• focus on stability of loose non-cohesive grains • rock: important material for protection • grains may vary in size from μc sand to m rock... occasional movement at some locations 2..
Trang 1Chapter 3
Flow - stability
Trang 2• focus on stability of loose non-cohesive grains
• rock: important material for protection
• grains may vary in size from μc (sand) to m (rock)
Trang 3Uniform flow – Horizontal bed
Forces on a grain in flow
1 2 1 2 1 2
Trang 4Balance equations
d g K
= u d
g
= d g
-
w
w s
d g )
(
-d u
d O W
= d O F
: 0
=
M
W
= F
: 0
= V
F W
x f
= F
: 0
= H
3 w
s
2 2 c w
S D, L
F S
D,
ρ ρ
Σ
= Σ
) ( )
(
Relation between load and strength
Trang 5Isbash (1930)
g 2
u 0.7
= d
or
1.7
= d g
u
or
d g 2
1.2
=
u
2 c c
Δ Δ
used for first approximation when:
• relation between velocity and waterdepth not clear
(e.g a jet entering a body of water)
Trang 6( ) ( )
2
* Re
Trang 7Critical shear stress
Shields Van Rijn
=
υ ρ
ρ
τ
d g
u d
g
c c
w s
c c
*
* 2
Trang 81500 10
33 1
002 0
u gd
u
c c
63 10
33 1
002
0 042
s m gd
u*c = ψ cΔ = 0 04 × 1 65 × 9 81 × 0 002 = 0 036 /
Guess: u*c = 1 m/s
Shields
Trang 9Example (cont.)
42 )
10 33
1 (
81 9 65 1 002
.
0 3
2 6
u*c = ψ cΔ = 0 04 × 1 65 × 9 81 × 0 002 = 0 036 /
Van Rijn
Trang 10Relative protrusion
Trang 11Load and strength distribution
0 no movement at all
1 occasional movement at some locations
2 frequent movement at some locations
3 frequent movement at several locations
4 frequent movement at many locations
5 frequent movement at all locations
6 continuous movement at all locations
7 general transport of the grains
Shields
Trang 12Videos on stability of rock on a bed
with current only
Trang 14n
d
Trang 15C u
ψ
= Δ
1.7
ic
u
gd = Δ
Isbash: 18log12
r
R C
Trang 16Influence waterdepth on critical
velocity
Trang 18Roughness and threshold of motion
Trang 19Angles of repose for non-cohesive
Trang 20Influence of slope on stability
Case b: slope parallel to flow Case c: slope perpendicular to flow
φ = 40 ο
Trang 21Slope parallel to current
φ
α φ
W
= F(0)
)
F(
= )
K(
tan
sin tan
cos //
//
φ
α
φ φ
α φ
α φ
=
sin
sin sin
sin cos
cos
2
2 2
2
=
-
= F(0)
α α
sin
sin tan
tan cos
=
1
-=
Trang 22Stability on top of sill
use velocity on top of the sill
Experiments: first damage at downstream crest
Trang 23Stability and head difference
Shields is useless here because Shields contains waterdepth
waterlevel downstream is below the top of the dam
Shields for flow over sill
) h - (h g 2
) d
h 0.04 +
(0.5
= ) h - (h g 2
=
n
d d
Trang 24Vertical constriction Stability with flow under weir
Trang 25Shields in horizontal constriction
sin
2 4
Trang 26Stability on head of dam
Trang 27cs
cu c
c v
u
u structure
with u
structure without
u
ucu: vertically averaged critical velocity in uniform flow
ucs: velocity in case with a structure
Trang 28Effect of flow field
Trang 29Relation between K v and turbulence
cs
cs cu
ucu : vertically averaged critical velocity in uniform flow
ucs : velocity in case with a structure
rcu : turbulence intensity in uniform flow
rcs : vertically averaged turbulence intensity
Trang 30Stability downstream of a sill
high dam
no dam
D h
h K
u D h
h u
h u D
2
2 1
2 2 2
K v in vertical constriction
Trang 31Damage after some time
Trang 32Stone stability downstream of a
hydraulic jump
Trang 33Peak velocities and incipient motion
Trang 34damage after constriction
Trang 35Kv - factors for various structures
Structure Shape K v0 K vG K vM
angular
Rect-b 0 *K vG /b G 1.3 - 1.7 1.1 - 1.2 Groyne
zoidal
Trape-b 0 *K v b G 1.2 1
Angular
Rect-b 0 *K v /b G 1.3 - 1.7 1.2
Round b 0 *K v /b G 1.2 - 1.3 1.2 Abutm ent
Stream Lined
b 0 *K v /b G 1 - 1.1 1 - 1.1
Round b 0 *K v /b G ⊗
2*K v
1.2 - 1.4 ⊗ 1 - 1.1 Pier
Angular
Rect-b 0 *K v /b G ⊗
2*K v
1.4 - 1.6 ⊗ 1.2 - 1.3
Abruptly 1 Outflow
Stream Lined
Top Section
3.6.1
Section 3.6.1
Section 3.6.1 Sill
Down Stream
Fig 3.13 Fig 3.13 Fig 3.13
⊗ For many piers in a river the first expression for K v is appropriate The second
is valid for a detached pier in an infinitely wide flow, where K G is not defined.
Trang 36Definition of velocities
groyne vertical pole
Trang 37Combined equation
C K
u
*
K
=
d
2 c
s
c
2 2
v
Δ
ψ
Kv : reduction for constriction, etc.
Ks : reduction for slope (parallel, perpendicular))
Trang 38ρ
ρ ρ
Gabions
Clay soils
Vegetation
Trang 39Placed blocks
Mats