat yeu cau ve hinh thuc, noi dung

- Than doan: biet bam vao ngtr lieu, khai thac hieu qua cac tin hieu nghe thuat, co

dan chung, li le lam ro tarn trang, cam xuc cua nha tha trong 4 cau tha:

+ Tarn trang mong moi the hien qua each xung ho, thai do

+ Cam xuc trao dang dugc ra tham lang, cam nhan sue song cua hang tre, dan toe

# Dung y, dien dat duac song y chua that sdu 1,5d

# Dien xuoiy tha, dai dong, con mac mot vai loi dien dat 1,0d

# Y qua sa sai, nhieu loi dien dat 0,5d

# Chua the hien duac phan lan soyhoac sai lac ve noi dung, dien dat kem 0,25d

GK can cu vao muc diem tren de cho cac diem con lai

- Su dung phep noi de lien ket (dung, co gach duoi)

- Co mot cau ghep (dung noi dung va hinh thuc, co gach duoi)

Doan van qua dai (qua ngdn) hoac nhieu doan (sai kieu doan) trie 0,5 diem

0,5

1,0 1,0

0,5 0,5

Ph§n II (3,5 diem)

Cau 1

(0,753)

HS neu dung:

- Nam sang tac: 2001

- Y nghia dac biet: thoi dilm chuyln tiep giua hai the ki, hai thien nien ky

0,25 0,50

Cau 2

(0,753)

HS giai thich dugc: thS ki XXI thS ki cua khoa hoc-cong nghe, lap tre co nhieu thoi

gian, dieu kien hgc tap, ren luyen va trau doi kien thuc, cong hien cho dat nude 0,75

Cau 3

(2,03)

HS phai dam bao nhung yeu cau ve:

- Noi dung:

+ Nhan thuc dung ve mot thoi quen tot dep; thay dugc y nghia, vai tro va neu dugc

suy nghT ve mot thoi quen tudng nhu nho be ay trong cuoc song cua moi ca nhan,

cua ngudi Viet Nam trong nhjp song hien nay, tir do cd nhung lien he can thiet

- Hinh thuc: la mot doan van nghi luan (tu chgn kieu lap luan), cd su ket hop vdi cac

phuong thuc bieu dat, diln dat sinh dpng, do dai theo quy dinh,

Limy: Khuyen khich HS cd suy nghT rieng, tuy nhien phai li giai hgp li, thuyet phuc

Phkn lien he can chan thanh Khong cho diem doan cd suy nghT lech lac, tieu cue

N6u doan van qua dai hoac qua ngan hoac nhieu doan trir 0,5 diem

1,5

0,5

1 * ^ * 9

Luu y : - HS co each dien dat khdc ma dam bao du y thi van cho diem

- Diem toan bai la tong diem thanh phan, le den 0.25, khong lam trdn so

PHONG GD&DT ME LINH KHAO SAT CHAT LlfONG NAM HOC 2015-2016

HUONG DAN CHAM MON: TIENG ANH 9

A GRAMMAR - V O C A B U L A R Y - LANGUAGE FUNCTIONS (4.0pts)

/ Choose the best option A, B, C or D which best completes or responds to each sentence (3.0 pts)

II Complete the sentences by writing the correct tense of the verbs in blankets(l.Opt)

16 bought 17 gets 18 was cleaning 19 has used/ has been 20 doesn't come

using

B READING (4.0pts)

/ Read the following passage and decide which option A, B, C or D best fits each space (2.0

// Read the following passage and choose the best answers (2.0 points)

C WRITING (2.0pts)

31 We have learned/learnt (have been learning ) English for four/4 years

32 Ba is the tallest (person/one/student/boy) in my class

33 Trung was given a computer on his birthday (by his parents)

34 Peter told me that Nam was working in Ho Chi Minh city then

35.1 wish (that) I could speak English perfectly