Đáp án môn phương pháp tính

d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu) Cau 02:a) (1 d) P(x) = (95.0000) + (41.4000) x + ( 60.0000) x2, b) (0.5 d) ss = 80.0000 Cau 03:a) (0.5 d) X2 = ( 0.0711 ; 0.1160) b) (0.5 d) N_Gauss = 5 c)(0.5 d) N_Jacobi = 5 Cau 4: a) (1 d) Muc nuoc = 7.8821 b)(bo qua) So buoc lapd) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu) Cau 02:a) (1 d) P(x) = (95.0000) + (41.4000) x + ( 60.0000) x2, b) (0.5 d) ss = 80.0000 Cau 03:a) (0.5 d) X2 = ( 0.0711 ; 0.1160) b) (0.5 d) N_Gauss = 5 c)(0.5 d) N_Jacobi = 5 Cau 4: a) (1 d) Muc nuoc = 7.8821 b)(bo qua) So buoc lapd) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu) Cau 02:a) (1 d) P(x) = (95.0000) + (41.4000) x + ( 60.0000) x2, b) (0.5 d) ss = 80.0000 Cau 03:a) (0.5 d) X2 = ( 0.0711 ; 0.1160) b) (0.5 d) N_Gauss = 5 c)(0.5 d) N_Jacobi = 5 Cau 4: a) (1 d) Muc nuoc = 7.8821 b)(bo qua) So buoc lap

===========================

M= 1.4

Cau 01:a) (1 d) x3 = 0.5766, SSx3 = 0.0107,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-41.4000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0711 ; 0.1160)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8821

b)(bo qua) So buoc lap = 134

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.9000) x + ( 0.7500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.7300

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 1.5

Cau 01:a) (1 d) x3 = 0.6005, SSx3 = 0.0094,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-41.5000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0702 ; 0.1242)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8738

b)(bo qua) So buoc lap = 125

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.8000) x + ( 0.6500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.8125

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 1.6

Cau 01:a) (1 d) x3 = 0.6235, SSx3 = 0.0083,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-41.6000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0694 ; 0.1324)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8655

b)(bo qua) So buoc lap = 117

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.7000) x + ( 0.5500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.8800

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 1.7

Cau 01:a) (1 d) x3 = 0.6459, SSx3 = 0.0073,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-41.7000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0685 ; 0.1407)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8571

b)(bo qua) So buoc lap = 110

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.6000) x + ( 0.4500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.9325

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 1.8

Cau 01:a) (1 d) x3 = 0.6675, SSx3 = 0.0064,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-41.8000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0676 ; 0.1489)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8488

b)(bo qua) So buoc lap = 104

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.5000) x + ( 0.3500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.9700

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 1.9

Cau 01:a) (1 d) x3 = 0.6886, SSx3 = 0.0056,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-41.9000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0667 ; 0.1571)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8405

b)(bo qua) So buoc lap = 99

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.4000) x + ( 0.2500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.9925

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.0

Cau 01:a) (1 d) x3 = 0.7090, SSx3 = 0.0049,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.0000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0659 ; 0.1653)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8323

b)(bo qua) So buoc lap = 94

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.3000) x + ( 0.1500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 3.0000

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.1

Cau 01:a) (1 d) x3 = 0.7288, SSx3 = 0.0043,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.1000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0650 ; 0.1735)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8240

b)(bo qua) So buoc lap = 89

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.2000) x + ( 0.0500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.9925

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.2

Cau 01:a) (1 d) x3 = 0.7480, SSx3 = 0.0037,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.2000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0641 ; 0.1816)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8157

b)(bo qua) So buoc lap = 85

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.1000) x + ( -0.0500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.9700

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.3

Cau 01:a) (1 d) x3 = 0.7668, SSx3 = 0.0032,

b) (0.5 d) CO the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.3000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0632 ; 0.1898)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.8075

b)(bo qua) So buoc lap = 81

Cau 5: (1 diem) N(x) = ( 2.3000) + ( -0.0000) x + ( -0.1500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.9325

