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Because of the unboundedness of the domain, the Sobolev compact embedding does not hold.. In 17,18, the authors studied the problem in symmetric Sobolev spaces which possess Sobolev comp

Trang 1

Volume 2009, Article ID 185319, 19 pages

doi:10.1155/2009/185319

Research Article

1 School of Mathematics Science, Institute of Mathematics, Nanjing Normal University, Jiangsu,

Nanjing 210097, China

2 College of Zhongbei, Nanjing Normal University, Jiangsu, Nanjing 210046, China

Correspondence should be addressed to Zuodong Yang,zdyang jin@263.net

Received 20 October 2009; Accepted 6 December 2009

Recommended by Wenming Zou

The nonlinear elliptic eigenvalue problem −div|∇u| p−2 ∇u − div|∇u| q−2 ∇u  λax|u| p−2 u  λbx|u| q−2 u  fx, u, u ∈ W 1,p ∩ W 1,qRN , where 2 ≤ q ≤ p < N and ax ∈ L N/pRN , bx ∈

L N/qRN , ax, bx > 0 are studied The key ingredient is a special constrained minimization

method

Copyrightq 2009 M Wu and Z Yang This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited

1 Introduction

In this paper, we are interested in finding nontrivial weak solutions for the nonlinear eigenvalue problem

− div|∇u| p−2 ∇u− div|∇u| q−2 ∇u ax|u| p−2 u  bx|u| q−2 u  f x, u,

u ∈ W 1,p ∩ W 1,q

RN

, u /  0,

1.1

where 2 ≤ q ≤ p < N and ax ∈ L N/pRN , bx ∈ L N/qRN , ax, bx > 0, inf ax, inf bx /  0, fx, u satisfy the following conditions:

A f ∈ CR N × R, R, lim t → 0 fx, t/|t| p−1   0, and lim |t| → ∞ fx, t/|t| p−1p2/N  0

uniformly in x ∈ R N,

B lim|x| → ∞ fx, t  ft uniformly for t in bounded subsets of R.

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Remark 1.1 We can see if ax ∈ L N/pRN , bx ∈ L N/qRN, then



RN

ax|u| p dx <



RN

ax N/p

1−p/p∗

RN

u p

p/p

< ∞,



RN bx|u| q

dx <



RN bx N/q1−q/q∗

RN u q

q/q

< ∞,

1.2

where p Np/N − p and q Nq/N − q.

Problem1.1 comes, for example, from a general reaction-diffusion system:

u t  divDu∇u  cx, u, 1.3

where Du  |∇u| p−2 |∇u| q−2 This system has a wide range of applications in physics and related sciences such as biophysics, plasma physics, and chemical reaction design In such

applications, the function u describes a concentration, the first term on the right-hand side of

1.3 corresponds to the diffusion with a diffusion coefficient Du; whereas the second one

is the reaction and relates to source and loss processes Typically, in chemical and biological

applications, the reaction term cx, u is a polynomial of u with variable coefficients.

When p  q  2, problem 1.1 is a normal Schrodinger equation which has been extensively studied, for example,1 8 The authors used many different methods to study the equation In8, the authors established some embedding results of weighted Sobolev spaces of radially symmetric functions which are used to obtain ground state solutions In

6, the authors studied the equation depending upon the local behavior of V near its global

minimum In3, the authors used spectral properties of the Schrodinger operator to study nonlinear Schrodinger equations with steep potential well In9, the author imposed on

functions k and K conditions ensuring that this problem can be written in a variational form.

We know that W 1,pRN  is not a Hilbert space for 1 < p < N, except for p  2 The space

W 1,pRN  with p / 2 does not satisfy the Lieb lemma e.g., see 9 And RNresults in the loss

of compactness So there are many difficulties to study equation 1.1 of p  q / 2 by the usual methods There seems to be little work on the case p  q / 2 for problem 1.1, to the best of our knowledge In this paper, we overcome these difficulties and study 1.1 of p ≥ q ≥ 2 Recently, when p  q, ax  bx, and fx, u  0 then the problem is the following

eigenvalue problem has been studied by many authors:

− div|∇u| p−2 ∇u V x|u| p−2 u,

u ∈ D 1,p0 Ω, u / 0, 1.4

whereΩ ⊆ RN We can see10–13 In 13, Szulkin and Willem generalized several earlier results concerning the existence of an infinite sequence of eigenvalues

