CHAPTER 5Transistor Circuits: OBJECTIVES ppt

Because a transistor’s beta varies 2 to 1 or more from device to device, biasing circuitry needs to be designed so that the Q-point is not a function of beta.. Likewise, the gain of a tr

CHAPTER 5

Transistor

Circuits

OBJECTIVES Describe and Analyze:

• Need for bias stability

• Common Emitter Amplifier Biasing

• RC-coupled Multistage Amplifiers

• Direct-Coupled Stages

• Troubleshooting

Introduction

The DC bias values for VCE and Ic are collectively called the “Q-Point” Because a transistor’s beta

varies 2 to 1 or more from device to device, biasing circuitry needs to be designed so that the Q-point is not a function of beta

Likewise, the gain of a transistor amplifier should not depend on beta Gain should be set by the values of external components such as resistors

Beta Changes with

Temperature

Not only does it vary from device to device, beta is also strongly dependent on

temperature

Voltage Divider Biasing

• Choose Rb1 & Rb2 so that: Rb1 || Rb2 <<  Re for the worst-case value of beta

• Vb is fixed by Rb1 and Rb2, and: Ve = Vb – 0.7V

• Re >> r’e Therefore Ic = Ie = Ve / Re

Biasing Example

For a circuit like the one on the previous slide, calculate Vb,

Ve, Ie, Ic, Vc, and Vce given:  = 50

Vcc =12V, Rb1 = 100k, Rb2 = 20k, Rc = 4k, Re = 2k,

Vb = [Rb2 / (Rb1 + Rb2)]  Vcc = 12V / 6 = 2 Volts

Ve = Vb – 0.7 = 2 – 0.7 = 1.3

Ic = Ie = Ve / Re = 1.3V / 2k = 0.65 mA

Vc = Vcc - Rc  Ic = 12V – 4k  1.3mA = 6.8V

Vce = Vc – Ve = 6.8V – 1.3V = 5.5V

r’e = 25mV / Ie = 25mV / 0.65mA = 38.5 Ohms

Is Re >> r’e? Is 2000 >> 38.5 ? Yes!

Input Impedance

Zin will not depend on  if: Rb1 || Rb2 << Re

Voltage Gain: Unbypassed Re

Av = rc / Re where rc = Rc || RL Gain is stable but low

Voltage Gain: Bypassed Re

Av = rc / r’e where rc = Rc || R L But r’e = 25mV / Ie

Gain is high, but changes with the signal current

Voltage Gain: Compromise

A trade-off between high gain and gain stability

Emitter Biasing

Very stable Q-point, but requires two voltage supplies

Emitter Bias Example

For a circuit like that of the previous slide, calculate

Ie, Ic, Ve, Vc, Vce given

Since, effectively, Vb is zero, Ve = -0.7V

Ie = (Ve – Vee) / Re =11.3V / 10k = 1.13mA

Ic is about the same as Ie, so Ic = 1.13mA

Vce = Vc – Ve = 6.7V – 0.7V = 6.0 Volts

Voltage-Mode Feedback

Can never saturate or cut off High gain Limited Vce

RC-Coupled Stages

Circuit is no longer used, but illustrates the principle

Choosing Capacitors

Key Idea:

Compared to the values of Zin and Zout, the

reactances of the capacitors (Xc) should be negligible

in the frequency range the input signals

• Xc = 1 / (2fC)

• Xc << Zin and Xc << Zout

Xc Compared with Zin or Zout

What ratio of Z to Xc is required to say that Xc is negligible

compared to Zin or Zout? Not as high as you might assume Zin and Zout are determined by resistors Let Zx be the sum of

Xc and R But remember, it’s a vector (phasor) sum: Zx = sqrt[

R2 + X2 ]

Let Xc be about a third of R That is, Xc = 3R

Then Zx = sqrt[ R2 + 09R2 ] = R  sqrt(1.09) = 1.04R

So there is only a 4% effect if Xc is as big as a third of Zin or Zout

A Numerical Example

The first stage of a two-stage amplifier has an output

impedance of 2k The input impedance of the second stage is 4k The frequency range is 50 Hz to 5000 Hz Select a

coupling capacitor

Since Zout < Zin, we will compare Xc to Zout to be

conservative

Let Xc = 3  Zout = 3  2k = 600 Ohms

Xc is highest at the low end of the frequency range

Xc = 1 / 2 f C => C = 1 / 2f Xc

C = 1 / 6.28  50  600 = 5.3 uF

A 10 uF electrolytic capacitor should do nicely

Direct Coupled Amplifiers

Having PNP as well as NPN transistors allows us to do

away with coupling capacitors

Gain of a Multi-Stage Amp

Suppose you have two single-stage amplifiers, each with a voltage gain of 20 If the stages are coupled

Not necessarily In fact, probably not!

The problem is that Zin of stage two “loads down” the output of stage one With a transistor amp, the Zin of the second stage is effectively in parallel with the Rc of the first stage So the voltage gain (Av) will be:

Av = (Rc || Zin) / Re

Troubleshooting

• Check the power-supplies, but keep your fingers off any high-voltage that may be present

• Check the DC bias levels with no signal applied

• Check for shorted capacitors

• Check for open capacitors

• Try signal tracing using amplifier’s “normal” input

• Try signal tracing with an injected signal

• Try disconnecting one stage from the next, but

remember to use resistors to simulate Zout