Power system analysis and design
Trang 1J DUNCAN GLOVER MULUKUTLA 5 SARMA
THOMAS J OVERBYE
ISBN-13: 978-0-405-20587-6 ISBN- 10: 0-495-29597-3 THOMSON THOMSON,
ENGINEERING
3?2ã0815”81351?k
Trang 2be reproduced or used in any form or by any means—graphic, electronic, or mechanical, including photocopying, recording, taping, web distribution or information storage and retrieval systems-—without the written permission of the publisher.
Trang 3Symmetrical Faults Symmetrical Components Unsymmetrical Faults
System Protection
Power-System Controls Transmission Lines: Transient Operation Transient Stability
Trang 5% Aye -b-daa J aeig ¬ ( lau: TỆ “a 24 +5 (255V s $233.42"
Vena = G@THEV 5 1T went ụ Zoo A
Nes G79-8//2 2 AROV 4 © > 200/fP 214rad
Trang 6ACey) = VA-68 đơa Cob each) A
+ WÍ2 : (tr 130°) [am La») 273-46 [~G0°A ÄLCC) + 76:46 I et Cab ¬ 667) z 103% an (wb 60°) A (49 Z:2 ~42% H
cor Ys Ceol ye 5 lane 2 70°F ¿z6 5 Go Bees tet APPEAR te THE Answer,
ch3 ASC LY a vee JR ce Cate 20’) 5 waste Gas BUT
yCe js lard œ@ ( tt tE 6” 5
Trang 7eCede ake bir: Jz Ref de® ‘|
THE RESOLTAMT HAS WE SAVE FREGuUEnCyY GI,
(ay Ee (ioe Lo") /(e (534°) = 20 /-5a.0 &
THE CoRReey LAGS Te SeuRce veLTAGE BY E3 ?‹\
Power FaeteR 2 Get SEV =» a-G LAGQIng
gh Bast
Trang 8«vk: 120 Zo s (G0 9") Corte jos d+ Veons
Cay pled = WCEVACEY = [67B-B ex Cat =te8" }Ï [ 200 en Cáb~ 8 31
= & (678-8) (200) [ane + cos 26a vo]
(b> Ps: va ca (5+ B) 2 A486 x aia Ga ô
= -LING xo” bị ABSesBED = <c 1⁄14 ri peLiveerp
% =—G.Cѧ6Š AT” VAR Agse Renn + + 66-65 kvae DBELWE ECO
(AD THE PuAsee cuReenT (-T) a jana /=stoine’ = tad ves? A
LEAVES ‘ThE Positive TERMWAL OF THIS GENERATER + THE Conteaseg Pewee FACTOR 1S Tas GC toS 185°) = @IIBG LAGEING
Trang 9ail ”
cos (3+ CE) AC) x mu 219-58 et Cube acd
= @-†66®% ¬ Co [ve ee Cat NA“
x 5:5 RÍO + A.Sbáa.nioP đa (2+6) Vị
SauReé Povs6©& €ÐCY4E, s Sø CẾ- B3: Ge CB6.38) = 1.0
= Avot wie” CL) Lo Be? ae Cua Cack.2) |
c Bobs» to” Ge Crat-ed dD Ww
Pe Vian (8-8) 2 221% 73:46 Gn C2460) 20 Vị
PS 2 Ga C¥~BYs 9 LAGaing
Cod PCED = CE) ACEI= BAT» (SGV Cor Caste a0" Cos (eot-~ 20")
% Gas ate CL) (om C-ad) vom CzezÈ x 180°) 1
= B.064 wie? Cae C resk te } WwW
€): MĂX „3w Cá-e› 2 2s Wek Ady (4079
= <BoGikvag Agsoreed =< + 3.069 kvAR Dativerep
212
Co Peck): 6788 verse cnt Cabs 4s?)
