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INTRODUCTION TO COMMON PROBABILITY DISTRIBUTIONS Probability distribution: A probability distribution describes the values of a random variable and the probability associated with these

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Reading 10 Common Probability Distributions

–––––––––––––––––––––––––––––––––––––– Copyright © FinQuiz.com All rights reserved ––––––––––––––––––––––––––––––––––––––

1 INTRODUCTION TO COMMON PROBABILITY DISTRIBUTIONS

Probability distribution: A probability distribution

describes the values of a random variable and the

probability associated with these values

Types of distribution:

1 Uniform

2 Binomial

3 Normal

4 Lognormal

Random variable: A variable that has uncertain future

outcomes is called random variable The two basic types

of random variables are:

1)Discrete random variables: Discrete random variables

have a countable number of outcomes i.e all

possible outcomes can be listed without missing any

of them For example, counts, dice, number of

students, quoted price of a stock etc A discrete

random variable can take

• On a limited (finite) number of outcomes i.e x1, x2,

…,xn

• On an unlimited (infinite) number of outcomes i.e y1,

y2, …

2)Continuous random variables: Continuous random

variables have an infinite and uncountable range of

possible outcomes; thus, we cannot list all possible

outcomes For example, time, weight, distance, rate

of return etc The range of possible outcomes of a

continuous random variable is the real line i.e

between -∞ and +∞ or some subset of the real line

Probability function: The probability function describes

the probability of a specific value that the random

variable can take

For a discrete random variable, it is denoted as:

P(X = x) read as the “probability that a random

variable X takes on the value x

where,

X represents the name of the random variable

x represents the value of the random variable

Example:

Suppose, X = number of heads in 15 flips of a coin

P(X = 5) = P (5)  probability of 5 heads (x) in 15 flips of a

coin

For a continuous random variable, the probability

function is called the probability density function

(pdf) and is denoted as f(x)

Properties of a probability function:

1)0 ≤ P(x) ≤ 1, for all x

2)The sum of the probabilities p(x) over all values of X =

1 i.e ∑   = 1

Cumulative distribution function or distribution function:

The cumulative distribution function describes the

probability that a random variable X ≤ particular value x

i.e P(X ≤ x) For both discrete and continuous random variables, it is denoted as F(x) = P(X ≤ x)

F(x) = Sum of all the values of the probability function for all outcomes ≤ x

Properties of Cumulative distribution function (cdf):

1)The cdf lies between 0 and 1 for any x i.e 0 ≤ F(x) ≤ 1

2)With an increase in x  the cdf either increases or remains constant

For detailed understanding, please refer to Example given after Table 1, Reading 10, Volume 1

2.1 The Discrete Uniform Distribution

It the simplest form of probability distribution

The discrete uniform distribution has a finite number

of specified outcomes

• The probability of each outcome in a discrete uniform distribution is equally likely

2.2 The Binomial Distribution

A distribution that involves binary outcomes is referred to

as binomial distribution It has following properties:

1 A binomial distribution has fixed number of trials i.e

Practice: Example 1,

Volume 1, Reading 10

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n

2 Each trial in a binomial distribution has two possible

outcomes i.e a “success” and a “failure”

3 Probability of success is denoted as P (success) = p

and Probability of failure is denoted as P (failure)

=1– p → for all trials

4 The trials are independent, which means that the

outcome of one trial does not affect the outcomes

of any other trials

Assumptions of the binomial distribution:

a)The probability of success (i.e p) is constant for all

trials

b)The trials are independent

Bernoulli trial: A trial that generates one of two

outcomes is called a Bernoulli trial

In a Bernoulli trial with n number of trials, we can

have 0 to n successes

• If the outcome of an individual trial is random, then

the total number of successes in n trials is also

random

Binomial random variable X: It represents the number of

successes in n Bernoulli trials i.e

X = sum of Bernoulli random variables

X = Y1 + Y2 + …+ Yn

where,

Yi = Outcome on the i th trial

• A binomial random variable is completely described

by two parameters i.e n and p It is stated as X~ B (n,

p)  read as “X has a binomial distribution with

parameters n and p”

Thus, a Bernoulli random variable is a binomial

random variable with n = 1 i.e Y~B (1, p)

Probability function of the Bernoulli random variable Y:

• When the outcome is success Y = 1

• When the outcome is failure Y = 0

p (l) = P(Y= 1) = p = probability of success

p (0) = P( Y = 0) = 1 – p = probability of failure

For example, a stock price is a Bernoulli random variable

with probability of success (an up move) = p and

probability of failure (a down move) = 1 – p

Suppose, Stock price today = S

• When the stock price increases, ending price = uS =

(1 + rate of return if the stock moves up) × S

• When the stock price decreases, ending price = dS

One-Period Stock Price as a Bernoulli Random Variable

Source: Example 2, Volume 1, Reading 10

Number of sequences in n trials that result in x up moves (or successes) and n – x down moves (or failures) is calculated as follows:

!

