of the charge relative to the speed of light by ¼ v=c.For a linearly oscillating charge we saw that the emitted radiation was linearlypolarized and its intensity dependence varied as si
Trang 1of the charge relative to the speed of light by ¼ v=c.
For a linearly oscillating charge we saw that the emitted radiation was linearlypolarized and its intensity dependence varied as sin2 This result was derived for thetivistic form of the radiation field Before we can do this, however, we must firstshow that for the relativistic regime ð 1Þ the radiation field continues to consistonly of transverse components, E and E, and the radial or longitudinal electriccomponent Eris zero If this is true, then we can continue to use the same definition
of the Stokes parameters for a spherical radiation field
The relativistic radiated field has been shown by Jackson to be
The brackets ½ ret means that the field is to be evaluated at an earlier or retardedtime, t0¼t Rðt0Þ=c where R/c is just the time of propagation of the disturbancefrom one point to the other Furthermore, c is the instantaneous velocity of theparticle, c _is the instantaneous acceleration, and n ¼ R=R The quantity ! 1 fornonrelativistic motion For relativistic motion the fields depend on the velocity as
Trang 2well as the acceleration Consequently, as we shall soon clearly see the angulardistribution is more complicated.
In Fig 20-1 we show the relations among the coordinates given in (20-1a)
We recall that the Poynting vector S is given by
In (20-3), S n is the energy per unit area per unit time detected at an tion point at time t due to radiation emitted by the charge at time t0¼t Rðt0Þ=c
observa-To calculate the energy radiated during a finite period of acceleration, say from
Trang 3Before we proceed to apply these results to various problems of interest, wemust demonstrate that the definition of the Stokes parameters (20-9) is valid forrelativistic motion That is, the field is transverse and there is no longitudinalcomponent ðEr¼0Þ We thus write (20-1a) as
so (20-11) can be rewritten as
4"0c2 3R urður _Þ _ðururÞ _ður _Þ þ _ðurÞ ð20-13Þ
In spherical coordinates the field Eðr, tÞ is
Taking the dot product of both sides of (20-13) with urand using (20-14), we see that
Er¼ ður _Þ ður _Þ ðurÞður _Þ þ ður _ÞðurÞ ¼0 ð20-15Þ
Trang 4so the longitudinal (radial) component is zero Thus, the radiated field is alwaystransverse in both the nonrelativistic and relativistic regimes Hence, the Stokesparameters definition for spherical coordinates continues to be valid.
The components E and E are readily found for the relativistic regime Wehave
c ¼ ð _xsin þ _zz cos Þurþyyu_ þ ðx_cos _zz sin Þu ð20-18aÞ
c _ ¼ ð €xsin þ €zz cos Þurþyyu€ þ ðx€cos €zz sin Þu ð20-18bÞThe transverse components E and Eare then
4"0c2 3R ðx€cos €zz sin Þ
€
x_zz _x€zzc
For a linear charge that is accelerating along the z axis, and _are parallel, so
Eðr, tÞ ¼ e
4"0c2R
ur ður_vvÞ3
ð20-21bÞ
Trang 5According to (20-11) and (20-14), the field components of (20-21b) are
sin2ð1 cos Þ5
100
0B
@
1C
which is the well-known dipole radiation distribution In (20-25), the nonrelativisticresult, the minimum intensity I ð Þis at ¼ 0, where I 0ð Þ ¼0, and the maximumintensity is at ¼ 90, where I 90ð Þ ¼I0
Equation (20-24), on the other hand, shows that the maximum intensity shiftstoward the z axis as increases To determine the positions of the maximum andminimum of (20-24), we differentiate (20-24) with respect to , set the result equal tozero, and find that
Trang 6so ’ 0 We see that the maximum intensity has moved from ¼ 90ð 1Þ to
¼0ð ’1Þ, that is, the direction of the maximum intensity moves toward thecharge moving along the z axis
In Fig 20-2 the intensity contours for various values of are plotted Thecontours clearly show the shift of the maximum intensity toward the z axis forincreasing In the figure the charge is moving up the z axis from the origin, andthe horizontal axis corresponds to the y direction To make the plot we equated IðÞwith , so