2-204 x và
9 + 2Ö b5Á net On Come wae} W
oe
Trang 102.4% SaktO
a B43 elo” Ges Cote &B°) Gen Coal ~ tag")
(4> @e vi fx = (ans.8/da Ÿ 25 = 4.216 tố” VAR DeLivaned
(a) Be R-Ax = le-4252 2G0Q5 [68.2 R
ACky=s (678-2/26.93) an C tae A874 68-2)
n 2S21 Gn Cakeus-2) A
Packd= (26-2 cass Coat & 03.297) Lasart an Cea + ia.279]
G.eS5 xio? an” Cok + 3.2")
=e BAW MIS 4 Brig nw Com C ack + 2264?) Ww (by BCke) ® [25a Gar (cake WSR WL 620.2 Cn (Cob mia.e? nae 1
ae 3 (28-~t/ f8 3 Casy + UGA evar DEUVERED
@ bí ;s G^ [ tex (@/P3 Cas | tant C1444 | 3.82]
4.5 T4, LEaving
2
Trang 11P3 ÂCE) {CC [8E đa Cát] [4Œ eaat]
2 G4 C&S [ cn Cae ds ee Camb-45*)|
& 22-63 + 2 as (aat—-as°> My
Pe VL os CE-B) = &* & est (45 0°) = 20-63 MW
DELIVELED G@Qa VLAN d-B): Bx 4 Aw (-48-0") 2
= — 22.63% MvVAR DEWERED = 4 22-64% MVAR ABSeRBED
VỆ r Gn Cd-B) = en C- 48°) 2 O-TO7 Leaping
Ee (Cla) Lol] (2lae) s ta
ACK) a 2Ger Cok wad) A wim Gis ATT ned(s,
pled = wiley Acky = Ay | Can ao" fe Ge C2esk + qo" >)
s BAG AG Cant a4) Và
WCED ACL omd pLt) are pleted below: (gee wext baged
The Imakavtomesus Peuter la om anenage value of BAG bà,
and bhe Snag wency e bustee Ảxak of Woe nsolkage dt Cuanenk ,
w/e
Trang 12THE REAL PowEe ABSeRBED QT TRA LeAD 93 Givew ay
Pe teen G-6Rn Gas BE 5 AAG
2
TAG REACTIVE Co 6Œ AQ@sefø% GT THE Leap 1S
Qs WoxGEB% Am S64 2 GER VAR
2
fe > PEAK MAGMETIC SHÁSGY 2 bh) a LIT a oad Cz.es»Ÿ se ie FS
Gà „ €3» V © 3t 1G 2 G6B VAR 19 SANISTIED,
Trang 13#
& S.y ik = ZTI% = BF = Jord
Q s 1.5] = cou XẾ -aÖ—=se=
Ce aisCkyde ob ae 2 +2 OUT Pon Cost + 9)
(2z zCk3-ACE3+ ~2caL x? Ÿs Có E+ ø) Gợi Cosk+Ø)
eH WL Ama ate) «—
= — Q/A*+23(aE+@8)
Co) AVERACE REAL PoweR Ê SUPELIEĐ T6 Tác (DUCToQ 2 Œ at
INSTANTANEOUS POWER SUPPLIED Cro SUSTAIN THE CUAMAING BNERG'T
IN TAs MAQNETE FURBD WAS A MAXIMUM VALUB GF G}, —
Trang 14Whiew ARE THE RERCTWR Cou26ES [ATO LAND C ABR SPECTIVELY,
EF ca”L€s\, Q(c+@$c >Q xe
a
TS BC) z P Cle emeat )j
m1 we
Trang 15Cay 6.4 #” 2 Gse fae) Cs /-s¢) 2 750 {ge
2 B75 +A 644-5
Pe Re C Sd 2 B15 W AesoeGen, + 1x C5: GA%.S VAR ASsesece
The Fou Sh TRIACGLE (6 Gives BELetat
©) @, = P kea 6, = B15 tao Cee 9:32 2 190.62 vaR
@ > @ - Ge = G4A,.5 -V\B\.62 = A67.88 VAR
PR, 2V'G, = Gee) 0433 2 ABB WL ASSORELD
P= V*G, a(oof 903 5 BOOM AOSa§BEĐ
8 a a ye Đố * Qae Ÿ 2.58 % Bea VAR Detiverep
Seava
fe
Trang 16+ (eoe ew Cassa 5 94.94 VAR
Qạr: Q&- 8, * te2e-2 - 484:32 BSAS-A kvag
Rose VỀ (tas.a8Ÿ Co.e8%243x ABTGW
Py 2 VÀ 2 (od.08) Cen): 1062-6y
(by ¥ y 5:88 4 s.VAAI z ^:2 2093 /— AB.s\
eq = (lod-o8) (288%) 2 24.63 A
Trang 17$%x Ñ kêu 3 Gas és) Cas [-30°) = Bece /-30
Ge@t:Pt.É6 x3 Powe ABBR BREE GY THÊ, To CAU Loá® Shean? Ser Ss 5 2 2060 [s30
PowkR TRiAW GLE ;
Gererex 2x66 206Li406G6 2 ý Thể, 0666 19 (Goa VAR
Seounce, =.V x* os ¿a ›C^a — > = 2606 [ase
FRE GOMPLES Powee DELIVERED Gy Tue SevAce 1G EQUAL TO TRE TeTAL Comftay
Fowl AGSoRGED OM THE Leo hi,
“(B=
Trang 18REACTIVE POWER LOSS ts THE Ling 16 Gi = Ft
ch Ss; = PgeA@, = tre +4 C4 Ai B6 de BG B12) = 200-7 [5328 \eva
TWE INPUT VOLTAGE 1S Given BY Vat ĐC [3 2 682-4 (RÀO
Tue Powe EACTER AT ME INeET 1S đơa 53228 = O-G LAGGING
+ GB88+9586 = Gana fas’ Vo Cramay
CPS), = Go Cars’ ata) = 0G LaAgane
mtd.
