cisco semester 1 chapter 5 osi network layer v 4 0

... over a 56-Kbps WAN circuit  Load = 5 x 10 x 1,024 = 51,200 bps  Utilization = 51,200/56,000 = 91.4%  Average number of packets in queue = (0.914)/(1-0.914) = 10.63 packets Trang 45Hochiminh ... San Francisco = SFO, Oakland = OAK Trang 60Discontiguous Subnets Area 1 Subnets 10.108.16.0 - 10.108.31.0 Area 0 Network 192.168.49.0 Area 2 Subnets 10.108.32.0 - 10.108.47.0 Trang 61Hochiminh ... Nines” availability Trang 32Availability Downtime in Minutes 4.32 1.44 72 01 30 10 5 10 1577 99.70% 526 99.90% 263 99.95% 5 99.999% Per Hour Per Day Per Week Per Year .18 06 03 .0006

Ngày tải lên: 26/11/2016, 02:11

... Phương trình đặc trưng: hoặc1 G s H s( ) ( ) 0  G s H s ( ) ( ) 1  Điều kiện biên độ: G s H s ( ) ( ) 1  Điều kiện pha: G s H s( ) ( )  180 (2 1), 0 l  l  0,1, 2,  Lưu ý: G(s)H(s) ... nếu các điều kiện về pha và biên Trang 15Phương pháp quỹ đạo nghiệm số Thí dụ 1 (cont)  Nhận xét Trang 16Phương pháp quỹ đạo nghiệm số Thí dụ 1 (cont)  Nhận xét Trang 17Phương pháp quỹ ... Locus) Trang 3 Ví dụ: Nghiệm của phương trình đặc trưng khi K thay đổi3 ( 1)( 2)( 4)( 5) s K  Trang 5H(s) E(s)Điều kiện pha và biên độ  Cho hệ thống có sơ đồ khối như sau: ( ) 1 ( ) ( ) C s

Ngày tải lên: 12/12/2013, 16:15

... 11000000 11100000 Subnet mask 255.255.255.224 11100000 Trang 4400000000 00010000 00100000 0011000010000000 10010000 10100000 00110000 01000000 01010000 01100000 01110000 10110000 11000000 11010000 11100000 ... 192.168.1.0 192.168.1.32 192.168.1.64 192.168.1.96 00000000 00100000 01000000 01100000 192.168.1.96 192.168.1.128 192.168.1.160 192.168.1.192 192.168.1.224 01100000 10000000 10100000 11000000 ... Host 01000110 70 192.168.1.70 Subnet mask 00000000 0 255.255.255.0 Subnet mask 00000000 0 255.255.255.0 Network 00000000 0 192.168.1.0 Broadcast 11111111 255 192.168.1.255 First host 00000001 1 192.168.1.1

Ngày tải lên: 01/04/2014, 12:20

... lam a most devout Radical [have a vote, too, and you may count upon me “Lam very glad to hear it," Grooks answered “Shall I put you down on the list ‘to be fetched’?" Trang 11The Marquis ... Trang 10ordered "And will you send out some tea to my servants, please? It will save them from trying to obtain drinks from the hotel next door, and ensure us a safe drive home.” "And ... something less depressing." "You shall tell me," she suggested, "who is going to win the election.” "Henslow!" be answered, promptly “Owing, | suppose " Trang 6“To his agent,

Ngày tải lên: 06/07/2014, 02:20

... fifty in her fleet The English had three armies, 5,000 men in Catalonia; 10,000 in Portugal; 50,000 Trang 8in Flanders; and besides, was paying £1,666,666 a year to monarchical and diplomatic Europe, ... we have just observed, was popular What was she doing to be so? Nothing Nothing! that is all that is asked of the sovereign of England He receives for that nothing £1,250,000 a year In 1705, England ... devote herself to stage plays She had an absurd academy of music, copied after that of France In 1700 a Frenchman, named Foretroche, wanted to build a royal circus at Paris, at a cost of 400,000