Trang 3

When p  q and ax, bx is constant then the problem is the following quasilinear

elliptic equation:

− div|∇u| p−2 ∇u λ|u| p−2 u  fx, u, in Ω,

u ∈ W01,p Ω, u / 0, 1.5

where 1 < p < N, N ≥ 3, λ is a parameter, Ω is an unbounded domain in R N There are many results about it we can see14–18 Because of the unboundedness of the domain, the Sobolev compact embedding does not hold There are many methods to overcome the difficulty In

15, the authors used the concentration-compactness principle posed by P L Lions and the mountain pass lemma to solve problem1.5 In 17,18, the authors studied the problem in symmetric Sobolev spaces which possess Sobolev compact embedding By the result and a min-max procedure formulated by Bahri and Li16, they considered the existence of positive solutions of

− div|∇u| p−2 ∇u u p−1  qxu α inRN , 1.6

where qx satisfies some conditions We can see if λ is function, then it cannot easily be

proved by the above methods

When ax, bx is positive constant, He and Li used the mountain pass theorem and

concentration-compactness principle to study the following elliptic problem in19:

− div|∇u| p−2 ∇u− div|∇u| q−2 ∇u m|u| p−2 u  n|u| q−2 u  f x, u in R N ,

u ∈ W 1,p ∩ W 1,q

RN

where m, n > 0, N ≥ 3, and 1 < q < p < N, fx, u/u p−1 tends to a positive constant l as

u → ∞ The authors prove in this paper that the problem possesses a nontrivial solution even if the nonlinearity fx, t does not satisfy the Ambrosetti-Rabinowitz condition.

In20, Li and Liang used the mountain pass theorem to study the following elliptic problem:

− div|∇u| p−2 ∇u− div|∇u| q−2 ∇u |u| p−2

u  |u| q−2 u  fx, u in R N ,

u ∈ W 1,p ∩ W 1,q

RN

where 1 < q < p < N They generalized a similar result for p-Laplacian type equation in 15

It is our purpose in this paper to study the existence of ground state to the problem

1.1 in RN We call any minimizer a ground state for1.1 We inspired by 9,16,21 try to use constrained minimization method to study problem1.1 Let us point out that although the idea was used before for other problems, the adaptation to the procedure to our problem

is not trivial at all But since both p- and q-Laplacian operators are involved, careful analysis is

needed A typical difficulty for problem 1.1 in RNis the lack of compactness of the Sobolev imbedding due to the invariance ofRN under the translations and rotations However, our method has essential difference with the methods used in 19,20 In order to obtain the

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results, we have to overcome two main difficulties; one is that RN results in the loss of

compactness; the other is that W 1,pRN  is not a Hilbert space for 1 < p < N and it does not satisfy the Lieb lemma, except for p  2.

The paper is organized as follows InSection 2, we state some condition and many lemmas which we need in the proof of the main theorem InSection 3, we give the proof of the main result of the paper

2 Preliminaries

Let

Fx, t 

t

0

f x, sds, Ft 

t

0

fsds 2.1

and we define variational functionals I : W 1,p ∩W 1,qRN  → R and I: W 1,p ∩W 1,qRN  → R

by

Iu  1 p



RN |∇u| p

dx  1 q



RN |∇u| q

dx −



RN

Fx, udx,

Iu  1

p



RN

|∇u| p dx  1

q



RN

|∇u| q dx −



RN

Fudx.

2.2

Solutions to problem1.1 will be found as minimizers of the variational problem

I λ inf

Iu; u ∈ W 1,p

RN

,



RN ax|u| p  bx|u| q

dx  λ , λ > 0 I λ

To find a solution of problemI λ we introduce the limit variational problem

I λ∞ inf

Iu; u ∈ W 1,p

RN

,



RN ax|u| p  bx|u| q

dx  λ , λ > 0 I

λ 

0 Ω a bounded sequence and p ≥ 2 Going if necessary to a subsequence, one may assume that u n  u in W01,p Ω, u n → u almost everywhere, where Ω ⊆ R N is an open subset.