  ! !

where, n! = n factorial = n(n - 1) (n - 2) 1 (and 0! = 1 by convention)

Probability function for a binomial random variable:

       1  

  ! ! !1  

for x = 0, 1, 2, …, n

where,

x = # successes out of n trials

n – x = # failures out of n trials

p = probability of success

1 – p = probability of failure

n = number of trials

Probability of success:

P(X=1)=

1 1

 

 p1(1−p)1 − 1=p

Probability of failure:

p p

p X

=

1 ) 1 ( )

0

1

0

NOTE:

When the probability of success on a trial is 0.50, the

binomial distribution is symmetric; otherwise, it is

asymmetric or skewed

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Example:

If a coin is tossed 20 times, what is the probability of

getting exactly 10 heads?

p = 0.50

1 – p = 0.5

n = 20

x = 10

10

20

(0.5)10

(0.5)10 = 0.176

Stock price movement on three consecutive days:

• Each day is an independent trial

• When the stock moves up  u = 1 + rate of return for

an up move

• When the stock moves down  d = 1 + rate of return

for a down move

A binomial tree is shown below Each boxed value that

represents successive moves (branch in the tree) is

called a node

• In the fig below, a node reflects the potential value

for the stock price at a specified time

• At each node, the transition probability for an up

move is p and for a down move is (1 – P)

• Each of the sequences uud, udu, and duu, has

probability = p2 (l – p)

• Stock price after three moves = P (S3 = uudS) = 3p2 (l -

p)

e.g Number of ways to get 2 up moves in three periods

= 3! / (3 – 2)! 2! = 3

3.1 Continuous Uniform Distribution

The continuous uniform distribution is the simplest continuous probability distribution The uniform distribution has two main uses

• It plays an important role in Monte Carlo simulation

• It is an appropriate probability model to represent an uncertainty in beliefs with equally likely outcomes

Probability density function (pdf): It is used to assign the probabilities to a continuous random variable and is

denoted as f (x) According to pdf,

The probability that value of x lies between a and b

is the area under the graph of f(x) that lies between

a and b or the integral of f(x) over the range a to b



=

elsewhere 0

b a for 1 ) (

x a

b x f

• Over the range of values from a to b, density of the

distribution of a random variable x = 

• Elsewhere, density of the distribution of a random

variable x = 0

Finding probability: The probabilities can be estimated

as follows:

!  

• F (x) = area under the curve graphing the pdf

• Under a Continuous uniform distribution, probabilities

for values of a continuous random variable x are assigned across an interval of values of x; thus, the probability that x takes on a specific value = 0

• Since the probabilities at the endpoints a and b = 0 for any continuous random variable X, P (a ≤ X ≤ b)

= P (a < X ≤ b) = P (a ≤ X< b) = P (a< X < b)

For a continuous uniform random variable:

Mean = µ = (a + b) / 2 Variance = σ2 = (b – a) 2 / 12 S.D =

• Note that S.D is not a useful risk measure for a uniform distribution; rather, the S.D is a good risk measure for Normal Distribution

Practice: Example 4, 5 & 6,

Volume 1, Reading 10

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Example:

Suppose,

At the lower bound = a =100,000 km  total cost

= $40,000

At the upper bound = b =150,000 km  total cost

= $60,000

Outside the lower and upper bound  total cost = $0

x = total anticipated annual travel costs in thousands of

dollars

the distribution has density f(x) = 1/ (60 - 40) = 1/20

• Elsewhere, the distribution has density f(x) = 0

The probability that travel costs are between 40 and 60 =

Total area under the density function f(x) between 40

and 60 = height × length (or base) = (1/20) × (60–40) = 1

The probability that travel costs are between 40 and 50 =

Area under the curve between 40 & 50 = (1/20) × (50–40)

= 0.50

3.2 The Normal Distribution

• A normal distribution is a distribution that is symmetric

about the centre (mean) and is bell-shaped Thus,

o Skewness = 0

o Kurtosis = 3 and Excess kurtosis = 0

distribution is the entire real line i.e all real numbers

lying between -∞ and +∞

• The tails of the normal distribution never touches the

horizontal axis and extend without limit to the left

and to the right; however, as we move away from

the center, the tails get closer and closer to the

horizontal axis This characteristic is referred to as the

distribution is asymptotic to the horizontal axis

• The normal distribution is described by two

parameters i.e its mean (µ) and its variance (σ2) or

standard deviation (σ) It is stated as:

X ~ N (µ, σ2)  read “X follows a normal distribution

with mean µ and variance σ2”

shifts to the right (left)

• The smaller the S.D., the more the observations are concentrated around the mean

• Since the normal distribution is symmetrical, it tends

to underestimate the probability of extreme returns

Thus, it is not appropriate to use for Options

• The normal distribution can be used to model

returns; however, is not appropriate to use to model asset prices

According to the central limit theorem, sum and mean of a large number of independent random variables is approximately normally distributed

• It is important to note that a linear combination of two or more normal random variables is also normally distributed

A univariate normal distribution describes the probability

of a single random variable

A multivariate normal distribution describes the

probabilities for a group of related random variables It is completely defined by three parameters:

1 The list of the mean returns on the individual securities i.e total means = n

2 The list of the securities’ variances of return i.e total variances = n

3 The list of all the distinct pair-wise return correlations i.e total distinct correlations = n (n - 1) / 2

For example, a bivariate normal distribution (i.e a distribution with 2 stocks) has:

• Means = 2

• Variances = 2

• Correlation = 2 (2 –1) / 2 = 1

For a normal random variable standard deviation of:

• Sample skewness = 6/ n

• Sample kurtosis = 24/ n Normal density function: It is expressed as follows:

 = 1

%√2&

−( − ()

2% ) for − ∞ <  < + ∞

The probability that a normally distributed variable x takes on values in the range from a to b = Area

Practice: Example 7,

Volume 1, Reading 10

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• The total area under the curve = 1

• The area under the curve to the left of centre = 0.5

and the area right of centre = 0.5

o Approximately 50% of all observations fall in the

interval µ ± (2/ 3) σ

o Approximately 68% of all observations fall in the

interval µ ± σ

o Approximately 95% of all observations fall in the

interval µ ± 2σ

o Approximately 99% of all observations fall in the

interval µ ± 3σ

• More-precise intervals are µ ± 1.96σ for 95% of the

observations and µ ± 2.58σ for 99% of the

observations

Standard normal distribution or unit normal distribution: It

is a normal distribution with:

• The mean (µ ) = 0

• Standard deviation (σ) =1

When X is normally distributed, it can be standardized

using the following formula:

Z =



away from the mean the point x lies

Example:

Suppose, a normal random variable, X = 9.5 with µ = 5

and σ = 1.5

Z = (9.5 - 5) / 1.5 = 3 Example:

Finding the Probability i.e P (Z < 2.67) It is found by first

finding 2.6 in the left hand column, and then moving

across the row to the column under 0.07 (Refer to table

on the next page) Thus,

The area to the left of z = 2.67 = 0.9962

• In order to find the area to the right of z, we use the

Standard Normal Table given below to find the area

that corresponds to z-value and then subtract the

area from 1

• Probability to the right of x = 1.0 - N(x)

• Since the normal distribution is symmetric around its

mean, the area and the probability to the right of x =

area and the probability to the left of -x, N (-x)

•The probability to the right of –x i.e P (Z ≥ -x) = N(x)

Example:

• Finding P (Z > 1.23):

• Finding P (-0.75 < Z < 1.23):

• Finding P (Z< -2.33):

Example:

The average (µ) on a corporate finance test was 78 with

a standard deviation of 8 (σ) If the test scores are normally distributed, find the probability that a student receives a test score greater than 85

Z = 

 = 0.875 ≈ 0.88

P(x> 85) = P (z> 0.88) = 1 −P(z< 0.88) = 1 − 0.8106

= 0.1894

Trang 6

NOTE:

• P (Z ≤ 1.282) = 0.90 = 90% → It implies that 90th percentile point = 1.282 and % of values in the right tail = 10%

• P (Z ≤ 1.65) = 0.95 = 95% → It implies that the 95th percentile point = 1.65 and % of values in the right tail = 5%

• P (Z ≤ 2.327) = 0.99 = 99% → It implies that the 99th percentile point = 2.327 and % of values in the right tail = 1%

3.3 Applications of the Normal Distribution

• The mean-variance analysis is based on the assumption that returns are normally distributed

Safety-first rule: Safety-first rule focuses on shortfall risk i.e the risk that portfolio value will fall below

some minimum acceptable level over some specified time horizon For example, the risk that the assets in a defined benefit plan will fall below plan liabilities