Trang 7Furthermore, using notation, ¼ _zz=c, we can express the velocity and acceleration
2c"0
ez04c
0B
@
1C
Thus, the radiation appears at the same frequency as the frequency of oscillation.With respect to the intensity distribution we now have radiation also appearingbelow the z ¼ 0 axis because the charge is oscillating above and below the xyplane Thus, the intensity pattern is identical to the unidirectional case but is nowsymmetrical with respect to the xy plane InFig 20-3we show a plot of the intensitycontour for ¼ 0:4
Figure 20-3 Intensity contours for a relativistic oscillating charge ¼ 0:4ð Þ
Trang 820.2 RELATIVISTIC MOTION OF A CHARGE MOVING IN
A CIRCLE: SYNCHROTRON RADIATION
In the previous section we dealt with the relativistic motion of charges moving in astraight line and with the intensity and polarization of the emitted radiation Thistype of radiation is emitted by electrons accelerated in devices known as linearaccelerators We have determined the radiation emitted by nonrelativistic chargesmoving in circular paths as well In particular, we saw that a charge moves in acircular path when a constant magnetic field is applied to a region in which the freecharge is moving
In this section we now consider the radiation emitted by relativistically movingcharges in a constant magnetic field The radiation emitted from highly relativisticcharges is known as synchrotron radiation, after its discovery in the operation of thesynchrotron A charge moving in a circle of radius a is shown in Fig 20-4
The coordinates of the electron are
Using the familiar complex notation, we can express (20-36) as
_x
€x
For the nonrelativistic case we saw that !, the cyclotron frequency, was given by
! ¼eB
where e is the magnitude of the charge, B is the strength of the applied magnetic field,
mis the mass of the charge, and c is the speed of light in free space We can obtain
Figure 20-4 Motion of a relativistic charge moving in a circle of radius a in the xy planewith an angular frequency !
Trang 9the corresponding form for ! for relativistic motion by merely replacing m in (20-38),the rest mass, with the relativistic mass m by
The frequency ! in (20-40) is now called the synchrotron frequency
To find the Stokes vector of the emitted radiatin, we recall from Section 20-1that the relativistic field components are
4"0c2 3R ðx€cos €zz sin Þ
€
x_zz _x€zzc
ð20-42bÞSubstituting (20-37b) and (20-37c) into (20-42), we find
2 cos
0BB
1C
where we emphasize that is the observer’s angle measured from the z axis Equation(20-44) shows that for synchrotron radiation the radiation is, in general, ellipticallypolarized The Stokes vector (20-44) is easily shown to be correct because the matrixelements satisfy the equality:
We saw earlier when dealing with the motion of a charge moving in a circle forthe nonrelativistic case that the Stokes vector reduces to simpler (degenerate) forms
Trang 10A similar situation arises with relativistically moving charges Thus, when we observethe radiation at ¼ 0, the Stokes vector (20-44) reduces to
1
0BB
1C
0
0BB
1C
2 cos
0BB
1C
where ! ¼ eB=m ¼ !cis the cyclotron frequency This is the Stokes vector we found
in Section 17.3 for a charge rotating in the xy plane We now examine the intensity,orientation angle, and ellipticity of the polarization ellipse for synchrotron radiation(20-44)
The intensity of the radiation field, IðÞ, can be written from (20-44) asIðÞ ¼e
The orientation angle and the ellipticity angle are ¼1
is further emphasized in Figs 20-6 and 20-7 Figure 20-6 shows (20-49) for
Trang 11¼0:3, 0:4, and 0.5 Similarly,Figure 20-7shows (20-49) for ¼ 0:6, 0:7, and 0.8.For , say, equal to 0.99 we have Ið0Þ=Ið90Þ ¼2 109, which is an extraordinarilynarrow beam.
