Digraphs and Relations Warm Up... The Divisibility Relation• Let “|” be the binary relation on N×N such that a|b “a divides b” iff there is an n∈N such that a∙n=b.. • What does that mean
Trang 1Digraphs and Relations
Warm Up
Trang 2The Divisibility Relation
• Let “|” be the binary relation on N×N such that a|b (“a divides b”) iff there is an n∈N such that a∙n=b
• Examples:
– 2|4 but not 2|3 and not 4|2
– 1|a for any a since 1∙a=a
– What about 0|a?
– What about a|0?
• Show that “|” is a partial order but not a total order
• What does that mean?
• Reflexive, transitive, antisymmetric
• But not true that for any a and b, either a|b or b|a
Trang 3a|b iff for some n∈N, a∙n = b
• Reflexive?
a|a for any a since a∙1=a.
• Transitive?
If a|b and b|c, then there exist n, m∈N such that a∙n=b and b∙m=c Then a∙(nm)=c so a|c.
• Antisymmetric?
Suppose a|b and a≠b
We want to say “then a<b” but that is not right! Why?
If b≠0 then a<b (why?) so it cannot be that b|a.
If b=0 then NOT b|a since 0|a only if a=0.
Trang 4• So “|” is a partial order
• It is not a total order because, for example, neither 2|3 nor 3|2 is true
Trang 5FINIS