14.7.1 Rigid Pile under Vertical Loading Consider a rigid pile of length L and radius R in clay with shear modulus G and undrained shear strength c, under purely vertical loading.. At
Trang 1there are a number of other possible forms for compressible large strain
elastic-ity On differentiation, this gives (with no summation over i)
which is very similar to the incompressible result Note that J cannot be
ex-pressed analytically in terms of O because of the transcendental nature of
Now consider that embedded within this material is a (dilute) proportion of
unidirectional fibres, with a small concentration c (volume of fibres divided by
total volume) The fibres have a Young’s modulus E , and they are aligned in f
the direction with unit vector n i
We assume that the fibres are bonded to the parent (matrix) material and
therefore undergo the same strain in the direction n The elongational strain in i
Trang 2this direction is Hij i j n n , so it is straightforward to see that the free energy of the
ij K kk ij G ijc cE kl k l i j n n n n
For a given strain, the material simply exhibits a stress that is augmented by
a term that depends on the fibres
Now consider the possibility that the matrix material exhibits von Mises type
plasticity, as described (in terms of the Gibbs free energy) in Section 5.2.2 The
Helmholtz free energy becomes
Equating F and ij F immediately gives ij / , and eliminating the general-0
ised stresses, we obtain an expression for the yield surface in strain space:
4G H Dijc ij H Dijc ij 2k (14.60) 0
In principle we can solve (14.57) for the strains in terms of the stresses and
in-ternal variables, and substitute this result in (14.60) to obtain the yield surface in
terms of the stress and internal variables In practice, this is most
straightfor-wardly carried out by numerically inverting the expression:
The presence of the internal variables in the expression for the yield surface
in terms of stresses means that the composite material exhibits strain hardening
Trang 314.7 Analysis of Axial and Lateral Pile Capacity
The final example, drawn from geotechnical engineering, demonstrates how the
continuous hyperplastic approach can be used to analyse simple systems
involv-ing soil-structure interaction Unlike some previous applications, in this case we
can give a physical meaning to the internal coordinate K We consider a pile
analysed by the “Winkler” method in which the reaction from the soil is
deter-mined by pointwise load-displacement relationships along the pile, but
interac-tions among the relainterac-tionships are not taken into account The method is
other-wise known as the use of “t-z” curves for vertical loading and “p-y” curves for
lateral loading
14.7.1 Rigid Pile under Vertical Loading
Consider a rigid pile of length L and radius R in clay with shear modulus G and
undrained shear strength c, under purely vertical loading The resistance to
movement is provided by shaft resistance on the side of pile and end bearing at
the tip, see Figure 14.8 At each point along the pile, we assume a simple
elastic-plastic relationship (the “t-z” relationship) between the vertical displacement w
and the shear stress W (these variables are usually called z and t, respectively, in
the piling literature) We specify the response at any point along the pile by the
following functions, in which it is convenient to work from the Helmholtz free
where ] and a are dimensionless factors (see Fleming et al., 1985) and D is the
plastic vertical displacement of the pile shaft The standard approach gives
Trang 4The end-bearing stress V on the pile is also specified by an elastic-plastic
rela-tionship:
22
where the stiffness and end-bearing factors follow the approach taken by
Flem-ing et al., (1985) We distFlem-inguish D , the plastic displacement of the pile base, L
from D (the equivalent for the pile shaft) because we have in effect two parallel
plasticity mechanisms in which the onset of plastic strains occurs at a much
smaller displacement on the shaft than at the base The analogy is shown in
Figure 14.9
Figure 14.8 Tractions on a pile
Trang 5Figure 14.9 Conceptual models of shaft and base of pile
Trang 6w R
and the yield function at the pile tip can be derived as y F L N c c 0
The entire pile response can now be obtained by integrating the energy and
dissipation terms over the shaft of the pile and adding the end-bearing term
summed over the end area For convenience, we express the distance down the
pile in terms of a dimensionless coordinate K z L , where z is the distance
below ground level and L is the length of the pile To emphasise that it is now
a function of K, we rewrite D as ˆD Again, we must distinguish here between
ˆ 1
D , the plastic displacement at the tip relevant to skin friction, and D , the L
plastic displacement at the tip of the pile relevant to end bearing The free
en-ergy and dissipation functions are
2 0
2
2ˆ1
L L
R GR
1
2 0
Application of the standard approach now results in the following expression
for the vertical load V:
1 0
Trang 7
41
It is straightforward to show that these equations correctly define the
me-chanical behaviour of the pile, in that the total load is the integral of the shear
stress over the surface of the pile, plus the end bearing; each of these terms is