According to Roy's safety-first criterion, the optimal portfolio is the one that minimizes the probability that

portfolio return (Rp) falls below the threshold level (RL) When returns are normally distributed, the safety-first

optimal portfolio is the portfolio that maximizes the

safety-first ratio (SFRatio):

!*  = +,* − *-/%

• Investors prefer the portfolio with the highest SFRatio

• Probability that the portfolio return < threshold level =

P (Rp< RL) = N (-SFRatio)

• The optimal portfolio has the lowest P (Rp< RL) Example:

• Portfolio 1 expected return = 12% and S.D = 15%

• Portfolio 2 expected return = 14% and S.D = 16%

• Threshold level = 2%

• Assumes that returns are normally distributed

SFRatio of portfolio 1 = (12 – 2) / 15 = 0.667 SFRatio of portfolio 2 = (14 – 2) / 16 = 0.75

• Since SFRatio of portfolio 2 > SFRatio 1, the superior Portfolio is Portfolio 2

Practice: Example 8, Volume 1, Reading 10

Trang 7

Probability that return < 2% = N (–0.75) = 1 – N (0.75)

= 1 – 0.7734*

≈ 23%

*Refer to table on previous page

Sharpe Ratio:

Sharpe ratio = [E (Rp) – Rf] / σp

• The portfolio with the highest Sharpe ratio is the one

that minimizes the probability that portfolio return will

be less than the risk-free rate (assuming returns are

normally distributed)

Managing Financial risk: Two important measures used

to manage financial risk include:

losses (in money terms) expected over a specified

time period (e.g a day, quarter, year etc.) at a

specified level of probability (e.g 5%, 1%) VAR

estimated using variance-covariance or analytical

method assumes that returns are normally

distributed

Example:

A one week VAR of $10 million for a portfolio with 5%

probability implies that portfolio is expected to loss

$10 million or more in a single week

• Stress testing/scenario analysis: It involves a use of

set of techniques to estimate losses in extremely

worst combinations of events or scenarios

3.4 The Lognormal Distribution

A random variable (i.e Y) whose natural logarithm (i.e ln

Y) has a normal distribution, is said to have a Lognormal

distribution

Reason :

Since, negative values do not have logarithms, Y is

always > 0 and thus the distribution is positively skewed

(unlike normal distribution that is bell-shaped)

• Like normal distribution, it is completely described by

two parameters i.e the mean and variance of In Y,

given that Y is lognormal

Mean (µL) of a lognormal random variable = exp (µ + 0.50σ2)

Variance (σL2) of a lognormal random variable

= exp (2µ+ σ2) × [exp (σ2) – 1]

Strengths of lognormal distribution:

(relative to normal distribution) to use to model asset prices because asset prices cannot be negative

• It is used in Black-Scholes-Merton model, which assumes that the asset’s price underlying the option

is lognormally distributed

It is important to note that when a stock's continuously

compounded return is normally distributed, then future stock price is necessarily lognormally distributed

ST = S0exp (r0,T) Where,

exp = e

r0,t = Continuously compounded return from 0 to T

• Since ST is proportional to the log of a normal random variable → ST is lognormal

Price relative = Ending price / Beginning price =

St+1/ St=1 + Rt, t+1

where,

Rt, t+1 = holding period return on the stock from t to t + 1

Continuously compounded return associated with a holding period from t to t + 1:

rt, t+1= ln(1 + holding period return)

Or

rt, t+1 = ln(price relative) = ln (St+1 / St) = ln (1 + Rt,t+1) NOTE:

The continuously compounded return < associated holding period return

Continuously compounded return associated with a holding period from 0 to T:

R0,T= ln (ST / S0)

Or

,= ,+  ,+ ⋯ + ,

Where,

rT-I, T = One-period continuously compounded returns

Practice: Example 9,

Volume 1, Reading 10

Trang 8

Example:

Suppose, one-week holding period return = 0.04

Equivalent continuously compounded return =

one-week continuously compounded return = ln (1.04)

= 0.039221

the observations of a normally distributed random

variable are expected to lie are symmetric around

the mean

the observations of a lognormally distributed

random variable are expected to lie are not

symmetric around the mean

In many investment applications, it is assumed that

returns are independently and identically distributed

(IID)

• Returns are independently distributed implies that

investors cannot forecast future returns using past

returns (i.e., weak-form market efficiency)

• Returns are identically distributed implies that the

mean and variance of return do not change from

period to period (i.e stationarity)

