Check: We note that the Plane Stress case reduces to our first order estimate for θ = 0.. Also note that KI/ σys2 has dimensions of length.. Next we will compare the extent of the plast
Trang 1Substitute the known expression for σ xx, σ yy and σ xy
in the Mode I crack problem (derived last time) and
find that:
2
sin
1 2
cos 2
1
r
K I
K
(plane strain); σ3= 0 (plane stress)
2
cos 2
2 3
r
K I
2
sin
1 2
cos 2
2
r
K I
Trang 2Substitute in to the Mises yield condition:
Plane strain:
2
2
2 cos
1 2
1
sin 2
3
I
r
K
Plane stress:
2 2
2
2 cos
sin 2
3 1
I
r
K
Trang 3These expressions can be used to solve for the radius
of the plastic zone rp as a function of θ:
Plane strain:
2
3 4
2
I p
K r
p
Plane stress:
2
I p
K r
Trang 4Check: We note that the Plane Stress case reduces to
our first order estimate for θ = 0.
Also note that (KI/ σys)2 has dimensions of length
Next we will compare the extent of the plastic zone
Next we will compare the extent of the plastic zone
in the two situations, plane stress and plane strain,
for two cases, θ = 0 and θ = 45˚.
Trang 5For θ = 0, ,
3
1
1
stress plane
r
strain plane
r p p
For θ = 45˚, ,
3
1
1 381
.
stress plane
r
strain plane
r
p p
3
Extent of the plastic zone is significantly larger for the
plane stress case.
Trang 6Plastic Zone Shape Plane stress/plane strain
Trang 7Plastic Zone Shape Plane stress/plane strain
Trang 8Plastic Zone Size Engineering Formulae
1
ys
I p
K r
For Plane Strain:
For Plane Strain:
2
3
1
ys
I p
K r
Similar analyses can be done to determine the plastic zone size and shape for Mode II and Mode III loading
Trang 9Specimen Thickness Effects
Plane stress/plane strain
Trang 10Meaning of ς
Recall the Strain Energy Release Rate ς
What does it physically represent? It is the rate of
decrease of the total potential energy with respect to crack length (per unit thickness of crack front),i.e
a
PE
What is the connection between ς and K?