Control Valve SelectionActuator Sizing Actuators are selected by matching the force required to stroke the valve with an actuator that can supply that force.. For rotary valves a similar
Trang 1Representative Sizing Coefficients for Rotary Shaft Valves Valve Size
Degrees of Valve
90
15.6 34.0
0.86 0.86
0.53 0.42
90
28.5 77.3
0.85 0.74
0.50 0.27
2 V−Notch Ball Valve
High Performance Butterfly Valve
60 90 60 90
59.2 132 58.9 80.2
0.81 0.77 0.76 0.71
0.53 0.41 0.50 0.44
0.49 0.70
3 V−Notch Ball Valve
High Performance Butterfly Valve
60 90 60 90
120 321 115 237
0.80 0.74 0.81 0.64
0.50 0.30 0.46 0.28
0.92 0.99 0.49 0.70
4 V−Notch Ball Valve
High Performance Butterfly Valve
60 90 60 90
195 596 270 499
0.80 0.62 0.69 0.53
0.52 0.22 0.32 0.19
0.92 0.99 0.49 0.70
6 V−Notch Ball Valve
High Performance Butterfly Valve
60 90 60 90
340 1100 664 1260
0.80 0.58 0.66 0.55
0.52 0.20 0.33 0.20
0.91 0.99 0.49 0.70
90
518 1820
0.82 0.54
0.54 0.18
0.91 0.99
Trang 2Representative Sizing Coefficients for Rotary Shaft Valves (continued) Valve Size
Opening Valve Style
12 V−Notch Ball Valve
High Performance Butterfly Valve
60 90 60 90
1530 3980 2500 5400
0.78 0.63
0.49 0.25
0.92 0.99 0.49 0.70
16 V−Notch Ball Valve
High Performance Butterfly Valve
60 90 60 90
2380 8270 3870 8600
0.80 0.37 0.69 0.52
0.45 0.13 0.40 0.23
0.92 1.00
Trang 3Chapter 5 Control Valve Selection
Actuator Sizing
Actuators are selected by matching
the force required to stroke the valve
with an actuator that can supply that
force For rotary valves a similar
pro-cess matches the torque required to
stroke the valve with an actuator that
will supply that torque The same
fun-damental process is used for
pneu-matic, electric, and electrohydraulic
actuators
Globe Valves
The force required to operate a globe
valve includes:
D Force to overcome static
unbal-ance of the valve plug
D Force to provide a seat load
D Force to overcome packing
fric-tion
D Additional forces required for
certain specific applications or
constructions
Total force required = A + B + C + D
A Unbalance Force
The unbalance force is that resulting from fluid pressure at shutoff and in the most general sense can be ex-pressed as:
Unbalance force = net pressure differ-ential X net unbalance area
Frequent practice is to take the maxi-mum upstream gauge pressure as the net pressure differential unless the process design always ensures a back pressure at the maximum inlet pressure Net unbalance area is the port area on a single seated flow up design Unbalance area may have to take into account the stem area de-pending on configuration For bal-anced valves there is still a small un-balance area This data can be obtained from the manufacturer Typi-cal port areas for balance valves flow
up and unbalanced valves in a flow down configuration are listed below;
Typical Unbalance Areas of Control Valves Port Diameter
Unbalance Area Single seated unbalanced valves
Unbalance Area Balanced Valves
Trang 4Chapter 5 Control Valve Selection
130
Figure 5-3 Minimum Required Seat Load for Metal-Seated Valves for Improved Seat Life for Class II-V and Recommended Seat Load for
Optimum Performance in Boiler Feedwater Service
900
800
700
600
500
400
300
200
100
0
SHUTOFF PRESSURE DROP, PSI
A2222−4
CLASS V (METAL SEAT)
CLASS IV
CLASS III
CLASS II
1000
CLASS V (METAL SEAT WITH C−SEAL TRIM)
CLASS V (METAL SEAT FOR OPTIMUM PER-FORMANCE AND LIFE IN BOILER FEEDWATER SERVICE.
