Đồ án thiết kế mạng điện gia đình

:1 ô=10km

1

Ð

1.2.2

1: S

3

40

10,5 10,5 Cos 0,85

P = 40M cos = 0,8 U 

40=120 MW -90%)P

%P Pkt = 90%P

Pkt= 90 3 40 108 100    MW

%P Pkt= 90 2 40 72 100    MW

: PF=2 40  80MW

Tmax kV

: G

.

S P  jQ MVA SmaxMVA

.

S P  jQ MVA SminMVA

1.3

–

U = 4,34 16.P kV (1)

- i , km;

P - công , MW;

 160 = 110 kV

V – 8: U8 = 4.34 50 16.38 = 111,33 kV

Ð

P,MW

dây ,km

,kV HT-1 30 50 99,91 110 HT-2 25 72,1 94.3 HT-3 35 58,3 82,3 HT-4 32 44,7 102,4 HT-6 30 80,6 102,76 -5 38 50 111,33 -7 30 60,8 100,93 -8 38 50 111,33 = 110 kV 1.4

P + PHT = Ptt = mPmaxP +Ptd+Pdt (2)

P - ;

PHT – ;

– ;

Pmax- ;

P - P=5% max P  Ptd –

;

Pdt – dt=10% max P 

dt=0; Ptt – ;

max P  =P1+P2+P3+P4+P5+P6+P7+P8=30+25+35+32+38+30+30+38=258 MW

P



g tro Ptd=8% P = 0, 08 120  9, 6MW

Ptt= Pmax+ P = 258+12,9 + 0 + 9,6 = 280,5 MW T Pkt =P =108 MW

PHT= Ptt - P =280,5 – 108 = 172,5 MW 1.5

Q F + QHT = Qtt = m QmaxQ LQ c +Q b+ Qtd + Qdt (3)

QF -

QHT –

max Q  -

Q L-

c Q  -

 

Q b- Q b= 15% Qmax;

Qtd -

Qdt –

dt dt = 0

QF = PF tgF= 108  0,62 = 66,96 MVAr

max

Q

 = Q1 + Q2 +… + 8 = 16,2 + 13,5 + 18,9 + 17,28 + 20,52 + 20,52 +16,2 + 16,2 + 20,52 = 139,32 MVAr

Qtt = 139,32 + 20,9 + 7,2 = 167,42 MVAr

QHT = Qtt – QF = 167,42 – 66,96

= 100,46 MVAr

-

PF = 90%  120 = 108 MW

+ td = 8% 108 = 8,64 MW + N = 108 – 8,64 = 99,36 MW

PH = Ptt – PN = 280,5 – 99,36 = 181,14 MW

Pttmin = 50% Pttmax = 50% 280,5 = 140,25 MW

W

PF = 90% 80 = 72 MW

+ Ptd = 8% 72 = 5,76 MW

+ N = 72 – 5,76 = 66,24 MW

PH = 140,25 – 66,24 = 74,01 MW

W

công s PF = 2  40 = 80 MW

+ Ptd = 8%  80 = 6,4 MW + N = 80 – 6,4 = 73,6 MW

PH = 280,5 – 73,6 = 206,9 MW

PF ,MW %P Ptd , MW PN , MW PH , MW 108 90 8,64 99,36 181,14 72 90 5,76 66,24 74,01 80 100 6,4 73,6 206,9

–

-

-

-

-

Ð

Ð

Ð

Ð

Ð

-

kt

A

tb

Tmax kt = 1,1(A/mm2)

– – trang 295 ) imax i kt I F J 

Fi – 2

]; Iimax – max max 3 i i đm S I n U   103 [A] maxi -

A ; –

U – ;

 70mm2

(%) i. i 2 i. i 100%

i

đm

P R Q X U

U

  

Pi, Qi W MVAr)

P N - W ;

kt = 108 MW; Ptd = 8,64 MW; P N = 5%PN = 0,05  106 = 5,3

MW;

-3 – – – - W

P3- = 11,94 MW suy ra Q3- = tg(arccos0,88).P3- = 6,45 MVAr 3- = 13,57 MVA a)

Imax 3- = max 3 3 13,57 3 10 10 3 2 3.110 NĐ đm S n U     = 35,61 A Fkt = max 3 35, 61 1,1 NĐ kt I J   = 32,37 A A - 2

Icp A - -

- trang 258 )

Ftc = 70mm2 = 70mm2

– –

-

-

0, 46 90, 6 20,84 / 2

o

n

4 0

67, 78 1,1

Ð

kt = 70mm2

-

62,5

3 110 2 3 110

HT HT

kt = 150mm2 > 70mm2

-

Isc = 2.Ibtmax = 2164,04 = 328,08 A < Icp A

A - o= 0,21 /km , xo = 0,42 /km ; b0 = 2,74.10-6 2;3;4 - - trang 258)

67, 78 1,1

Ð

kt = 70mm2

-

81,34 1,1

Ð

kt = 95mm2

ki

-

70, 46

3 110 2 3 110

HT HT

kt = 150mm2 > 70mm2

-

Isc = 2.Ibtmax = 2184,92 = 369,83 A < Icp A

b)

