The bubble will be in mechanical equilibrium when the pressure dif-ference between the inside and the outside of the bubble is balanced by the forces of surface tension, σ , as indicate
Trang 1Figure 9.4 Enlarged sketch of a typical metal surface.
9.2 Nucleate boilingInception of boiling
Figure9.4shows a highly enlarged sketch of a heater surface Most finishing operations score tiny grooves on the surface, but they also typ-
metal-ically involve some chattering or bouncing action, which hammers small
holes into the surface When a surface is wetted, liquid is prevented bysurface tension from entering these holes, so small gas or vapor pocketsare formed These little pockets are the sites at which bubble nucleationoccurs
To see why vapor pockets serve as nucleation sites, consider Fig.9.5.Here we see the problem in highly idealized form Suppose that a spher-ical bubble of pure saturated steam is at equilibrium with an infinitesuperheated liquid To determine the size of such a bubble, we imposethe conditions of mechanical and thermal equilibrium
The bubble will be in mechanical equilibrium when the pressure
dif-ference between the inside and the outside of the bubble is balanced by
the forces of surface tension, σ , as indicated in the cutaway sketch in
Fig.9.5 Since thermal equilibrium requires that the temperature must
be the same inside and outside the bubble, and since the vapor inside
must be saturated at Tsup because it is in contact with its liquid, theforce balance takes the form
psat at Tsup − pambient (9.1)
The p–v diagram in Fig. 9.5 shows the state points of the internalvapor and external liquid for a bubble at equilibrium Notice that the
external liquid is superheated to (Tsup− Tsat) K above its boiling point at
the ambient pressure; but the vapor inside, being held at just the rightelevated pressure by surface tension, is just saturated
Trang 2§9.2 Nucleate boiling 465
Figure 9.5 The conditions required for simultaneous
mechan-ical and thermal equilibrium of a vapor bubble
1.256
1− 0.625
1− Tsat T c
mN
where both Tsat and the thermodynamical critical temperature, T c =
647.096 K, are expressed in K The units of σ are millinewtons (mN)
per meter Table9.1gives additional values of σ for several substances.
Equation 9.2a is a specialized refinement of a simple, but quite
ac-curate and widely-used, semi-empirical equation for correlating surface
Trang 3466
Trang 4We include correlating equations of this form for CO2, propane, and some
refrigerants at the bottom of Table 9.1 Equations of this general form
are discussed in Reference [9.8]
It is easy to see that the equilibrium bubble, whose radius is described
by eqn (9.1), is unstable If its radius is less than this value, surface
tension will overbalance [psat(Tsup)− pambient] Thus, vapor inside will
condense at this higher pressure and the bubble will collapse If the
bubble radius is slightly larger than the equation specifies, liquid at the
interface will evaporate and the bubble will begin to grow
Thus, as the heater surface temperature is increased, higher and higher
values of [psat(Tsup)−pambient] will result and the equilibrium radius, R b,
will decrease in accordance with eqn (9.1) It follows that smaller and
smaller vapor pockets will be triggered into active bubble growth as the
temperature is increased As an approximation, we can use eqn (9.1)
to specify the radius of those vapor pockets that become active
nucle-ation sites More accurate estimates can be made using Hsu’s [9.9]
bub-ble inception theory, the subsequent work by Rohsenow and others (see,
e.g., [9.10]), or the still more recent technical literature
Example 9.1
Estimate the approximate size of active nucleation sites in water at
1 atm on a wall superheated by 8 K and by 16 K This is roughly in
the regime of isolated bubbles indicated in Fig.9.2
Solution. psat = 1.203 × 105 N/m2at 108◦ C and 1.769 × 105 N/m2
at 116◦ C, and σ is given as 57.36 mN/m at Tsat = 108 ◦C and as
55.78 mN/m at Tsat= 116 ◦C by eqn (9.2a) Then, at 108◦ C, R b from
Trang 5This means that active nucleation sites would be holes with diametersvery roughly on the order of magnitude of 0.005 mm or 5µm—at least
on the heater represented by Fig 9.2 That is within the range ofroughness of commercially finished surfaces
Region of isolated bubbles
The mechanism of heat transfer enhancement in the isolated bubbleregime was hotly argued in the years following World War II A few con-clusions have emerged from that debate, and we shall attempt to identifythem There is little doubt that bubbles act in some way as small pumpsthat keep replacing liquid heated at the wall with cool liquid The ques-tion is that of specifying the correct mechanism Figure 9.6shows theway bubbles probably act to remove hot liquid from the wall and intro-duce cold liquid to be heated
It is apparent that the number of active nucleation sites generating
bubbles will strongly influence q On the basis of his experiments,
Yam-agata showed in 1955 (see, e.g., [9.11]) that
where∆T ≡ T w − Tsat and n is the site density or number of active sites
per square meter A great deal of subsequent work has been done to
fix the constant of proportionality and the constant exponents, a and b The exponents turn out to be approximately a = 1.2 and b = 1
3.The problem with eqn (9.3) is that it introduces what engineers call
a nuisance variable A nuisance variable is one that varies from system
to system and cannot easily be evaluated—the site density, n, in this case Normally, n increases with ∆T in some way, but how? If all sites were identical in size, all sites would be activated simultaneously, and q
would be a discontinuous function of∆T When the sites have a typical distribution of sizes, n (and hence q) can increase very strongly with ∆T
It is a lucky fact that for a large class of factory-finished materials, n
varies approximately as ∆T5 or 6, so q varies roughly as ∆T3 This has
made it possible for various authors to correlate q approximately for a
large variety of materials One of the first and most useful correlationsfor nucleate boiling was that of Rohsenow [9.12] in 1952 It is
Trang 6§9.2 Nucleate boiling 469
A bubble growing and departing in saturated liquid.