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.4

Cau 01:a) (1 d) x3 = 0.7850, SSx3 = 0.0028,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.4000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0624 ; 0.1980)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7992

b)(bo qua) So buoc lap = 78

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.1000) x + ( -0.2500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.8800

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.5

Cau 01:a) (1 d) x3 = 0.8028, SSx3 = 0.0025,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.5000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0615 ; 0.2061)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7910

b)(bo qua) So buoc lap = 75

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.2000) x + ( -0.3500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.8125

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.6

Cau 01:a) (1 d) x3 = 0.8201, SSx3 = 0.0021,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.6000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0606 ; 0.2143)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7828

b)(bo qua) So buoc lap = 72

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.3000) x + ( -0.4500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.7300

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.7

Cau 01:a) (1 d) x3 = 0.8370, SSx3 = 0.0019,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.7000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0598 ; 0.2225)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7746

b)(bo qua) So buoc lap = 69

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.4000) x + ( -0.5500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.6325

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.8

Cau 01:a) (1 d) x3 = 0.8535, SSx3 = 0.0016,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.8000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0589 ; 0.2306)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7664

b)(bo qua) So buoc lap = 67

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.5000) x + ( -0.6500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.5200

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 2.9

Cau 01:a) (1 d) x3 = 0.8696, SSx3 = 0.0014,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-42.9000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0580 ; 0.2387)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7582

b)(bo qua) So buoc lap = 64

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.6000) x + ( -0.7500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.3925

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 3.0

Cau 01:a) (1 d) x3 = 0.8853, SSx3 = 0.0012,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-43.0000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0571 ; 0.2469)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7500

b)(bo qua) So buoc lap = 62

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.7000) x + ( -0.8500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.2500

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 3.1

Cau 01:a) (1 d) x3 = 0.9007, SSx3 = 0.0010,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-43.1000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0563 ; 0.2550)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7419

b)(bo qua) So buoc lap = 60

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.8000) x + ( -0.9500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 2.0925

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 3.2

Cau 01:a) (1 d) x3 = 0.9157, SSx3 = 0.0009,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-43.2000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0554 ; 0.2631)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7337

b)(bo qua) So buoc lap = 58

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 0.9000) x + ( -1.0500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 1.9200

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 3.3

Cau 01:a) (1 d) x3 = 0.9304, SSx3 = 0.0008,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-43.3000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0545 ; 0.2712)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7256

b)(bo qua) So buoc lap = 57

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 1.0000) x + ( -1.1500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 1.7325

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

===========================

M= 3.4

Cau 01:a) (1 d) x3 = 0.9448, SSx3 = 0.0007,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-43.4000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0536 ; 0.2793)

b) (0.5 d) N_Gauss = 5

c)(0.5 d) N_Jacobi = 5

Cau 4: a) (1 d) Muc nuoc = 7.7175

b)(bo qua) So buoc lap = 55

Cau 5: (1 diem) N(x) = ( 2.3000) + ( 1.1000) x + ( -1.2500) x(x-1)

Cau 6: (1 d) A = 1.5419 , B = -3.2484, C = 2.3452

b) (0.5 d) KHONG the su dung da thuc noi suy, vi du lieu x1 =x2

Cau 7: (1 d) I = 1.5300

Cau 8:(1 d) y(1.25) = 0.0215, y(1.5) = 0.1547

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M= 3.5

Cau 01:a) (1 d) x3 = 0.9588, SSx3 = 0.0006,

b) (0.5 d) KHONG the su dung pp lap don (khong cho diem neu khong de cap den he so co hoac tinh hoi tu)

Cau 02:a) (1 d) P(x) = (-95.0000) + (-43.5000) x + ( 60.0000) x^2,

b) (0.5 d) ss = 80.0000

Cau 03:a) (0.5 d) X2 = ( 0.0528 ; 0.2874)

b) (0.5 d) N_Gauss = 6

c)(0.5 d) N_Jacobi = 6