Class I As required by user specification, no factory leak test required
Class II 20 pounds per lineal inch of port circumference
Class III 40 pounds per lineal inch of port circumference
Class IV
Standard (Lower) Seat only—40 pounds per lineal inch of port circumference (up through a 4-3/8 inch diameter port)
Standard (Lower) Seat only—80 pounds per lineal inch of port circumference (larger than 4-3/8 inch diameter port)
Class V Metal Seat—determine pounds per lineal inch of port circumference from
figure 5-3
Class VI Metal Seat—300 pounds per lineal inch of port circumference
B Force to Provide Seat Load
Seat load, usually expressed in
pounds per lineal inch of port
circum-ference, is determined by shutoff
re-quirements Use the following guide-lines to determine the seat load required to meet the factory accep-tance tests for ANSI/FCI 70-2 and IEC
Trang 5Chapter 5 Control Valve Selection
534-4 leak classes II through VI See
table for recommended seat load
Because of differences in the severity
of service conditions, do not construe
these leak classifications and
corre-sponding leakage rates as indicators
of field performance To prolong seat
life and shutoff capabilities, use a
higher than recommended seat load
See Figure 5-3 for suggested seat
loads If tight shutoff is not a prime
consideration, use a lower leak class
C Packing Friction
Packing friction is determined by stem size, packing type, and the amount of compressive load placed on the pack-ing by the process or the boltpack-ing Packing friction is not 100% repeat-able in its friction characteristics Live loaded packing designs can have sig-nificant friction forces especially if graphite packing is used The table below lists typical packing friction val-ues
Trang 6Chapter 5 Control Valve Selection
132
Typical Packing Friction Values STEM SIZE
RIBBON/ FILAMENT
-3/8
125 150 250
-125
-190 600
900 1500
250 320 380
1/2
125 150 250 300
-180
-230 600
900 1500 2500
320 410 500 590
5/8
125 150 250 300 600
-218
-290 400
3/4
125 150 250 300
-350
-440 600
900 1500 2500
660 880 1100 1320
1
300 600 900 1500 2500
610 850 1060 1300 1540
1-1/4
300 600 900 1500 2500
800 1100 1400 1700 2040
2
300 600 900 1500 2500
1225 1725 2250 2750 3245
Values shown are frictional forces typically encountered when using standard packing flange bolt torquing procedures.
D Additional Forces
Additional forces may be required to
stroke the valve such as: bellow
stiff-ness; unusual frictional forces
result-ing from seals; or special seatresult-ing forces for soft metal seals as an ex-ample The manufacturer should ei-ther supply this information or take it into account when sizing an actuator
Trang 7Chapter 5 Control Valve Selection
Actuator Force Calculations
Pneumatic diaphragm actuators
pro-vide a net force with the additional air
pressure after compressing the spring
in air to close, or with the net
precom-pression of the spring in air to open
This may be calculated in pounds per
square inch of pressure differential
For example: Suppose 275 lbf is
re-quired to close the valve calculated
following the process described
earli-er An air-to-open actuator with 100
square inches of diaphragm area and
a bench set of 6 to 15 psig is one
available option The expected
operat-ing range is 3 to 15 psig The
precom-pression can be calculated as the
dif-ference between the lower end of the
bench set (6 psig) and the beginning
of the operating range (3 psig) This 3
psig is used to overcome the
precom-pression so the net precomprecom-pression
force must be;
3 psig X 100 sq in = 300 lbf
This exceeds the force required and is
an adequate selection
Piston actuators with springs are
sized in the same manner The thrust
from piston actuators without springs
can simply be calculated as:
(Piston Area)(Minimum Supply
Pressure) = Available Thrust
(be careful to maintain compatibility of
units)
In some circumstances an actuator
could supply too much force and
cause the stem to buckle, to bend
suf-ficiently to cause a leak, or to damage
valve internals This could occur
be-cause the actuator is too large or the
maximum air supply exceeds the mini-mum air supply available
The manufacturer normally takes re-sponsibility for actuator sizing and should have methods documented to check for maximum stem loads Manufacturers also publish data on actuator thrusts, effective diaphragm areas, and spring data
Rotary Actuator Sizing
In selecting the most economical ac-tuator for a rotary valve, the determin-ing factors are the torque required to open and close the valve and the torque output of the actuator