The bubble grows, absorbing heat from the
superheated liquid on its periphery As it leaves, it
entrains cold liquid onto the plate which then warms
up until nucleation occurs and the cycle repeats
A bubble growing in subcooled liquid.
When the bubble protrudes into coldliquid, steam can condense on the topwhile evaporation continues on thebottom This provides a short-circuit forcooling the wall Then, when the bubblecaves in, cold liquid is brought to the wall
Figure 9.6 Heat removal by bubble action during boiling Dark
regions denote locally superheated liquid
where all properties, unless otherwise noted, are for liquid at Tsat The
constant Csf is an empirical correction for typical surface conditions
Table 9.2 includes a set of values of Csf for common surfaces (taken
from [9.12]) as well as the Prandtl number exponent, s A more extensive
compilation of these constants was published by Pioro in 1999 [9.13]
We noted, initially, that there are two nucleate boiling regimes, and
the Yamagata equation (9.3) applies only to the first of them Rohsenow’s
equation is frankly empirical and does not depend on the rational
anal-ysis of either nucleate boiling process It turns out that it represents
q( ∆T ) in both regimes, but it is not terribly accurate in either one
Fig-ure9.7shows Rohsenow’s original comparison of eqn (9.4) with data for
water over a large range of conditions It shows typical errors in heat
flux of 100% and typical errors in∆T of about 25%.
Thus, our ability to predict the nucleate pool boiling heat flux is poor
Our ability to predict ∆T is better because, with q ∝ ∆T3, a large error
in q gives a much smaller error in ∆T It appears that any substantial
improvement in this situation will have to wait until someone has
man-aged to deal realistically with the nuisance variable, n Current research
efforts are dealing with this matter, and we can simply hope that such
work will eventually produce a method for achieving reliable heat
trans-fer design relationships for nucleate boiling
Trang 7Table 9.2 Selected values of the surface correction factor for
use with eqn (9.4) [9.12]
It is indeed fortunate that we do not often have to calculate q, given
∆T , in the nucleate boiling regime More often, the major problem is
to avoid exceeding qmax We turn our attention in the next section topredicting this limit
Example 9.2
What is Csffor the heater surface in Fig.9.2?
Solution. From eqn (9.4) we obtain
where, since the liquid is water, we take s to be 1.0 Then, for water at
Tsat = 100 ◦ C: c p = 4.22 kJ/kg·K, Pr = 1.75, (ρ f − ρ g ) = 958 kg/m3,
σ = 0.0589 N/m or kg/s2, h fg = 2257 kJ/kg, µ = 0.000282 kg/m·s.
Trang 8This value compares favorably with Csffor a platinum or copper
sur-face under water
Trang 99.3 Peak pool boiling heat fluxTransitional boiling regime and Taylor instability
It will help us to understand the peak heat flux if we first consider theprocess that connects the peak and the minimum heat fluxes Duringhigh heat flux transitional boiling, a large amount of vapor is gluttedabout the heater It wants to buoy upward, but it has no clearly definedescape route The jets that carry vapor away from the heater in the re-gion of slugs and columns are unstable and cannot serve that function inthis regime Therefore, vapor buoys up in big slugs—then liquid falls in,touches the surface briefly, and a new slug begins to form Figure9.3cshows part of this process
The high and low heat flux transitional boiling regimes are different
in character The low heat flux region does not look like Fig.9.2c but is most indistinguishable from the film boiling shown in Fig.9.2d However,both processes display a common conceptual key: In both, the heater isalmost completely blanketed with vapor In both, we must contend withthe unstable configuration of a liquid on top of a vapor
al-Figure 9.8 shows two commonplace examples of such behavior Ineither an inverted honey jar or the water condensing from a cold waterpipe, we have seen how a heavy fluid falls into a light one (water or honey,
in this case, collapses into air) The heavy phase falls down at one node
of a wave and the light fluid rises into the other node
The collapse process is called Taylor instability after G I Taylor, who first predicted it The so-called Taylor wavelength, λ d, is the length ofthe wave that grows fastest and therefore predominates during the col-lapse of an infinite plane horizontal interface It can be predicted using
dimensional analysis The dimensional functional equation for λ dis
λ d = fnσ , g
ρ f − ρ g
(9.5)since the wave is formed as a result of the balancing forces of surfacetension against inertia and gravity There are three variables involving m
and kg/s2, so we look for just one dimensionless group:
Trang 10§9.3 Peak pool boiling heat flux 473
a Taylor instability in the surface of the honey