Then,

lim

n → ∞



Ω|∇u n|p

dx ≥ lim

n → ∞



Ω|∇u n − ∇u| p

dx  lim

n → ∞



Ω|∇u| p

dx. 2.3

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Proof When p  2 from Brezis-Lieb lemma see 21, Lemma 1.32 we have

lim

n → ∞



Ω|∇u n|2

dx  lim

n → ∞



Ω|∇u n − ∇u|2

dx  lim

n → ∞



Ω|∇u|2

dx, 2.4

when 3 ≥ p > 2, using the lower semicontinuity of the L p-norm with respect to the weak

convergence and u n  u in W 1,pΩ, we deduce

|∇u n|p−2 ∇u n , ∇u n

|∇u| p−2 ∇u, ∇u  o1,

lim

n → ∞

|∇u n − ∇u| p−2 ∇u n , ∇u n

≥ lim

n → ∞

|∇u n − ∇u| p−2 ∇u n , ∇u

 lim

n → ∞

|∇u n − ∇u| p−2 ∇u, ∇u n

 lim

n → ∞

|∇u n − ∇u| p−2 ∇u, ∇u .

2.5

Then,

lim

n → ∞



Ω



|∇u n|p − |∇u| p

dx

 lim

n → ∞



Ω|∇u n|p−2

|∇u n|2− |∇u|2

dx  lim

n → ∞



Ω



|∇u n|p−2 − |∇u| p−2

|∇u|2

dx

 lim

n → ∞



Ω



|∇u n|p−2  |∇u| p−2

|∇u n|2− |∇u|2

dx

 lim

n → ∞



Ω



|∇u n|p−2 |∇u|2− |∇u| p−2 |∇u n|2

dx.

2.6

From u n  u in W 1,p Ω,

lim

n → ∞



Ω



|∇u n|p−2 |∇u|2− |∇u| p−2 |∇u n|2

dx  0. 2.7

So

lim

n → ∞



Ω



|∇u n|p − |∇u| p

dx  lim

n → ∞



Ω



|∇u n|p−2  |∇u| p−2

|∇u n|2− |∇u|2

dx

≥ lim

n → ∞



Ω|∇u n − ∇u| p−2

|∇u n|2− |∇u|2

.

2.8

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So we have

|∇u n|p−2 ∇u n , ∇u n

 |∇u n − ∇u| p−2 ∇u, ∇u n

 |∇u n − ∇u| p−2 ∇u n , ∇u

|∇u n − ∇u| p−2 ∇u n , ∇u n

 |∇u n − ∇u| p−2 ∇u, ∇u  |∇u| p−2 ∇u, ∇u  o1. 2.9

Then,

|∇u n|p−2 ∇u n , ∇u n

|∇u n − ∇u| p−2 ∇u n − ∇u, ∇u n − ∇u  |∇u| p−2 ∇u, ∇u  o1

lim

n → ∞



Ω|∇u n|p dx ≥ lim

n → ∞



Ω|∇u n − ∇u| p dx  lim

n → ∞



Ω|∇u| p dx,

2.10

when p > 3, there exists a k ∈ N that 0 < p − k ≤ 1 Then, we only need to prove the following

inequality:

lim

n → ∞



Ω



|∇u n|p − |∇u| p

dx ≥ lim

n → ∞



Ω|∇u n − ∇u| p−k

|∇u n|k − |∇u| k

. 2.11

The proof of it is similar to the above, so we omit it here So, the lemma is proved

Lemma 2.2 Let {un } be a bounded sequence in W 1,pRN  such that

lim

n → ∞sup

y∈R N



By,Ru

q

n dx  0, p ≤ q < p∗ 2.12

for some R > 0 Then u n → 0 in L sRN  for p < s < p, where p Np/N − p.