determined by a simple elastic-plastic relationship Note that no additional
diffi-culty is caused if the strength c is a function of depth
14.7.2 Flexible Pile under Vertical Loading
The only modification to the energy expressions necessary to accommodate
a pile that is flexible rather than rigid is that there is now an additional free
en-ergy term due to elastic compression of the pile:
where we have written the vertical displacement w as wˆ wˆ K to emphasise
that it is now a function of the distance down the pile The total free energy
therefore becomes
2 1
2 2
and the dissipation expression is unchanged
We consider the possibility of the following externally applied loading on the
pile: (a) a vertical load V at the top (as before) and (b) a distributed load ˆ v per
unit length along the pile Later, we shall assume that the latter is zero, but it is
convenient to introduce it at this stage The work done by these external forces
is the Frechet differential of the free energy with respect to the displacement ˆw
(Compare it with the usual equation V w wH for a continuum, so that f
ˆ 0 ˆ ˆ w,ˆ
Trang 8Carrying out the Frechet derivative, we obtain
Applying integration by parts to the second term in the integral on the
right-hand side, this becomes:
ˆˆ
Noting though that ˆw is arbitrary, we can simply compare coefficients in
terms in ˆw For 0 K (note the strict inequalities), we compare the terms 1
within the integrals to obtain
2 2
ˆˆ
w S W
which is simply the relationship between the applied vertical load and the
com-pressive strain at the top of the pile
Similarly, at the base, we compare terms in wˆ 1 to obtain
which is the relationship between the end-bearing force and the compressive
strain at the pile toe
Trang 9Finally, if we express f and d in ways similar to those used for the rigid pile,
1
2 0
which is the differential equation for the compression of the pile in terms of the
mobilised shear stress on the pile shaft (which is in turn given by an
which expresses the elastic-plastic response for the end bearing at the pile tip
and its relationship to the strain in the base of the pile
The above equations could have been readily (and more easily) obtained by
conventional methods of analysis of the mechanics of the pile, but our purpose
here is to demonstrate the consistency and generality of the hyperplasticity
ap-proach The important principle illustrated in this example is that we were able
to define the correct mechanical behaviour from a free energy functional that
contained differential as well as algebraic terms
Note that the above formalism for describing the pile problem is only one of
a number of possible approaches In particular, we chose to treat ˆw as if it were
an external kinematic variable An alternative would be to treat ˆw as an internal
variable for 0 K d and just the displacement 1 wˆ 0 as an external variable In
this latter case, the orthogonality condition results in a vertical equilibrium
equation at any point down the pile, and this provides an example which brings
physical meaning to the interpretation of orthogonality as an “internal
equilib-rium” condition
Trang 1014.7.3 Rigid Pile under Lateral Loading
Now consider the rigid pile under lateral loading We shall consider the
resis-tance to movement provided solely by shaft resisresis-tance (i e we ignore any lateral
shear resistance on the tip) At each point along the pile, we assume a simple
elastic-plastic relationship (the “p-y” relationship) between the lateral
displace-ment ˆu u z T K T and the normal stress V (called y and p, respectively, u L
in piling literature) We specify the following functions:
where k is the “modulus of subgrade reaction” and N is a lateral bearing h
capacity factor The internal variable ˆD now represents the lateral plastic
dis-placement of the pile The standard approach gives
w
ˆS
Now the entire pile response can be obtained by integrating the energy and
dissipation terms over the length of the pile:
Trang 11It is straightforward to show that these equations correctly define the
me-chanical behaviour of the pile, in that the horizontal load is the integral of the
lateral stress over the length of the pile, and the moment is the integral of the
lateral stress times distance from the surface The lateral stress is given by
a simple elastic-perfectly plastic relationship
14.7.4 Flexible Pile under Lateral Loading
In the same way as for the axially loaded pile, the only change in the energy
functions that needs to be considered for a flexible pile under lateral loading is
to add an energy term that accounts for the bending stiffness:
and the dissipation is still as given by Equation (14.99)
Now consider that the pile is subjected to the following external loads: (a)
a horizontal force H and moment M at the head of the pile and (b) distributed
lateral load ˆh and moment ˆ m The latter are again just introduced for
conven-ience and will both be set to zero later As for the vertical pile, we can relate the
external loads to the Frechet differential of the free energy:
Trang 12Applying integration by parts (a) to the last term in the integral on the
left-hand side of the equation and (b) twice to the last term in the integral on the
right-hand side, we obtain