in an inverted honey jar
b Taylor instability in the interface of the water condensing on
the underside of a small cold water pipe
Figure 9.8 Two examples of Taylor instabilities that one might
Trang 11Experiment 9.3
Hang a metal rod in the horizontal position by threads at both ends.The rod should be about 30 cm in length and perhaps 1 to 2 cm in diam-eter Pour motor oil or glycerin in a narrow cake pan and lift the pan upunder the rod until it is submerged Then lower the pan and watch theliquid drain into it Take note of the wave action on the underside of therod The same thing can be done in an even more satisfactory way byrunning cold water through a horizontal copper tube above a beaker ofboiling water The condensing liquid will also come off in a Taylor wavesuch as is shown in Fig.9.8 In either case, the waves will approximate
λ d1 (the length of a one-dimensional wave, since they are arrayed on aline), but the wavelength will be influenced by the curvature of the rod
Throughout the transitional boiling regime, vapor rises into liquid on
the nodes of Taylor waves, and at qmaxthis rising vapor forms into jets.These jets arrange themselves on a staggered square grid, as shown inFig.9.9 The basic spacing of the grid is λ d2(the two-dimensional Taylorwavelength) Since
[recall eqn (9.6)], the spacing of the most basic module of jets is actually
λ d1, as shown in Fig.9.9.Next we must consider how the jets become unstable at the peak, tobring about burnout
Helmholtz instability of vapor jets
Figure9.10shows a commonplace example of what is called Helmholtz
instability This is the phenomenon that causes the vapor jets to cave in
when the vapor velocity in them reaches a critical value Any flag in abreeze will constantly be in a state of collapse as the result of relativelyhigh pressures where the velocity is low and relatively low pressureswhere the velocity is high, as is indicated in the top view
This same instability is shown as it occurs in a vapor jet wall inFig 9.11 This situation differs from the flag in one important partic-ular There is surface tension in the jet walls, which tends to balance theflow-induced pressure forces that bring about collapse Thus, while the
flag is unstable in any breeze, the vapor velocity in the jet must reach a limiting value, u g, before the jet becomes unstable
Trang 12a Plan view of bubbles rising from surface
b Waveform underneath the bubbles shown in a.
Figure 9.9 The array of vapor jets as seen on an infinite
hori-zontal heater surface
475
Trang 13Figure 9.10 The flapping of a flag due to Helmholtz instability.
Lamb [9.16] gives the following relation between the vapor flow u g,shown in Fig.9.11, and the wavelength of a disturbance in the jet wall,
Trang 14§9.3 Peak pool boiling heat flux 477
Figure 9.11 Helmholtz instability of vapor jets.
will be better developed than the others and therefore more liable to
collapse
Example 9.3
Saturated water at 1 atm flows down the periphery of the inside of a
10 cm I.D vertical tube Steam flows upward in the center The wall of
the pipe has circumferential corrugations in it, with a 4 cm wavelength
in the axial direction Neglect problems raised by curvature and the
finite thickness of the liquid, and estimate the steam velocity required
to destabilize the liquid flow over these corrugations, assuming that
the liquid moves slowly
Solution.The flow will be Helmholtz-stable until the steam velocity
reaches the value given by eqn (9.8):
u g =
2
2π (0.0589) 0.577(0.04 m) Thus, the maximum stable steam velocity would be u g = 4 m/s.
Beyond that, the liquid will form whitecaps and be blown back
upward
Trang 15Example 9.4
Capillary forces hold mercury in place between two parallel steel plateswith a lid across the top The plates are slowly pulled apart until themercury interface collapses Approximately what is the maximumspacing?
Solution. The mercury is most susceptible to Taylor instabilitywhen the spacing reaches the wavelength given by eqn (9.6):
λ d1= 2π √3
2
σ g(ρ f − ρ g ) = 2π √3
2
0.487 9.8(13600) = 0.021 m = 2.1 cm
(Actually, this spacing would give the maximum rate of collapse It
can be shown that collapse would begin at 1 3 times this value, or
For any heater configuration, two things must be determined One
is the length of the particular disturbance in the jet wall, λ H, which will
trigger Helmholtz instability and fix u gin eqn (9.8) for use in eqn (9.9)
The other is the ratio A j A h The prediction of qmaxin any pool boilingconfiguration always comes down to these two problems
qmax on an infinite horizontal plate The original analysis of this type
was done by Zuber in his doctoral dissertation at UCLA in 1958 (see [9.17])
He first guessed that the jet radius was λ d1 4 This guess has receivedcorroboration by subsequent investigators, and (with reference to Fig.9.9)