Proof We consider the case N ≥ 3 Let q < s < pand u ∈ W 1,pRN Holder and Sobolev inequalities imply that

|u| L s By,R ≤ |u|1−λL q By,R |u| λ

L p∗ By,R

≤ C|u|1−λ

L q By,R

By,R



|u| p  |∇u| pλ/p

,

2.13

where λ  s − q/p− qp/s Choosing λ  p/s, we obtain



By,R

|u| s ≤ C s |u| 1−λs L q By,R



By,R



|u| p  |∇u| p

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Now, coveringRN by balls of radius r, in such a way that each point of R Nis contained

in at most N  1 balls, we find



RN |u| s ≤ N  1C ssup

y∈R N By,R

|u| q

1−λs/q

By,R



|u| p  |∇u| p

. 2.15

Under the assumption of the lemma, u n → 0 in L sRN , p < s < p∗ The proof is complete

Corollary 2.3 Let {um } be a sequence in W 1,pRN  satisfying 0 < ρ RN |u m|p dx and such that

u m  0 in W 1,pRN  Then there exist a sequence {y m} ⊂ RN and a function 0 /  u ∈ W 1,pRN

such that up to a subsequence u m ·  y m   u in W 1,pRN .

lim

|s| → ∞

f x, s

|s| p∗ −1  0 2.16

uniformly in x ∈ R N and

f x, s ≤ C|s| p−1  |s| p∗−1

2.17

for all x ∈ R N and t ∈ R If u m  u0in W 1,pRN  and u m → u0a.e onRN , then

lim

m → ∞



RN Fx, u m dx −



RN Fx, u0dx −



RN Fx, u m − u0dx



 0, 2.18

where Fx, u u

0fx, tdt.

Proof Let R > 0 Applying the mean value theorem we have



RN Fx, u m dx 



|x|≤R F x, u m dx 



|x|≥R Fx, u0 u m − u0dx





|x|≤R F x, u m dx 



|x|≥R



Fx, u m − u0  fx, θu0 u m − u0u0



dx,

2.19

Trang 8

where θ depends on x and R and satisfies 0 < θ < 1 We now write





RN Fx, u m dx −



RN Fx, u0dx −



RN Fx, u m − u0dx



≤







|x|≤R Fx, u m  − Fx, u0dx



 









|x|≥R Fx, u0dx













|x|≤R Fx, u m − u0dx



 









|x|≥R fx, θu0 u m − u0u0dx



.

2.20

For each fixed R > 0

lim

m → ∞



|x|≤R Fx, u m  − Fx, u0dx  0,

lim

m → ∞



|x|≤R Fx, u m − u0dx  0.

2.21

Applying2.20 and the Holder inequality we get that









|x|≥R fx, θu0 u m − u0u0dx





≤ C



|x|≥R



|θu0 u m − u0|p−1 |u0|  |θu0 u m − u0|p∗−1|u0|dx

≤ C



|x|≥R |u0|p

1/p

|x|≥R |θu0 u m − u0|p

p−1/p

 C



|x|≥R |u0|p

1/p∗

|x|≥R |θu0 u m − u0|p

p−1/p

.

2.22

Since{u m } is bounded in W 1,pRN we see that

lim

R → ∞









|x|≥R f x, θu0 u m − u0u0dx



 0. 2.23

The result follows from2.21 and 2.23

I λ  and  I λ are bounded in W 1,pRN .

Trang 9

Proof From condition A, we observe that for each ε > 0 there exists C ε > 0 such that



Fu, |Fx, u| ≤ ε

RN |u| p

dx  ε



RN |u| pp2/N

dx  C ε



RN |u| α

dx, 2.24

where p < α < p  p2/N and ε > 0.

By the Holder and Sobolev inequalities we have



RN |u| pp2/N dx 



RN |u| pp−p−p2/N/p−ppp2/N/p−p dx



RN |u| p

p−p−p2/N/p−p

RN |u| p

p2/N/p−p

≤ S−1

RN |u| pp/N

RN |∇u| p

dx,

2.25

where|u| p

p≤ S−1|∇u| p

p Similarly we have



RN |u| α dx 



RN |u| pp−α/p−ppα−p/p−p dx



RN |u| p

dx

p−α/p−p

RN |u| p

dx

α−p/p−p

≤ S −pα−p/pp−p

RN |u| p

dx

p−α/p−p

RN |∇u| p

dx

p∗α−p/pp−p

.

2.26

Consequently by the Young inequality we have



RN |u| α

dx ≤ η



RN |∇u| p

dx  K

η

RN |u| α

dx

pp−α/p2p−p2−pα

2.27

for η > 0, where Kη > 0 is a constant.