InFig 20-8we have plotted the logarithm of the intensity IðÞ from ¼ 0to
180for ¼ 0 to 0.9 in steps of 0.3
Figure 20-5 Relativistic intensity contours for ¼ 0:0, 0:1, and 0.2
Figure 20-6 Relativistic intensity contours for ¼ 0:3, 0:4, and 0.5
Trang 12In order to plot the orientation angle , (20-50), as a function of , wenote that, for ¼ 0:0 and 1.0, ¼ 0 and =4, respectively In Fig 20-9we plot
as a function of where the contours correspond to ¼ 0:0, 0:1, , 1:0 fordecreasing
Figure 20-7 Relativistic intensity contours for ¼ 0:6, 0:7, and 0.8
Figure 20-8 Logarithmic plot of the intensity for ¼ 0:0 through 0.9
Trang 13In Fig 20-10 the ellipticity angle , (20-51), is plotted for ¼ 0 to 1.0 over arange of ¼ 0 to 180 For the extreme relativistic case (20-51) becomes
¼ 1
2sin
Figure 20-9 Orientation angle for synchrotron radiation
Figure 20-10 Ellipticity angle for synchrotron radiation
Trang 14It is straightforward to show that (20-52) can be rewritten in the form of an equationfor a straight line, namely,
¼
245
ð20-53Þand this behavior is confirmed inFig 20-10 We see that Fig 20-10 shows that theellipticity varies from ¼ 45(a circle) at ¼ 0and ¼ 45 (a counterclockwisecircle) at ¼ 180
Finally, it is of interest to compare the Stokes vector for ¼ 0 and for ¼ 1.The Stokes vectors are, respectively,
S ¼ K
1 þ cos2sin20
2 cos
0BB
1C
and
S0¼K0
1sin2sin cos cos
0BB
1C
0B
@
1C
1001
0B
@
1C
S ¼ K
1100
0B
@
1C
1100
0B
@
1C
Thus, in the extreme cases of ¼ 0 and ¼ 1, the Stokes vectors—that is, thepolarization states—are identical! However, between these two extremes the polari-zation states are very different
Synchrotron radiation was first observed in the operation of synchrotrons.However, many astronomical objects emit synchrotron radiation, and it has beenassociated with sunspots, the crab nebula in the constellation of Taurus, and radia-tion from Jupiter Numerous papers and discussions of synchrotron radiations haveappeared in the literature, and further information can be found in the references
Trang 15light in the medium Such radiation is called Cˇerenkov radiation, after its discoverer,
P A Cˇerenkov (1937) According to the great German physicist A Sommerfeld, theproblem of the emission of radiation by charged particles moving in an opticalmedium characterized by a refractive index n was studied as early as the beginning
of the last century
The emission of Cˇerenkov radiation is a cooperative phenomenon involving alarge number of atoms of the medium whose electrons are accelerated by the fields ofthe passing particle and so emit radiation Because of the collective aspects of theprocess, it is convenient to use the macroscopic concept of a dielectric constant "rather than the detailed properties of individual atoms
In this section our primary concern is to determine the polarization ofCˇerenkov radiation The mathematical background as well as additional informa-tion on the Cˇerenkov effect can be found in Jackson’s text on classical electro-dynamics Here, we shall determine the radiated field Eðx, tÞ for the Cˇerenkoveffect, whereupon we then find the Stokes parameters (vector)
A qualitative explanation of the Cˇerenkov effect can be obtained by ing the fields of the fast particle in the dielectric medium as a function of time Themedium is characterized by a refractive index n, so the phase velocity of the light isc/n, where c is the speed of light in a vacuum The particle velocity is denoted by v Inorder to understand the Cˇerenkov effect it is not necessary to include the refractiveindex in the analysis, however Therefore, we set n ¼ 1, initially At the end of theanalysis we shall see the significance of n
consider-If we have a charged particle that is stationary but capable of emitting sphericalwaves, then after the passage of time t the waves are described by
