Tiêu chuẩn tiêu chuẩn iso 05495 2005 amd1 2016

© ISO 2016 Sensory analysis — Methodology — Paired comparison test AMENDMENT 1 Analyse sensorielle — Méthodologie — Essai de comparaison par paires AMENDEMENT 1 INTERNATIONAL STANDARD ISO 5495 Third e[.]

Sensory anal ysis — Methodolog y —

An lyse sensorie lle — Méth dolo ie — Essai de comp raison p r

p ire s

T ir d edition

2 0 -1 -1

Reference n mb r

ISO 549 :2 0 /A md.1:2 16(E)

AMENDMENT 1

2 16-0 -1

COPYRIGHT PROTECTED DOCUMENT

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The commit e r sp nsible for this document is ISO/TC 34, Fo d products , Subcommit e SC 1 ,

Sens ory a al ys i s

Sensory anal ysis — Methodolog y — P aired c omparison test

Pa e 15 , An ex B,B.5.2

R eplac B.5.2with the folowing:

B.5.2 Analy sis and interpretatio of results

In Ex mple 1 (one-sided p ir d t es ), the data we e as folow s:n = 3 , x = 2 , α = 0,0 From these data,

the analy st calculat es

— p

c

= x/n=2 / 0= 0,7,

—

ˆ

p

d

(pro ortion of dis inguishe s) =2p −1 =2×0 7−1=0 4

c

— s

d

( tan ard e ror of p

d

=

ˆ

0 4 1 64 0 1 7 0 1 5

The sensory analy st can the efor be 9 % c rtain that the pro ortion of consume s w ho pe c ive the

prot oty e t o be c ispie than the control is larg er than the pro ortion of consume s w ho pe c ive the

control t o be c ispie than the prot oty e b at leas 1 % This r sult a r es with the conclusion given

in Ex mple1, sinc it shows that the one-sided conf idenc int erv l does not contain the n l v lue

In Ex mple 3 (wo-sided p ir d dife enc t es ), the data we e as fol ow s: n = 44, x = 3 , α = 0,0 It

folow s that

— p

c

= x/n=3 /4 = 0,7 ,

—

ˆ

p

d

(pro ortion of dis inguishe s) =2p −1 =2×0 7 −1=0 45

c

— s

d

( tan ard e ror of p

d

— 9 % uppe conf idenc lmit =

ˆ

p

d + z

/ s

d

= 0,45 +1, 96 × 0,1 4 = 0,7 , an

ˆ

d α 2 d

0 45 1 9 0 1 4 0 1

The sensory analys can the efor be 9 % c rtain that at leas 1 % and at mos 7 % of the

po ulation is ca a le of dis inguishing thesamples Thisr sult concords with the conclusion given in

Ex mple 3, in icating sample A as being saltie , sinc it shows that the conf idenc inte v l does not

contain the n l v lue

In Ex mple 4 ( wo-sided p ir d simi arity t es ), the data we e as folow s: n = 1 0, x = 6 , β = 0,0 an

the c itical p

d

= 3 % In the two-sided case, the v lue of x is chosen t o be the ma imum of the two

choic cou t , r g rdles of w hich sample was chosen mos oft en The calculation the efor gives

— p

c

= x/n=6 / 12 = 0,5 ,

—

ˆ

p

d

(pro ortion of dis inguishe s) =2p −1 =2×0 5 −1=0 1

c

— s

d

( tan ard e ror of p

d

=

— 9 % up e conf idenc lmit =

ˆ

p

d + z

β/

s

d

= 0,1 + 1, 96× 0,09 =0,2

The sensory analy st can the efor be 9 % c rtain that he actual pro ortion of thepo ulation ca a le

of dis inguishing the samples is no gr at er than 2 % F or the simiarity t es , the analy st chose the

conf idenc level t o be 1 0 (1 – β) = 9 % Sinc 2 % is les than the pr -es a lshed lmit ( i.e c itical

p

d

= 3 % ), the analys can conclu e with 9 % conf idenc that the samples ar sufficiently simi ar in

surfac sl p t o be used int er hang ea ly

Sinc x was defined as the ma imum choic cou t r g rdles of w hich sample r c ived the highe cou t,

only the up er-lmit of the two-sided conf idenc int erv l ne ds t o be calculat ed

ICS  67.240