Because u ∈ W 1,p ∩ W 1,qRN  so we can by Sobolev embedding and λ RN ax|u| p

bx|u| q dx letting λ 

RN |u| p dx < ∞, we derive the following estimates for Iu and Iu: Iu, Iu ≥

 1

p − εS−1λ p/N − C ε η



RN

|∇u| p dx

 1

q



RN |∇u| q dx − ελ − K

η

C ε λ pp−α/p2p−p2−pα

2.28

Trang 10

Choosing ε > 0 and η > 0 so that

1

p − εS−1λ p/N − C ε η > 0, 2.29

we see that I λ and I λ∞ are finite and moreover minimizing sequences for problemsI λ and

I λ are bounded It is easy to check that I λ and I λ∞are continuous on0, ∞.

We observe that I μ≤ 0 for all μ > 0 Indeed, let u ∈ C

0R N and



RN ax

ux/σ σ N/q



p dx 



RN bx

ux/σ σ N/q



q dx  μ, 2.30

then for each σ > 0 we have

I μ∞≤ 1

pσ pp/q−1N



RN |∇u| p

dx  1

qσ q



RN |∇u| q

dx − σ N



RN F

σ −N/q u

dx −→ 0 2.31

as σ → ∞.

λ < 0 for some λ > 0, then I μ/μ is nonincreasing on 0, ∞ and

limμ → 0I

μ /μ  0 Moreover there exists λ≤ λ such that

I μ

μ >

I λ

λ for μ ∈ 0, λ. 2.32

Proof We observe that

inf Iu

RN ax|u| p  bx|u| q dx



u

x/σ 1/N



RN a

x/σ 1/Nu

x/σ 1/Np

dx  b

x/σ 1/Nu

x/σ 1/Nq

dx .

2.33

So if 

RN ax|u| p  bx|u| q

dx  k and 

RN ax/σ 1/N |ux/σ 1/N|p dx  bx/σ 1/N |ux/

σ 1/N|q dx  k then Iux  Iux/σ 1/N   I

k

We have that if σ > 0 and α > 0 with

RN ax|u| p  bx|u| q dx  α, then



RN

a



x

σ 1/N



uσ 1/N x



p dx  b



x

σ 1/N



uσ 1/N x



q dx  σα, I



u



x

σ 1/N



 I

σα

2.34

Trang 11

Consequently, for all α1> 0 and α2> 0 we have

I α∞1  inf



1

p



α1

α2

N−p/N

RN

|∇u| p dx  1

q



α1

α2

N−q/N

RN

|∇u| q dx − α1

α2



RN

Fudx;



RN

ax|u| p  bx|u| q dx  α2 .

2.35

If 0 < α1 < α2, then for each ε > 0 there exists u ∈ W 1,p ∩ W 1,qRN withRN ax|u| p

bx|u| q dx  α2such that

I α∞1 ε > 1

p



α1

α2

N−p/N

RN

|∇u| p dx 1

q



α1

α2

N−q/N

RN

|∇u| q dx − α1

α2



RN

Fudx

α1

α2



1

p



RN |∇u| p dx 1

q



RN |∇u| q dx −



RN Fudx



α1

α2I α∞2.

2.36

This inequality yields

I α∞1

α1 > I

α2

Since I μ≤ 0 for all μ > 0, we see that

lim

μ → 0

I μ

We claim that c  0 Indeed, it follows from 2.36 and from the estimate obtained in the

Lemma 2.1that for every 0 < μ < λ there exists an u μ ∈ W 1,p ∩ W 1,qRN, withRN ax|u μ|p

bx|u μ|q dx  λ such that

I μ μ2> 1

p

λ

N−p/N

RN ∇u μp

dx 1 q

μ λ

N−q/N

RN ∇u μq

dx − μ λ



RN F

u μ



dx

μ

λ



1

p



RN ∇u μp

dx 1 q



RN ∇u μq

dx −



RN F

u μ



dx



μ

λ



C1λ



RN ∇u μp

dx  C2λ



RN ∇u μq

dx − C3λ



,

2.39

where C1λ > 0, C2λ > 0, and C3λ > 0 are constants Hence

μ2≥ μ

λ



C1λ



RN ∇u μp

dx  C2λ



RN ∇u μq

dx − C3λ



, 2.40

... λ∞ are bounded in W 1,pRN .

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Proof From...

By,R



|u| p  |∇u| p

Trang 7

Now,... n|2− |∇u|2

.

2.8

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So

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