Ngày tải lên: 07/07/2014, 05:20

... puts checksum value into UDP checksum field Receiver:  compute checksum of received segment  check if computed checksum equals checksum field value: Trang 105: DataLink Layer 5a-10Checksumming: ... other node transmits in [p0-1,p0] = p (1-p) (1-p) P(success by any of N nodes) = N p (1-p) (1-p) … choosing optimum p as n -> infty Trang 265: DataLink Layer 5a-26CSMA: Carrier Sense ... increases:  pkt sent at t0 collide with other pkts sent in [t0-1, t0+1] Trang 25Pure Aloha (cont.)P(success by given node) = P(node transmits) . P(no other node transmits in [p0-1,p0] . P(no other

Ngày tải lên: 04/12/2015, 20:37

... © 2014 Computer Networks 2 Chapter 5: Network Design 172.16.10.2 172.16.30.2 172.16.50.2 172.16.20.1 172.16.40.1 172.16.10.1 172.16.30.1 172.16.50.1 172.16.20.2 172.16.40.2 Trang 50Hochiminh ... University Of Technology Computer Networks 2 Default Routing Example 172.16.10.2 172.16.30.2 172.16.50.2 172.16.20.1 172.16.40.1 172.16.10.1 172.16.30.1 172.16.50.1 172.16.20.2 172.16.40.2 ... 2014 Computer Networks 2 Chapter 5: Network Design 29 Designing Networks with Subnets Trang 30Hochiminh City University Of Technology Computer Networks 2 More Practice  Network is 172.16.0.0

Ngày tải lên: 26/11/2016, 02:12

... Technical Advisory Group 802.8 Fiber-Optic Technical Advisory Group 802.9 Integrated Voice/Data Networks 802.10 Network Security 802.11 Wireless Network 802.12 Demand Priority Access LAN, 100BaseVG-AnyLAN ... 100BaseVG-AnyLAN 802.13 Unused Trang 22Project 802 LLC and MAC Sublayers Trang 23Project 802 LLC and MAC Standards Trang 24Device Drivers and OSI Role of Drivers  Network Environment  Network Driver Interface ... receiver  Add timing and error-checking information  Put data on the network and send it Trang 4Seven-Layer OSI ModelTrang 5OSI Layer RelationshipsTrang 6Application Layer (7) Topmost layer

Ngày tải lên: 15/05/2017, 14:44

... 1A-23-F9-CD-06-9B 222.222.222.220 111.111.111.110 E6-E9-00-17-BB-4B CC-49-DE-D0-AB-7D 111.111.111.112 111.111.111.111 A74-29-9C-E8-FF-55 222.222.222.221 88-B2-2F-54-1A-0F B 222.222.222.222 49-BD-D2-C7-56-2A ... 10 Mbps, 100 Mbps, 1Gbps, 10G bps  different physical layer media: fiber, cable application transport network link physical MAC protocol and frame format 100BASE-TX 100BASE-T4 100BASE-FX 100BASE-T2 ... datagram (or other network layer protocol packet) in Ethernet frame Preamble:  7 bytes with pattern 10101010 followed by one byte with pattern 10101011  used to synchronize receiver, sender clock

Ngày tải lên: 11/01/2020, 00:30

... Trang 16100 meters IEEE 802.3 10-Mbps Ethernet 2 multimode optical fibers 10Broad36 Trang 17100BaseT 100BaseT2 100BaseT4 4 pairs Category-3 or better UTP 100 meters IEEE 802.3 100-Mbps ... better UTP 100 meters 100BaseX Trang 181000BaseX 2 multimode optical fibers using shortwave laser optics 550 meters 2 multimode or single-mode optical fibers using longwave Trang 1910GBase ... Fiber Cabling 300 meters Single-mode optical fibers 40 km 10GBaseLR Single-mode optical fibers 10 km IEEE 802.3 10-Gbps Ethernet Trang 2010GBase with Copper Cabling Trang 21Metro Ethernet

