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Tiêu đề Derivatives and integrals
Chuyên ngành Engineering
Thể loại Handbook
Năm xuất bản 2004
Thành phố New York
Định dạng
Số trang 10
Dung lượng 126,8 KB

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In any arithmetical progression or part of progression, let a =first term considered 1 =last term considered n =number of terms d =common difference S =sum of 7 terms a+Ï ——xñ 2 In these

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Machinery's Handbook 27th Edition

Series.— Some hand calculations, as well as computer programs of certain types of math- ematical problems, may be facilitated by the use of an appropriate series For example, in some gear problems, the angle corresponding to a given or calculated involute function is found by using a series together with an iterative procedure such as the Newton-Raphson method described on page 33 The following are those series most commonly used for such purposes In the series for trigonometric functions, the angles x are in radians (1 radian = 180/n degrees) The expression exp(—x”) means that the base ¢ of the natural log- arithm system is raised to the —x? power; e = 2.71828 18

3) tanx=x42x°/3 + 225/15 + 17x7/315 + 62x9/2835 + for |x] < 1/2 (4) arcsinx=x+x⁄6+1-3-x⁄2:4-5)+1:3-5:-x”/(2:4:6:7)+ for |x| < 1

(5) arccos x=72 — arcsinx

(Œ7)_ 1/4=1- 1/3 + 1/5 —- 1/7 + 1/9 -+1/(2x— 1)+ for all values of x

(11) a'=1+xlog.z+(zxlog, a)7/2! + log, a)/3! ++ for all values of x

(14) 1/1 4x)? =1-2x43x?-4x3 4 5x4- + for |x| < 1 (5) 1/0 —x)? = 14204322 +4234 5x5 4-5 for |x] <1

(16) A1 +x) =1+x/2—+2/2:4)+1:3 -x3/ - 4-6) for |x| < 1

~1:3:5-:34/(2:4-6-8) —.-

q7) 1/(/Ú+x) =1—z/2+1:3:x2/2:4)—1:3-5-33/(2:4-6)+-e for |x| < 1 (18) (a+x)?=a"+nat—! x+ nín— 1)a?~2 x2/2! + nín — 1)(nS— 2)a"™3 PB! 40 for x2 < 42 Derivatives and Integrals of Functions.—The following are formulas for obtaining the derivatives and integrals of basic mathematical functions In these formulas, the letters a and c denotes constants; the letter x denotes a variable; and the letters u and y denote func- tions of the variable x The expression d/dx means the derivative with respect to x, and as such applies to whatever expression in parentheses follows it Thus, d/dx (ax) means the derivative with respect to x of the product (ax) of the constant a and the variable x

Formulas for Differential and Integral Calculus

Derivative Value Integral Value

Suis) x v(x)) w(x)-Lv(x) + rx) Lux) fe@r@ax u(x)v(x) — [v(x)du(x)

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Formulas for Differential and Integral Calculus (Continued)

d (ula v(x) Lu(x) — u(x) Lv(a) a

TP) dx dee [> 2h

d 7 2 :

d

1

—(logt ant og tanx) — sin2x —d sink Ix log og an tan=

—(l ant 08 19%) — = flogx x logxd xlogx —x logx —

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Machinery's Handbook 27th Edition

GEOMETRY Arithmetical Progression

An arithmetical progression is a series of numbers in which each consecutive term differs from the preceding one by a fixed amount called the common difference, d Thus, 1,3, 5,7, etc., is an arithmetical progression where the difference dis 2 The difference here is added

to the preceding term, and the progression is called increasing In the series 13, 10, 7, 4, etc., the difference is (—3), and the progression is called decreasing In any arithmetical progression (or part of progression), let

a =first term considered

1 =last term considered

n =number of terms

d =common difference

S =sum of 7 terms

a+Ï

——xñ

2

In these formulas, dis positive in an increasing and negative in a decreasing progression When any three of the preceding live quantities are given, the other two can be found by the formulas in the accompanying table of arithmetical progression

