Airfoil dynamic motionθ t Khh KTθ xθ P=-L aero center e Ma V 2Purdue Aeroelasticity... This is what we’ll get when we use the V-g method to calculate frequency vs... When we do the V-g m
Trang 1AAE 556 Aeroelasticity The V-g method
g
V/b ωθ
k decreasing
flutter point
mode 1
mode 2
1Purdue Aeroelasticity
Trang 2Airfoil dynamic motion
θ (t)
Khh
KTθ
xθ P=-L
aero center
e
Ma
V
2Purdue Aeroelasticity
Trang 3This is what we’ll get when we use the V-g method to calculate frequency vs airspeed and
include Theodorsen aero terms
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 0
0.2 0.4 0.6 0.8 1 1.2 1.4 1.6
Velocity (V/ ωθ b)
/ ω θ
3Purdue Aeroelasticity
Trang 4When we do the V-g method here is
damping vs airspeed
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 -1
-0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1
Velocity (V/ ωθ b)
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flutter
divergence
Trang 5To create harmonic motion at all airspeeds we need an energy source or sink at all airspeeds
except at flutter
i Input energy when the aero damping takes energy out (pre-flutter)
i Take away energy when the aero forces put energy in (post-flutter)
5Purdue Aeroelasticity
Trang 62D airfoil free vibration with everything
but the kitchen sink
h g
ω
&
&& &&
Iθθ Mx h Kθ θ gθ g θ M M e ω
ω θ
&& &
&&
( − ω2M K + h 1 + i gh + g ) h − ω2Mxθθ = P
( − ω2Iθ + Kθ 1 + i gθ + g ) θ ω − 2Mx hθ = Ma
6Purdue Aeroelasticity
Trang 7We will get matrix equations that
look like this
A(k, ω , g)E(k, ω , g) − B(k)D(k) = 0
A B
D E
h / b
θ
=
0 0
…but have structural damping that
requires that …
7Purdue Aeroelasticity
2
m b
µ
πρ
=
Trang 8The EOM’s are slightly different from those before (we also multiplied the previous
equations by µ)
h / b
θ
=
0 0
/ ω2
)[1 + i(gh + g)]} + Lh
B = µ xθ + Lα = Lh (1 / 2 + a)
E = µ rθ2{1 − ( ωθ2
/ ω 2
)[1 + i(gθ + g)]}
−M h(1 / 2 + a) + Mα − Lα(1 / 2 + a)+ L h(1 / 2 + a)2
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Each term contains inertial, structural stiffness, structural damping and aero
information
1 2
h h
Trang 9Look at the “A” coefficient and identify the eigenvalue – artificial damping is added to keep
the system oscillating harmonically
Ω2
= ( ωθ2
/ ω 2
)(1 + ig) = Ω2R
+ i Ω2I
9Purdue Aeroelasticity
We change the eigenvalue from a pure frequency term to a
frequency plus fake damping term So what?
2
1 h 1 h fa
ω
= − ÷ + +
2
fakie
2
r
1
Trang 10The three other terms are also
modified
h / b
θ
=
0 0
B = µ xθ + Lα = Lh (1 / 2 + a)
D =+ µ xθ + Mh − Lh(1/ 2 + a)
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Purdue Aeroelasticity
Each term contains inertial, structural stiffness, structural damping and aero
information
( )
2
2
2
1
1
2
ig
θ
θ
ω ω
− + ÷+ − + ÷+ + ÷
+
÷
Trang 11To solve the problem we input k and
compute the two values of Ω2
Ω12 = ( ΩR2
)1 + i( Ω2I
)1
Ω22 = ( ΩR2
ω1 = ωθ / ( ΩR)1
ω2 = ωθ / ( ΩR)2
g1 = ( ΩI2
)1 / ( Ω2R
)1
g2 = (ΩI2
)2 / (ΩR2
)2
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Purdue Aeroelasticity
2
2
2
I
g
i θ
ω
ω ω
÷
=
The value of g represents the amount of damping that would be required to keep the system oscillating harmonically It should be negative for a stable system
Trang 12Now compute airspeeds
using the definition of k
V 1 = b ω 1 / k
ω1 = ωθ / ( ΩR)1
ω2 = ωθ / ( ΩR)2
Remember that we always input k so the same value of k is used in both cases One k, two airspeeds and damping values
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Purdue Aeroelasticity
Trang 13Typical V-g Flutter Stability Curve
g
V/bωθ
k decreasing
flutter point
mode 1
mode 2
gh ≈ gθ
Ω2 = ( ωθ2
/ ω 2
)(1 + i g ) ′
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Purdue Aeroelasticity
' h
g = g + = g gθ + g
Trang 14Now compute the eigenvectors
(b θ / h)1 = − D / E( Ω1 ) ; h
b = 1 ( Ω2 = Ω12
)
(h / b θ )2 = − B / A( Ω2) ; θ = 1 ( Ω2 = Ω22
)
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Purdue Aeroelasticity
Trang 15Example
Two-dimensional airfoil mass ratio, µ = 20
quasi-static flutter speed VF = 160 ft/sec
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0.03
h
Trang 16Example
1 / k = 3.1250
Mα = 0.37500 − i3.1250
Mh = 0.50000
ωh = 10 rad / sec
ωθ = 25 rad / sec.
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Purdue Aeroelasticity
Trang 17The determinant
A = 19.8 96 − i4.0973 − 3.2 Ω2
B = − 11.3767 − i2.54 40
D = 2.5311 + i1.22919
E = 9.2380 − i2.3618 − 5.0 Ω2
A E− BD = 16(Ω)4 + (−129.043+ i28.044)Ω2 +199.794 − i64 418= 0
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Purdue Aeroelasticity
Trang 18Final results for this k value – two
g’s and V’s
Ω2
= 4.0326 − i0.87638 ± 3.0067 − i3.0420
− 4.0326 − i0.87638 ± (1.9084 − i0.79702)
= 5.9410 − i1.67340
Ω22 = 2.1242 − i0.07936
ω2 = 17.153 rad / sec ( ωθ = 25 rad / sec)
V1 = 96.157 ft / sec
V2 = 160.810 ft / sec
b = 3.0 ft
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g = + g gθ = −
g = + g gθ = −
Trang 19Final results
g = 0.03 Flutter
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Purdue Aeroelasticity