Ngày tải lên: 26/11/2016, 02:14

... 6 24 RJ21x 2 ADCPP245100TEL 5100 patch panel 1, 2–3, 6 48 RJ21x 2 ADCPP485100TEL 5800 patch panel, T568B 1–8 24 RJ21x 1 ADCPP245800BTEL 5800 patch panel, T568B 1–8 48 RJ21x 2 ADCPP485800BTEL O ... field assembly kits 100-pair, 4-pair color-coded kit 14.75" x 10.75" x 5.25" 6642 1 115-04 Includes (4) 25-pair FT blocks with 4-pair (374.7mm x 273.1mm x 133.4mm) color-coding, 2 ... ordered separately 300-pair, 4-pair color-coded kit 14.75" x 10.75" x 5.25" 6642 1 315-04 Includes (12) 25-pair FT blocks with 4-pair (374.7mm x 273.1mm x 133.4mm) color-coding, 2

Ngày tải lên: 24/01/2014, 11:20

... VTY 29 As network administrator, what is the subnet mask that allows 510 hosts given the IP address 172.30.0.0? 255.255.0.0 255.255.248.0 255.255.252.0 255.255.254.0 255.255.255.0 255.255.255.128 ... through 172.16.159.255? 172.16.128.0 255.255.255.224 172.16.128.0 255.255.0.0 172.16.128.0 255.255.192.0 172.16.128.0 255.255.224.0 172.16.128.0 255.255.255.192 36 During the encapsulation process, ... Gateway: 192.168.100.17 IP address: 192.168.100.21; Subnet Mask: 255.255.255.248; Default Gateway: 192.168.100.18 IP address: 192.168.100.22; Subnet Mask: 255.255.255.240; Default Gateway: 10.1.1.5

Ngày tải lên: 13/12/2013, 19:16

... truyền về tế bào con IV Đột biến thay thế một cặp nuclêôtit vẫn có thể làm tăng số axit amin của chuỗi polipeptit Trang 55 HƯỚNG DẪN GIẢI CHI TIẾT 11.D 12.D 13.D 14.D 15.C 16.C 17.A 18.A 19.B 20.C ... 20.C 21.C 22.A 23.D 24.A 25.B 26.A 27.C 28.D 29.B 30.D 31.A 32.C 33.B 34.C 35.B 36.B 37.A 38.D 39.B 40.B Câu 1 (NB): Phương pháp: Sợi cơ bản (11nm) Sợi nhiễm sắc (30nm) Siêu xoắn (300nm) ... AABb 0,5AB:0,5ab Chọn A Câu 23 (NB): Phương pháp: Thể ba có dạng 2n + 1 Cách giải: 2n = 14  2n +1 = 15 Chọn D Câu 24 (TH): Phương pháp: Viết sơ đồ lai Cách giải: ♀ XaXa  ♂ XAY  1XAXa:1XaY

Ngày tải lên: 23/05/2022, 20:54

... Communications: Network layer and circuit level design, Edited by Salma Ait Fares and Fumiyuki Adachi p cm ISBN 978-953-307-042-1 Trang 5Preface Mobile and wireless communications applications have clear ... wireless networks has been evaluated The analysis has been supported by experimental results on the prototypes Chapter 14 discusses the development of a 60-GHz wireless transceiver-on-a-chip on a 130-nm ... number of call requests, provided that the BER violation probability does not exceed a satisfactory level ε1 (Wu, 2005) Trang 13Call Admission Control in Mobile and Wireless Networks 3schemes base

Ngày tải lên: 21/06/2014, 14:20

... structure, we have called it “the Double-Beveled Patch -30 -20 -10 0 -30 -20 -10 0 -30 -20 -10 0 -30 -20 -10 0 Antenna” [Alshehri & Sebak, 2008] To obtain UWB bandwidth, we use several bandwidth ... measured radiation patterns in the E-plane -30 -20 -10 0 -30 -20 -10 0 -30 -20 -10 0 -30 -20 -10 0 Trang 13(a) H-plane at 3.5 GHz (b) H-plane at 9.5 GHz Fig 7 The simulated and measured radiation ... obtained when the two transitions steps are used -40 -35 -30 -25 -20 -15 -10 -5 0 W2=14mm W2=16mm W2=20mm Fig 4 Effects of step width 6.4 Results and discussion After taking into account the