A - o= 0,21 /km , xo = 0,42 /km , bo = 2,74.10-6 2;3; - - trang 258)

0, 21 44, 7 4, 69 / 2

– 5 – 7

37,51 20, 25

3 110 1 3 110

NĐ NĐ

kt = 185mm2 > 70mm2

–

+ – 7

+ – 7

– :

31 16, 47

3 110 1 3 110

NĐ NĐ

kt = 95mm2 > 70mm2

–

–

– 5

A -185 o= 0,17 /km , xo = 0,414 /km , bo= 2,84.10-6 2;3;4 )

0, 21 60,8 12, 77 / 1

0, 46 42,9 19, 73 / 1

max – max = 5000h

4 2 (0,124 5000.10 ) 8760 3411( )h

  Pmax  14, 20(MW)

4.1 g

–

40

47, 060,85

max

đm

S

S 

MBA

Io(%)

R ()

X ()

,

o

Q

Cao

TPDH 25000/110

TPDH 32000/110

- 

-

L<70 L>70

C

: T ,HT

dây

,

d

.10 , 2

S MVA

' ,

S MVA

,

,

b

S MVA

,

2 2

2 2

12,38 5, 67

(20,84 19,93) 0,32 0,31110

m Pcc = 280,46 MW

280, 46 0, 62 173,89

dây

,

d

.10 , 2

HT – 1 8,25+j10,73 1,33 0,12+j0,8 2,54+j55,9 15+j8,1

S MVA

,

,

b

S MVA

,

2 2

2 2

6,59 2,92

(20,84 19,93) 0, 08 0, 09110

QCHc = 11021,57.10-4 = 1,9 MVAr

QCHd = 115,521,57.10-4 = 2,09 MVAr

m Pcc = 132,67 MW

– –

,

dây

,

d

S MVA

,

cs

cs = 115,5kV

t

– 3 –

3 H'. H H' . H cs cs P R Q X U U U    3 49, 26.8, 715 26,37.34, 08 121 110, 02 121 U     kV

3 3 3 b b b b q P R Q X U U U    3 35,12.0,935 21,12.21, 75 110, 02 105,5 110, 02 q U     kV

3

3

N

P R Q X

U U

U



 

12, 7.20,84 5,89.19,93

110, 02

N

U     kV

– 5

– 3 –

: 3 H'. H H' . H cs cs P R Q X U U U    3 11,19.9, 65 2,58.55,83 115,5 113,32 115,5 U     kV 3 3 3 b b b b q P R Q X U U U    3 17,51.1,87 9, 72.43,5 113,32 109,3 113,32 q U  kV    3 '' ''

3 N N N N N P R Q X U U U    6,51.20,84 2,83.19,93 109,3 111, 06 109,3 N U     kV – 5 –

34:

A 1 2 3 4 5 6 7 8 Uq,kV 108,64 108,73 109,3 109,63 103,43 107,56 103,51 103,43 5.2.1.3

– 3 –

: 3 H'. H H' . H cs cs P R Q X U U U    3 46,57.8, 715 29,39.34, 08 121 109,37 121 U  kV    3 3 3 b b b b q P R Q X U U U    3 35,12.0,935 21, 74.21, 75 109,37 104,8 109,37 q U  kV    3 '' ''

3 N N N N N P R Q X U U U    8, 21.20,84 4,5.19,93 109,37 106,99 109,37 N U     kV – 5 –

35:

A 1 2 3 4 5 6 7 8 Uq,kV 108,23 105,15 104,8 109,52 95,58 103 95,85 95,58 5.2.3

- -32000/110

  9 1, 78%, U = 115kV , U = 11kV

- max% = +5% - min% = 0% - sc% = 0 – 5%

Uyc = U + dU%.U

max 10 5 10 10,5 100 yc U     kV min 10 0 10 10 100 yc U     kV max 10 5 10 10,5 100 yc U     kV

max max

max

117, 77 10,5

min min

min

108, 64 11

10, 03119,10

min min

csc

108, 23 11

10,54112,95

 P d 9,98MW

4 2 (0, 029 0, 035) 0,512 o io P P MW        

9,98 0,96 0,512 11, 452 d b o P P P P MW           

max 11, 452 % 100 100 4, 44% 258 P P P      

( d b). o. A P P  P t        –

 -

4 2 4 2 max (0,124 T .10 ) 8760 (0,124 5000.10 ) 8760 3411h          

(9,98 0,96) 3411 0,512 8760 41801, 46 A MW h       

132, 25.10

102,52 / 1290.10

Y

đ kW h A

W

9 max

1334, 7.10

5,17.10 / 258

o

K

P



–

–

17 W 109 W 5,17

1

1

1

1

2

3

4

5

7

9

9

9

9

10

10

14

14

n 1 16

23

28

33

38

46

46

47

3 47

48

49

49

51

51

51

52

52

53

53

A 54

công 54

54

62

68

71

5.2.1 71

74

76

78

5.3 T – 79

79

80

81

82

82

82

82

82