Now, noting that ˆu is arbitrary, we follow the same procedure as before for
the vertically loaded pile First, we set ˆh and ˆ0 m to obtain for 00 K , 1
which is simply the differential equation relating bending of the pile to the
ap-plied lateral load
Next, at the top of the pile, we note that uˆ 0 and uˆ 0
which are effectively the boundary conditions at the top of the pile for shear
force and bending moment
Trang 13Finally, at the bottom of the pile, we treat uˆ 1 and uˆ 1
K
w wK as ent to obtain the conditions of zero shear force and bending moment at the base:
The response of the pile is thus represented by the differential equation for
the bending of the pile as a function of the applied lateral loading, which in turn
is determined by an elastic-plastic relationship:
supplemented by the boundary conditions at the top and bottom of the pile
It is freely admitted that a conventional structural analysis approach to
deri-vation of the governing equations for the pile would be slightly more
straight-forward, and certainly would involve simpler mathematics Our purpose here is
not, however, to find the simplest way of describing pile behaviour Instead, it is
to demonstrate the power and generality of the continuous hyperplastic
ap-proach Solutions can be obtained by consistently applying the hyperplastic
formulation in cases where the functionals describing the system behaviour are
rather more complex than we have encountered hitherto In particular, they
include functions of differentials of continuous kinematic variables
The application of hyperplasticity principles to modelling foundation
behav-iour is finding a number of applications Einav (2005) presents an analysis of the
behaviour of piles which follows a rather similar approach to the analysis
pre-sented above Houlsby et al (2005) use a similar approach for the analysis of
shallow foundations under cyclic loading Finally the “force resultant” models
for shallow foundation behaviour, originally expressed in terms of conventional
plasticity theory [Martin and Houlsby (2001), Houlsby and Cassidy (2002)], can
be expressed in the hyperplasticity framework, enabling the extension to
con-tinuous hyperplasticity, e g Lam and Houlsby (2005)
Trang 14Concluding Remarks
15.1 Summary of the Complete Formalism
In conclusion, we restate the complete hyperplastic formalism in a concise form
To make it sufficiently general, we accommodate (a) infinite numbers of internal
variables, (b) total dissipation, and (c) rate effects For brevity, we use a
sym-bolic rather than subscript notation for tensors
Assume that the local state of the material is completely defined by
knowl-edge of (a) the strain H, (b) the entropy s, and (c) certain internal variables D
The form of H is tensorial, s is scalar, and we make no restrictions at this stage on
the form of D (for instance, they could be scalars or tensors, possibly infinite in
number) Then, the constitutive behaviour of the material will be completely
defined by specifying two thermodynamic potential function(al)s of state
The first potential is the specific internal energy, a function(al) of state
> , , @
u u H D , which is a property satisfying the first law of thermodynamics: s
where V is the stress tensor that is work-conjugate to the strain rate and q is the
heat flux vector
The second potential is the force potential z z>H D K D , a function(al) of , , , ,s @
state, change of internal variable D , and entropy flux K q T ( T is the
non-negative thermodynamic temperature) such that
where F D denotes the action of the linear operator F on , D (F is the Frechet
derivative of z with respect to D ) The quantity d is the specific total dissipation
(the first part is usually called the thermal dissipation, and the second part the
Trang 15mechanical dissipation) It satisfies the Second Law of Thermodynamics in the
Assuming that u u>H D is Frechet-differentiable and denoting F as the , ,s @
linear operator that is minus the Frechet derivative of u with respect to D, we
and Ziegler’s orthogonality condition in the form that the following two linear
operators are identical:
F F (15.9) from Equation (15.7), we obtain (for the mutually independent processes of
straining and change of entropy):
w
T
Equations (15.8)–(15.11) are sufficient to establish the constitutive behaviour
of a material defined by u u>H D and , ,s @ z z>H D K D In particular, the , , , ,s @
entire response arises from the fact that these functionals serve as potentials for
various dependent variables
It is sometimes convenient to supplement the above potentials by constraints,
either in terms of certain variables or of their rates For cases involving either
unilateral or bilateral constraints, the formalism of convex analysis allows
... “modulus of subgrade reaction” and N is a lateral bearing hcapacity factor The internal variable ˆD now represents the lateral plastic
dis-placement of the pile The standard... modelling foundation
behav-iour is finding a number of applications Einav (2005) presents an analysis of the
behaviour of piles which follows a rather similar approach to the analysis
pre-sented... particular, we chose to treat ˆw as if it were
an external kinematic variable An alternative would be to treat ˆw as an internal
variable for 0 K d and just the displacement