Then the general formulas are] = a+(n—1)d and S=

Example: Tn an arithmetical progression, the first term equals 5, and the last term 40 The difference is 7 Find the sum of the progression

5 +40 2x7

s= ST +d~a) = (40+7—5) = 135

Geometrical Progression

A geometrical progression or a geometrical series is a series in which each term is derived by multiplying the preceding term by a constant multiplier called the ratio When the ratio is greater than 1, the progression is increasing; when less than 1, it is decreasing Thus, 2, 6, 18, 54, etc., is an increasing geometrical progression with a ratio of 3, and 24,

12, 6, etc., is a decreasing progression with a ratio of 1/2

In any geometrical progression (or part of progression), let

a =first term

/ =last (or nth) term

n =number of terms

r=ratio of the progression

S =sum of 7 terms

rl—a

Then the general formulas are? = ar”~! and S= r— 1

When any three of the preceding five quantities are given, the other two can be found by the formulas in the accompanying table For instance, geometrical progressions are used for finding the successive speeds in machine tool drives, and in interest calculations Example: The lowest speed of a lathe is 20 rpm The highest speed is 225 rpm There are

18 speeds Find the ratio between successive speeds

=1 17 Ratio r = UE = = = 7/125 = 1.153

a

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Formulas for Arithmetical Progression

don S| az=S-Belyg

a

441 [14a —8ds

= <+=A/(2l+đ)ˆ—- SdsS

41 § |a= 545 WK )

1

l-a

d=

2S —2an

d=

AM

2S—l-a 2nl—2S

d=

1

d on § | l=S4tetya

d-2a,1 fas (Qanay

ad § In" 231 2a (2a—d)

1

atl

21+d 1 (2122)2-8d§

a dad n |§= 3124 + (n— 1d]

2 2

a dad 1 |S = Gt Pea _ atl, g_g)

d 1 n |S= 312!~(w= 1)4]

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Machinery's Handbook 27th Edition

Formulas for Geometrical Progression

_ ol

r* — ]

a

Loon Š |a(S-a)""l= I(sS—jm=1

a n r | 2 =art-!

1

a n S | WS-D*-! = a(S-a)"-!

nor.) 6S} = S@e De

r*_— ]

AI

logr

a r s lane log[a + (r—1)S]-loga

logr

4 J5 |" Z1as(-a)-log(S-—))

] r s lane logl—log[Ir-(r=1)S] , |

logr

n-l

a ỉ H r= J

a

a n Ss ri = Sr a-$

Srtal l

r—-l _ lr_—a

r—]

n—1]_n= la

ho

] n ris = 2b

(r—1)rm=1

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Analytical Geometry Straight Line.— A straight line is a line between two points with the minimum distance Coordinate System: It is possible to locate any point on a plane by a pair of numbers called the coordinates of the point If P is a point on a plane, and perpendiculars are drawn from P to the coordinate axes, one perpendicular meets the X—axis at the x— coordinate of P and the other meets the Y—axis at the y—coordinate of P The pair of numbers (x, y,), in that order, is called the coordinates or coordinate pair for P

47

P(x; y))

>

2 +

-3—L

—4 Fig 1 Coordinate Plan Distance Between Two Points: The distance d between two points P,(x,,y,) and P,(x3,y)

is given by the formula:

4(P:P2) = jŒ¿—xi) +¿—y¡)

Example 1: What is the distance AB between points A(4,5) and B(7,8)?