This method assumes the valve has been properly sized for the application and the application does not exceed pressure limitations for the valve
Torque Equations
Rotary valve torque equals the sum of
a number of torque components To avoid confusion, a number of these have been combined and a number of calculations have been performed in advance Thus, the torques required for each valve type can be repre-sented with two simple and practical equations
Breakout Torque
TB = A(nPshutoff) + B
Dynamic Torque
TD = C(nPeff) The specific A, B, and C factors for each valve design are included in fol-lowing tables
Trang 8Chapter 5 Control Valve Selection
134
Typical Rotary Shaft Valve Torque Factors V−Notch Ball Valve with Composition Seal VALVE
SIZE,
INCHES
VALVE
SHAFT
DIAMETER,
INCHES
A
B
M T D , LBFSIN Composition
Bearings
60 Degrees
70 Degrees
2
3
4
6
8
1/2 3/4 3/4 1 1-1/4
0.15 0.10 0.10 1.80 1.80
80 280 380 500 750
0.11 0.15 1.10 1.10 3.80
0.60 3.80 18.0 36.0 60.0
515 2120 2120 4140 9820 10
12
14
16
18
20
1-1/4
1-1/2
1-3/4
2 2-1/8
2-1/2
1.80 4.00 42 60 60 97
1250 3000 2400 2800 2800 5200
3.80 11.0 75 105 105 190
125 143 413 578 578 1044
9820 12,000 23,525 23,525 55,762 55,762
High Performance Butterfly Valve with Composition Seal
VALVE
SIZE,
INCHES
SHAFT
DIAMETER
INCHES
INCH-POUNDS
B Dynamic T D
Maximum Rotation
Maximum rotation is defined as the
angle of valve disk or ball in the fully
open position
Normally, maximum rotation is 90
grees The ball or disk rotates 90
de-grees from the closed position to the
wide open position
Some of the pneumatic spring-return
piston and pneumatic
spring-and-dia-phragm actuators are limited to 60 or
75 degrees rotation
For pneumatic spring-and-diaphragm
actuators, limiting maximum rotation
allows for higher initial spring
com-pression, resulting in more actuator
breakout torque Additionally, the
ef-fective length of each actuator lever
changes with valve rotation Published
torques, particularly for pneumatic
pis-ton actuators, reflect this changing le-ver length
Non-Destructive Test Procedures
Successful completion of specific non-destructive examinations is required for valves intended for nuclear service and may be required by codes or cus-tomers in non-nuclear applications, particularly in the power industry Also, successful completion of the ex-aminations may permit uprating of ASME Standard Class buttwelding end valves to a Special Class rating The Special Class rating permits use
of the butt-welding end valves at
high-er pressures than allowed for Stan-dard Class valves Procedures re-quired for uprating to the Special Class are detailed in ASME Standard B16.34
Trang 9Chapter 5 Control Valve Selection
While it is not feasible to present
com-plete details of code requirements for
non-destructive examinations, this
book will summarize the principles
and procedures of four major types of
non-destructive examinations defined
in ANSI, ASME, and ASTM standards
Magnetic Particle (Surface)
Examination
Magnetic particle examination can be
used only on materials which can be
magnetized The principle includes
application of a direct current across a
piece to induce a magnetic field in the
piece Surface or shallow subsurface
defects distort the magnetic field to
the extent that a secondary magnetic
field develops around the defect If a
magnetic powder, either dry or
sus-pended in liquid, is spread over the
magnetized piece, areas of distorted
magnetic field will be visible,
indicat-ing a defect in the piece in the area of
distortion After de-magnetizing the
piece by reversing the electric current,
it may be possible to weld repair the
defect (normal procedure with
cast-ings) or it may be necessary to
re-place the piece (normal procedure
with forgings and bar stock parts)
Af-ter repair or replacement, the
magnet-ic partmagnet-icle examination must be
re-peated
Liquid Penetrant (Surface)
Examination
This examination method permits
detection of surface defects not visible
to the naked eye The surface to be
examined is cleaned thoroughly and
dried The liquid penetrant dye, either
water or solvent soluble, is applied by
the applicable light source (Some de-velopers require use of an ultraviolet
or black light to expose defective areas) If defects are discovered and repaired by welding, the piece must
be re-examined after repair
Radiographic (Volumetric) Examination
Radiography of control valve parts works on the principle that X-rays and gamma rays will pass through metal objects which are impervious to light rays and will expose photographic film just as light rays will The number and intensity of the rays passing through the metal object depend on the
