The machine is required to operate with rated load torque at one third of the rated speed.. Determine necessary resistance that has to be added in series with the armature.. a The machin
Trang 1
Vv
Vv
Vv
Vv
—
B
Vv
v
v
M
>
Vv
Vv
Vv
Trang 2~~ >
Te
Ww
<— base speed region —» 7 <— field weakening —»
Dac tinh co
Te
wo
o>
Ti
forward motoring
2S
ch)
@ +
forward braking
T +
oO + N
~~)
&)
T 4
reverse motoring
—\
Co)!
(@
reverse braking
WO 1
Pout < 0 Pout > 0
Forward braking Forward motoring
II | T,
Il IV
Pout > 0 Pout < 0
Reverse motoring Reverse braking
4 phan tư
Trang 3T, =ko
T, A : \ | ° he
`
(Electric vehicle type) (Crane type) Dac tinh tai
5.3 Speed Control of DC Machines
5.3.1 Separately Excited DC Motor
Ve =E+ R, i
0; = ely
E =c;©® ,@=Kkl -@
T, = 0,0 1, =k yl,
T, = T,
V, = E+ Ryly = klp@ + Ryly = 1, = (Vy — Mo) /R,
T„ = KI,l„ = KH r (V„ — kIy@Ì (R,
V, R
O= a — a T
Tin =Vin [Ry
_— an _ a
KE, (kL jy
e
Trang 4_ Ven _ (R, + Ridded |
Rik
L_—
R¿ Vr= Re Ip
+4—————
V, T.=klrl,
Van, reducing Vr
¬ a v
® =(V_—Ra Ia) /k Ip= Va/k Ip — Ra Te / (k 1p)?
Thém Ryaa nOi tiép cudn dây phần ứng
Example 1:
A separately excited DC motor has data 40 kW, 220 V, 1500 rpm, 200 A and armature resistance is 0.1 Q Voltage supply of both windings is constant and rated The machine
is required to operate with rated load torque at one third of the rated speed Determine necessary resistance that has to be added in series with the armature Evaluate efficiency in this operating point, assuming that power loss in the excitation winding is
1 kW
Example 2:
A separately excited DC motor has data 40 kW, 220 V, 1500 rpm, 200 A and armature resistance is 0.1 Q Voltage supply for both windings 1s provided from power electronic converters
a) The machine is required to operate with rated load torque at one third of the rated
speed Determine required armature voltage value for operation at this speed
b) The machine is required to operate with half of the rated torque at twice the rated speed Determine necessary percentage reduction in the excitation winding voltage for such an operation
Example 3:
Separately excited DC motor, with constant rated excitation flux, drives a load whose
load torque is 7, = 0.000S@*+15 [Nm] Calculate operating speed and electromagnetic
torque when armature voltage is 100%, 50% and 25% of the rated value Motor rated data are 5 kW, 230 V, 26.1 A, 150 rad/s, and armature resistance is 1.1 Q
Trang 53.3.2 Series Excited DC Motor
V =E+(R,+R,)I
lạ=lr=l
E = klr@ = kl@
T, = KIL, = KI?
[, = Tì
V =(R,+R,)\[+E =(R,+R,)1+klo = 1 = !
(R, +R,)+ ko
kV?
(Re + R,] + ke]
For rated voltage supply
kV,
T=
(R, + R;) + ka|
1:
reducing voltage
V
Đặc tính cơ của động cơ DC kích từ nối tiếp Example 4:
A series DC motor operates under rated conditions with 161.2 Nm torque, 1000 rpm
speed, 41 A current and 420 V voltage Resistance of excitation and armature winding
is 0.2 Q Find the speed and current of the motor if the torque is now 87 Nm
Example 5:
Series DC motor operates under rated conditions at 380 V with speed of 400 rpm and
current of 33.3 A Sum of excitation and armature winding resistances is | Q Load
torque is proportional to the speed squared Determine the voltage that needs to be
supplied to the motor if the motor is required to operate at 300 rpm
Trang 65.4 Rectifiers and Rectifier Control of Separately Excited DC Motors
_ 2N2W/
7 7
_ 22,
V diode bridge rectifier
¬ O ¬
Single-phase bridge rectifier
Three-phase bridge rectifier
` ⁄
v 41,4 2,3 1,4 v4 1,4 2,3
180 360 eC |
Trang 7
FT v
Lid
+
3 phase
380V
50 Hz
armature excitation
Smri6
3[—cos(Ø— z/ 6)| „„
7
27m
27 0 2
xi2
Trang 8231;
y= 3/2 V31/ _ 212 Vir-1
V = 5-6 [2431 sin(Ø— z/ 6) = oe 3|cos(Zz/ 3+ ø) — cos(2Z / 3+ ø\|
mi2+a
lạ
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Rectifier output voltage
a
Reference and carrier waves
|
Switch driving signals
4 pf
† Voltage across motor
nnfTn
Switch
ti
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J
aan
FDA
J
Speed
controller
(PI)
Voltage
reference
Actual
speed
Firing
circuit
or chopper
arma- ture
Tachogenerator
Trang 11Speed
| Pl
speed c
Current
control
Firing
circuit
Rectifier /
chopper
Measured armature current
Measured speed of rotation