Solution: The length of line AB is

d = (7-4) +(8-5)° = 3°43? = J18 = 32

Intermediate Point: An intermediate point, P(x, y) on a line between two points, P)(x,,y,) and P.(x,,y), Fig 2, can be obtained by linear interpolation as follows,

x= and y L1 22

where r, is the ratio of the distance of P, to P to the distance of P, to P,, and r, is the ratio of the distance of P, to P to the distance of P, to P, If the desired point is the midpoint of line P,P then r, =r, = 1, and the coordinates of P are:

- 1”? and _-?1~1”2

Example 2: What is the coordinate of point P(x,y), if P divides the line defined by points A(0,0) and B(8,6) at the ratio of 5:3

- x0+3xÓ6_ 18

- x0+3x8_ 22 _ạ y=2XU†3x6_ lỗ _ 22s

Solution: x

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Machinery's Handbook 27th Edition

External Point: A point, Q(x, y) on the line P,P,, and beyond the two points, P,(x,,y,) and P;(x;„y;), can be obtained by external interpolation as follows,

ryxy- 131 F232 and — M17 — 1232 a) Pols where r, is the ratio of the distance of P, to Q to the distance of P, to P,, and r, is the ratio

of the distance of P, to Q to the distance of P, to P,

Y

GB (xpy)

Fig 2 Finding Intermediate and External Points on a Line

Equation of a line P,P: The general equation of a line passing through points P,(x,,y,)

y—y| _ X-#t

Yi7¥q 31—*2

The previous equation is frequently written in the form y—y, = (x—x,)

17 *2

where 1s the slope of the line, m, and thus becomes y—y, = m(x—x,) where y,

*Ị—32

is the coordinate of the y-intercept (0, y,) and x, is the coordinate of the x-intercept (x,, 0)

If the line passes through point (0,0), then x, = y, =0 and the equation becomes y= mx The y-intercept is the y-coordinate of the point at which a line intersects the Y-axis atx =0 The x-intercept is the x-coordinate of the point at which a line intersects the X-axis at y=0

If a line AB intersects the X—axis at point A(a,0) and the Y—axis at point B(0,)) then the equation of line AB is

Slope: The equation of a line in a Cartesian coordinate system is y= mx +b, where x and

y are coordinates of a point ona line, is the slope of the line, and bis the y-intercept The slope is the rate at which the x coordinates are increasing or decreasing relative to the y coordinates

Another form of the equation of a line is the point-slope form (y — y,) = m(x — x,) The slope, m, is defined as a ratio of the change in the y coordinates, y, — y,, to the change in the

x coordinates, x, —x,,

Ay _ Y27%1 m=

Ax_ Xy—Xy

Copyright 2004, Industrial Press, Inc., New York, NY

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Example 3: What is the equation of a line AB between points A(4,5) and B(7,8)? Solution:

yryy _ X-#i

3132 31 —*2

< Cờ =

x

5-8 y-5=

y-x=1 Example 4: Find the general equation of a line passing through the points (3, 2) and (5, 6), and its intersection point with the y-axis

First, find the slope using the equation above

Ay 6-2 _4_ 2

Ax 5-3 2

The line has a general form of y = 2x + b, and the value of the constant b can be determined

by substituting the coordinates of a point on the line into the general form Using point (3,2), 2=2 x3 + band rearranging, b= 2 —6=—4 As acheck, using another point on the line, (5,6), yields equivalent results, y= 6 = 2 x 5 + b and b= 6— 10= —4

The equation of the line, therefore, is y = 2x — 4, indicating that line y = 2x — 4 intersects the y-axis at point (0,—4), the y-intercept

Example 5: Use the point-slope form to find the equation of the line passing through the point (3,2) and having a slope of 2

(y—2) = 2(x-3)

y = 2x-6+2

y = 2x-4 The slope of this line is positive and crosses the y-axis at the y-intercept, point (0,—4) Parallel Lines: The two lines, P,P, and Q,Q,, are parallel if both lines have the same slope, that is, if m)= my

(x;y

+ B222) 3 50202)

Q2:34)

P@) POD Qf1z34)

Fig 3 Parallel Lines Fig 4 Perpendicular Lines Perpendicular Lines: The two lines P,P, and QQ, are perpendicular if the product of their slopes equal —1, that is, mym,= —1

Example 6: Find an equation of a line that passes through the point (3,4) and is (a) parallel

to and (b) perpendicular to the line 2x — 3y = 16?