densi-ty of the object Subsurface defects represent changes in density of the material and can therefore be photographed radiographically The piece to be inspected is placed be-tween the X-ray or gamma ray source and the photographic film Detail and contrast sensitivity are determined by radiographing one or more small flat plates of specified thickness at the same time the test subject is exposed The small flat plate, called a penetra-meter, has several holes of specified diameters drilled in it Its image on the exposed film, along with the valve body or other test subject, makes it possible to determine the detail and contrast sensitivity of the radiograph Radiography can detect such casting defects as gas and blowholes, sand inclusions, internal shrinkage, cracks, hot tears, and slag inclusions In cast-ings for nuclear service, some defects such as cracks and hot tears are ex-pressly forbidden and cannot be re-paired The judgment and experience
of the radiographer is important
Trang 10be-Chapter 5 Control Valve Selection
136
Ultrasonic (Volumetric)
Examination
This method monitors sound wave
re-flections from the piece being
in-spected to determine the depth and
size of any defects Ultrasonic
ex-amination can detect foreign materials
and discontinuities in fine-grained
metal and thus lends itself to
volumet-ric examination of structures such as
plate, bar, and forgings The test is
normally conducted either with a
spe-cial oil called a coupler or under water
to ensure efficient transmission of
sound waves The sound waves are
generated by a crystal probe and are
reflected at each interface in the piece
being tested, that is, at each outer
face of the piece itself and at each
face of the damaged or malformed
in-ternal portion These reflections are
received by the crystal probe and
dis-played on a screen to reveal the
loca-tion and severity of the defect
Cavitation and Flashing
Choked Flow Causes Flashing
and Cavitation
The IEC liquid sizing standard
calcu-lates an allowable sizing pressure
drop, nPmax If the actual pressure
drop across the valve, as defined by
the system conditions of P1 and P2, is
greater than nPmax then either
flash-ing or cavitation may occur Structural
damage to the valve and adjacent
pip-ing may also result Knowledge of
what is actually happening within the
valve will permit selection of a valve
that can eliminate or reduce the
ef-fects of cavitation and flashing
The physical phenomena label is used
to describe flashing and cavitation
be-cause these conditions represent
ac-tual changes in the form of the fluid
media The change is from the liquid
state to the vapor state and results
from the increase in fluid velocity at or
just downstream of the greatest flow
restriction, normally the valve port As
liquid flow passes through the
restric-Figure 5−4 Vena Contracta Illustration
RESTRIC-TION
VENA CONTRACTA FLOW
A3444/IL
tion, there is a necking down, or con-traction, of the flow stream The mini-mum cross−sectional area of the flow stream occurs just downstream of the actual physical restriction at a point called the vena contracta, as shown in figure 5−4
To maintain a steady flow of liquid through the valve, the velocity must
be greatest at the vena contracta, where cross sectional area is the least The increase in velocity (or ki-netic energy) is accompanied by a substantial decrease in pressure (or potential energy) at the vena
contrac-ta Further downstream, as the fluid stream expands into a larger area, ve-locity decreases and pressure in-creases But, of course, downstream pressure never recovers completely to equal the pressure that existed up-stream of the valve The pressure dif-ferential (nP) that exists across the valve is a measure of the amount of energy that was dissipated in the valve Figure 5−5 provides a pressure profile explaining the differing perfor-mance of a streamlined high recovery valve, such as a ball valve, and a valve with lower recovery capabilities due to greater internal turbulence and dissipation of energy
Regardless of the recovery character-istics of the valve, the pressure differ-ential of interest pertaining to flashing and cavitation is the differential be-tween the valve inlet and the vena contracta If pressure at the vena con-tracta should drop below the vapor pressure of the fluid (due to increased fluid velocity at this point) bubbles will form in the flow stream Formation of