Trang 19THE CARCUIC fØlÁOG(&@APA (4 SWobeMW BELows
{B=
Trang 20Some = Di tS, + Sy = (Bo 84445-5417) kva
CL) LET 2 BE THE TMTEDAWCE CEA SERIES ComBinAtion bf Rawn X
" a
= mon — » Since Sa GT* = (S) = ¬ > tT Foltows TAAT
Daye _— 3+ = O44 ANB ae
PAWILARLY a (aS+4o5) we AAV mH CO eG O22 MON MAO tem
Sao = o0 Sax = OHA A—~
Av Bus 4, a3 = Say & 33, = (o gargvR)+ Ga-jon)= 4:54 Á*\ i
~
Trang 21a TA 2 GOkW Ò Qorat aokvaR „KV 9x2 100 VA
Surrey ef 2 Cos (C9348) = OG LAGaING ae
Qe) T › EM Loox io? £25393"
Cos Coa) 2 BEB7’
Trang 22Nove: TEV Lenos Va, XS TẾ We Positwe Aud THE REAL PER Blows FRom Neve A te MeDE 2
REY LAGS UY, , ENS WEGADVE Aud PewER Foews FROM Neds 2 Tr NOE A,
Trang 23Preblem 2.32
Qeap = 5 Mvar minimizes the real power line losses (0.25 MW)
if Qeap has a value of 5.5 Mvar, the MVA power flow is minimized with a value of 10.25 'MVA
Trang 24(Admittance valves are Shaton) RẺ
sees ona = (4956 - 34450) -386t,4ep) kh(b-t8ax-@3 | Vio] ~ (4980 tease) ][%] faci vier? [1-461 LIL
OoB17Tb +3109 | - 0.49604) 4980 ¥e| _ | veel [E4e67©
2.36
METE THAT THERE ARE Two BUSES FLUS THE REC ERENCE Bus
Awpy ONG LINE Fe@ THIS PReBLEm AFTER ConpvEeRTIVNG THE
VOLTAGE SGuRceS in FIG.2.23% Te CỤ RR€MT SGUÉC£6, THỂ,
EQuivALEMT Sougee impenances ARE:
Sẽ = Ben = (04 + $0.8) ff (-io.s) = O-1480-8) (seri)
Trang 25Agter Converting impedance valves mm Figure 2:32
to aAÀwxitlasee Valves tue bus adumltiaue muctrin ioe
“! (so-il (co.sswstii) =0,x§ Vag -| o
O (-o.38334)1) (0.33¢3-Jo.as) - $0.28 Vie ©
Trang 26Far Yan Xá» Nea
aot bia * đa 7 Nee? Gra tag © doy
WHERE Yu * Bro «Sie, “` # Ÿa»#
44° Yaa 5 Tat? Vase Sa 5 Vine Want Figs Yon t Vent "3%
ano Ya, 2 Yan > 7 Fee
Trang 28Fae = đề Mew Ey La“ Ces) = fe 208 x26 [Sse
+ *1:aeS xiet //26:872 = Fog = Re C324) 2 S164 ku Pewee , 7 6Œ ,> 1.5, sẻ C s4) \; 4.323 kar PEuweeeS
BGA RIS 44 A B23 wie”
Pa n G322 VY ý Quà 6\42 VÀR ý Ben AGSRSED BY THE LoAD
PS = CnC BEaT?) zeBiacana, Sa,~ | Saale sesava
Trang 292.4.5 ane
(Hi) - ThuaSfeBliiG THE Ax Gammeeted Lea tte AN EQUINELENT N,
TAL IMPEDANCE PER PUASE of Tue EQuivaLauT Yo ig
Pa i€@goW awk G2 O VAR DeuvERED Bt WE SéniBintc-EmD SeuRcE
Co) PHASE VeLTAGE AT Loan TeRmmeats V2 t2ofo"—(24ja) Ca le")
2 Wo-Aze = Wig ¿>ta.a° Vv
THE LING VOLTAGE MAGI TUDE AT Tue Leap TERMINAL 15