Trang 16The maximum and minimum values of the spherical wave along the y axis arefound from the condition dy=dx ¼ 0 From Eq (20-59) we can then show that themaximum and minimum values of y occur at
It is of interest to plot (20-63) for ¼ 0, 0.5, and 1.0 We see from (20-61b) that for
¼1 we have x¼0; that is, the trailing edges of the spherical wave fronts cide In Figs 20-11to20-13.we have made plots of (20-63) for ¼ 0, 0:5, and 1.0.However, to describe the expansion of the spherical wave with the passage of time asthe particle moves, the coordinates of the x axis have been reversed That is, thelargest circle corresponds to 4 sec and appears first, followed by decreasing circles for
coin-3, 2, and 1 sec For completeness we have included a plot for ¼ 0 The plot for
¼1, Fig 20-13, confirms that when the particle is moving with the speed of lightthe trailing edges, which are shown as the leading edges in the plot, coincide
Figure 20-11 Propagation of a spherical wave for a staionary particle ð ¼ 0Þ
Trang 17Figure 20-13 is especially interesting because it shows that the wave fronts onlycoincide for ¼ 1 The question now arises, what happens when > 1? To answerthis question we return to (20-63) We observe that yðtÞ is imaginary if
Figure 20-12 Propagation of a spherical wave for a particle moving with a velocity ¼ 0:5
Figure 20-13 Propagation of a spherical wave for a particle moving with a velocity ¼ 1:0
Trang 18Figure 20-14 Propagation of a spherical wave for a particle moving with a velocity ¼ 1:5.
Trang 19occur because there is a sudden change in the medium (the medium is unaffected),but because the waves, which were previously noninterfering ð 1Þ, now interfereð >1Þ InFig 20-16we have drawn the straight line from the origin through thetangents of the spheres.
The tangents line in Fig 20-16 is called a wake The normal to the wake makes
an angle c, which is called the critical angle From the figure we see that it can beexpressed as
cos c¼c
In free space a particle cannot propagate equal to or faster than the speed oflight However, in an optical medium the phase velocity of the light is less than c and
is given by c=n Thus, if a particle moves with a speed greater than c=n it will generate
an interference phenomenon exactly in the same manner as we have been describing.This behavior was first observed by Cˇerenkov, and, consequently, in optics thephenomenon is called the Cˇerenkov effect and the emitted radiation, Cˇerenkovradiation Furthermore, the critical angle c is now called the Cˇerenkov angle; theshock wave is in the direction given by c
The Cˇerenkov radiation is characterized by a cone Its most important tion is to measure the velocity of fast particles; that is, c is measured by moving adetector such that the maximum intensity is observed At this condition cis deter-mined, and v can then be immediately found
applica-With this background we now determine the intensity and polarization of theCˇerenkov radiation Our analysis draws heavily on Jackson’s treatment of theCˇerenkov effect and classical radiation in general
Figure 20-15 Propagation of a spherical wave for a particle moving with a velocity ¼ 2:5
Trang 20We restate the first two equations of the chapter The electric field emitted by
an accelerating charge is given by
accel-for the relations among the coordinates
The instantaneous energy flux is given by the Poynting vector:
... 20- 11to20-13.we have made plots of (20- 63) for ¼ 0, 0:5, and 1.0.However, to describe the expansion of the spherical wave with the passage of time asthe particle moves, the coordinates of the. .. by the fields ofthe passing particle and so emit radiation Because of the collective aspects of theprocess, it is convenient to use the macroscopic concept of a dielectric constant "rather... data-page="16">The maximum and minimum values of the spherical wave along the y axis arefound from the condition dy=dx ¼ From Eq (20- 59) we can then show that themaximum and minimum values of y occur