Solution (a): Line 2x — 3y = 16 in standard form is y = % x—!%, and the equation of a line passing through (3,4) is y—4 = m(x-3)

Copyright 2004, Industrial Press, Inc., New York, NY

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Machinery's Handbook 27th Edition

If the lines are parallel, their slopes are equal Thus, y—4 = Ae —3) is parallel to line 2x — 3y =—6 and passes through point (3,4)

Solution (b): As illustrated in part (a), line 2x — 3y = -6 has a slope of % The product of the slopes of perpendicular lines = —1, thus the slope m of a line passing through point (4,3) and perpendicular to 2x —3y =—6 must satisfy the following:

3 The equation of a line passing through point (4,3) and perpendicular to the line 2x — 3y = 16is y—4= 4x - 3), which rewritten is 3x + 2y = 17

Angle Between Two Lines: For two non-perpendicular lines with slopes m, and m,, the angle between the two lines is given by

m,—m tang =|_ 1L 2

l+mm,

Note: The straight brackets surrounding a symbol or number, as in |x|, stands for absolute value and means use the positive value of the bracketed quantity, irrespective of its sign Example 7: Find the angle between the following two lines: 2x — y= 4 and 3x + 4y =12 Solution: The slopes are 2 and —%, respectively The angle between two lines is given by

2-(-2) 2„3| |8+3

— = = 4 =

1+2(-3) 1-§

1

atan— = 79.70°

2

THỊ — My

tan

- juju

2 2

+ | ON

l+mm,

0

Distance Between a Point and a Line: The distance between a point (x,,y,) and a line given byAx+By+C=Ois

i= |Ax, +By,+ C|

NA +B Example 8: Find the distance between the point (4,6) and the line 2x + 3y —-9=0 Solution: The distance between a point and the line is

i= [Axi t+Byi tC] _ 2x4+3x6-—9| _ [8418-9] _ 17

Coordinate Systems.— Rectangular, Cartesian Coordinates: In a Cartesian coordinate system the coordinate axes are perpendicular to one another, and the same unit of length is chosen on the two axes This rectangular coordinate system is used in the majority of cases

Polar Coordinates: Another coordinate system is determined by a fixed point O, the ori- gin or pole, and a zero direction or axis through it, on which positive lengths can be laid off and measured, as a number line A point P can be fixed to the zero direction line at a dis- tance r away and then rotated in a positive sense at an angle 8 The angle, 0, in polar coor- dinates can take on values from 0° to 360° A point in polar coordinates takes the form of (rv, 8)

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Changing Coordinate Systems: For simplicity it may be assumed that the origin on a Cartesian coordinate system coincides with the pole on a polar coordinate system, and it’s axis with the x-axis Then, if point P has polar coordinates of (7,8) and Cartesian coordi- nates of (x, y), by trigonometry x = r x cos(8) and y = r x sin(@) By the Pythagorean theo- rem and trigonometry

Example 1: Convert the Cartesian coordinate (3, 2) into polar coordinates

r= A342? = Jed = jJl3=36 O= aian2 = 33.69°

Therefore the point (3.6, 33.69) is the polar form of the Cartesian point (3, 2)

Graphically, the polar and Cartesian coordinates are related in the following figure

G3, 2)

, 3

0 1 2 3

Example 2: Convert the polar form (5, 608) to Cartesian coordinates By trigonometry, x

=r x cos(Q) and y =r x sin(Q) Then x = 5 cos(608) = —1.873 and y = 5 sin(608) = —4.636 Therefore, the Cartesian point equivalent is (-1.873, —4.636)

Spherical Coordinates: It is convenient in certain problems, for example, those con- cerned with spherical surfaces, to introduce non-parallel coordinates An arbitrary point P

in space can be expressed in terms of the distance r between point P and the origin O, the angle @ that OP’makes with the x-y plane, and the angle A that the projection OP’ (of the segment OP onto the x—y plane) makes with the positive x-axis

—=—————_—_—VY

The rectangular coordinates of a point in space can therefore be calculated by the formu- las in the following table

Copyright 2004, Industrial Press, Inc., New York, NY

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