(Viens Ju = Jš WES 2 \S%.6A V
Ce) Tee cuggent Fee PuASE IN THE Y—COmMECTED LeAD Awp in THE Baan y
or me A-neap; Fiz Me = yee 2206/-63.8 A
Trang 30243 GontD,
eer
C3 THe TUREL- PHASE GewPiix Yew e@ AGSCRRED GX dace LoAD |
Se BY, EP 2 AsOW ~ Ả 666 VÀ
B.5 av, 3) m (266K — 4 Goo VaR
Tah TAREE -CUASE Came.ean PawER ABGORGELD BY Te Lind 1S
Sit SBCRL+aRLD 22 BC 2444) GY = (5694 + 2560 VaR
ThE GU GF LEAD Gawhes AMD Line LESGES 18 Bua TÔ WE Cawee
DEL ve ROD VÑOWA THẺ Se Phey + $
¬
> \feøVA « jo VAR
~L6°
Trang 31(QD THR PER-CBASE E@CIVALEMT Gigewt Goh TRE PROBLEM 1S Strown Below
Tota ComFLan Pewbh AT The LoaS Eu o@ BECELVING BaD (6
Seed + 56&o0.t6-1e+4e.7et «22 + 688 #4 B96 2 Geo [36.81
VarTs PBASE VOLTAGE VV, AG QEFERENCE ,
= % 3x Se cae) _ G60,0ce £23681" = lee [= B¢87° A
ay @ Cazes fo") :
/PHASE VeLTAGE AT SEanming EMD 6S Givan BY
UW, = 220e fore Co-aadad Cioo (236-87) = 24011/4.58 y
THE MAGHITUDE of Tet Lint Vo LisG VeLIaag AT THE GEa Bina EWD OF tha Line 1g
Que «BV, 2/2 (#24010) = 4160 V
(o> THE THRRE- PHASE CoMPLEeN— Powe LoSS IN THE Lind 19 Gwen BY
(G> - TUE THREE- PHASE SEMDING Powe 19
= BY, E*« B Caacin £4.58") Clo 26 ©8192)
S40kn «+ 4477 kvar
Sscags
NOTE MAT Se cney * Sacaey # Sicaey
f7
Trang 32car Vax ® & ie áo 2 6.661 (60° ou
, UsinG VeLTAGE Distant » 2 YY Vans = Nay “ Bala | 3
Vv AN = 2a8 TE 6-667 £60" Gecrfers (oer jee) SL ET Ce 1b) 1o8- 4 / 2.46 * * 2n, ˆ * %
LOAD vacTaa® Vag = 2 16-4 = 162-6 Cr-cd
Trang 33~ Buea tar > fe ig? - Cu +32) (3 s»(=® ì
216-4 fa BIS NÓ tông to MEV TRAL
(> 8g, = Ve, Eqh = B Casad L-0-63°) (Gave [Arar )
e Ze-t2 we” + 4 ide to”
Par * gonna 5 Qa, zt \evaR 5 Bets DALIVERED
Trang 34(o> Lex 2, = 24 rầp * 2e z 5 FoR A BALANCED YO LOAD
2, 2 2 Bap FOR ABALANCED A-LOAD
USING EQvationsS wi FIG 2-2
Trang 35-=5Q@«-` 7 2Á 2
: aye 4g PER PHASE EB@UIVALENT GtiReult 1S Blown Bets ý
REPLACE DEutTA BY WE EBUWALENT ME
Trang 36ON A&A PER-PHASE BASIS Sys S564 te) 2 Gor44o) kva
AT THR SENDING ED
-32~
Trang 37ND 1 &eiGo
CA LET Mà BE THE REFERENCE ¢ Vat
[oe #2400 /o’y TOTAL (MRE DANCE PER CUAS E Zz % (4 <1<5 43+ (6= Á 133 Gxátø3)~
? LANE cu@&eAt „ 249049 ` “ -
BeAto
Wim PoeSitwe A=GB-C PHRASE SEQUENCE |
¬- ^^ nh 2vA c1 T 3e 4 ~a\Ar (S66 Ä x—
b Ñ = 2ac0 fo” ~\@ 1 /~63-& Joa e4i Ì
Ce? Sy) cons ace Le Gras lo )€ a")