When one-period continuously compounded returns (i.e

r0,1) are IID random variables with mean µ and variance

σ2, then

And

,/ = % 0

S.D = σ (r0,T) = σ√0

compounded returns are normally distributed, then

the T holding period continuously compounded

return (i.e r0,T) is also normally distributed with mean

µT and variance σ2T

one-period continuously compounded returns is

approximately normal even if they are not normally

distributed

Volatility:

Volatility reflects the deviation of the continuously compounded returns on the underlying asset around its mean It is estimated using a historical series of

continuously compounded daily returns

Annualized volatility = sample S.D of one period

continuously compounded returns

× √0 where,

T = Number of trading days in a year = 250

Example:

Michelin Daily Closing Prices Date (2003) Closing Price (€)

Since, rt, t+1 = ln (St+1 / St) = ln (1 + Rt,t+1)

• ln (25.21 / 25.20) = 0.000397

• ln (25.52 / 25.21) = 0.012222

• ln (26.10 / 25.52) = 0.022473

• ln (26.14 / 26.10) = 0.001531 Sum = 0.036623

Mean = 0.009156 Variance = 0.000107 S.D = 0.010354 Annualized volatility = 0.010354 × √250 = 0.163711 Expected continuously compounded annual return

= Sample mean × T

= 0.009156 (250)

= 2.289

Source: Example 10, Volume 1, Reading 10.

probability distribution It can be used in conjunction

Uses:

•It can be used in valuing complex securities e.g

• It can be used to estimate VAR e.g using Monte Carlo simulation, portfolio's profit and loss performance for a specified time horizon are simulated to generate a frequency distribution for changes in portfolio value; the point that reflects the end point of the least favorable 5% of simulated changes is 95% VAR

• It can be used to examine a model's sensitivity to changes in the assumptions

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Advantages: Monte Carlo simulation can be used to

value complex securities i.e European-style

options

Drawbacks: Unlike analytical methods (e.g

Black-Scholes-Merton option pricing model),

Monte Carlo simulation provides only

statistical estimates, not exact results In

addition, unlike black-scholes model,

Monte Carlo simulation model cannot be

used to quickly measure the sensitivity of

call option value to changes in current

stock price and other variables

Steps of Monte Carlo simulation technique to examine a

model's sensitivity to changes in assumptions:

1)Specify the underlying variable or variables e.g stock

price for an equity call option

2)Specify the beginning values of the underlying

variables e.g stock price

• C iT = Value of the option at maturity T The subscript I

reflects a value resulting from the ith simulation trial

3)Specify a time period

Time increment = ∆t

= Calendar time / Number of sub-periods (K)

4)Specify the regression model for changes in stock

price



where,

Zk= Risk factor in the simulation It is a standard normal

random variable

5)K random variables are drawn for each risk factor

using a computer program or spreadsheet function

6)Now the underlying variables are estimated by

substituting values of random observations in the

model specified in Step 4

7)The value of a call option at maturity i.e CiT is

calculated and then this value is discounted back at

time period 0 to get Ci0

8)This process is repeated until a specified number of trials, i, is completed (e.g tens of thousands of trials) NOTE:

For obtaining each extra digit of accuracy in results, the appropriate increase in the number of trials depends on the problem For example, in option value, tens of thousands of trials may be appropriate Generally, the number of trials should be increased by a factor of 100 9)Finally, mean value and S.D for the simulation are calculated

Mean value = Average value of the option over all trials

in the simulation

• The mean value will be the Monte Carlo estimate of the value of the call option

Random number generator: An algorithm that generates uniformly distributed random numbers between 0 and 1

is referred to as random number generator It is important to note that random observations from any distribution can be generated using a uniform random variable

Steps to generate random observations on variable X:

0 and 1 using the random number generator

observation on variable X

Historical simulation or Back simulation: Under a historical simulation, samples are generated using a historical record of underlying variables to simulate a process It is based on the assumption that historical data can be used to predict future

Drawback of Historical simulation: Unlike Monte Carlo

simulation, historical simulation cannot be used to perform “what if” analyses

Practice: Example 11 & 12, Volume 1, Reading 10 & End of Chapter Practice Problems for Reading 10

...

• ln (26 .10 / 25.52) = 0.022473

• ln (26.14 / 26 .10) = 0.001531 Sum = 0 .036 623

Mean = 0.009156 Variance = 0.00 0107 S.D = 0.0 103 5 4 Annualized volatility = 0.0 103 5 4 × √250 =... Portfolio

Practice: Example 8, Volume 1, Reading 10

Trang 7

Probability that return < 2% = N (–0.75)... assumes that returns are normally

distributed

Example:

A one week VAR of $10 million for a portfolio with 5%

probability implies that portfolio is expected to loss

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