Bµi 10 d¹ng I
C1=
1
4 kd
s
π
ε C
2=
2
4 kd
s
π
ε
2 1
1 1 1
C C
s
kd
ε
π 1
4 +
s
kd
ε
π 2
4 =
s
d d k
ε
π ( )
4 1+ 2 =
s
kd
ε
π
4
=
C
1 → T1 =T/
Bµi 8 d¹ng III
I=
1 3
12
/ = +
+r
r
Bµi 3 d¹ng IV
A.λ/= λ
6
5
B.λ/= λ
5
6
B.λ/ = λ
3
4
C.λ/ =
4 3
C1= C3=
3
4 k d
s
π
ε
=
kd
s
π
4
1
3 = 3C
C2=
3
4
.
/
d
k
s
π
ε
=
kd
s
π
4
2
3 =
kd
s
π
4
6 = 6C
3 2
1
1 1
1
1
C C
C
5
6C →λ/=c.T =c.2 π LC B
B
C
C
=
/
λ
6
5 →λ/= λ
5
6
Bµi 6 d¹ng IV
= +
=
+
= +
+
= +
=
−
−
−
m C
L
c
F C
C C
C
20 10
).
10 (
2
.
10 ).
10 (
10 ) 0 10 ( 6 0
1
6 0
6 0
1 0
1
π
λ
= +
=
+
= +
+
= +
=
−
−
−
10 20 10
).
190 (
2
.
10 ).
190 (
10 ) 180 10 ( 6 0
2
6 0
6 0
2 0
2
C L
c
F C
C C
C
π
λ
190
10
0
0
2
1
+
+
=
C
C
λ
λ
10
1 →
10
1 190
10 0
+
+
C C
→ C0= 10 pF