We have Using ground roughness category 3, Class B, with height of thebuilding=21.0m, from Table 3, CP3, Chapter V: Part 2 Therefore design wind speed is and dynamic wind pressure is Fro
Trang 1Table 12.1 Loading on wall A per metre run
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Trang 2Table 12.1 (Contd)
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Trang 4Table 12.2 Loading on wall B per metre run; inner leaf
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Trang 6walls will provide the resistance to wind loading In an actual design, thedesigner must of course check that the structure is safe for wind blowingeast-west and vice versa.
In the calculation below it has further been assumed that the walls act
as independent cantilevers; and hence moments or forces areapportioned according to their stiffness
12.5.2 Wind loads
These are calculated according to CP 3, Chapter V: Part 2 We have
Using ground roughness category 3, Class B, with height of thebuilding=21.0m, from Table 3, CP3, Chapter V: Part 2
Therefore design wind speed is
and dynamic wind pressure is
From Clause 7.3, CP3, Chapter V: Part 2, total wind force
The total maximum bending moment is
total max BM=F×h/2 where h is the height under consideration Total BM just above floor level
is given for each floor by:
Trang 7Fig 12.3 The variation of the factor S2 and the wind velocity along the height of the building (Assumptions made in the design shown in full lines.)
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Trang 812.5.3 Assumed section of wall resisting the wind moment
The flange which acts together with the web of I-section is the lesser of
• 12 times thickness of flange+thickness of web
• centre line to centre line of walls
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Trang 9Table 12.3 Distribution of bending moment stresses and shear force in walls
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Trang 1512.6.2 Selection of brick and mortar combinations for wall
Trang 16(Table 7 of BS 5628), m=3.5 (see section 12.3) The design loads from theprevious subsection and the characteristic strengths are shown in Table12.4 along with the suitable brick/mortar combinations.
Check for shear stress: design characteristic shear fv=f mv (shear force/
area) < 0.35 +0.6gA (clause 25), f=1.4 and mv=2.5 (12.3) The value ofshear force is taken from Table 12.3 For the sixth floor
For the ground floor
There is no need to check at any other level, since shear is not a problemfor this type of structure
The BS 5628 recommends gA as the design vertical load per unit area ofwall cross-section due to vertical load calculated from the appropriateloading condition specified in clause 22 The critical condition of shearwill be with no imposed load just after and during the construction
12.6.3 Load combination, wall B
The design principle has been covered in great detail for wall A; hencefor wall B this will be limited to the ground floor level to explain furthersalient points
Inner leaf wall B –ground floor level
(i) Dead and imposed loads
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Trang 17Table 12.4 Design load and characteristic brickwork strength
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Trang 18The worst combination for this wall just above ground level also isdead+wind, and the design load is (1.96×102.5×103)/103=201kN/m.
12.6.4 Selection of brick and mortar for inner leaf of wall B
The design vertical load resistance of the wall is (ßtfk)/m (clause 32.2.1)
The value of ß depends on the eccentricity of loading; hence the value of
e needs to be evaluated before design can be completed.
12.6.5 Calculation of eccentricity
The worst combination of loading for obtaining the value of e at top of
the wall is shown in Fig 12.6 Axial load
P=(0.9×78.54+1.6×7.29) (Gk and Qk from Table 12.2)
Trang 19BM at centre of the panel=627.8×(Cpe+CPi)h×0.104×1.4
=627.8×(1.1+0.2)×(2.85)2×0.104×1.4
=964.6Nm/m (Cpe and Cpi from CP3, Chapter V: Part 2)
(BM coefficient for four-sided simply supported panel is 0.104; table 3.1,
BS 8110)
(since both leaves are of same stiffness)
where
Resultant
(b) Wind blowing west-east direction
The panel B is not only subjected to dead and imposed loads, but alsosubjected to wind loading from west to east direction Then
(the bending moment induced due to wind loading acts against thosedue to the vertical load)
Since resultant eccentricity of case (b) is greater than case (a), case (b)eccentricity is considered in the design
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Trang 2012.6.6 Calculation of characteristic compressive stress fk for wall B
Trang 21• Leeward side
The design is similar to the inner leaf and will not be considered anyfurther The slight tension which is developing is of no consequence,since 6 to 10% of the dead and imposed load will be transferred to theouter leaf even in cases where the slab is supported on the inner skin
The bending stress caused by the wind will be smaller if S2 factor isassumed variable as explained in section 12.5.2: the staircase and lift wellwill also provide the stability against the wind which has been neglected.However, any facing brick having water absorption between 7 and 12%
in 1:¼:3 mortar may be used, provided that it satisfies the lateral loaddesign The grade of mortar is kept the same as for the inner leaf.Characteristic flexural strength:
(Table 3)
Design characteristic shear as in inner leaf:
Instead of the conventional design calculations described in this chapter
a more sophisticated analysis of the structure is possible by idealizing it
as a frame with vertical loading as shown in Fig 12.7 Similarly, thestructure can be idealized and replaced by a two-dimensional frame (Fig.12.8) and analysed as discussed in Chapter 6 for wind loading
12.7 DESIGN CALCULATION ACCORDING TO EC6 PART 1–1(ENV 1996–1:1995)
To demonstrate the principle of design according to EC6, the wall A inthe ground floor will be redesigned The dead and live loading is taken
as calculated before and as in Table 12.1 The bending moments andshear forces due to wind loading are given in Table 12.3 The category ofmanufacturing and execution controls are assumed to be II and Crespectively; thus ␥m=3 as given in Table 4.6
Load combination for ultimate limit state:
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Trang 22Design vertical load resistance of wall , where depends
Trang 23Fig 12.9 Calculation of eccentricity of the loading (not to scale).
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Trang 24EC6 allows the use of the value from the national code Hence 50N/mm2brick in mortar will be sufficient.
In the absence of test data a formula as given below is suggested foruse:
or
Therefore, 100N/mm2 bricks are required which is much higher than theprevious case It would be better and economical to do tests on prisms toobtain the characteristic strength
For the ground floor
G has been taken as 1 for favourable effect
The allowable shear due to precompression in BS 5628 is higher than
in the Eurocode, but it does not make much difference to the design
12.8 DESIGN OF PANEL FOR LATERAL LOADING: BS 5628
(LIMIT STATE)
To explain the principle of the design only panel B between sixth floorand roof will be considered The low precompression on the inner leaf isignored in this design Assume:
• Inner leaf 102.5mm brickwork in 1:1:6 mortar
• Outer leaf 102.5mm brickwork with facing brick in 1:1:6 mortar
• Boundary conditions: two sides simply supported and two sides fixed
as shown in Fig 12.10
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