Ngày tải lên: 21/06/2014, 14:20

... Website: www.bkacad.com 11 Network Layer Fields • bits • Indicates version of IP used • IPv4: 01 0 0; IPv6: 01 1 0 H c vi n m ng Bách khoa - Website: www.bkacad.com 12 Network Layer Fields • • bits Indicates ... to 5 .1. 1 ) H c vi n m ng Bách khoa - Website: www.bkacad.com Network Layer Protocols • Protocols implemented at the Network layer that carry user data include: – Internet Protocol version (IPv4)* ... www.bkacad.com 10 IPv4 packet header • Identify the major header fields in the IPv4 protocol and describe each field's role in transporting packets H c vi n m ng Bách khoa - Website: www.bkacad.com 11 Network...

Ngày tải lên: 22/12/2013, 13:17

... First Look Network 19 2 .16 8 .1. 0/ 24 Network 19 2 .16 8.2 .0/ 24 19 2 .16 8 .1. 2 54 / 24 C 19 2 .16 8.2 .0/ 24 is direction connected, FastEthernet0 /1 Routers know about: Directly connected networks (C): Network addresses ... Exploration Semester 18 IP Fragmentation Original IP Packet IP Data = 14 80 bytes IP Header = 20 bytes IP Packet Fragments IP Data = 50 0 IP Data = 50 0 IP Data = 48 0 L2 Data = 52 0 L2 L2 Data = 52 0 L2 ... that network This is just like a host that is configured with an IP address/mask (coming) 17 -Jul -12 CCNA Exploration Semester 34 Routing – First Look Network 19 2 .16 8 .1. 0/ 24 Network 19 2 .16 8.2 .0/ 24...

Ngày tải lên: 01/04/2014, 12:20

... 802 .11 b and 802 .11 g standards IEEE 802 .11 b - Operates in the 2 .4 GHz frequency band, speed up to 11 Mbps Longer range and better able to penetrate building structures than devices based on 802 .11 a ... on 802 .11 a IEEE 802 .11 g - Operates in the 2 .4 GHz frequency band, speed up to 54 Mbps Devices implementing this standard therefore operate at the same radio frequency and range as 802 .11 b but ... the bandwidth of 802 .11 a IEEE 802 .11 n - Is currently in draft form The proposed standard defines frequency of 2 .4 Ghz or GHz The typical expected data rates are 10 0 Mbps to 2 10 Mbps with a distance...

Ngày tải lên: 22/12/2013, 13:17

... regional service, pay Teir -1 for connectivity Tier-3 providers: Provide service directly to end users, usually connected through Tier-2 providers 43 Quality of Service 44 Quality of Service 45 QoS ... physical limitations become less relevant 12 Networks are integral in our daily lives http://www.youtube.com/watch? v= fQKNvPn 3V8 &mode=related&search= 13 14 Examples of Today’s Popular Communication ... protocols 33 Converged Networks Traditional telephone, radio, television, and computer data networks each have their own individual versions of the four basic network elements Technology advances are...

Ngày tải lên: 01/04/2014, 12:20

... 15 16 Client Server 31 16-bit Source Port Number 16 -bit Destination Port Number 16 -bit UDP Length 16 -bit UDP Checksum Time Data (if any) Cumulative Sum: 11 0 01 0 1 01 1 0 01 0 10 1s complement: 0 01 1 01 0 10 01 1 01 0 1 ... 15 16 Client Server 31 16-bit Source Port Number 16 -bit Destination Port Number 16 -bit UDP Length 16 -bit UDP Checksum Time Data (if any) Cumulative Sum: 11 0 01 0 1 01 1 0 01 0 10 1s complement: 0 01 1 00 01 0 01 1 01 0 1 ... 0 01 1 01 0 10 01 1 01 0 1 Total: 11 111 111 111 111 11 UDP checksum provides error detection, any changed bits or missing segments Simplified explanation (see RFC 10 71 for more details): Sender UDP adds 16 bit...

Ngày tải lên: 01/04/2014, 12:20